電大《c語(yǔ)言程序設(shè)計(jì)》第1、2、3、4次作業(yè)及答案參考小抄

PAGEPAGE1電大《C++語(yǔ)言程序設(shè)計(jì)》第1、2、3、4次作業(yè)及答案第一次作業(yè)一、寫(xiě)出下列每個(gè)程序運(yùn)行后的輸出結(jié)果1.#include<stdio.h>voidmain(){ intx=5;switch(2*x-3){ case4:printf("%d",x); case7:printf("%d",2*x+1); case10:printf("%d",3*x-1);break; default:printf("%s","default\n"); } printf("%s\n","switchend."); } 2.#include<stdio.h>voidmain(){ inti,s=0; for(i=1;i<=6;i++) s+=i*i; printf("s=%d\n",s);}3.#include<stdio.h>voidmain(){ inti,s1=0,s2=0; for(i=0;i<10;i++) if(i%2)s1+=i; elses2+=i; printf("%d%d\n",s1,s2);}4.#include<stdio.h>voidmain(){ intn=10,y=1; while(n--){y++;y++;} printf("y=%d\n",y);}5.#include<stdio.h>voidmain(){ intf,f1,f2,i; f1=f2=1; printf("%d%d",f1,f2); for(i=3;i<=10;i++){ f=f1+f2; printf("%d",f); if(i%5==0)printf("\n"); f1=f2; f2=f; } printf("\n");}6.#include<stdio.h>#include<math.h>voidmain(){ inti,n; for(n=2;n<=20;n++){ inttemp=(int)sqrt(n);//sqrt(n)求出n的平方根并取整 for(i=2;i<=temp;i++) if(n%i==0)break; if(i>temp)printf("%d",n); } printf("\n");}7.#include<stdio.h>#include<math.h>constintM=20;voidmain(){ inti,c2,c3,c5; c2=c3=c5=0; for(i=1;i<=M;i++){ if(i%2==0)c2++; if(i%3==0)c3++; if(i%5==0)c5++; } printf("%d%d%d\n",c2,c3,c5);}8.#include<stdio.h>#include<math.h>constintM=20;voidmain(){ inti,s; for(i=1,s=0;i<15;i++){ if(i%2==0||i%3==0)continue; printf("%d",i); s+=i; } printf("%d\n",s);}參考答案：1、答案：1114switchend.2、答案：s=91.3、答案：2520.4、答案：y=21.5、答案：112358132134556、答案：2357111317197、答案：10648、答案：157111337第二次作業(yè)一、根據(jù)下列每個(gè)題目要求編寫(xiě)程序1．編寫(xiě)一個(gè)函數(shù)，函數(shù)頭格式為“voidfun4(char*a,intb[])”，分別求出由字符指針a所指向的字符串中包含的每種十進(jìn)制數(shù)字出現(xiàn)的次數(shù)，把統(tǒng)計(jì)結(jié)果保存在數(shù)組b的相應(yīng)元素。2．編寫(xiě)一個(gè)函數(shù)，函數(shù)頭格式為“doubleMean(doublea[M][N],intm,intn)”，要求返回二維數(shù)組a[m][n]中所有元素的平均值，假定在計(jì)算過(guò)程是采用變量v存放平均值。3．編寫(xiě)一個(gè)遞歸函數(shù)“intFF(inta[],intn)”，求出數(shù)組a中所有元素n個(gè)元素之積并返回。4．編寫(xiě)一個(gè)主函數(shù)，利用while循環(huán)，求出并顯示滿足不等式1+1/2+1/3+……+1/n>5的最小n值。5．編寫(xiě)一個(gè)主函數(shù)，求滿足不等式22+42+……+n2<1000的最大n值，假定分別用i和s為取偶數(shù)值和累加值的變量，并限定使用do循環(huán)編程。6．編寫(xiě)一個(gè)主函數(shù)，計(jì)算并輸出n！的值，其中n值由鍵盤(pán)輸入。 參考答案：1、答案：#include<stdio.h>voidfun4(char*a,intb[]){ do{ if(*a>='0'&&*a<='9')b[*a-48]++; }while(*a++);}/*voidmain(){ char*a="122333444499888"; intb[10]={0}; fun4(a,b); for(inti=0;i<10;i++) printf("%d",b[i]);}*/2、答案：#include<stdio.h>constintM=2,N=3;doubleMean(doublea[M][N],intm,intn){ doublev=0; for(inti=0;i<m;i++) for(intj=0;j<n;j++) v+=a[i][j]; returnv/(m*n);}/*voidmain(){ doublea[2][3]={1,2,3,4,5,6}; printf("%lf\n",Mean(a,2,3)); }*/3、答案：#include<stdio.h>intFF(inta[],intn){ intmul=1; if(n==1)mul*=a[0]; elsemul=a[n-1]*FF(a,n-1); returnmul;}/*voidmain(){ inta[6]={1,2,3,4,5,6}; printf("%d\n",FF(a,6)); }*/4、答案：#include<stdio.h>voidmain(){ doublesum=0; intn=1; while(true) { if(sum+1/(double)n>5)break; else sum+=1/(double)n; n++; } printf("%d,%lf\n",n,sum);}5、答案：#include<stdio.h>voidmain(){ ints=0,i=2; do { s+=i*i; if(s+(i+2)*(i+2)>=1000)break; elsei+=2; }while(true); printf("i=%d,s=%d",i,s);}6、答案：#include<stdio.h>voidmain(){ ints=0,n; printf("請(qǐng)輸入n的值："); scanf("%d",&n); for(inti=1;i<=n;i++) s=s*i; printf("n=%d,s=%d",n,s);}第三次作業(yè)一、寫(xiě)出下列每個(gè)程序運(yùn)行后的輸出結(jié)果程序代碼：#include<stdio.h>voidSB(charch){ switch(ch){ case'A':case'a': printf("WW");break; case'B':case'b': printf("GG");break; case'C':case'c': printf("PP");break; default: printf("BB");break; }}voidmain(){ chara1='b',a2='C',a3='f'; SB(a1);SB(a2);SB(a3);SB('A'); printf("\n");}程序代碼：#include<stdio.h>#include<stdlib.h>doubleSD(inta,intb,charop){ doublex; switch(op){ case'+':x=a+b;break; case'-':x=a-b;break; case'*':x=a*b;break; case'/':if(b)x=(double)a/b;elseexit(1);break; default:{printf("運(yùn)算符錯(cuò)！\n");exit(1);} } returnx;}voidmain(){ intx=20,y=8; printf("%3.2lf",SD(x,y,'-')); printf("%3.2lf",SD(x,y,'*')); printf("%3.2lf\n",SD(x+y,y,'/'));}程序代碼：#include<stdio.h>voidWF(intx,inty){ x=x+y; y=x+y; printf("subs:x,y=%d,%d\n",x,y);}voidmain(){ intx=18,y=23; printf("main:x,y=%d,%d\n",x,y); WF(x,y); x=2*x; printf("main:x,y=%d,%d\n",x,y);}程序代碼：#include<stdio.h>#include<string.h>voidfun(charss[]);voidmain(){ chars[15]="567891234"; fun(s); printf("%s\n",s);}voidfun(charss[]){ inti,n=strlen(ss); for(i=0;i<n/2;i++){ charc=ss[i]; ss[i]=ss[n-1-i]; ss[n-1-i]=c; }}程序代碼：#include<stdio.h>voidInsertSort(inta[],intn){ inti,j,x; for(i=1;i<n;i++){//進(jìn)行n-1次循環(huán) x=a[i]; for(j=i-1;j>=0;j--)//為x順序向前尋找合適的插入位置 if(x>a[j])a[j+1]=a[j]; elsebreak; a[j+1]=x; }}voidmain(){ inti; inta[6]={20,15,32,47,36,28}; InsertSort(a,6); for(i=0;i<6;i++)printf("%d",a[i]); printf("\n");}程序代碼：#include<stdio.h>voidmain(){ inta[8]={3,5,7,9,11,13,15,17}; inti,*p=a; for(i=0;i<8;i++){ printf("%5d",*p++); if((i+1)%4==0)printf("\n"); }}程序代碼：#include<stdio.h>intLA(int*a,intn){ inti,s=0; for(i=0;i<n;i++) s+=a[i]; returns;}voidmain(){ inta[]={5,10,15,20,25,30}; intb=LA(a,4); intc=LA(a+2,3); printf("%d%d\n",b,c);}程序代碼：#include<stdio.h>intLB(int*a,intn){ inti,s=1; for(i=0;i<n;i++)s*=*a++; returns;}voidmain(){ inta[]={1,2,3,4,2,4,5,2}; intb=LB(a,4)+LB(&a[3],4); printf("b=%d\n",b);}二、寫(xiě)出下列每個(gè)函數(shù)的功能程序代碼：intWB(inta[],intn,intx){ inti; for(i=0;i<n;i++) if(a[i]==x)return1; return0;}程序代碼：intWC(inta[],intn,intk){ intc=0,i; for(i=0;i<n;i++) if(a[i]>=k)c++; returnc;}程序代碼：#include<stdio.h>#include<stdlib.h>#include<time.h>constintN=10;intff(intx,inty){ intz; printf("%d+%d=",x,y); scanf("%d",&z); if(x+y==z)return1;elsereturn0;}voidmain(){ inti,a,b,c=0; srand(time(0));//初始化隨機(jī)數(shù)序列 for(i=0;i<N;i++){ a=rand()%20+1;//rand()函數(shù)產(chǎn)生0~32767之間的一個(gè)隨機(jī)數(shù) b=rand()%20+1; c+=ff(a,b); } printf("得分：%d\n",c*10);}*程序代碼：intfun6(intm,intn,intb){ if(m<b&&n<b)returnm*n; elseif(m%b==0&&n%b==0)returnb*fun6(m/b,n/b,b); elsereturnfun6(m,n,++b);}程序代碼：#include<stdio.h>#include<stdlib.h>voidLI(intn){ int*a=malloc(n*sizeof(int)); inti; for(i=0;i<n;i++)scanf("%d",a+i); for(i=n-1;i>=0;i--)printf("%d",*(a+i)); printf("\n"); free(a);}程序代碼：intLK(doublea[],intn){ doubles=0; inti,m=0; for(i=0;i<n;i++)s+=a[i]; s/=n; for(i=0;i<n;i++) if(a[i]>=s)m++; returnm;}參考答案：一、1、答案：運(yùn)行結(jié)果：GGPPBBWW2、答案：運(yùn)行結(jié)果：12.00160.003.503、答案：運(yùn)行結(jié)果：main:x,y=18,23subs:x,y=41,64main:x,y=36,234、答案：運(yùn)行結(jié)果：4321987655、運(yùn)行結(jié)果：4736322820156、答案：運(yùn)行結(jié)果：3579111315177、答案：運(yùn)行結(jié)果：50608、答案：運(yùn)行結(jié)果：b=184二、1、答案：在整型數(shù)組a的前n個(gè)元素中查找值為x的元素，找到返回1，找不到返回0。2、答案：統(tǒng)計(jì)整型數(shù)組a的前n個(gè)元素中不小于k的元素個(gè)數(shù)并返回3、答案：程序隨機(jī)產(chǎn)生10道20以內(nèi)整數(shù)加法題，請(qǐng)用戶回答。并統(tǒng)計(jì)得分，4、答案：調(diào)用fun6(m,n,2)求m和n的最小公倍數(shù)5、答案：讀入n個(gè)整數(shù)，然后逆序輸出6、答案：返回雙精度數(shù)數(shù)組a的前n個(gè)元素中不小于平均值的元素個(gè)數(shù)。第四次作業(yè)一、寫(xiě)出下列每個(gè)程序運(yùn)行后的輸出結(jié)果程序代碼：#include<stdio.h>structWorker{ charname[15];//姓名 intage;//年齡 floatpay;//工資};voidmain(){ structWorkerx={"wanghua",52,2350}; structWorkery,*p; y=x;p=&x; printf("%s%d%6.2f\n",,y.age,y.pay); printf("%s%d%6.2f\n",p->name,p->age+1,p->pay+20);}程序代碼：#include<stdio.h>#include<string.h>structWorker{ charname[15];//姓名 intage;//年齡 floatpay;//工資};voidmain(){ structWorkerx; char*t="liouting"; intd=38;floatf=493; strcpy(,t); x.age=d;x.pay=f; x.age++;x.pay*=2; printf("%s%d%6.2f\n",,x.age,x.pay);}程序代碼：#include<stdio.h>structWorker{ charname[15];//姓名 intage;//年齡 floatpay;//工資};intLess(structWorkerr1,structWorkerr2){ if(r1.age<r2.age)return1; elsereturn0;}voidmain(){ structWorkera[4]={ {"abc",25,420},{"def",58,638}, {"ghi",49,560},{"jkl",36,375}}; structWorkerx=a[0]; inti; for(i=1;i<4;i++) if(Less(x,a[i]))x=a[i]; printf("%s%d%6.2f\n",,x.age,x.pay);}二、寫(xiě)出下列每個(gè)函數(shù)的功能程序代碼：structWorker{ charname[15];//姓名 intage;//年齡 floatpay;//工資};voidQA(structWorkera[],intn){ inti; for(i=1;i<n;i++) scanf("%s%d%f",&a[i].name,&a[i].age,&a[i].pay);}程序代碼：structStrNode{ charname[15];//字符串域 structStrNode*next;//指針域};structStrNode*QB(intn){ structStrNode*f,*p; if(n==0)returnNULL; f=malloc(sizeof(structStrNode)); scanf("%s",f->name); p=f; while(--n){ p=p->next=malloc(sizeof(structStrNode)); scanf("%s",p->name); } p->next=NULL; returnf;}程序代碼：structIntNode{ intdata;//結(jié)點(diǎn)值域 structIntNode*next;//結(jié)點(diǎn)指針域};structIntNode*FindMax(structIntNode*f){ structIntNode*p=f; if(!f)returnNULL; f=f->next; while(f){ if(f->data<p->data)p=f; f=f->next; } returnp;}*程序代碼：structIntNode{ intdata;//結(jié)點(diǎn)值域 structIntNode*next;//結(jié)點(diǎn)指針域};intCount(structIntNode*f){ intc=0; while(f){ c++; f=f->next; } returnc;}程序代碼：structIntNode{ intdata;//結(jié)點(diǎn)值域 structIntNode*next;//結(jié)點(diǎn)指針域};structIntNode*Input(intn){ structIntNode*f,*p; f=malloc(sizeof(structIntNode)); if(n==0)returnNULL; f->next=NULL; printf("從鍵盤(pán)輸入%d個(gè)整數(shù)：",n); while(n--){ scanf("%d",&(f->data)); p=f; f=malloc(sizeof(structIntNode)); f->next=p; } returnf->next;}程序代碼：#include<stdio.h>#include<stdlib.h>#include<string.h>voidJA(char*fname){ FILE*fout=fopen(fname,"w"); chara[20]; printf("輸入若干個(gè)字符串，每個(gè)字符串長(zhǎng)度小于20，字符串end作為結(jié)束標(biāo)志\n"); while(1){ scanf("%s",a); if(strcmp(a,"end")==0)break; fputs(a,fout); fputc('\n',fout); } fclose(fout);}voidmain(){ char*p="d:\\xxk\\xuxk1.txt"; JA(p);}參考答案：一、1、答案：運(yùn)行結(jié)果：wanghua522350.00wanghua532370.002、答案：運(yùn)行結(jié)果：liouting39986.003、答案：運(yùn)行結(jié)果：def58638.00二、1、答案：從標(biāo)準(zhǔn)輸入設(shè)備讀入n-1個(gè)人員的信息，依次存到結(jié)構(gòu)數(shù)組的a[1]到a[n-1]元素中2、答案：創(chuàng)建具有n個(gè)structStrNode結(jié)點(diǎn)的單向鏈表并返回其表頭結(jié)點(diǎn)地址，n為0時(shí)返回NULL。3、答案：函數(shù)功能：查找單向鏈表中結(jié)點(diǎn)值域最大的結(jié)點(diǎn)，并返回其地址。如鏈表為空則返回NULL4、答案：函數(shù)功能：統(tǒng)計(jì)并返回單向鏈表結(jié)點(diǎn)個(gè)數(shù)5、答案：函數(shù)功能：從表尾結(jié)點(diǎn)開(kāi)始，逆序創(chuàng)建具有n個(gè)structIntNode結(jié)點(diǎn)的單向鏈表并返回其表頭結(jié)點(diǎn)地址，n為0時(shí)返回NULL6、答案：函數(shù)功能：將輸入的若干個(gè)字符串保存到文本文件d:\xxk\xuxk1.txt中，每個(gè)字符串一行。輸入的單個(gè)字符串長(zhǎng)度必須小于20，輸入字符串end結(jié)束請(qǐng)您刪除一下內(nèi)容，O(∩_∩)O謝謝！??！【China's10must-seeanimations】TheChineseanimationindustryhasseenconsiderablegrowthinthelastseveralyears.Itwentthroughagoldenageinthelate1970sand1980swhensuccessivelybrilliantanimationworkwasproduced.Hereare10must-seeclassicsfromChina'sanimationoutpouringthatarenottobemissed.Let'srecallthesecolorfulimagesthatbroughtthecountrygreatjoy.CalabashBrothersCalabashBrothers(Chinese:葫蘆娃)isaChineseanimationTVseriesproducedby

Shanghai

Animation

Film

Studio.Inthe1980stheserieswasoneofthemostpopularanimationsinChina.ItwasreleasedatapointwhentheChineseanimationindustrywasinarelativelydownedstatecomparedtotherestoftheinternationalcommunity.Still,theserieswastranslatedinto7differentlanguages.Theepisodeswereproducedwithavastamountofpaper-cutanimations.BlackCatDetectiveBlackCatDetective(Chinese:黑貓警長(zhǎng))isaChineseanimationtelevisionseriesproducedbytheShanghaiAnimationFilmStudio.ItissometimesknownasMr.Black.Theserieswasoriginallyairedfrom1984to1987.InJune2006,arebroadcastingoftheoriginalserieswasannounced.Criticsbemoantheseries'violence,andlackofsuitabilityforchildren'seducation.Proponentsoftheshowclaimthatitismerelyforentertainment.Effendi"Effendi",meaningsirand

teacherinTurkish,istherespectfulnameforpeoplewhoownwisdomandknowledge.Thehero'srealnamewasNasreddin.Hewaswiseandwittyand,moreimportantly,hehadthecouragetoresisttheexploitationofnoblemen.Hewasalsofullofcompassionandtriedhisbesttohelppoorpeople.AdventureofShukeandBeita【舒克與貝塔】AdventureofShukeandBeita(Chinese:舒克和貝塔)isaclassicanimationbyZhengYuanjie,whoisknownasKingofFairyTalesinChina.ShukeandBeitaaretwomicewhodon'twanttostealfoodlikeothermice.ShukebecameapilotandBeitabecameatankdriver,andthepairmetaccidentallyandbecamegoodfriends.ThentheybefriendedaboynamedPipilu.WiththehelpofPiPilu,theyco-foundedanairlinenamedShukeBeitaAirlinestohelpotheranimals.Althoughthereareonly13episodesinthisseries,thecontentisverycompactandattractive.Theanimationshowsthepreciousnessoffriendshipandhowpeopleshouldbebravewhenfacingdifficulties.Evenadultsrecallingthisanimationtodaycanstillfeeltouchedbysomescenes.SecretsoftheHeavenlyBookSecretsoftheHeavenlyBook,(Chinese:天書(shū)奇談)

alsoreferredtoas"LegendoftheSealedBook"or"TalesabouttheHeavenlyBook",wasreleasedin1983.Thefilmwasproducedwithrigorousdubbingandfluidcombinationofmusicandvividanimations.Thestoryisbasedontheclassicliterature"PingYaoZhuan",meaning"TheSuppressionoftheDemons"byFengMenglong.Yuangong,thedeacon,openedtheshrineandexposedtheholybooktothehumanworld.Hecarvedthebook'scontentsonthestonewallofawhitecloudcaveinthemountains.Hewasthenpunishedwithguardingthebookforlifebythejadeemperorforbreakingheaven'slaw.Inordertopassthisholybooktohumanbeings,hewouldhavetogetbytheantagonistfox.ThewholeanimationischaracterizedbycharmingChinese

painting,includingpavilions,ancientarchitecture,ripplingstreamsandcrowdedmarkets,whichfullydemonstratetheuniquebeautyofChina'snaturalscenery.PleasantGoatandBigBigWolf【喜洋洋與灰太狼】PleasantGoatandBigBigWolf(Chinese:喜羊羊與灰太狼)isaChineseanimatedtelevisionseries.TheshowisaboutagroupofgoatslivingontheGreenPasture,andthestoryrevolvesaroundaclumsywolfwhowantstoeatthem.Itisapopulardomesticanimationseriesandhasbeenadaptedinto

movies.NezhaConquerstheDragonKing（Chinese:哪吒鬧海）

isanoutstandinganimationissuedbytheMinistryofCulturein1979andisbasedonanepisodefromtheChinesemythologicalnovel"FengshenYanyi".Amothergavebirthtoaballoffleshshapedlikealotusbud.Thefather,LiJing,choppedopentheball,andbeautifulboy,Nezha,sprungout.Oneday,whenNezhawassevenyearsold,hewenttothenearbyseashoreforaswimandkilledthethirdsonoftheDragonKingwhowaspersecutinglocalresidents.ThestoryprimarilyrevolvesaroundtheDragonKing'sfeudwithNezhaoverhisson'sdeath.Throughbraveryandwit,Nezhafinallybrokeintotheunderwaterpalaceandsuccessfullydefeatedhim.ThefilmshowsvariouskindsofattractivesceneriesandthetraditionalcultureofChina,suchasspectacularmountains,elegantseawavesandexquisiteancientChineseclothes.Ithasreceivedavarietyofawards.HavocinHeavenThestoryofHavocinHeaven（Chinese:大鬧天宮）isbasedontheearliestchaptersoftheclassicstory

JourneytotheWest.ThemaincharacterisSunWukong,akatheMonkeyKing,whorebelsagainsttheJadeEmperorofheaven.Thestylizedanimationanddrumsandpercussionaccompanimentusedinthisfilmareheavilyinfluencedby

Beijing

Operatraditions.ThenameofthemoviebecameacolloquialismintheChineselanguagetodescribesomeonemakingamess.Regardlessthatitwasananimatedfilm,itstillbecameoneofthemostinfluentialfilmsinallofAsia.CountlesscartoonadaptationsthatfollowedhavereusedthesameclassicstoryJourney