




版權(quán)說(shuō)明:本文檔由用戶(hù)提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
1、Process Capability Analysis(Measure Phase)Scope of ModuleProcess VariationProcess CapabilitySpecification, Process and Control LimitsProcess Potential vs Process PerformanceShort-Term vs Long-Term Process CapabilityProcess Capability for Non-Normal DataCycle-Time(Exponential Distribution)Reject Rate
2、(Binomial Distribution)Defect Rate(Poisson Distribution)Process VariationProcess Variation is the inevitable differences among individual measurements or units produced by a process.Sources of Variationwithin unit(positional variation)between units(unit-unit variation)between lots(lot-lot variation)
3、between lines(line-line variation)across time(time-time variation)measurement error(repeatability & reproducibility)Types of VariationInherent or Natural VariationDue to the cumulative effect of many small unavoidable causesA process operating with only chance causes of variation present is said to
4、be “in statistical control Types of VariationSpecial or Assignable VariationMay be due to a) improperly adjusted machine b) operator error c) defective raw materialA process operating in the presence of assignable causes of variation is said to be “out-of-controlProcess CapabilityProcess Capability
5、is the inherent reproducibility of a processs output. It measures how well the process is currently behaving with respect to the output specifications. It refers to the uniformity of the process.Capability is often thought of in terms of the proportion of output that will be within product specifica
6、tion tolerances. The frequency of defectives produced may be measured ina)percentage (%)b)parts per million (ppm)c)parts per billion (ppb)Process CapabilityProcess Capability studies can indicate the consistency of the process outputindicate the degree to which the output meets specificationsbe used
7、 for comparison with another process or competitorProcess Capability vs Specification Limitsa)b)c)a) Process is highly capableb) Process is marginally capablec) Process is not capableThree Types of LimitsSpecification Limits (LSL and USL) created by design engineering in response to customer require
8、ments to specify the tolerance for a products characteristicProcess Limits (LPL and UPL)measures the variation of a processthe natural 6 limits of the measured characteristicControl Limits (LCL and UCL)measures the variation of a sample statistic (mean, variance, proportion, etc)Three Types of Limit
9、sDistribution of Individual ValuesDistribution of Sample AveragesProcess Capability IndicesTwo measures of process capabilityProcess PotentialCpProcess PerformanceCpuCplCpkProcess PotentialThe Cp index assesses whether the natural tolerance (6) of a process is within the specification limits.Process
10、 PotentialA Cp of 1.0 indicates that a process is judged to be “capable, i.e. if the process is centered within its engineering tolerance, 0.27% of parts produced will be beyond specification limits. Cp Reject Rate1.000.270 %1.330.007 %1.506.8 ppm2.002.0 ppbProcess Potentiala)b)c)a) Process is highl
11、y capable (Cp2)b) Process is capable (Cp=1 to 2)c) Process is not capable (Cp1.5)b) Process is capable (Cpk=1 to 1.5)c) Process is not capable (Cpk1)a)Cp = 2Cpk = 2b)Cp = 2Cpk = 1c)Cp = 2Cpk 1Example 1Specification Limits:4 to 16 gMachineMeanStd Dev(a) 10 4(b) 10 2(c) 7 2(d) 13 1Determine the corres
12、ponding Cp and Cpk for each machine.Example 1AExample 1BExample 1CExample 1DProcess CapabilityFor a normally distributed characteristic, the defective rate F(x) may be estimated via the following:For characteristics with only one specification limit:a)LSL onlyb)USL onlyLSLUSLExample 2Specification L
13、imits:4 to 16 gMachineMeanStd Dev(a) 10 4(b) 10 2(c) 7 2(d) 13 1Determine the defective rate for each machine.Example 2Mean Std Dev ZLSL ZUSL F(xUSL) F(x) 10 4 -1.51.5 66,807 66,807133,614 10 2 -3.03.0 1,350 1,350 2,700 7 2 -1.54.5 66,807 3 66,811 13 1 -9.03.0 0 1,350 1,350Lower Spec Limit= 4 gUpper
14、 Spec Limit= 16 gProcess Potential vs Process Performance(a) Poor Process Potential(b) Poor Process PerformanceLSLUSLLSLUSLExperimental Design to reduce variationExperimental Design to center mean to reduce variationProcess Potential vs Process Performance Process Potential Index (Cp) Cpk 1.0 1.2 1.
15、4 1.6 1.8 2.0 1.02,699.91,363.31,350.01,350.01,350.01,350.0 1.2 318.3 159.9 159.1 159.1 159.1 1.4 26.7 13.4 13.4 13.4 1.6 1.6 0.8 0.8 1.8 0.1 0.0 2.0 0.0Defective Rate (measured in dppm) is dependent on the actual combination of Cp and Cpk.Process Potential vs Process Performancea)Cp = 2Cpk = 2b)Cp
16、= 2Cpk = 1c)Cp = 2Cpk 1Cp Cpk Missed OpportunityAlternative Process Performance IndexProcess capability statistics measure process variation relative to specification limits. The Cp statistic compares the engineering tolerance against the processs natural variation.The Cpk statistic takes into accou
17、nt the location of the process relative to the midpoint between specifications. If the process target is not centered between specifications, the Cpm statistic is preferred.Process StabilityA process is stable if the distribution of measurements made on the given feature is consistent over time.Time
18、Stable ProcessTimeUnstable ProcessucllclucllclWithin vs Overall CapabilityWithin Capability (previously called short-term capability) shows the inherent variability of a machine/process operating within a brief period of time.Overall Capability (previously called long-term capability) shows the vari
19、ability of a machine/process operating over a period of time. It includes sources of variation in addition to the short-term variability.Within vs Overall CapabilityWithinOverallSample Size30 50 units 100 unitsNumber of Lotssingle lotseveral lotsPeriod of Timehours or daysweeks or monthsNumber of Op
20、eratorssingle operatordifferent operatorsProcess Potential Cp PpProcess Performance Cpk PpkWithin vs Overall CapabilityWithin CapabilityOverall CapabilityThe key difference between the two sets of indices lies in the estimates for Within and Overall .Estimating Within and OverallConsider the followi
21、ng observations from a Control Chart: S/NX1X2 XkMeanRangeStd Dev1x1,1x2,1 xk,1 X1 R1 S12x1,2x2,2 xk,2 X2 R2 S2: : : : : : :mx1,mx2,m xk,m Xm Rm SmThe overall variation Overall is estimated byEstimating Within and OverallThe within variation Within may be estimated by one of the following:(a)R-bar Me
22、thodwhered2 is a Shewhart constant = (k)(b)S-bar Methodwherec4 is a Shewhart constant = (k)(c)Pooled Standard Deviation MethodIn MiniTab, the Pooled Standard Deviation is the default method.Estimating Within and OverallIn cases where there is only 1 observation per sub-group (i.e. k=1), the Moving R
23、ange Method is used, where .The within variation Within is then estimated using eithera)the Average Moving Range :b)the Median Moving Range :Example 3The length of a camshaft for an automobile engine is specified at 600 2 mm. Control of the length of the camshaft is critical to avoid scrap/rework.Th
24、e camshaft is provided by an external supplier. Assess the process capability for this supplier.The data is available in Process Capability Analysis.MTW.Example 3Stat Quality Tools Capability Analysis (Normal)Example 3Example 3AHistogram of camshaft length suggests mixed populations. Further investi
25、gation revealed that there are two suppliers for the camshaft. Data was collected over camshafts from both sources.Are the two suppliers similar in performance?If not, what are your recommendations?Example 3AStat Quality Tools Capability Sixpack(Normal)Example 3AExample 3AWhats Six Sigma Quality The
26、nOriginal Definition by Motorola:if the specification limits are at least 6 away from the process mean , i.e. Cp 2,and the process shifts by less than 1.5, i.e. Cpk 1.5,then the process will yield less than 3.4 dppm rejects.66Shift1.54.5Whats Six Sigma Quality NowMikel J Harry claims that the proces
27、s mean between lots will vary, with an average process shift of 1.5.k = z + 1.5 k = z + 1.5 Shift1.5zNote:Sigma Capability = (dpmo) (dppm)Process Capability for Non-Normal DataNot every measured characteristic is normally distributed.CharacteristicDistributionCycle TimeExponential Reject RateBinomia
28、lDefect RatePoissonProcess Capability for Cycle TimeThe Weibull Distribution is a general family of distribution withwherescale parameter is the value at which CDF=68.17%,andshape parameter determines the shape of the PDF.Process Capability for Cycle TimeAt =1,the Weibull Distribution is reduced toF
29、or an Exponential Distribution,The Exponential Distribution is thus a Weibull Distribution with =1.Weibull (x; =1, )Exponential (x; )Example 4A customer service manager wants to determine the process capability for his department. A primary performance index is the time taken to close a customer com
30、plaint. The goal for this index is to close a complaint within one calendar week.Performance over the last 400 complaints was reviewed.Example 4Stat Quality Tools Capability Analysis (Weibull)Example 4Example 4AStat Quality Tools Capability Sixpack (Weibull)Example 4AProcess Capability for Reject Ra
31、teFor a Normal Distribution, the proportion of parts produced beyond a specification limit isReject RateProcess Capability for Reject RateThus, for every reject rate there is an accompanying Z-Score, whereRecall thatHenceProcess Capability for Reject RateEstimation of Ppk for Reject RateDetermine th
32、e long-term reject rate (p)Determine the inverse cumulative probability for p,using Calc Probability Distribution NormalZ-Score is the magnitude of the returned valuePpk is one-third of the Z-ScoreExample 5A sales manager plans to assess the process capability of his telephone sales departments hand
33、ling of incoming calls. The following data was collected over a period of 20 days:number of incoming calls per daynumber of unanswered calls per daysExample 5Stat Quality Tools Capability Analysis (Binomial)Example 5Ppk = 0.25Process Capability for Defect RateOther applications, approximating a Pois
34、son Distribution :error ratesparticle countchemical concentrationProcess Capability for Defect RateEstimation of Ytp for Defect RateDefine size of an inspection unitDetermine the long-term defects per unit (DPU)DPU= Total Defects Total UnitsDetermine the throughput yield (Ytp)Ytp= expDPUProcess Capability for Defect RateEstimation of Sigma-Capability for Defect RateDetermine the opportunities per unitDetermine the long-term defects per opportunity (d)d= defects per unit opportunities per unitDetermine the inverse cumulative probability for d,using Calc Probability Distribution NormalZ-Sc
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶(hù)所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶(hù)上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶(hù)上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶(hù)因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 基于大數(shù)據(jù)的數(shù)字化教學(xué)資源評(píng)估模型研究
- 2025年辦理居住證所需的房屋租賃合同范本
- 企業(yè)生態(tài)系統(tǒng)的數(shù)字化轉(zhuǎn)型與商業(yè)機(jī)遇
- 嬰幼兒配方食品營(yíng)養(yǎng)配方優(yōu)化:2025年行業(yè)嬰幼兒營(yíng)養(yǎng)素補(bǔ)充劑市場(chǎng)產(chǎn)品研發(fā)趨勢(shì)報(bào)告
- 基于云計(jì)算的教育資源整合與應(yīng)用研究
- 2025年數(shù)控機(jī)床智能化改造對(duì)水泥制造設(shè)備制造的影響與機(jī)遇報(bào)告
- 提升企業(yè)競(jìng)爭(zhēng)力的數(shù)字化轉(zhuǎn)型與敏捷領(lǐng)導(dǎo)藝術(shù)
- 光伏電站發(fā)電量提升策略在2025年的智能化運(yùn)維設(shè)備可靠性分析報(bào)告
- 2025年歷史文化街區(qū)保護(hù)與開(kāi)發(fā):城市更新中的建筑風(fēng)格與風(fēng)貌保護(hù)
- 幼兒園語(yǔ)言教學(xué)與數(shù)字化技術(shù)的深度融合
- 語(yǔ)文教學(xué)法與評(píng)價(jià)2025年試卷及答案
- 《生態(tài)環(huán)境的密碼:竺可楨的科學(xué)研究課件》
- 碩士外語(yǔ)水平考試指南與答案
- 2025年入團(tuán)考試歷年總結(jié)試題及答案
- 2025年福建省三明市中考二模生物試題(原卷版+解析版)
- 中國(guó)的耕地與糧食安全課件高二下學(xué)期地理魯教版(2019)選擇性必修3
- 完形填空15篇(答案解析)-2025年中考英語(yǔ)分類(lèi)專(zhuān)練(深圳專(zhuān)用)
- 2025年服裝進(jìn)貨合同范本下載8篇
- 2025年事業(yè)單位e類(lèi)考試真題及答案
- 2024年江蘇省寶應(yīng)縣事業(yè)單位公開(kāi)招聘緊缺人才37名筆試題帶答案
- 《急性冠狀動(dòng)脈綜合征》課件
評(píng)論
0/150
提交評(píng)論