版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡介
專題02函數(shù)的值域考點(diǎn)一常見函數(shù)值域一、單選題1.下列函數(shù)中值域?yàn)镾KIPIF1<0的是(
)A.y=|x-1|B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.當(dāng)SKIPIF1<0時(shí),則函數(shù)SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的最小值是(
)A.SKIPIF1<0 B.0 C.1 D.24.函數(shù)SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題6.下列函數(shù)中,最小值為2的函數(shù)是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0三、填空題7.已知SKIPIF1<0,函數(shù)SKIPIF1<0的值域?yàn)開_____________8.函數(shù)SKIPIF1<0的值域?yàn)開_____.四、解答題9.求下列函數(shù)的值域.(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0,SKIPIF1<0.10.求下列函數(shù)的值域:(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0;(4)SKIPIF1<0;(5)SKIPIF1<0;(6)SKIPIF1<0;(7)SKIPIF1<0;(8)SKIPIF1<0;(9)SKIPIF1<0.考點(diǎn)二復(fù)雜函數(shù)值域一、單選題1.函數(shù)SKIPIF1<0的值域是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、填空題2.函數(shù)SKIPIF1<0的最大值與最小值分別為M和m,則SKIPIF1<0的值為__________.3.已知函數(shù)SKIPIF1<0為偶函數(shù),則函數(shù)SKIPIF1<0的值域?yàn)開__________.4.求函數(shù)SKIPIF1<0的值域?yàn)開________.5.函數(shù)SKIPIF1<0的值域?yàn)開_.6.函數(shù)SKIPIF1<0的值域?yàn)開_____.7.函數(shù)SKIPIF1<0的最大值為______.8.若SKIPIF1<0,則函數(shù)SKIPIF1<0的值域是__________.9.函數(shù)SKIPIF1<0的值域是______.三、解答題10.已知SKIPIF1<0,求SKIPIF1<0的取值范圍.11.已知冪函數(shù)SKIPIF1<0過點(diǎn)SKIPIF1<0.(1)求實(shí)數(shù)m的值;(2)求函數(shù)SKIPIF1<0的值域.考點(diǎn)三抽象函數(shù)值域一、單選題1.函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0,值域?yàn)镾KIPIF1<0,那么函數(shù)SKIPIF1<0的定義域和值域分別是(
)A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<02.已知函數(shù)SKIPIF1<0對任意SKIPIF1<0,都有SKIPIF1<0,當(dāng)SKIPIF1<0,SKIPIF1<0時(shí),SKIPIF1<0,則函數(shù)SKIPIF1<0在SKIPIF1<0,SKIPIF1<0上的值域?yàn)椋?/p>
)A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0 C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<03.定義在R上的函數(shù)SKIPIF1<0對一切實(shí)數(shù)x、y都滿足SKIPIF1<0,且SKIPIF1<0,已知SKIPIF1<0在SKIPIF1<0上的值域?yàn)镾KIPIF1<0,則SKIPIF1<0在R上的值域是(
)A.R B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、填空題4.若函數(shù)SKIPIF1<0的值域是SKIPIF1<0,則函數(shù)SKIPIF1<0的值域是____________.5.若函數(shù)SKIPIF1<0的值域是SKIPIF1<0,則函數(shù)SKIPIF1<0的值域?yàn)開_.6.SKIPIF1<0是SKIPIF1<0上的奇函數(shù),SKIPIF1<0是SKIPIF1<0上的偶函數(shù),若函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0,則SKIPIF1<0的值域?yàn)開____________.三、解答題7.已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0,且同時(shí)滿足:(Ⅰ)對任意SKIPIF1<0,總有SKIPIF1<0;(Ⅱ)SKIPIF1<0;(Ⅲ)若SKIPIF1<0,則有SKIPIF1<0(1)試求SKIPIF1<0的值;(2)試求函數(shù)SKIPIF1<0的最大值;(3)試證明:當(dāng)SKIPIF1<0時(shí),SKIPIF1<0.考點(diǎn)四復(fù)合函數(shù)值域一、單選題1.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的值域?yàn)椋ǎ〢.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0,則函數(shù)SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知SKIPIF1<0,則SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0 C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<0二、填空題4.函數(shù)SKIPIF1<0的最大值為______.5.函數(shù)SKIPIF1<0的值域是________________.6.若SKIPIF1<0,SKIPIF1<0,求函數(shù)SKIPIF1<0的值域________.7.函數(shù)SKIPIF1<0的值域?yàn)開_____.8.方程SKIPIF1<0有正數(shù)解,則SKIPIF1<0的取值范圍是_________.9.函數(shù)SKIPIF1<0的最小值=__________________.考點(diǎn)五根據(jù)函數(shù)值域求參一、單選題1.已知函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.(0,4) B.[1,4]∪{0} C.(0,1]∪[4,+∞) D.[0,1]∪[4,+∞)2.已知函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0的值域?yàn)镾KIPIF1<0,則SKIPIF1<0(
)A.7 B.8 C.9 D.103.已知函數(shù)SKIPIF1<0,若存在區(qū)間SKIPIF1<0,使得函數(shù)SKIPIF1<0在SKIPIF1<0上的值域?yàn)镾KIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0的值域?yàn)镽,則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0,SKIPIF1<0,若對任意的SKIPIF1<0,存在SKIPIF1<0,使SKIPIF1<0,則SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.已知函數(shù)SKIPIF1<0若SKIPIF1<0的值域?yàn)镾KIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題7.已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0,值域?yàn)镾KIPIF1<0,則實(shí)數(shù)對SKIPIF1<0的可能值為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0三、填空題8.已知函數(shù)SKIPIF1<0在閉區(qū)間SKIPIF1<0上的值域?yàn)镾KIPIF1<0,則SKIPIF1<0的最大值為________.9.若函數(shù)SKIPIF1<0的定義域和值域均為SKIPIF1<0,則SKIPIF1<0的值為__________.10.已知SKIPIF1<0,x,y滿足SKIPIF1
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 煙草局保密合同范例
- 石材花盆購銷合同范例
- 企業(yè)商務(wù)合同范例
- 物管聘用合同范例
- 農(nóng)村廠房收租合同范例
- 汽車買賣簡易合同范例
- 2025車位租賃合同范本
- 別墅合同買賣合同范例
- 網(wǎng)絡(luò)耗材購銷合同范例
- 新房子貸款合同范例
- 全面設(shè)備保養(yǎng)TPM培訓(xùn)教材課件
- 二保焊作業(yè)指導(dǎo)書
- 垃圾焚燒發(fā)電廠項(xiàng)目給排水安裝工程專項(xiàng)方案
- DB64-T 1147-2022 寧夏工業(yè)單位產(chǎn)品能源消耗限額
- 授課比賽評分表
- XXXX供電項(xiàng)目可行性研究報(bào)告
- 抗菌藥物供應(yīng)目錄備案表
- TSG G0002-2010 鍋爐節(jié)能技術(shù)監(jiān)督管理規(guī)程
- cass實(shí)體名稱,圖層,實(shí)體代碼對照表
- 印刷工藝-ppt課件
- 員工訪談?dòng)涗洷硗暾麅?yōu)秀版
評論
0/150
提交評論