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MoreEquations-WestPenderMiddleSchool更多的方程-西德中學MoreEquations-WestPenderMiddleSchool更多的方程-西德中學MoreEquations-WestPenderMiddleSchool更多的方程-西德中學MoreEquationsSolvingMultistepEquationsSomeequationsmayhavemorethantwostepstocomplete.Youmayhavetosimplifytheequationfirstbycombiningliketermsorevenremovefractionstomakesolvingeasier.SamanthaandRebeccawanttorentsportsequipmentatthecitypark.Samanthawantstorentinlineskates,andRebeccawantstorentamotorscooter.Howwouldyouwriteanequationandsolvetheproblemtofindthetotalcostforaspecifiednumberofhours.Let’stakealookathowyouwouldsolvethisproblem.MoreEquationsSolvingMultistepEquationsSomeequationsmayhavemorethantwostepstocomplete.Youmayhavetosimplifytheequationfirstbycombiningliketermsorevenremovefractionstomakesolvingeasier.SamanthaandRebeccawanttorentsportsequipmentatthecitypark.Samanthawantstorentinlineskates,andRebeccawantstorentamotorscooter.Howwouldyouwriteanequationandsolvetheproblemtofindthetotalcostforaspecifiednumberofhours.Let’stakealookathowyouwouldsolvethisproblem.Hereisthecostforeachoftheactivitiesthegirlswouldliketorent.Let’slookateachindividuallyandthentogether.InlineSkates$3.00plus$1.50/hourc=3+1.50xc=individualcostx=numberofhoursrentalMotorscooter$10.00plus$2.75/hourc=10+2.75xc=individualcostx=numberofhoursrentalIndependentvariableDependentvariableconstantIndependentvariableDependentvariableconstantCombinedcost(C)
UsetheequationC=3+1.50x+10+2.75xtoanswereachofthefollowingquestions.
C=4.25x+13HowmuchwouldSamanthaandRebeccapayfor2hours’rental?HowmuchwouldSamanthaandRebeccapayfor3hours’rental?Iftheirtotalrentalcostis$38.50,forhowmanyhoursdidtheyusetheequipment?MultistepEquationsEquationswithLikeTermsEquationsthatcontainFractionsEquationswithvariablesonbothsidesImportant!
Tosolvemultistepequations,firstclearfractionsandcombineliketerms.Thenaddorsubtractvariablestobothsidessothatthevariableisononesideonly.MultistepequationsSTEP1:ClearfractionsSTEP2:removeparenthesisSTEP3:moveallvariablestoonesideoftheequation.Solvingequationscontainingliketerms8x+6+3x–2=3711x+4=37 Combineliketerms11x+4–4=37–4 SubtractionPropertyofEquality
11x=33
DivisionPropertyofEquality1111x=3Remembertokeepyourequalsignslineduptopreventyoufrommakingamistake.Onthenextslidewewillcheckouranswerbysubstitutingforx.Checkyouranswerbysubstitutingforx8x+6+3x–2=378(3)+6+3(3)–2=37 Substitute3forx24+6+9–2=37 Combineliketerms37=37?TrueSolve:
1)8d–11+3d+2=13
2)8x–3x+2=-33
3)2y+5y+4=25
4)4x+8+7x-2x=89
5)30=7y–35+6y
Solvingequationsthatcontainfractions
5n+7=-3
Multiplybothsideby4toclearfractions4444·5n+7=-3·4
Multiplybothsidesby4,
MultiplicationPropertyofEquality444 5n+7=-3 Subtract7frombothsides,SubtractionPropertyofEquality5n+7–7=-3–7
5n=-10
Dividebothsidesby5,DivisionPropertyofEquality
5
5
n=-2RemembertogobackansubstitutefornSolve:
1)4–2p=6
555
2)9z+1=2
444
3)x+2=5
236
Solvingequationswithvariablesonbothsidesissimilartosolvinganequationwithavariableononlyoneside.Youcanaddorsubtractatermcontainingavariableonbothsidesofanequation.2a+3=3a2a–2a+3=3a–2a
Subtract2afrombothsides.3=aRemembertokeepequal(=)signslineduptopreventerrors.Alwaysgobackandcheckeachequationbysubstitutingthesolutionintotheoriginalequation.Movingtermsisjustlikemovingasinglenumber,youusethePropertiesofEquality.Solvingequationswithvariablesonbothsides.4x–7=5+7x4x–4x-7=5+7x-4xSubtract4xfrombothsides.-7=5+3x-7-5=5–5+3xSubtract5frombothsides.-12=3x
-12=3x
Dividebothsidesby3.
3
3-4=xRemembergobackandsubstituteforx.Remember,youcanmoveawholeterm.Solve:
1)5x+2=x+6
2)4y–2=6y+6
3)4(x-5)+2=x+3
4)4x–5+2x=13+9x–21
5)8x–3=15+5x
Bothfigureshavethesameperimeter.Whatistheperimeter.Rememberhowtofindtheperimeterofapolygon?Well,thesetwoperimetersarethesame.Writeanequationandsolvethefollowingproblem.SamandTedhavethesamenumberofbaseballtradingcardsintheircollection.Samhas6completesetsplus2individualcards,andTedhas3completesetsplus20individualcards.Howmanycardsareinacompleteset?Findthreeconsecutivewholenumberssuchthatthesumofthefirsttwonumbersequalsthethirdnumber.Hint:Letnrepresentthefirstnumber.)Solveandcheck.6x+3x–x+9=33-9=5x+21+3x4–2p=6555y–3y+1=1
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