[理學]信號處理英文版習題答案1-6章另版ppt課件

1、第一章第一章1.16)mod(24)4sasfffHzf2)mod(8) 16sasfffHzff6)mod(12)2sasfffHzf6)mod(16)3sasfffHzfthe observer perceive the wrong sense of rotation the observer lose the sense of rotation the observer perceive the correct sense of rotation the observer perceive the correct sense of rotation )()()5/2sin(5)5/12s

2、in(5)5/8sin(10)5/2sin(10)()5/2sin(5)/2sin(5)2sin(5)()2sin(5)2sin(5)2sin(10)2sin(10)(; 1)5mod(6)mod(; 1)5mod(4)mod(; 1)5mod(1)mod(5 . 2 , 5 . 2 :5) 16,4,1321332211321nTxnTxnnnnnTxnfnnTnTxttftftftxfffffffffintervalNyquistHzfHzfHzfHzfasaaaaasasasas1.2 )()()10/8sin(5)10/2sin(10)10/12sin(5)10/8sin(10)10/

3、2sin(10)()10/8sin(5)10/2sin(10)()8sin(5)2sin(10)2sin(5)2sin(10)2sin(10)(; 4)10mod(6)mod(; 4)10mod(4)mod(; 1)10mod(1)mod(5 , 5 :10)2321332211nTxnTxnnnnTxnTxtttftftftxfffffffffintervalNyquistHzfaaaaaasasasas1.3)(2cos)(2cos2)()2)cos()2cos()2cos(2)(; 5 . 0)3mod(5 . 2)mod(; 5 . 0)3mod(5 . 0)mod() 15 . 2

4、,5 . 2 :35 . 2,05)5cos()cos(2)(2121221121tmfftmfftxttftftxffffffkkintervalNyquistkHzfkHzfkHzftttxssmnaaasasas1.9)()()20sin()10sin()(:)10sin(2)(;5)mod(;10)mod(;10)mod(;5)mod(20,20 :4045,30,10,5)443322114321tytytttyprefiltertheofoutputthebttykfffkfffkfffkfffkkintervalNyquistkHzfkHzfkHzfkHzfkHzfaaasasa

5、sasas)20sin(9605. 0)10sin(0016. 1)10sin(0016. 0)20(0395. 0)20sin()10sin()(:;5)mod(;10)mod(;10)mod(;5)mod()90sin(0016. 0)60sin(0395. 0)20sin()10sin()(:0016. 010)(156.56)2045(log48prefilter0395. 010)(078.28)2030(log48prefilter)4433221120/156.5642420/078.28323tttttttyistorreconstrucanalogtheofoutputthe

6、kfffkfffkfffkffftttttyisprefiltertheofoutputthefHdBffHdBfcasasasasa處的幅度值：后信號在頻率通過處的幅度值：后信號在頻率通過第二章第二章2.11 x=3.7 ; truncation ; twos complement bipolar ADCtestm24012112221623BRQ321bbbmQxQ)(Qxxuc2b3b0101001002Qx2 x=3.7 ; truncation ; twos complement bipolar ADCtestm-2-41-1-20-2-4321bbbmQxQ)(Qxxuc01111

7、12b3b0114Qx3 x=3.7 ; rounding ; offset binary bipolar ADCtestm00124136024321bbbmQxQ)(Qxyuc2b1b3b0110011110112Qxy4Qx4 x=3.7 ; rounding ; offset binary bipolar ADC2Qxytestm00024112024321bbb1b2b3b001010110010mQxQ)(Qxyuc4Qx2.3dBBQRRQeBBQRQQeBrmsBrms726)(log20) 3millivolt7 . 01221012212)2125 .11101221012

8、10112) 110123332.4Megabytes07.108388608108448bit8388608810241024Megabytes1bit108448216601044443第三章第三章3.1nonlinear time-invariantnonlinear time-variantnonlinear time-invariantlinear time-variantnonlinear time-varianta. 3.24023)()3(4) 1(2)(3)(nhnnnnh3.3)()9 . 0()(nunhn3.4)() 1(9 . 0)(nxnyny3.16)()()()

9、()()()()()()(00DnynyDnyDlnxlhmnxDmhmnxmhnymnxmhnyDDllDmmmDDDm）令第四章第四章y4.1 11121121 ,1211 xha the convolution tableb the LTI form of convolution arranged in a table form 111211211121111121121111221121111221112112111111221111111221111211121111clength-3ny109876543210321yyy14653114653113321

10ylength-521yy10987654321013467677531255775311344214.3a.The overall index range n for the output yn 2613632010201063nmnmmnm或62063103m)x(n-h(m)(2623m)x(n-h(m)(2317m)x(n-h(m)(1613)10, 6min()20, 3max(102063201063m)x(n-h(m)y(n):formdirectnmmnmnynnynnynnmnnmnmmnm20636310m)(n-(m)(2623m)(n-(m)(2

11、317m)(n-(m)(1613)3,20min()6,10max(362010632010m)(n-(m)y(n):formLTInmnnmnmhxnynhxnynhxnynnmnnmnmmnmhxb.261312344444444321)(nnyn1315: input-on transient; n=1623 steady state; n=2426 input-off transient 4.4a.)(11:;11:)(11)(0 , 000)()()(110nuaaresponsetransientthearesponsestatesteadythenuaaanynmmnmnmmnu

12、muanynnnmmmm)(1)(1) 1( :;1) 1(:)(1)(1) 1() 1()(0 , 000)() 1)()(110nuaaresponsetransientthearesponsestatesteadythenuaaanynmmnmnmmnumuanynnnnnnmmnmmmnmb.4.5aaaanyLnaaanyLnLnmmnmnLmmnuaLmumunynLnLmmnnnmmnmmn1)(11)(10) 1,min(0;0010)()()()(1110104.15a. 1001 ) 3()()(hhnnnb.+1z1z1zx(n)y(n)-1-11w2w3w)3 ,(30

13、0wdelaywwyxwxwwwwwwxy112233或yLTI form table4221111110 1001 h210021001141001131211也可以用其它方法求出結果c.d.n43210)(nx)(0nw)(1nw)(2nw)(3nw30wwy4221122110211001100031211422114.18a.b.2101 hy11121121213334231111111021011210111221021121102122110212201122110112102122c.ny10987654321021yy2133342311142031112133122d.+1

14、z1z1zx(n)y(n)-1 21w2w3w-1xwwwwwwwxy11223322第五章第五章5.2zROCzzX:)(55.30:5 . 01)5 . 0(15 . 01)5 . 0(5 . 011)()10()5 . 0()5 . 0()()5 . 0()(11011101011010zROCzzzzzzXnununxnn5.49 . 0:9 . 0119 . 011)()()9 . 0()9 . 0()()9 . 0()(1122zROCjzjzzXnujjnueenxnnnjnjn5.5變換，所以不存在的交集為空集兩者為：的序列為：的序列zROC4ROC)(4;25. 0ROC)

15、1()25. 0()25. 0:41125. 011)()425. 0:41125. 011)()4:41125. 011)()111111znuznudzROCzzzXczROCzzzXbzROCzzzXann5.7非因果，穩(wěn)定因果，穩(wěn)定)3(12)2(2)3(3)(5)()()3(12)2(4) 1(3)()(12431)()(321nnnnnxbnnnnnxzzzzXa5.8因果臨界穩(wěn)定）非因果非穩(wěn)定）因果穩(wěn)定）)()5 . 0()()5 . 0()(4(1:5 . 0115 . 01114)()() 1()5 . 0(2) 1()5 . 0(4)(8(5 . 0)()5 . 0(2)(

16、)5 . 0(4)(8(5 . 05 . 0125 . 0148)()(11111nunununxzROCzzzzXenununnxznununnxzzzzXbnnnnnn)4()8 . 0(5 . 0)4()8 . 0(5 . 0) 1()8 . 0(3) 1()8 . 0(3)(8 . 0)5()8 . 0(5 . 0)5()8 . 0(5 . 0)()8 . 0(3)()8 . 0(3)(8 . 0) 1()8 . 0(5 . 0) 1()8 . 0(5 . 0(8 . 0)()8 . 0(5 . 0)()8 . 0(5 . 0(8 . 08 . 015 . 08 . 015 . 064

17、. 011)()(5555111nununununxznununununxznununwznununwzzzzzWcnnnnnnnnnnnn時時）設：法一不可取。這種方法計算太麻煩，法二47. 1;53. 48 . 018 . 0164. 064. 064. 01664. 064. 064. 0)(211211213121213AAzAzAzzzzzzzX第六章第六章6.14 . 0, 5 . 02, 3)4(2 . 09 . 0161)()3()()4 . 0(136)()5 . 0(105)(30)(4 . 011365 . 0110530)()2(2 . 09 . 0161)() 1 (

18、22112121zzzzeeeeHnununnhzzzHzzzzzHjjjjnn極點：零點：5見黑板6 direct form+1z1zx(n)y(n)1z1z1z-6-0.20.91v2v2w1wxwwwyvvvwwxvvy1121122121;62 . 09 . 07 canonical form+1zx(n)y(n)1z1w2w0w-0.20.9-6011221021062 . 09 . 0wwwwwwwywwxw6.5 e的圖零點：極點：)(708 . 00, 8 . 08 . 01)8 . 0(1)(8 . 01)8 . 0(1)(828181HnezzzeeHzzzHnjijj6.12) 1()5 . 0(7 . 0)()5 . 0()()()()6 . 0(21)(;6 .