電子技術(shù)基礎(chǔ)課后習(xí)題答案

1、rb2+vccrfrb1rebecrc直流通道直流通道)(4 . 2210510152. 012)()1 ()(10152. 0)(10152. 0)1000300)(1001 (2()(1 ()(2122555322421121221vrririvuaiiaurruuivvrrruiiiiqiiiqefbqccqccceqbqcqbeqefbeqbqbqccbbbbqbqbq）忽略則有點，往往通常為了穩(wěn)定點：2.8i2i1ibqrbercrliuiibicioubirfrb2rb186. 7300)1001 (5 .1810)5/5(100)1 ()/()(5 .18105 .1710100

2、10152. 0)1001 (1026)1001 (10026)1 (43kkrrrraimvrrfbelcueqbbbekrrco5變大。絕對值變小，會引起，此時相當(dāng)于再串聯(lián)了開路時，當(dāng)iuefefbebbbbbfbbebfbbebiiirarrckrrrrirrririririiur)(7 . 3)1 (/)/()/()1 ()1 (2121rb+vccrebceib)(4 . 203. 080)(03. 03)801 (20015)1 (maiimakkrruviqbqcqebbeqccbq點：)(7 . 71031003. 0)801 (1533vrivueeqccceq2.10rbe

3、iu ii bi ci ou bi brrerl)/)(1 ()/)(1 ()/)(1 ()/()/)(1 ()/(lebeleulebbebleebebilebleeorrrrrarririrririurrirriu/)(1 (/lebebirrrrr）時當(dāng)）（時當(dāng)krrrrrrrkkrrrrrakrkrrrrrrrrrrrrrrrrarbeblebebilebeleulebeblebebiebeelebeleul(765 .3225 .1222005 . 1 )1 (/)(1 (/15 . 1 )1 (15 . 1 )1 ()/)(1 ()/)(1 (39 .109444244200)1

4、(/)(1 (/1)1 ()1 ()/)(1 ()/)(1 ()(4 .368 .36/801)200/2(1/1)/(/37.eebsbeeorrrrrrrp見教材：00)1 (2)(1010-20-:)(15210202:121211112121cicocccecebeccocciiidiiicauuaararrruuamvuuumvuuu，則因則差模輸入電壓值（差值），差模信號即它們的不同則共模輸入電壓值，共模信號即它們的平均uicuoc1, uocib1rc ib1reirerbe1 ib1rbe1ic1共模輸入的微變等效電路共模輸入的微變等效電路（單管）（單管）2.14b1c1euodrc ib1rbeib1b2c2 ib2rbeib2uid差模輸入的微變等效電路差模輸入的微變等效電路mvuuumvuau