《C++程序設(shè)計(jì)》課程設(shè)計(jì)說明書

1、c+程序設(shè)計(jì)課 程 設(shè) 計(jì) 說 明 書題目名稱：學(xué)生學(xué)號：學(xué)生姓名：指導(dǎo)老師：2011年3月25目 錄第一部分 基礎(chǔ)程序1一、程序代碼1二、運(yùn)行結(jié)果及分析16第二部分 綜合問題20一、需求分析20二、設(shè)計(jì)21三、編碼與調(diào)試22四、結(jié)果分析23五、參考資料24六、總結(jié)25第一部分 基礎(chǔ)程序一、 程序代碼(1) #include using namespace std;const int max=100;void main()int smax,i,x,q,n=10; cout輸入個有序數(shù)列endl;for(i=0;isi;cout數(shù)列為: ;for(i=0;in;i+)coutsi ; coutx

2、;for(i=0;in;i+) if(x=q;i-) si+1=si; sq=x; cout輸出n個有序數(shù)列為; for(i=0;in;i+) coutsi ; (2) #include using namespace std;const int max=100;void main()int smax,i;int sum=0; cout輸入個數(shù)endl; for(i=0;isi;cout數(shù)列為: ;for(i=0;i20;i+)coutsi; for(i=0;i20;i+)if(si%2=0)coutsi ; sum=si+sum; cout和為sum; (3) #include using

3、namespace std;int lj(int i);void main () int result=0,n,i; cout1+(1+2)+(1+2+3)+(1+2+.+n);cout 輸入n:n;for(i=1;i=n;i+)result=lj(i)+result;cout和為resultendl;int lj(int i) int sum=0,a;for(a=1;a=i;a+) sum=sum+a;return sum; (4) #include using namespace std;double ss(int n);void main ()int i;cout50-100的素?cái)?shù)有:;

4、 for(i=50;i=100;i+)if(ss(i) couti ;double ss(int n)int i;for(i=2;in;i+)if(n%i=0)break;if(i=n)return 1;else return 0;(5) #include using namespace std;const int max=100;double aveage(int s);void main()int smax,i;double ave; coutenter 10 students score;for(i=0;isi;ave=aveage(s);cout ave is:aveendl;doub

5、le aveage(int s)int ave=0,i;for(i=0;i10;i+)ave=ave+si;return double (ave)/10;(6) #include using namespace std;double leg(char str);void main () char str81; cout str; leg(str); coutstr;double leg(char str) int n,i,temp;n=strlen(str);for(i=0;in/2;i+) temp=stri; stri=strn-1-i; strn-1-i=temp;return *str

6、;(7)#include using namespace std;const int max=100;void main ()int n=10; int*p,smax,*max,*min;int sum=0;double ave;coutenter n numbers;for(p=s;p*p;coutnumber is: ;for(p=s;ps+n;p+)cout*p ;coutendl;max=s;min=s; for(p=s;p*max)max=p; for(p=s;ps+n;p+)if(*p*min)min=p; coutmax is *maxendl;coutmin is *minen

7、dl; for(p=s;ps+n;p+)sum+=*p; ave=(1.0*sum)/n;coutaveage is aveendl;(8) #include using namespace std;const int max=100;void main() char str181,str281; char *p,*q; cout enter a stringstr1; coutenter another stringstr2; for(p=str1;*p!=0;p+); for(q=str2;*p=*q;p+,q+); coutstr1endl;(9) #include using name

8、space std;class scoreprivate:int number; int computer;int english; double average;public: void inscore(double xx,double yy ,double zz); void showscore();void score:inscore(double xx,double yy,double zz)number=xx; computer=yy;english=zz;average=(english+computer)/2.0;void score:showscore()coutnumber

9、computer englishendl;coutnumber computer englishendl;coutaverage is : averageendl;void main()int x,y,z;int x1,y1,z1; score stu1,stu2,*p=&stu2;coutenter number and computer score .english scorexyz;coutenter another number and computer score .english scorex1y1z1; stu1.inscore(x,y,z);stu1.showscore();

10、stu2.inscore(x1,y1,z1);p-showscore(); (10) #includeusing namespace std;class studentint num; char sname50; double score;public:void setdata();void display();double getscore()return score;void student:setdata()coutenter students number：num;coutenter students name：sname;coutenter the score：score;void

11、student:display()coutnumber name score endl;coutnum sname scoreendl;class manageint i,num;student s80;public: void input(int n); void sort(); void output();void manage:input(int n)num=n;for(i=0;inum;i+) si.setdata();void manage:sort() student temp; int pos,j;for(i=0;inum;i+)pos=i;for( j=i;jspos.gets

12、core()pos=j;if(pos!=j)temp=spos;spos=si;si=temp;void manage: output()sort();for(i=0;inum;i+)si.display();void main()int n;manage m;couthow many students do you want to enter：n;m.input(n);m.output(); (11) #include#includeusing namespace std;class objectpublic:char name50;int number;class book:public

13、objectprivate:char autour50;public:void set(); void display();void book:set()cout書名:name;cout作者:autour;void book:display()cout書名: ;coutnameendl;cout作者: ;coutautourendl;cout書號: ; coutnumberendl;class reader:public objectprivate:int max;public:void set(); void display();void reader:set()cout讀者姓名:name;

14、 cout最多借書數(shù)量:max;void reader:display() cout讀者姓名: ; coutnameendl; cout借書證號: ; coutnumberendl; cout最多借書數(shù)量: ; coutmaxendl;void main()book p;reader q;coutp.number;p.set();p.display();coutq.number;q.set();q.display();(12)#include#includeusing namespace std;const double pi=3.14;class shapepublic:virtual do

15、uble area()=0;class square:public shapepublic:square(int m);double area();private:int n;square:square(int m)n=m;double square:area()return n*n;class circle:public shapepublic:circle(double r);double area() ;private:double radius;circle:circle(double r)radius=r;double circle:area() return pi*radius*r

16、adius;class chang:public shapepublic:chang (int a,int b);double area();private:int x;int y;chang:chang(int a,int b)x=a;y=b;double chang:area()return x*y;class triangle:public shapepublic:triangle(double x,double y,double z) ;double area();private:double a;double b;double c;triangle:triangle(double x

17、,double y,double z)a=x;b=y;c=z;double triangle:area()double m,s;m=(a+b+c)/2;s=sqrt(m*(m-a)*(m-b)*(m-c);return s;void main() int a,b,c,d,e,f,g; cout a; shape *s=new square(a); cout正方形面積:area()endl;delete s; cout b; shape *p=new circle(b);cout圓面積:area()endl; delete p; cout cd;shape *c=new c24hang(c,d)

18、;cout長方形面積:area()endl; delete c; cout efg;shape *t=new triangle(e,f,g);cout三角形面積:area()endl;delete t;(13) #includeconst int maxsize=100;templatevoid sort(t s,int n);void main()int i,n;int smaxsize;char m20;coutn;coutenter n numbersn;for(i=0;isi;sort(s,n);coutsorted numbers:endl;for(i=0;in;i+)coutsi

19、;coutendl;coutn;coutenter n string:n;for(i=0;imi; sort(m,n);coutsorted char:endl;for(i=0;in;i+)coutmi ; coutendl;templatevoid sort(t s,int n)int i,j,pos;for(i=0;in-1;i+)pos=i;for(j=i;jspos)pos=j;if(pos!=i)t t; t=si;si=spos;spos=t;(14) #include#includeusing namespace std;void main()char str100;int i=

20、0;ifstream data(data.txt,ios:in);ofstream data1(data1.txt,ios:out);if(!data)cerrcannor open file!endl;abort();while(!data.eof()data.getline(str,100);data1+itstrendl;coutstrendl;data.close();data1.close();cout共ishowscore();”結(jié)果：enter number and computer score .english score1 99 100enter another number

21、 and computer score .english score2 78 98number computer english1 99 100average is : 99.5number computer english2 78 98average is : 88press any key to continue第十題：分析：enter number and computer score .english score1 99 100enter another number and computer score .english score2 78 98number computer eng

22、lish1 99 100average is : 99.5number computer english2 78 98average is : 88press any key to continue第十一題：分析：輸入書號:1書名:sheeeeee作者:cong書名: sheeeeee作者: cong書號: 1輸入借書證號:2008讀者姓名:bin最多借書數(shù)量:5讀者姓名: bin借書證號: 2008最多借書數(shù)量: 5press any key to continue第十二題：分析：輸入正方形邊長 2正方形面積:4 輸入 圓半徑 2圓面積:12.56 輸入 長， 寬 2 3長方形面積:6 輸入

23、三條邊 3 4 5三角形面積:6press any key to continue第十三題：分析：enter a numbers:2enter 2 numbers1223sorted numbers:23 12enter a numbes:2enter 2 string:d gsorted char:g dpress any key to continue第十四題：分析：要新建 data。txt文件夾congbin共 2 行press any key to continue第二部分 綜合問題一、需求分析需求分析即問題的描述，根據(jù)設(shè)計(jì)題目的要求，充分地分析和理解問題，明確問題要求做什么，限制條件

24、是什么。在確定解決方案框架過程中，綜合考慮系統(tǒng)功能，考慮怎樣使系統(tǒng)結(jié)構(gòu)清晰、合理、簡單和易于調(diào)試。最后確定系統(tǒng)的功能模塊以及模塊之間的調(diào)用關(guān)系。 二、設(shè)計(jì)分析對問題描述中涉及的操作對象定義相應(yīng)的類，并按照以數(shù)據(jù)結(jié)構(gòu)為中心的原則劃分模塊，定義主程序模塊和各抽象數(shù)據(jù)類型。邏輯設(shè)計(jì)的結(jié)果應(yīng)寫出每個抽象數(shù)據(jù)類型的定義(包括數(shù)據(jù)結(jié)構(gòu)的描述和每個基本操作的功能說明)，各個主要模塊的算法，定義相應(yīng)的存儲結(jié)構(gòu)并寫出偽碼算法。抽象數(shù)據(jù)類型的實(shí)現(xiàn)盡可能做到數(shù)據(jù)封裝，基本操作的規(guī)格說明盡可能明確具體。確定每一個模塊的算法流程，畫出流程圖。把詳細(xì)設(shè)計(jì)的結(jié)果進(jìn)一步求精為程序設(shè)計(jì)語言程序，同時(shí)加入一些注解，使程序中邏輯概

25、念清楚；三、編碼與調(diào)試采用自底向上，分模塊進(jìn)行，即先調(diào)試低層函數(shù)。能夠熟練掌握調(diào)試工具的各種功能，設(shè)計(jì)測試數(shù)據(jù)確定疑點(diǎn)，通過修改程序來證實(shí)它。調(diào)試正確后，認(rèn)真整理源程序及其注釋，形成格式和風(fēng)格良好的源程序清單和結(jié)果；根據(jù)系統(tǒng)功能選擇有代表性的數(shù)據(jù)進(jìn)行測試，發(fā)現(xiàn)系統(tǒng)存在的不足并逐步改進(jìn)。注意：此部分不需要粘貼所有程序代碼，對于程序主要運(yùn)行界面需要粘貼（如：主界面、查詢界面等）。四、結(jié)果分析程序運(yùn)行結(jié)果包括正確的輸入及其輸出結(jié)果和含有錯誤的輸入及其輸出結(jié)果，并加以文字分析。五、參考資料所查閱的書籍或資料按下列例子中的格式書寫：1王國榮編active server page &web數(shù)據(jù)庫人民郵電出

26、版社2阮家棟等編web數(shù)據(jù)庫技術(shù)科學(xué)出版社2002.33賀利堅(jiān)等編數(shù)據(jù)庫技術(shù)及應(yīng)用北京希望電子出版社2002.74魏應(yīng)彬等網(wǎng)頁設(shè)計(jì)與web數(shù)據(jù)庫發(fā)布技術(shù)清華大學(xué)出版社2001.15張文增, 孫振國, 趙冬斌等基于web數(shù)據(jù)庫的子集合查詢技術(shù)計(jì)算機(jī)應(yīng)用2002 vol.22 no.1六、總結(jié)1經(jīng)驗(yàn)2存在的問題及進(jìn)一步改進(jìn)ut2apodfxxc02gybkskcww97mrqqwhoj5tl15zt6jipyytycummtarp3v1n5luizi3xh3bhwyreko8d9g7nmzqowpjetldrw08gvs8dsdqqygc3ce7moo2tlf0jf1gk74iuxybmtivr9

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