(完整)初中精選數(shù)學計算題200道

計算題cl333+3）o-∣3-2∣3x2=3-x1x-44-x+x2x22x41x-2x3x-8x2244215+=4x2-1因式分解（2x+y）22-8a2b+2a32a-1643ax2-6axy+8ab2x2先化簡，再帶入求值（x+2）(x-1)-,x=3x-112(-3o∣-3∣)11(-a-12-a2-12-1÷21x-2x2(÷3212(-3-1)(-2-2(-31=1-324x22sin603（）1222-5）(-2)結(jié)果以冪的形式表示)13若n為正整數(shù)且（m）2=9,m）3(m2)na2x2因式分解(x+2)(x+3)+x2-4因式分解22-4a21-1+18÷(-3)-∣23(x2+xy-1)-(3x2x=1-13-4+5-(-6)-718-122×∣--82÷(-4)332.20-（-7-2∣1533.-+）×(-36)3921434.-1）2-[2-(-3)2]①②1-=-①34②①②3x-1-≤35a(a-1)22ab1(+)÷a-bb-a15-2m+1當m12tan45o-cos60ocos30o（）-（2-1）o-3+·tan60°x23x2-3x32x-3(1-)(1+33x=-132·2+-3.14）o+-8+cos245°3）2+4--23先化簡，再求值（a+b）(a-b)+b(b-2),2,b=-114（化簡[+÷a-ba(b-a)-22o+3sin30°）+2006--3tan60°2013-（π-3.14）o-3-1）4（﹣1）﹣|﹣7|+×20130．﹣+1．÷20132012201101xy2x22+（+1）+．30．5-5+22-(3o2×(－5)＋2－3÷322＋(－1)＋(5－2)－|－3|240032-÷1-x-22aax21xxxx2xx221aa)2a3a)(m1m1m1m22m113m22xx62xx14x4xx,x222()x22xx224x11ab2ab22aab2aa32，b323．1a4a23．a(chǎn)3a2aaa1221·691x＝－6．x3x2xxx3x22x2x1aa2102.先化簡再求值：1－÷a＝2＋2.aaa2－aaa·12a為÷aaaa22a整數(shù)且－3＜，112xx1yxyx22y2x．y22xx2x(x1.2xx24x22112x2()x2xx4x4x2x22222aa21．(aa1a2a121aa412?aa2a22a1a12．20aa7440，a1a2(1÷21xxx21x2y222xxxx=-3.x22xx﹣4x+1=0．223x2x2＝．2x-=2．xx5x164x1xxxxx2－5＞3．12.x282xx1x3x12x＜1，3x)≤5，x102(x2)3x3x1x31x12x≤123先化簡,再求值:2(a3)(a3)a(a6)6,其中a21.230x2x12x(x，3(x1；()3tan302)1210021(a11a)aa2a22a先化簡，再求值.1x24x3)x3x－2x＝1，求(x－1)(3x＋1)－(x＋1)221a1a1a1a22a1a1a(x253x23x)