模糊聚類與模糊識(shí)別實(shí)例

1、實(shí)驗(yàn)1模糊聚類與模糊識(shí)別實(shí)驗(yàn)?zāi)康模赫莆漳：嗨凭仃嚨慕⒎椒ㄅc最大隸屬原則，會(huì)求傳遞閉包矩陣；會(huì)使用數(shù)學(xué)軟件MATLAB進(jìn)行模糊矩陣的有關(guān)運(yùn)算.實(shí)驗(yàn)學(xué)時(shí)：2學(xué)時(shí)實(shí)驗(yàn)內(nèi)容：根據(jù)已知數(shù)據(jù)進(jìn)行數(shù)據(jù)標(biāo)準(zhǔn)化.根據(jù)已知數(shù)據(jù)建立模糊相似矩陣，并求出其傳遞閉包矩陣.根據(jù)模糊等價(jià)矩陣?yán)L制動(dòng)態(tài)聚類圖.根據(jù)原始數(shù)據(jù)或標(biāo)準(zhǔn)化后的數(shù)據(jù)和的結(jié)果確定最佳分類.根據(jù)已知數(shù)據(jù)用最大隸屬原則進(jìn)行模糊識(shí)別.實(shí)驗(yàn)日期：2010年11月3日地點(diǎn)：104操作步驟：題目*5設(shè)有4種產(chǎn)品，它們的指標(biāo)如下：=(3738JZ16.13.12).兀=(69,73,742Z64,17),=(7X86.49.27.6839).=(57.58.64.8

2、4.6X28).試用相關(guān)系數(shù)法建走相似知1陣，并丿刖專遞閉包法進(jìn)行模糊聚類。解答：其特性指標(biāo)矩陣為：373812161312、X*=697374226417738649276839A=373812161312;697374226417;738649276839;575864846328;n=4;m=6;a1=0;a2=0;fori=1:ma1=A(1,i);a2=A(1，i);forj=1:nif(a1A(j,i)a1=A(j,i);endif(a2c=0;s=0;b1=0;b2=0;b3=0;b4=0;fori=1:nforj=1:ns=0;c=0;fork=1:mb1=b1+A(i,k);

3、b2=b2+A(j,k);b3=b3+(A(i,k)-b1/m)A2;b4=b4+(A(j,k)-b2/m)A2;s=s+abs(A(i,k)-b1/m)*abs(A(j,k)-b2/m);c=sqrt(b3)*sqrt(b4);endif(j=i)R(ij)=s/c;elseR(ij)=1;endendendR1.0000NaNNaNNaN081811.00000.47870.47530.44400.35761.00000.31410.30420.24830.22971.0000傳遞閉包:tR(n,n)=l;s=0;whilesn*nfori=1:nforj=1:ntR(i,j)=0；for

4、k=1:nif(R(i,k)vR(k,j)s=R(i,k);%先取小elses=R(k,j);endif(tR(i,j)tRtR=1.00001.00001.00001.00000.81811.00000.81810.81810.44400.44401.00000.44400.30420.30420.30421.0000飛設(shè)有$個(gè)企業(yè)，記為1=輕衛(wèi)2衛(wèi)),對(duì)每個(gè)企業(yè)用以下m個(gè)指標(biāo)來(lái)刻畫(huà)企業(yè)的技術(shù)密集水平：生產(chǎn)工人勞動(dòng)生產(chǎn)率、每百萬(wàn)元固定資產(chǎn)所容納的職工人數(shù)和技術(shù)管理人員在職工中的比例，令U.=(兀,工，再J,兀1，X，兀3依次表示上述m個(gè)指標(biāo)坷=(1-&9黑0-15),込=(2丄99,0.21

5、),遇=(3.2,101,0.18),碼=(2.2,103,0.17),硝=(2.5,98,0.16),%=(2&102,0.20),嗎=(1.9,120,0.09),遍=(2.0,130,0.11).其中第1個(gè)指標(biāo)的單位是萬(wàn)元/(年人)，試用絕對(duì)值指標(biāo)法進(jìn)行聚類分析口注:56題為實(shí)驗(yàn)室作業(yè)題。解答：每一步實(shí)現(xiàn)原理和上題大致同理，其中使用的不同的聚類公式見(jiàn)下。A=18950.15990.211010.181030.172.5980.162.81020.201.91200.092.01300.11;n=8;m=3;a1=0;a2=0;fori=1:ma1=A(1,i)；a2=A(1，i);for

6、j=1:nif(a1A(j,i)a1=A(j,i);endif(a2R(n,n)=1;fori=1:nforj=1:ns=0;fork=1:ms=s+abs(A(i,k)-A(j,k);endif(j=i)R(ij)=exp(-s);elseR(ij)=1;endendendR1.00000.43670.24140.50610.51220.26420.27650.22850.43671.00000.3353059510.48150.51220.17500.16690.24140.33531.00000.42540.47120.61820.10850.1034050610.59510.42541

7、.00000.64370.49310.25500.24310.51220.48150.47120.64371.00000.51590.19390.18490.26420.5122061820.49310.51591.00000.12570.11990.27650.17500.10850.25500.19390.12571.00000.59230.22850.16690.10340.24311.0000tR(n,n)=1;s=0;whilesG=1645186.4325.495124;1605381.47238448624446.72;A=84.3422.1147568

8、4.342211475684.3422.114756;B=abs(G-A)/10B=0.22800.20900.33800.36800.17000.28700.17300.10600.40600.31800.067000840C=B.C=0.22800.17000.40600.20900.28700.31800.33800.17300.06700.36800.10600.0840sum(C)/4ans=0.28580.18400.2188ans.ans=0.28580.18400.2188%藍(lán)色字段為兩次轉(zhuǎn)置，因?yàn)镸ATLAB中的求和與取大都是默認(rèn)按照列進(jìn)行計(jì)算的%所以為了需要方便，我把行變換