c++運(yùn)算符重載習(xí)題

1、Task8-1/*1.定義一個復(fù)數(shù)類Complex,重載運(yùn)算符“+”，使之能用于復(fù)數(shù)的加法運(yùn)算將運(yùn)算符函數(shù)重載為非成員、非友元的普通函數(shù)。編寫程序，求兩個復(fù)數(shù)之和*/#include<iostream>usingnamespacestd;cIassCompIex(pubIic:Complex()real=0;imag=0;CompIex(doubler,doublei)real=r;imag=i;voiddisplay();doublereaI;doubleimag;voidComplex:display()(cout«"("«real

2、71;","«imag«"i)”；)CompIexoperator+(CompIex&d,CompIex&c2)CompIexp;二十；二十；returnp;intmain()(CompIexc1(3,5),c2(2,5),c3;0;cout«"+"0;cout«"="c3=c1+c2;0;f5匚+*腎習(xí)»8章作電收5k8口由相p,5i>+<2,5£>-<5,IBi>Pr-oGcssr-etiir-rt"d0C

3、QKaexscutiontime：=6.481sPressanykeytocontinue,Task8-2/*2.定義一個復(fù)數(shù)類Complex,重載運(yùn)算符“”/",使之能用于復(fù)數(shù)的加、減、乘、除。運(yùn)算符重載函數(shù)作為Complex類的成員函數(shù),編程，分別求兩個復(fù)數(shù)之和差積商。*/#incIude<iostream>usingnamespacestd;cIassCompIexpubIic:Complex()real=0;imag=0;CompIex(doubIer,doublei)real=r;imag=i;CompIexoperator+(CompIex&c2);C

4、ompIexoperator-(CompIex&c2);CompIexoperator*(CompIex&c2);CompIexoperator/(Complex&c2);voiddispIayo;private:doublereaI;doubleimag;CompIexComplex:operator+(CompIex&c2)CompIexc;=real+;=imag+;returnc;Comp I ex Comp lex:operator"(Comp I ex &c2)Comp I ex c;returnc;)Complex c;CompI

5、exComplex:operator*(CompIex&c2)二real*;=imag*;returnc;)CompIexComplex:operator/(CompIex&c2)CompIexc;二(reaI*+imag*/*+*;二(imag*/*+*;returnc;)voidComplex:display()cout«"("«real«n,"«imag«"i)"«endI;)intmain()CompIexd(3,4),c2-10),c3;c3=c1+c2;co

6、ut«"c1+c2="0;c3=c1-c2;cout«"c1-c2="0;c3=c1*c2;cout«nc1*c2="0;c3=d/c2;cout«"c1/c2="0;return0;司gC+期習(xí)饃8空作業(yè)M煎k&Tfxecl+c2=<8,-6i>cI-c2=<-2,X4i5匚1利cI/c2=<-0-2,0.4i?Processreturned0<0x0>executIontine-0.638sPressanyke51tocontinue_T

7、ask8-3/*3.有兩個矩陣a和b,均為n行m歹U（m、n的值自己給出），求兩個矩陣之和、差、積、商，重載運(yùn)算符“使之能用于矩陣向加減乘除，如c=a+b、c=a*bo*/#incIude<iostream>#definen2#definem3usingnamespacestd;cIassMatrix1D:CH悌習(xí)8意作業(yè)'匕業(yè)"3總燼inputvalueofmatrix：1863894inputv"lueofmatrix：123432Matrixa：18E3894Matrixh：123432,3+c=N-atrixa+Mettrixk1?8612126

8、k7 4 Ga - Hatr-Ik bMatrixc-Matrixa.*Matrixb：18129322?8=Macpixa/rtAti*ixb：1831232Processreturned0CBxQ)&c：uti«ntimes46-669BPriisdnyk總y"Ieontinu.e.在第三題的基礎(chǔ)上,重載運(yùn)算符>>和<<，使之能用于該矩陣的輸入和輸出*/#include<iostream>#definen2#definem3usingnamespacestd;cIassMatrixjj8C1修習(xí)茜a克作業(yè)常輸人第一個陣ISB6

9、情輸入第二個nF1矩陣246W32tlatrixa：16S6S£4tlatrixb；Q46Matrixc=tlotrixQ+Matrix1212121296|32|Processreturnedg(0x0>executiontinc：36.78GsPressAnyketocontinue.實(shí)現(xiàn)分?jǐn)?shù)類中的運(yùn)算符重載，在分?jǐn)?shù)類中可以完成分?jǐn)?shù)的加減乘除(運(yùn)算后再化簡)、求反、比較(6種關(guān)系)的運(yùn)算*/#include<iostream>#include<>usingnamespacestd;intgcd(intm,intn);cIassFraction(pri

10、vate:intnume;/分子intdeno;/分母pubIic:Fraction(intnu=0,intde=1);/構(gòu)造函數(shù)，初始化用voidSet(intnu=Otintde=1);/置值，改變值時(shí)用Fractionoperator+(Fraction&c2);Fractionoperator-(Fraction&c2);Fractionoperator*(Fraction&c2);Fractionoperator/(Fraction&c2);booloperator>=(Fraction&c2);Fractionoperator-()；v

11、oiddispIay();voidSimplifyO;/化簡(使分子分母沒有公因子)；Fraction:Fraction(intnu,intde)(if(de!=0)(nume=nu;deno=de;)eIse(cout<<”格式錯誤，程序退出n”；exit(0);)voidFraction:Set(intnu,intde)(if(de!=0)(nume=nu;deno=de;)voidFraction:display()(cout«nume«'/'«deno«endI;)求分子，分母最大公約數(shù)intgcd(intm,intn

12、)intr;if(m<n)r=m;m=n;n=r;)while(r=m%n)(if(r=0)break;m=n;n=r;)returnn;)將分?jǐn)?shù)化簡voidFraction:SimpIify0(intn=gcd(nume,deno);nume=nume/n;deno=deno/n;cout«nume«1/1«deno;)FractionFraction:operator+(Fraction&c2)(Fractionc;二deno*;=nume*+*deno;returnc;)FractionFraction:operator-(Fraction&a

13、mp;c2)(Fractionc;二deno*;=nume*returnc;)FractionFraction:operator*(Fraction&c2)(Fractionc;二deno*;=nume*;returnc;FractionFraction:operator/(Fraction&c2)Fractionc;=deno*;=nume*;returnc;)boolFraction:operator>=(Fraction&c2)nume=nume*;=*deno;if(nume>=returntrue;eIsereturnfalse;FractionF

14、raction:operator-()Fractionc;=nume;=deno;returnc;)intmain()(Fractiond(1,2),c2(5,8),c;cout«"c1="；0;cout«"c2二"；0;c=c1+c2;cout«"c1+c2="0;cout«endI;c二c1-c2;cout«"c1-c2="0;cout«endI;c=c1*c2;cout«"c1*c2="0;cout«endI;c=c1/c2;cout«Hc1/c2=n;0；c