電工技術(shù)習題答案第二章

1．Y．．．．．．11YADBFEC解將組成的△形電路等效變換成1RR3YΩΩΩΩΩΩBBAAΩΩΩΩΩΩΩΩCC圖圖2ΩΩΩΩBAABΩΩΩCC圖圖ΩBAΩC22URRRRRRRIIs123456712和I。3IIII3II22RRR6R6++53RRUS--RRRR4477RRRRR解、R4、、356737462763278I3.375A16633969I2IAI3IA，6386341133aaΩΩΩ+++9V10V__b-）3aaΩ-ΩΩ12V+bb圖解aaaΩ+ΩΩ或_bbbaaa或ΩΩbbbaaa或ΩbbbI圖3aaΩ_或+bb圖44。ΩIΩ-ΩΩ+4解ΩΩaaa++ΩI_b3bbI3aIΩ+ΩΩbb圖I5A55UURRRs1s2123II和I。123+++UUURR3-3-IIR2II2R2I2131III0123RIUURI0解12s2111RIURI022s233III0123I5I125II233IAIAIA，，412366UUURRRR。s1s2s31234SSIIRR2R412RR_UIR+1+4R32+UUU4_U_2__S2+S3圖圖5解S121IIIIII032R124I4RR132RRIRIUU0+_U41122s21US1U+S3_RIRIU0_S22244s2I圖1I2A2I5A4S。1U。11111UUUU1s3RRRR1RRR12341231111U20510420510U20V1UUI1，11R120R52UUU20I3，1s2R10R43477UIIRRRRss1s21234U+I_S23U+1I_S3RII2IRI1IRs22I121s2IR21I4R1I434I4圖圖解對360III131III023s2III02s24URIRIRIRI0s33224411I4，I1，I2A，I2A1234PIR413，PIR(22W222211R222PIR3R214W，PIR2416W222233R444PUI240WUs3sPUI(RI)I34224WI11s1PUI236WIR2s1s2PP吸發(fā)88SAΩΩIIAI3A13IΩIΩ2S2_++++____++圖圖圖解S1UA1UA111303010U10521052A10V得UA7UI14AAUI24AA55UI30AA22S111303010U810521052A得U20VAUI5AA1UI22AA555AA2299UUIRRRAs1s123AAI1I2RRRRII1212RR++ss33UUU圖解As231212VUAUU129IA131R1UU124I2As2R22UI919WPU11s1UI4832WPUs22s2UI13AsPIsUUIRRRII和I。s1s2s1231238IIIIII1122R3R322+++R+RU3U3S1US1U__S2__S2圖解圖111UIUU1s2RRR1RR1s2312UV31UUI111UUI21s2R2U3I31R93－UUUIRRRRRs1s2s3s1234543IIII和I。12345UIR+22RR1254+-+Is2U5Us1-IIIR1334圖43U、U、U1n2n311111UU(UUU1s2RRR1RRRR1n2n32515212111U(UUIRRR41R1n2n3s5541111UUUU(Us3s2RRRRR3RR1n2n32424329UUU1n2n3UUU61n2n3UUU1n2n3U6VU6VU9V，，1n2n3UU106I112As1R12UUU669I2s21n3R32UU69I0As3n3R333UUI4R34UUR65UUIIRRRRs1s2s1s21234IIII和IU和U。1234512IIII22_1RR++22IIIIRR124433434+++RR++33UUIIUUs1-1-IIU1I--R2SI2SI155圖圖解3U、U、U，1n2n3111U(UURRI1RR1n3s213311111U(UUIRRR3R1n2n31344UU8Vn3s210U8Vn33452U5U21n331UUU6221n2n3U17VU18VU，，1n2n3UU1745I1114AnR12II5A2s2UUI3R3UUI4R24由III5(10A542U18VU1URIUU由22s21n32UΩ++ΩUΩ圖ΩΩ1+++_ΩΩΩU_U(2)_Ω圖解。，兩個6圖U13133姆定律可得U3611U(2)11196U6661U(2)U1UU336VU(2)VU(2)34V9UUU347V(2)SabII和I。123II13++I2Ωb32aSI(2)I(2)I(1)I(1)3131++I(2)ΩI(1)2ΩΩ2ΩΩΩSa，由11I1I2AII，1223，42由I(2)2I(2)4222I(2)2243I32AI(2)，(2)424213III41(2)111III(2)2322212III(2)224A333Sb26A2個電壓源U、U1s2，I，I。I123，I(2)6A，22462AI64AI(2)，(2)424213III32(2)111III(2)167A222III(2)44333aaΩ+-_b+b）aa+ΩΩ+--bb解4aaΩ_bb圖aaΩ+_bb圖13aaΩ+_bb圖abbIIRRRRR12345。Is255aIRRsI111SbIs2R53a+I2Ω+IRU11ocI_1b圖圖解RR44R。eqRRRR235eq135U，oc14II2A，II5A112s2由III0123I(II)7A312RIRIRI553(7)2250由UVoc523311R，4I2AUUUIRRs1s2s3s12RS2+++IIR2++s+RUUUS1_S_b圖ΩaΩ+RΩIbRUoc103I106I110由得11I16I1161117VUoc1RR1Req22RR12R4I2R2Uoc4R22ReqPR42maxeq15RUUUUIRRRR，，s1s2s3s4s12345RRLS4URRS4++4+22+++UUIS1RS1II33Uss++RUUocLRRS_3_S_31155圖圖R2IΩΩR+1R5LbULLoc(RRR)IUUU由得12311s2s31IA211UURIURI4461618V2s4s3ReqRRR(RR)R1145123I4R42U22RRPmaxoc4R44eqeqΩ2。I。II1R有源Ieq+ΩΩ_I圖圖ΩΩΩ+Ω++16解U為18VReqoc，18I12A8ReqReq，RU，ocI8I由IIssIIRIeqsΩ+ocs圖解URoceqIocs6ReqU652oc6ReqU633oc6ReqU54VRIURRRRI和I。ss123412II12R2Is4R317RI2I(1)(1)R1R213RR解34RIRI(2)422S電壓源U_s+UU12sI2A，II2AsR15圖12112Is51，6612111III21222R4UIRRRR）ss1234RR11aRIR++II33IsURsURRs-44bRR22圖RR22IascRRRR+4343Uscs_b圖圖RRa922I1AaΩRR43bb圖18RI解sc918VIA22210AI(2)sc9IIIA(2)22ReqRRRRR2214232I2UΩΩΩa++Uabb7I6aRI21+eq6+_Ωoc_b圖圖8142解將，，2(I由得333IA22UU(4)I7V3R，eq19R6Ω7AI126。ΩΩI1ΩΩΩI2++I++ΩbΩΩI3圖ΩaRIΩeq+ΩocbabΩU，UUococabIII0123和1212I8I0231IAI，3236IU4I3002oc313U4I6I4(632R5eq64R2，I53UIIRRRII和ss1s21231220IU和U。312IIs1s1_++URR2RR1111232+I+II++I2I2Is23U3URs2URU3232s_s___圖3U、U、U圖1n2n3UU30V1s1U(UU0RRRRR11123211RR122111U30VU24VU39V，，1UUI5A21I2n3R32U243I3n2R3UU39V2n3UUU0由得12sUUU39309V得12sI和I。12II111+ΩI+Ω+4II22+ΩΩ__4I121解1U1121104I1U712211102IU011U8V，I11U84AI1222U和U。121++++ΩΩUΩ22U+11解1U。111222UU217UV617UUV