解題報告快樂的蜜月

1、福建師大附問題的模型問題分析福建師大附問題的模型問題分析d天的收益也最大。因此，f(d)f(d)w考慮k1每次處理第i，gif(d,i)x.w1ik)，g進行歸并取前k復雜度 集合S200008bytes200008160000bytes復雜度 集合S200008bytes200008160000bytes小結參考程序FileIn = FileOut = Days :=(0,31,59,90,120,151, 181,212,243,273,304,334,TDay= PDay= d1, d2 GType : Pay: next : EachDay=array1.100of;Request:a

2、rray1.366ofr k, k2, :array1.100of;ti, : ;d: var day2 i, :F:s:p : procedure var d, j s1 j ( ,s); s1copy(s, j-1);Request:array1.366ofr k, k2, :array1.100of;ti, : ;d: var day2 i, :F:s:p : procedure var d, j s1 j ( ,s); s1copy(s, j-1);delete(s, 1,j+ j (/,s1);val(copy(s1,j-1),m,val(copy(s1,j+ 1,length(s1

3、)- d,day1:=daysm-1+ j (,s);s1:=copy(s,1,- delete(s, 1,j (/,s1);val(copy(s1,1,-1),m,val(copy(s1,j+ 1,length(s1)- d,day2:=daysm -1+ d- p.d1 := p.d2 := val(s,p.Gtype,p.next :=requestday2if then latest:= k, if (i 400 =or (i mod4 = 0)p.d1 := p.d2 := val(s,p.Gtype,p.next :=requestday2if then latest:= k, i

4、f (i 400 =or (i mod4 = 0)for i := 2 toreadln(f, for i :=1 to366 dorequesti:= for i := 1 to rreadln(f, fori:= 1totdoreadln(f, fori := 1 tolatest p := whilep nilwithpdopay:= *-+p:= k2 := * var i, l p2, p3t:p:f:g:array1.200of;procedure Sort(l,:i, : x, : ;i withpdopay:= *-+p:= k2 := * var i, l p2, p3t:p

5、:f:g:array1.200of;procedure Sort(l,:i, : x, : ;i j r;g(l+r) div:= ixgjdo j:=jif i if l jthenif i rthenfor i 0tolatest := for i 2 to kdo -for j 1tolatest p := dj := djwhile p until i if l jthenif i rthenfor i 0tolatest := for i 2 to kdo -for j 1tolatest p := dj := djwhile p with for :=to k i1- -gi:= dd1 1i+ gi :=-gi + k:=sort(1, p1 := p3 := djp3:= -while p1 k while p3 k while p1 k while p3 k djp3:= -p