C語(yǔ)言程序設(shè)計(jì)第三版譚浩強(qiáng)課后習(xí)題答案

1、1/ 151.5#in elude void mai n() Uery ood*Press any key to continue1.6#i nclude void mai n()float max(float x,float y,float z);float a,b,c;printf(請(qǐng)分別輸入a,b,c:n); sca nf(%f,%f,%f, &a, &b,&c); printf(max=%f,max(a,b,c);float max(float x,float y,float z)float m,n; m=xy? x: y;n=mz? m: z; return(

2、 n);請(qǐng)分別鈿入h”u：1_22_3,0.6piax=2 _30000BPress any key to cont in ue3.6#in clude void mai n()char c1 =a,c2=b,c3=c,c4=101,c5=116 printf(“a%cb%ctc%ctabcn”，c1,c2,c3);printf(“tb%c %cn”,c4,c5);printf(* n);printf(”Very good!n);printf(* n);2/ 15I aa bh cca beA NPeess any key to continue3.9.1#in elude void mai

3、n()double x=2.5,y=4.7,z;int a=7;z=x+a%3*(i nt)(x+y)%2/4;printf(該表達(dá)式的值為：f,z);達(dá)式的值2any kej/ to continue3.9.2 #in elude void mai n()int a=2,b=3;float x=3.5,y=2.5, z; z=(float)(a+b)/2+(i nt)x%(i nt)y; printf(該表達(dá)式的值為：f,z);#i nclude void mai n()int a=5,b=7;double x=67.8564,y=-789.124;char e=A;long n=12345

4、67;un sig ned u=65535;prin tf(%d%dn,a,b);prin tf(%3d%3dn,a,b);prin tf(%f,%fn,x,y);prin tf(%-10f,%-10fn,x,y);prin tf(%8.2f,%8.2f,%.4f,%.4f,%3f,%3fn,x,y,x,y,x,y);prin tf(%e,%10.2en,x,y);prin tf(%e,%d,%o,%xn, n,n,n);3/ 15prin tf(%ld,%lo,%xn, n,n,n);prin tf(%u,%o,%x,%dn,u,u,u,u);prin tf(%s,%5.3sn,COMPUT

5、ER,COMPUTER);5757G7-56400,-789-124M0067-856480 ,-789.12400067-86, -789丄267.S564. 1240,67.8554004-787.124000 k 785640e+001,-7.89e*0027123456?,4553207,252124123456?.4553207,12d68?65535,177777,fFff,65535COMPUTER, CONPress any key to cont inue4.6#in elude void mai n()int a,b;float x,y;char e1,e2;seanf(a

6、=%d b=%d,&a,&b);seanf( %f %e,&x,&y);sea nf(” %e %e,&c1,&e2);(-3 b-? a.5 ?.lS2s*60i AAess aiey key to continue4.7#in eludevoid mai n()int a,b;float x,y,z;ehar e1,e2;sea nf(%5d%5d,&a,&b);sea nf(%f%f%*f%f, &x,&y,& z);sea nf(%e%e, &c1,& e2);1320 A a 1.

7、5*I*BES：kei tzo continueH4/ 154.8#i nclude #defi ne pi 3.14void mai n()float r,h,l,s1,s2,v1,v2;5/ 15printf(”請(qǐng)輸入r,h的值：n);scan f(%f,%f, &r,&h);l=2*pi*r;s1=pi*r*r;s2=4*s1;v仁4/3*pi*r*r*r;v2=s1*h;prin tf(圓周長(zhǎng)為：%.2fn,l);printf(”圓面積為：%.2fn,s1);printf(”圓球表面積為：%.2fn,s2);printf(”圓球體積為:%.2fn ,v1);prin t

8、f(圓柱體積為:%.2fn ,v2);5.5 #i nclude void mai n()float x,y;printf(”請(qǐng)輸入x的值：n);scan f(%f, &x);if(x=1 &x10) y=2*x_1;elsey=3*x-11;printf(x與y的值分別為：n%f,%f,x,y);prin tf(n);月剔的值分別汕*r-es：s：kei to eontinue5.6 #in clude -19to continue2 7040- 1I I21W 0Y7T誥k:積為為 m為為面棗an 3 st體s 5,周面1es6/ 15void main() float b

9、;int a;printf(”請(qǐng)輸入該同學(xué)的成績(jī)：n);scan f(%f, &b);while (b100)printf(輸入有誤，請(qǐng)重新輸入：n); scan f(%f,&b);a= in t(b/10);if(a6) a=5;switch(a)case 10:case 9: printf(該同學(xué)為等級(jí)：A);break;case 8: printf(該同學(xué)為等級(jí)：B);break;case 7: printf(該同學(xué)為等級(jí)：C);break;case 6: printf(該同學(xué)為等級(jí)：D);break;case 5: printf(該同學(xué)為等級(jí)：E);break;喬輸入該

10、同莘的成績(jī);-101輸入有誤，請(qǐng)重新輸入:孟丈有誤，請(qǐng)重新輸入99.5該同學(xué)為等級(jí)：A Press anv key to continue#i nclude #in clude void mai n()int x,y,m, n,i=1,j=0;printf(請(qǐng)給出一個(gè)不多于5位的正整數(shù):n); sca nf(%d, &x);while(x=100000) printf(輸入有誤n請(qǐng)給出一個(gè)不多于5位的正整數(shù):n); sca nf(%d, &x);for(n=0;n0& y=0);printf(n逆序輸出為n);doprintf( %d,i nt(x/pow(10,j)%

11、10);j+；請(qǐng)給出一個(gè)不多于弓位的正整數(shù)個(gè)不多于石柱的正蔓數(shù)惟序輸出為ressAnykey to cont inue14235巨是石位數(shù) 氏高到低位依次為個(gè)不多于5位的IE整數(shù)L23456while(j-m0);prin tf(n)8/ 156.1輸入兩個(gè)正整數(shù)m和n,求其最大公約數(shù)和最小公倍數(shù)#i nclude void mai n()int m, n,i,j;printf(請(qǐng)分別輸入m,n的值：n); scanf(%d,%d,&m,&n);for(i=1;i=m;i+)if(m%i=0&n %i=0) j=i；printf(這兩個(gè)整數(shù)的最大公約數(shù)是：d,j);fo

12、r(i=j;i+)if(i%m=O&%n=0) break;printf(這兩個(gè)整數(shù)的最小公倍數(shù)數(shù)是：%d,i); prin tf(n);分別輸Am, n的值;更眾整數(shù)的最大公釣數(shù)是I d這兩個(gè)整數(shù)的最小公倍數(shù)數(shù)是I 105rieso Anp key to continue6.2題目：輸入一行字符，分別統(tǒng)計(jì)出其中英文字母、空格、數(shù)字和其他字符的 個(gè)數(shù)。#i nclude void mai n()int i=O,j=O,k=O,x=O;char c;printf(請(qǐng)輸入一行字符串：n);while(c=getchar()!=n)if(c=A&c=a&c=O&c=9

13、) k+;else x+;9/ 15printf(英文字母、 空格、 數(shù)字、 其他字符的個(gè)數(shù)分別為：d,%d,%d,%d,i,j,k,x); prin tf(n);晴輸入一行字符串：gxs123 CU-c2英文字毎空權(quán) 數(shù)宇二其他字符的個(gè)數(shù)分別為Pr*esslei/ ifco continue10/ 156.3求Sn=a+aa+aaa+aaa之值，其中a是- -個(gè)數(shù)字。2222+22222(此時(shí)n=5),n由鍵盤(pán)輸入。#i nclude#in cludevoid mai n()int i,n;int sum=0,s=0;printf(請(qǐng)輸入n的值：n);scan f(%d,&n);wh

14、ile( n1)printf(請(qǐng)重新輸入n的值：n);sca nf(%d,&n);for(i=0;i n ;i+)s+=pow(10,i);sum+=2*s;prin tf(sum=%dn,sum); 青輸入的值;i;un=246?0*ress niny key to continue6.8題目：有一分?jǐn)?shù)序列2/1,3/2,5/3,8/5,13/8,21/13,項(xiàng)之和。#i nclude void main()例如：2+22+222+求出這個(gè)數(shù)列的前2011/ 15int a=1,b=1,i;float sum=0.0;12/ 15for(i=0;i20;i+)a=a+b;b=a-b;

15、sum+=(float)a/b;printf(這個(gè)數(shù)列前二十項(xiàng)之和為:printf(n);n%f,sum);7.2#in cludevoid mai n() int i,j,t,a10; printf(請(qǐng)輸入十個(gè)整數(shù)：n);for(i=0;i10;i+)sca nf(%d,&ai);for(j=1;j10;j+)for(i=0;i10-j;i+) if(aiai+1)t=ai;ai=ai+1;ai+1=t;printf(這十位數(shù)從大到小排列為：n);for(i=0;i10;i+)prin tf(%5d,ai);prin tf(n ”);請(qǐng)瑜入十(整數(shù):12 E 6 -4 -2 5 8

16、9 -3這十位數(shù)從大到小排列如986 S 521-2-47.3#in cludevoid mai n()13/ 15Press an y key to cunt inue7.8#in cludevoid mai n()int a5 5,b5,c 5,d55;int i,j,k,l;int i,j,m,n,a33; printf(”請(qǐng)輸入3*3的整形矩陣n);for(i=0;i3;i+)for(j=0;j3;j+)scan f(%d,&aij); m=a00+a11+a22;n=a02+a11+a20;printf(3*3的整形矩陣對(duì)角線(xiàn)元素之和為：n);prin tf(%d,%d,m,

17、 n);輸入3購(gòu)的輕形矩陣I1256347891F刈的整形矩陣對(duì)角線(xiàn)方素之和為;7.4#in cludevoid mai n()static int a10=1,5,6,10,20,24,55,58,64; int i,t;printf(請(qǐng)輸入一個(gè)數(shù)：n);scan f(%d,&a9);for(i=9;i0;i-) if(aiai-1)t=ai-1;ai-1=ai; ai=t;for(i=0;i10;i+)prin tf(%4d,ai);prin tf(n ”); ia&214/ 15printf(請(qǐng)輸入5*5的整型數(shù)組n);15/ 15for(i=0;i5;i+)for(j=

18、0;j5;j+)sea nf(%d, &dij);for(i=0;i5;i+)for(j=0;j5;j+)aij=dij;for(i=0,k=0;i5;i+,k+) for(j=0;j=aij+1)bk=aij+1=aij;elsebk=aij+1;for(j=0,l=0;j5;j+,l+) for(i=0;i4;i+)if(aij=ai+1j) el=ai+1j=aij;elseel=ai+1j;for(i=0,k=0;i5;i+,k+) for(j=0,l=0;j5;j+,l+)if(dij-bk=0)if(dij-el=0)printf(鞍點(diǎn)為d%d%d=%dn”,i,j,dij

19、); elseprintf(沒(méi)有鞍點(diǎn)n);IM 11 12 13 14 151? IB 19 2 21 22 23 24 2G7.10#in clude#in clude void mai n()int i,j=O,k=O,l=O,m=O,n=0;char str0301,str1100,str2100,str3100;gets(strl);6s4224ILd0點(diǎn)點(diǎn)點(diǎn)點(diǎn)點(diǎn)有有有有技殳殳殳U- II*na al lOtyekunt inue16/ 15gets(str2);gets(str3);strcat(str0,str1);strcat(str0,str2);strcat(str0,st

20、；for(i=0;str0i!=0;i+)if(strOi=A&strOi=a&strOi=O&str0i=9) l+;else if(strOi=) m+;else n+;printf(”大寫(xiě)字母、小寫(xiě)字母、數(shù)字、空格以及其他字符的個(gè)數(shù)依次為:prin tf(%5d %7d %5d %6d %4dn,j,k,l,m, n);prin tf(n);7.14#i nclude #in clude void mai n()int i=0,resu;char s1100,s2100;printf(n請(qǐng)輸入string1:);gets(s1);printf(n請(qǐng)輸入string

21、2:);gets(s2);while(s1i=s2i&s1i!=0)i+;if(s1i=O&s2i=0)resu=0;else resu=s1i-s2i;printf(n result:%dn,resu);請(qǐng)輸入涇七卩inJ ： love請(qǐng)輸入衣ring2： 1 ileresvIt: 6n);17/ 15fress anv to cont inue8.1#in cludevoid mai n()int maxgy(i nt m,i nt n);int min gb(i nt o,i nt p);int a,b;printf(請(qǐng)輸入兩個(gè)正整數(shù)：a,bn);scan f(%d,%d,&a,&b);while(a=0|b=0)printf(注：請(qǐng)輸入兩個(gè)正整數(shù)：a,bn);scan f(%d,%d, &a, &b);printf(這兩個(gè)數(shù)的最大公約數(shù)是：%d,maxgy(a,b);printf(這兩個(gè)數(shù)的最小公倍數(shù)是：%d,mingb(a,b);prin tf(n ”);int maxgy(i nt m,i nt n)int i,k;for(i=1;i=m;i+)if(m%i=0&n %i=0)k=i;return k;int mingb(int o,int p)int j;for(j=o;j+)if(j%o=0&j%p=