精品解析2022年人教版八年級(jí)數(shù)學(xué)下冊(cè)第十八章平行四邊形同步測(cè)評(píng)試卷(含答案詳細(xì)解析)

經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁(yè)眉頁(yè)腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請(qǐng)聯(lián)系刪除，謝謝！人教版八年級(jí)數(shù)學(xué)下冊(cè)第十八章-平行四邊形同步測(cè)評(píng)I第I卷（選擇題30分）3OAOBOBPOABP⊥，BOACDOOAOAPDDP在向）ABCDACBB，ABDCE（）DABCAB′ACDBCD′ADAE＝AECE＝）ABCDAEBDEDBC⊥于）BEcmAEcmcmcmcm33ABCD是是EBCADAEFAEDFABCDFE）6393B．183273abcdab，，，，abcd22222）ABCDDEACEBDE⊥于ADEEDC）ABCD∠A∠B∠A與）ABCDACBDOACBD、6和為、為HABOH）4）第Ⅱ卷（非選擇題70分）46和ABCDABBCC，BCP1CD交，QPQPQN交的CNBA2EAERtABD△D＝ABADBDBDCDCBDPPADPDBPCCPABCDOBDADx∥ADA形ABCDODxCABCDABAD，為、為EBCFGAD3FEGFG∠x(chóng)OyAxmAB（，＝xxnnCx+（在m33mABAB；ACDCDACBD至＝．OAACOCBD＝OCACODPOD＝PBDPABCDACBDABCD＝ABCDEACCEEBBDDAABCDE＝＝＝＝ABCDEABCDEFCDBC、、．AEBDDEC是FCF，ABC60EFBFABCDACEFADFBCE交ACOAECFEFAC是OAOCOEOFEFAC∴＝，＝，⊥，AECFEFAC⊥，AECFAECFaABCDODDPOC作∥DP=OCCPCODPbc作C于，H于CGOAG,CHOBOBCH4,OPHBDGCGOBHB作C于，于G，HCHOB,，∵∴，,∴，∵，CHOB∴，∴OBPHCB，在和O，∴∴HCB(AAS)，OBP，∴OGOB，∵,，∴∴∴，DGCGOBHB，PDDGPGOBHBOPOG)OBHB(HBOB)OB8∴PDBACCABBACACDACDCABAECE∠=ABCDACBBBACCABABCD∵∥，BACACD，ACDCABAECE∴=，DABCDBAEABCDBADBDADBCAEBD∵⊥，DAEBAERtABE在△BAEBEcm，ABcm∴，AE∴=cm(ABBE21322221FMNFAE作，、是AEFMADFMFN2SSSS四邊形CDEF矩形ABCDABEADFF作MN、，，F(xiàn)MADFNBCABCD∴，，ABE90BCAD63EBC是1∴33，2FAE∵是19∴∴FMFN，AB22119SSSS63933963273．四邊形CDEF矩形ABCDABEADF222SSSS四邊形CDEF矩形ABCDABEADFa=bc=d，，abcd22222，a2abbc2cdd02222(ab)（cd)0，22abcd0，a=bc=d∴，，abcdab，，，，B．EDCODC．ABCDADC，∵，∴ADE，EDC，∵，∴DCE，∵ODOC，∴，∴，DOC60∴．BABCDADBC∴∥，BABAOHABCDAOOCOBODAOBO∴＝，＝，⊥，HAD是OH∴DABRtAOBAB在△AOBO221OHAB則2CAB26和628212ECBCDBCDABCDBECECDECB∥=BEBCECECDECB，ABCDABCD∴∥，BECECD，BECECB，BEBC∴=AEBEAB∴=-27232327ADOOPOC、、OPOCADOPOCO、PADPDBPDBADPPADADPAPDAOOD∵=，POOAAD∴==，∴ADABBD84432222OP∴=，23BDCDOD∵==23，∴222OCODDC23427,2PCOPOC∵≤+，PC∴≤，2723PC∴．2723．2723OPOC、或或，0230233023DxDxDx1O∵ABCDBDAODO∴⊥，DxAyABCCy、、在BADOAD1∴，22∴，OCOAADOD2322C23Dx2OC23，C23C23232323433FGABFEGEB與點(diǎn)CFEGGD與與FAFGABCDABAD322332343ABDABFAF∠=FG=AD-AF=23．tan60333FGABFEGFEGFEGEBCGDFA與與與FGABCDABAD3ABDABF2233AF∴=tan32343FG=AD-AF=23．3343．3OCBDOCBD＝，∥mAB，OCBDOCBDABxT＝，∥交＝OCCTCTBDBDCT2∥，ABOCTPPHOCHOTB交作⊥于（＝PHOAASBTOH30m，3m0m∴xn∴＝，An∴（ABx∵，Bn∴（AB∴OCBDOCBD＝，∥．ABxT交．ABx∵，ABOCATTB∴⊥，＝，AOAC∵＝，OTCT∴＝OCCT∴，ACCDATTB∵＝，＝，CTBDBDCT∴∥，，OCBDOCBD∴＝，∥；ABOCT交作，PH，B(3，ACOCCD∵＝＝，COAOACCOD，CDOOACCDOOACCDOAODABx∵，OTABOAOB∴⊥，＝，OBTOAT，CODAOCAOCOATOATCOD，OBTCODOBT，POHBDOC∵∥，PDBPOHOBTABDPBDABPOBPOBTABPOBTOPB，PBDPDBPDBOBPOPB，OBPO∴＝，在和，OTBPHOAAS（BTOH∴＝P3SSSABCBCDCDEDEAEABABCBCDCDEDEAEABSSSABEBCADECBAECBAEDC，AEBABEBACBCADCEDEC∠SSSACEBECACECEB，CEACAEEBCECBABCE∠ABCECBABCE∥ABEBECBACACEBAEABECBADAEDBCDABEBAE∠ABCDABBCCDDA＝＝＝，ABCDACBD∵＝，ABCDABCDABCDEABBCCDDEEA∴＝＝＝＝，ABCEABBCDCDEDEAABCBCDCDE≌（DEAEABSSSABCBCDCDEDEA，EABABCDE3ACBECE若＝＝ABCDEABEBCADEC，ABEBCADECSSS（BAECBAEDCAEBABEBACBCA，DCEDECACEBECAEBCBECEACCEACEBECSSS（ACECEBCEACAE，EBCECBABCEABCECBABCE∴∥，ABEBECBAC，ACECAECEAABE，BAEABE，CBADAEDBCD，ABEBAEABCDEABDCDEDFCF====ABDEABCDAB∥CDAB∥EDAB=CDABDE=EFBFCDEDDFCDED⊥，===DCFABCDAB∥CDAB∥EDAB=CD，∵，AEBDABDEABDE∴=，CDED∴=，DCE為ABDCDEDFCF====，EFBFCDED∵⊥，=，DFCDED∴==，AB∥CD，ABC∠∵DCFABCDCFCFCDDFABED∴====．ASAAOCO，EFACAECF是AC，，OAOC；OEOFABCDAD//BC．是AC，F(xiàn)ACECA，AOFCOE(ASA)