c程序設(shè)計(jì)(第四版)答案

1-5#incbde<stdhh>htmain0prhtfCVeryGood7Xp1);? ，，一，一，_?_，一，一，一，ー?_一，一，-，一?一，ー」一，一，一，一，一，一，一returnQb6#incbde<stdhh>intmahX{htahgin空prhtffpbaseiiputab,c\01);scanf(%d%4%d",&a&b,&0;maj^aif命ax<b)ma^=b;ifgax<。max=qprhtf(Thefalsestnumberis%d\p"ma>d；letumQ)34hebde<stdhh>hcbde<mathh>intmahX{fbatp,皿『QI;n=lQp=powd+；n)；prhtfCp=%g；?;letumQ}3-24hcbde<stdhh>#hebde<mathh>htmahX{fbatか,aにムmBpLpZpWpApNp=100Q15=QO58^6=0054;i2=Q046&rl=Q0414;iO=QOO72Jpl=p*(?+◎pl=p*(?+◎*?p2=p*t+2*r2)*t+3M；pj=p*4+3*6*4+2*r2；p4=p*pow4+rL);p5=p*pow?+!0/@4?》;prhtf(1pl=%Nn,,,pl)；prhtf(,p2=%Nn",p3；prhtfCp3=%F\n",p3;printfCp4=%g",p@;printfCp5=%NV；p?letumQ}3-2^#hcLde<stdhh>#hehde<mathh>pl=p*(4+◎*?p2=p*4+2?。?什3*6;p3=p*4+3?。?d+2*%p4=p*pow?+rL);p5=p*powQ+iQ/^4*?prhtffpl^En^pl);printf(,p2=%Kn,,,p3;pmtfCp3=%En”,p3;prhtf(1p4=%fxp,,,p4；prhtfCp5=%g",p5;letumQ}3^3”ー次存5年期〃先存2年期,到期后將本息再存3年期〃先存3年期,到期后將本息再存2年期〃存1年期,到期后將本息存再存1年期,連續(xù)存5次“存活期存款?；钇诶⒚恳患径冉Y(jié)算ー次〃輸出按第1方案得到的本息和〃輸出按第2方案得到的本息和〃輸出按第3方案得到的本息和ク輸出按第4方案得到的本息和ク輸出按第5方案得到的本息和intmahX{doubtか,役!2,rl,iQp,pLpZpap4p》p=100Q15=00585;ri=Q054;i2=Q046&rl=Q04HiO=Q007^クー次存5年期〃先存2年期,到期后將本息再存3年期”先存3年期,到期后將本息再存2年期〃存1年期,到期后將本息存再存1年期,連續(xù)存5次”存活期存款。活期利息每一季度結(jié)算ー次”輸出按第1方案得到的本息和”輸出按第2方案得到的本息和”輸出按第3方案得到的本息和”輸岀按第4方案得到的本息和ク輸出按第5方案得到的本息和#hcLide<stidhh>#hchde<matfih>iitmahX{fbati5.日2rl,iQp,pLp2,P*p4pNp=100Q6=(1058?i3=Q054;r2=Q0463rl=Q04HiO=Q0072；pl=p*pl=p*(什6?3；p2=p?什2?巧?(+3*6;p3=p*Q+3*6*?+2*D;p4=p*powQ+rL?；p5=p*pow什。44prhtf(,pl^%lQ2KnH,pD；prhtf(1p2=%lQ2f\p",p);prhtf(,p3=%lQ2NnH,p3；prhtfCpa％1Q2トパ,p0;prhtf(,p5^%lQ2NiH,p9;letumQ}甘#hchde<stdhh>〃ー次存5年期〃先存2年期,到期后將本息再存3年期”先存3年期,到期后將本息再存2年期〃存1年期,到期后將本息存再存1年期,連續(xù)存5次〃存活期存款?；钇诶⒚恳患径冉Y(jié)算ー次〃輸出按第1方案得到的本息和”輸岀按第2方案得到的本息和ク輸出按第3方案得到的本息和〃輸出按第4方案得到的本息和〃輸出按第5方案得到的本息和incbde<mathh>htmahX<fbatd=30000Qp=600Qf=Q01,id;m=bglOレ伊d*?)/bglO什?;prhtf0n=%62fsp",m);returnQ}Xhebde<stdhh>htmahX{htcLMcl=19^c2=19&prhtfCcl=%Gc2=%d\n",cLcZ;prhtf(cl=%d,c2=%d\p"cl,c2>;returnQ}3-5hebde<stdhh>htmahX{ht^b；fbatxxcharcl,scanf性=%db=%du,&a&b)；scanf(%f%e",&*&9;

scanfprhtfdd?b=%d,^=%iy=%fcl=%Gc2=%d\n?ab,xxcLcZ;returnQ3-6#incbde<stdhh>htmahXfcharcl=,Cz,c2=zhz,c3=zi,c4=znz,c5=za;cl=cl+4c2=c24-4c3=c升4c4=c44-4cXc5+4prhtffpasavoris%c%(%(%(%C\p"cl,c2,c3,c4c5);letumQバ#incbde<stdhh>intmahX{fbath,H§4vqv4fbatpバ#incbde<stdhh>intmahX{fbath,H§4vqv4fbatpA3.14152Gprhtf晴輸入圓半徑5scanf(%4%f',&g&h);1=2ケ汽S=I*I*p；sq=4*p卜1*,vq=3.Q/4〇?pi*!*!*,VZ=p2!*！*hprintf圓周長為:prhtf嵋面積為:prhtf嫗!球表面積為:printf圓球體積為:printfIB!柱體積為:letumQ/要求輸入圓半徑前圓柱高h(yuǎn)，計(jì)算圓周長1，計(jì)算圓面積s/計(jì)算圓球表面積囚ノ計(jì)算圓球體積vqノ計(jì)算圓柱體積vz等2ふり;s=%62g；$;Xf=%62Nnn,sq)；v=%6t2fMi",vq);vz=%62W,v力;3-84#hcbde<stdhh>intmahX/整型定義/整型定義printf睛輸入兩個(gè)整數(shù)cl,c2scanf呪d%d'；&cL&c2;prhtf胺字符輸岀結(jié)果:、0;prhtf呪G%d\p",cLc2；

prhtf股ASCI照輸出結(jié)果為、g;prhtf呪d%Z",cLc2;ietumQ3-8-2#incbde<stdhh>htmahX(charcL?htil,2prhtf。青輸入兩個(gè)字符cLc2り;scanf呪g%c",&cL&c?;i=cl;Q=c2,prhtf股字符輸出結(jié)果:7り;prhtf(%q%c\n",11,0;prhtf胺整數(shù)輸出結(jié)果:、0;prhtf呪4%Z",cLc2;ietumQ}#incbde<stidhh>htmahX1charcl,htil,りpriitfC青輸入兩個(gè)整數(shù)fl,2ツ;scanf(%4%d",&]&D；ckil;c2=Zprhtf股字符輸出結(jié)果:\g;prhtf呪g% ツcLprhtf胺整數(shù)輸出結(jié)果:、0;prhtf叱4%Z",cL。;ietumQ)3-8#helide<stdhh>htmahXcharcLc2prhtf晴輸入兩個(gè)字符cl,c2');cl=getcharX/定義字符型變量，定義整型變盤，賦值給整型變量/定義為字符型/定義為整型力將整數(shù)賦值給字符變量/定義字符型變量，定義整型變盤，賦值給整型變量/定義為字符型/定義為整型力將整數(shù)賦值給字符變量putchar(D；putchar￡2>;prhtfNi1);prhtfffiprhtf!吾句輸出結(jié)果為:力prhtf呪c%d\McLc2;letumQ}#hcbde<stdhh>iitmainX(intab>Gpmtf睛輸入三個(gè)整數(shù):1);scanf呪4%4%d",&a&b,&0;if紅ウift<0printf(tnax=%d\n''();elseprintf(taa^=%d\n照;elseif紅。prhtf(bna^=%d\pリ。;elseprhtf(tna?F=%d\pリletumQ)4-4-2#hehde<stdhh>htmahX{ht^b,Qteiip,ma^prhtfd青輸入三個(gè)整數(shù):り;scanf(%d,%4%da,&b,&0;temp=fi>t^?ab5 ?辱麗b中的大者存入fanp中ッmax=fcmp>()?tenp:q イ各說b中的大者與c比較取最大者ッprhtfケ個(gè)整數(shù)的最大數(shù)是％d\p",m的;ietumQ}4^-2#hchde<stdhh>#hebde<mathh>#defheM1000htmahXhtjk;priitf精輸入ー個(gè)小于％d的整數(shù)i"Mscanf(%dl,,&J;whife6M)わ巾tf輪入的數(shù)不符合要求,請重新輸入一個(gè)小于%d的整數(shù)iHMscanf}k=sqrti;pmtf呪d的平方根的整數(shù)部分是:％dXゼ,閡;ietuinQ)4-5#incbde<stdhh>#hehde<mathh>#defheM1000htmahX(intikPmtf睛輸入ー個(gè)小于％d的整數(shù)i'Mscanf(%dl,,&);ifgM)Jp由tf騎入的數(shù)不符合要求,請重新輸入一個(gè)小于％d的整數(shù)i"M);scanf(%dH,&);}k=sqitJ;prhtf叱d的平方根的整數(shù)部分是:%カゴ;困;ietumQ}■#hcbde<stdhh>htmahX{朮.prhtf輸入x1);scanf呪d?&力;if紅D 欣1シ{y=KprhtfO%3d, kx=%d\n",x9;}elseif紅1。 y*l=Vx<10シ{y=2*x-4;Prhtf(5f=%d,產(chǎn)2*E=%d\p",X9；}else /*A=10シ{y=3*x41;prhtff>F=%d,尸3*xTl=%d\ガな女letumQ}4^4#hcbde<stdhh>iitmahX|htKXprhtfCenterxscanf呪則&力;if@=0if90尸!；else產(chǎn)。printf(5?=%dパ<d\p",メゆ;letumQ}4-7^#hcljde<stdhh>iitmahX{htKXprhtffpteaseenterx*);scanf呪d",&力;產(chǎn)。if—0if?>0產(chǎn)］；else產(chǎn)TprhtfCx=%d,y=%cNn",^^;letumQ}せ#hcbde<stdhh>htmahX{fbatsco叱chargrad^prhtf騎輸入學(xué)生成績scanf(%f；&sco的;white^coie>100|IscoiecQわrintfZ)輸入有誤請重輸ッ;scanf(%f,&sco的;switch(g[&Z〇吟/I〇)fcaseIQcase9grade=/A/;breal;case8grade=zBz;bieak;case7grade=zCz;bieal;casedgrade=TDz;bieak;caseゝ.case4case3:case2case1:caseQgrade=zE；}prhtf城績是％5.1和應(yīng)的等級是％Zi,【seo吋grade；returnQ}4-9#incbde<stdhh>#hehde<mathh>htmahX{intnum,hd^,ten,hundted,thousand,ten_thousand,phcq 別代表個(gè)位十位百位千位,萬位和位數(shù)prhtfC青輸入ー個(gè)整數(shù)(W9999:聽scanf(%d,,,&nun);ifQun>9999place=5;elseifQun>999phce=4;elseifホun>99phce=*elseif6un>9phce=2elseplace=1;printf竝數(shù):％d\p",phe。;printf晦位數(shù)字為ten_thousanc^num/1000Qthousand仙,611nHeqthousand*1000Q/400Qhundied=れ。6umHen_thousand*10000-thousand*100()/40Qten=g。(iim-tEn^thousand*l0000-thousand*l000-hundied*l00/1Qindg你。fiunHen_thousand*10000-thousand*1000-hundied*100-^en*10;snitch「he,fcase5:prhtf(%d,%d,%6%<4%dten_thousan4thousand,hundted,ten,hdi0;prhtfZ反序數(shù)字為:')；prhtf呪叱叱叱叱d\pツndn,皿hundled,thousand,ten__thousan(J);bieak;case4:prhtf(%d,%d,%d,%dthousandhundled,ten,hdk);prhtf卜n反序數(shù)字為:力prhtf%胡叱叱d\o?indiv,ten,hundred,thousandl;bieak;caseiprhtf(%d,%d,%d]\hundled,ten,hd助;prhtf卜n反序數(shù)字為:1)；printf呪叱叱 hdiv,ten,hundie(J);bieak;case2prhtf(%d,%d'*ten,hdi0;prhtfZ!反序數(shù)字為:');prhtf呪叱d\pthdiv,ten);bieak;casel:prhtf(%d'*hdi0;prhtfZ反序數(shù)字為:たprhtf(%N?hd說;bieak;)letumQ}4404#hchde<stdhh>htmahX{htjdoublebonusbonLbon2,bon%bongbonIQbon1=10000O*QI;bon2=bonl+100000*Q075;bon4=bon2+100000*Q〇ユbon6=bon介100000*0〇?bonlgbon什40000〇?QOlgprhtf靖輸入利潤i?;scanf(%dH,&);ifQ100000bonus=rtQ1;elseifに=200000bonus=bonl4-H0000()*Q07^elseif《=40000。bonus=bon汁￠-20000()*Q0^elseif紅=600000bonus=bon人移00000*Q0ウelseif依=1000000bonus=bon圻絞00000?Q013elsebonus=bonl(H-H00000()*Q01;prhtf奘金是:％lQ2F\n?bonu§;letumQ}448#hchde<stdhh>intmainX{htjdoubtebonusbonLbon2,bon4bon。bon1Qintbranch;bonl=100000^Ql;bon2=bonl+100000*0.075;bon4=bon2+200000*0.0，bonabon4+200000*0.〇ナbon10=bon什40000〇文Q015;prhtf晴輸入利潤i1)；scanf(%d'i&I;brane仁jkl0000。ifBranched。bianch=lQ敏itchbranch{caseQbonus= 1;breal;caseLbonus=bonl+H00000075bieal^bonus=bon24-￠-20000()05;breal;bonus=bon4l-(400000?Q03;break;caseT.bonus=bon64-託00000*001エbieal;caseICtbonus=bonl04-(4000000*0.01;}printf獎(jiǎng)金是％lQ2F\pi；bonu$;letumQ}441#hcLide<stdhh>intmainX{httab,G4prhtf睛輸入四個(gè)數(shù):1);scanf(%《％4%4%dジ&a&b,&q&〇;prhtfPm%44%d8%dd=%d\(i"在“。;

ifif￠>0{t=4a=qc=t}if￠>4){t=aa=&d=t}ifg。{t=b;b=GG=t}ifgd){t=b;b=4d=Vife>@{PGG=dd="prhtf腓序結(jié)果如下:7!、prhtf(%d%d%d%d\pH用b,qd);letumQ|-N2#hehde<stdhh>htmahXhth=lQfbatxl=2?y1=Zx2=-Zy2=2>x3=-2,y3=-2,x4=2,y4，2*ydLd2d3,d4priitfC青輸入ー個(gè)點(diǎn)々y:力scanf叱％f；&￥&?;dl=仁④?憶@+卜y4?卜y@; /求該點(diǎn)到各中心點(diǎn)距離?/d2=—D*-D+/D*HD；d3= *fc-x2>+^y2)*d4=^5*^^+//H3;if01>1&&d2>l&&d>l&&d4>Dh=Q"リ斷該點(diǎn)是否在塔外ンprintf0亥點(diǎn)高度為％Z?h);returnQ}5-2#hcLide<stidD.h>#hehde<math.h>htmahX”程序中用到數(shù)學(xué)函數(shù)如§應(yīng)包含頭文件mathnhtsgn=l,coun^Qdoublepi=QQn=LQtEin=LQtem代表當(dāng)前項(xiàng)的值white圓”fem)>=le-^次方〃s前用來表示數(shù)值的符號,count用來統(tǒng)計(jì)循環(huán)次數(shù)

”程序中用到數(shù)學(xué)函數(shù)如§應(yīng)包含頭文件mathnhtsgn=l,coun^Qdoublepi=QQn=LQtEin=LQtem代表當(dāng)前項(xiàng)的值white圓”fem)>=le-^次方pNp+tem;ク把當(dāng)前項(xiàng)tem累加到pi中ク檢查當(dāng)前項(xiàng)tem的絕對值是否pNp+tem;ク把當(dāng)前項(xiàng)tem累加到pi中n=rri-Zsgn=^r^tem=sgnAi;countH-;}pip/printf①j=%10.8卜則pJ;priitffcoun^=%d\pワcounウ;ieturnQ〃什2是下ー項(xiàng)的分母〃s前代表符號,下ー項(xiàng)的符號與上一項(xiàng)符號相反〃求出下ー項(xiàng)的值tem/Zcount累加1ク多項(xiàng)式的和P乘以4オ是"的近似值”輸出n的近似值ク輸出循環(huán)次數(shù)5-3#hchde<stdhh>htmahX{ht卩耳陽,怕n爲(wèi)priitf睛輸入兩個(gè)正整數(shù)叫m:り;scanf叱d%4ソ&n&m)；iff<m){tanp=n;n=m;m=tHnR}產(chǎn)rPta;whife血!=0(4設(shè)m;n=m;m=;|pmtf的們的最大公約數(shù)為:％へパm；priitf船們的最小公約數(shù)為%d\M時(shí));ietumQ}5-4#hchde<stdhh>intmainX{charqhtヒtters=Qspace=QdigiHQolhc『aprhtf晴輸入一行字符Nツ;while(Ugetchar)O!=ヽp)ifC>=‘ゴ&&c<='イ||d>='A'&&(K='Z)elseifU=')spaceH";elseif(>=z(y&&e<=9)dgifr+;elseotherH";}prhtf序母數(shù):%d\p空格數(shù):%d\p數(shù)字?jǐn)?shù):%d\p其它字符數(shù):%ベツtetter^spacQdjgitothej;letumQド5^#inchde<stjdhh>intmahX{ht4n,^l,sn=Qtn=Qprhtfda,n=:');scanf(%d%d”,&a&rj);white<=rj)|tn=tn+a/W值后的tn為泠@成數(shù)的值ッsn=s!卄tniイK值后的sn為多項(xiàng)式前頊之和ッ后a*l。++i}printf(,a4-aabaaat-...=%d\p"srj);letumQ}5-6#incLideVstdhh>intmainXセ!oubtes=QHl;htn;for仁］;n<=2Qn++)|^=t*n;}prhtf(,l!+2+...+2a=%2215"；$;letumQ#hehde<stdb.h>

htmahXhtnl=10Qn2=5Qn3=lQdoubbksl=Qs2=Qs3=Qfor^l;K=nl；m-)/l十算1到100的和ッ{sl=sl+k;}for『!;k：=nと酢+)/計(jì)算1到50各數(shù)的平方和ッ{s2=s2-t-k*k;}for『!;k=n*kH)/I?十算1到10的各倒數(shù)和ッ{s3=s34-l/k;}prhtffsun=%15.6f\n^sl+s2+s3)；ietumQ}5-8#hchde<stdhh>iitmahX{htjjk"prhtffpaicissusnumbersaiefor(F10Qn<100Qn4-B{AM10Q戸ル4卄IQk=叱1。iftf=i*i*i+j*j*j+k*k*K)prhtf(%d'；n);}prhtff\p');ietumQ)5-94#defheM1000 /定義尋找范圍?/#hchde<stidb.h>htmahXhtiMSfor^=^a<=M;aH-)gQs=afor仁!;htiMSfor^=^a<=M;aH-)gQs=afor仁!;kaiH)

if殷i=0H-+；s=s-j/*a是24000之間的整數(shù),檢查它是否完數(shù)ッパn用來累計(jì)狛勺因子的個(gè)數(shù)ッ/s用來存放尚未求出的因子之和,開始時(shí)等于aシイ檢查謔否啲因子ッ如果是啲因子ッ/*n加L表示新找到ー個(gè)因子ッ/s減去已找到的因子,s的新值是尚未求出的因子之和ッ

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グ函數(shù)啦がリ斷是否為閏年ッhttap仙tyea?{htbapヒap=yea%4^C&&yea%!0(l=01Iyea%400=Qreturn(bap>;}a4#hcbde<stdhh>htmahX{voidwapSt*pLht*p2；htnLnZ>nロht*pL*pZ*p3prhtffhputthreeintegernl,n2^n3:1);scanf(%d,%d?%d恢n1,&n2?&n$;p!=&nl;p2=&n^p3=&n3if61>n2)avap￡Lp2；if61>n3avap￡Lp3；ifR2>n3mapSZp3；prhtf(Now,theolderis%d,%d,%d\nu,nl,n2,n3；letumQ|voidavap6tヤ)Liit*p3{ht居p=ヤ!;*pl=*p^*p2=n}&2#hcLide<stdhh>#incbde<stringh>intmahX{voidavap(har[charう;charstrl20],sti22Q],sti320];prhtffhputthieeIheXn*);gets6trD;gets6t⑵；gets6trS；if^tninp6trLstQ>0svap6trLst⑵；if6tmp6trLstけ>0avap6trLst均;if6trcmp6t區(qū)st6>0svap6t12,strS;prhtf(Now,theorderis\p*);printf(%K[i%Kp%Kp",strLsti2,str?);letumQ)voidavap(har*pLchar*p2tharp緲sticpyhpD；sticpybLp2；sticpy館位;}-8-3#hebde<stdhh>htmahX{voidhputiitう;voidmaxmhvalieStう;voidoutputiitう;htnunberJO];inputRumbeシ;maxmh_yaheQimbej);outputRumbe。;returnQvoidhput4it*numbej)(htjprhtffhput10nunbersツ;for(=Qk：lQtH-)scanf(%d",&nunberQ);}voidmaxminvahe￠it*nunbej){int^fna^^fnh,*p,t0np;ma^nh=nunbe;for^=nunberi-l;p<nunbeFl-lQp-l-H)if奪Ain函max=pelseifセ<ウniq)mh=Rtanp=nunber0;nunber0=^ir^^fnn=tanRif所ax=nunbeシmax=min;tanp=nunber0;nunber0=包招^nax=tanp}vodoutputSt*nunbe》{ht*Rprhtf(Now,theyare 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