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07傳質(zhì)與分離工程期末考試題,考試作弊將帶來(lái)嚴(yán)峻后果!
華南理工高校期末考試
2024《傳質(zhì)與分別工程英文》試卷A(含答案)
1.考前請(qǐng)將密封線內(nèi)填寫(xiě)清晰;
全部答案請(qǐng)直接答在試卷上(或答題紙上);
.考試形式:開(kāi)(閉)卷;
SintheairisabsorbedbyNaOHsolutionis(A).
2
B.liquidfilm“controls”;
C.twofilm“controls”.
AB=1.When
C).
>xA;B.yAtd;B.t>tw=td;C.t=tw>td;D.t=tw=td
w
oC,(C)ofreadingisoCB.77oCC.77.01oC;D.77.010oC
B).
WhenthewatercontentofsomematerialisclosetoitsequilibriumwatercontentX*,itsdryingratewill___C_.
B.decrease;
C.beclosetozero;
D.beuncertain
Forthedesorption(stripping)process,when(B)increasesand(A)
A)increases,itisgoodfortheoperation.
D)decreases,itisgoodfortheoperation.
A.dry-bulbtemperatureofair;
B.wet-bulbtemperatureofair;
C.dewpointtemperatureofair;
D.sizeofmaterialtobedried
(9)Forabsorptionprocess,whenthecoefficientskxaandkyaareofthesameorderofmagnitudeandequilibriumconstantmismuchgreaterthan1,(B)issaidtobecontrolling.Inordertoincreasemasstransferrate,itisbettertoincrease(E).
A.gasfilm;
B.liquidfilm;
C.bothgasfilmandliquidfilm;
D.gasphaseflowrate;
E.liquidphaseflowrate;
F.bothgasphaseflowrateandliquidphaseflowrate;
(10)Forabsorptionprocess,ifitistheliquidfilmcontrol,(D)isfeasibletoincreasemasstransferrateofabsorption.
Atodecreasegasflowrate.
Btodecreaseliquidflowrate
Ctoincreasegasflowrate.
Dtoincreaseliquidflowrate.
(11)WhentherefluxratioRincreasesandotherconditionskeepthesame,overflowofvaporVwill(increase);theconcentrationofoverheadproductxDwill(increase);steamconsumptionofreboilerwill(increase),thetheoreticplatenumbersrequiredwill(decrease)forthesamerecoverypercentageofoverheadproduct.
(12)Thefactorstoinfluencemasstransfercoefficientsofgasphaseinclude(T,P,gasflowrate
).
(13)Whensomemoistairispreheatedinapreheater,itshumiditywill(bethesame),itsrelativehumiditywill(decrease),itsenthalpywill(increase),itsdewpointwill(bethesame),itswet-bulbtemperaturewill(increase).
(14)Whentheliquidfloodingatapackedtoweroccurs,(pressuredrop)increasesremarkablyandtheentiretowermayfillwith(liquid)..
(15)MathematicexpressionofFick’slawis(JA=-DdCA/dz).
(16)Therequirementstosatisfyconstantmolaloverfloware(vaporizationheatofdifferentponentswillbethesame,sensibleheatexchangeofliquidandgasphasesontheplatescanbeignored,heatlossofcolumncanbeigored.)
(17)SomewetsolidsaredriedbyairwithtemperaturetandhumidityH.(1)WhenairvelocityincreasesandairtemperaturetandhumidityHkeepconstant,thedryingrateatconstant-rateperiodwill(increase);Ifairvelocityandairconditionskeepunchanged,butthicknessofmaterialsincreases,thecriticalmoisturecontentofwetmaterialXcwill(decrease).
2.(20points)AtaconstantpressureoperationacontinuousdistillationcolumnwithrefluxisusedfortheseparationofabinarymixturewithfeedrateF=1000kmol/handconcentrationxF=0.36(molfractionofmorevolatileponent).Feedissaturatedvapor,therelativevolatilityof
mixtureαis3,indirectsteamheatingisusedatarebolier,andtotalcondenserandbubblepointrefluxatthetopofcolumnareemployedandtherefluxratioRis3.2,respectively.Itisrequiredthattherecoverypercentofmorevolatileponentatthetopofcolumnis92%,andthattheconcentrationofmorevolatileponentatthetopxDis0.9.Calculate:
(1)Operatinglineequationforrectifyingsection;
(2)OverheadproductflowrateD,vaporoverflowVforrectifyingsectionandvaporoverflowV’forstrippingsection,inkmol/h.
(3)Ifthepracticalliquidconcentrationleavingthefirstplate(x1)is0.825,whatisthisplateefficiencyofplate1LME,?
Solution(1)y=0.762x+0.214
(2)DxD/FxF=0.92,D=0.92(1000*0.36)/0.9=368kmol/h
V=(R+1)D=4.2*368=1545.6kmol/h
V’=V-F=1545.6-1000=545.6kmol/h
(3)EmL=(xD-x1)/(xD-x1*)=(0.9-0.825)/(0.9-0.75)=0.5
y1=xD=αx1*/(=0.9=3x1*/
x1*=0.75
3.(20points)Somegasmixturecontainsacetonevaporwith3%(molarfraction)whichisabsorbedbypurewateratacountercurrentoperationabsorber.98%acetoneofoutletgasisremoved.Ratioofliquidtogasflowrateis2andtheequilibriumrelationis=*y1.05xFind
(1)whatistheacetoneconcentrationofoutletwateratthetowerbottom?
(2)whatistheoverallmasstransferunitnumberofgasphase?
(3)iftheinletpositionsofgasandliquidphaseskeepthesameandtheratioofliquidtogasflowrateis1.04,where(inwhatpositionoftower)istheequilibriumofgasandliquidphaseswhenthepackinglayerheightisinfinite?Whatisthemaximumrecoverypercentageofacetone?Solution:(1)x1=V(y1-y2)/L=0.03*0.98/2=0.0147
(2)Noy=(y1-y1)/?ym=0.03*0.98/0.00438=6.71
?ym=/ln=0.00438
(3)since
104
.105.104.105.1='=='=V
LmSV
LmSotheequilibriumwillbereachedatthebottomoftower.Maxremovalefficiencyofacetoneis
1
21maxyyy'-=η
0286.005
.103.005.11*1===yx0297.00286.004.1*121=?=='-xV
Lyy%9903
.00297.0121max=='-=yyyη
4.(15points)Amoistmaterialistobedriedfromwatercontent25%to5%(wetbasis)inanadiabaticdryer(constantenthalpydryingprocess)underatmosphericpressure.Thefeedofmoistmaterialsolidintothedryeris1000kg/h.Aftersomefreshairwithadry-bulbtemperatureof25oCandahumidityof0.013kgwater/kgdryairispreheatedto100oC,itissenttothedryer.Andtheairtemperatureleavingthedryeris65oC.
(1)Whatarethebore-dryair(inkg/h)andthevolumeoffreshairrequiredperunittime(inm3/h)?
(2)Howmuchheatisobtainedbyairwhenitpassesthroughthepreheater(inkJ/h)?Solution:(1)W=Gc(X1-X2)=1000*0.75(1/3-5/95)=210.5kg/h
I1=I2
(1.01+1.88H1)t1+2492H1=(1.01+1.88H2)t2+2492H2
H1=0.013,t1=100,t2=65,H2=0.0268
L=W/(H2-H
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