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DigitalLogicCircuits數(shù)字邏輯電路智慧樹知到課后章節(jié)答案2023年下南京理工大學(xué)南京理工大學(xué)
第一章測試
Thenumberofvaluesthatcanbeassignedtoabitare(
)
A:one
B:three
C:two
D:ten
答案:two
Comparedtoanalogsystems,digitalsystems(
)
A:arelesspronetonoise
B:
canrepresentaninfinitenumberofvalues
C:
alloftheabove
D:canhandlemuchhigherpower
答案:arelesspronetonoise
Thetermbitmeans(
)
A:
bothanswers(b)and(c)
B:asmallamountofdata
C:a1ora0
D:binarydigit
答案:
bothanswers(b)and(c)
Aquantityhascontinuousvalueis(
)
A:ananalogquantity
B:abinaryquantity
C:adigitalquantity
D:anaturalquantity
答案:ananalogquantity
VerilogHDLisa(
)
A:programminglogicdevice
B:computerlanguage
C:
hardware
D:logicdevice
答案:computerlanguage
Acategoryofdigitalintegratedcircuitshavingfunctionsthatcanbealteredisknownasfixed-functionlogic.
A:對B:錯
答案:錯
Dataareinformationonlyinnumeric.
A:錯B:對
答案:錯
Twobroadtypesofdigitalintegratedcircuitsarefixed-functionandprogrammble.
A:對B:錯
答案:對
Thenonrecurringengineering(NRE)costforanASICdesignisnormallylow.
A:對B:錯
答案:錯
Thereisan“invalid”regionbetweentheinputrangesforlogic0andlogic1
A:對B:錯
答案:對
第二章測試
Forthebinarynumber10000,theweightofthecolumnwiththe1is(
)
A:8B:10C:
4
D:16
答案:16
The2’scomplementof1000is(
)
A:1001B:0111C:1000D:1010
答案:1000
Thefractionalbinarynumber0.11hasadecimalvalueof(
)
A:
?
B:
?
C:noneoftheabove
D:?
答案:?
Thenumber1100inBCDis(
)
A:equaltodecimaltwelve
B:invalid
C:
equaltodecimaleight
D:equaltodecimalten
答案:invalid
Anexampleofanunweightedcodeis(
)
A:BCD
B:decimal
C:Graycode
D:binary
答案:Graycode
Anexampleofanalphanumericcodeis(
)
A:ASCII
B:BCD
C:CRC
D:hexadecimal
答案:ASCII
Theoverflowoccurswhenaddingthefollowing8-bittwo’scomplementnumber:01011101+00110001
A:錯B:對
答案:對
TheoverflowdoesNOToccurwhenaddingthefollowing8-bittwo’scomplementnumber:10111111+11011111
A:錯B:對
答案:對
Ingeneral,weneedatmostbitstoexpresstheproductwhenmultiplyingann-bitnumberbyanm-bitnumber.
A:錯B:對
答案:錯
Anadditionoverflowsiftheaddends’signsarethesamebutthesum’ssignisdifferentfromtheaddends’.
A:錯B:對
答案:對
第三章測試
TheBooleanexpressionA
.
1isequalto(
).
A:1B:BC:0D:A
答案:A
TheBooleanexpressionA
+1isequalto(
).
A:BB:AC:0D:1
答案:1
TheBooleanequationAB+AC=A(B+C)illustrates(
)
A:
thecommutativelaw
B:
theassociativelaw
C:DeMorgan’stheorem
D:thedistributionlaw
答案:thedistributionlaw
Theassociativelawforadditionisnormallywrittenas(
)
A:A+B=B+A
B:AB=BA
C:
(A+B)+C
=A
+(B+C)
D:A+AB=A
答案:
(A+B)+C
=A
+(B+C)
ABooleanexpressionthatisinstandardSOPformis(
)
A:containsonlyoneproductterm
B:noneoftheabove
C:haseveryvariableinthedomainineveryterm
D:theminimumlogicexpression
答案:haseveryvariableinthedomainineveryterm
AdjacentcellsonaKarnaughmapdifferfromeachotherby
A:answerdependsonthesizeofthemap
B:twovariables
C:threevariables
D:
onevariable
答案:
onevariable
SOPstandardformisusefulforconstructingtruthtablesorforimplementinglogicinPLDs.
A:對B:錯
答案:對
LogicsimplificationisstillusefulinnowadaysFPGAdesigns.
A:錯B:對
答案:錯
Insynthesis,anetlistwillbegeneratedtodescribethecircuitcompletely.
A:對B:錯
答案:對
InFPGAdesign,thestepthat“maps”thedesignfromthenetlisttofitittoatargetdeviceisknownas"programming".
A:對B:錯
答案:錯
第四章測試
The74138decodercanalsobeusedas(
).
A:
aMUX
B:
anencoder
C:aDEMUX
D:noneoftheabove
答案:aDEMUX
Assumeyouwanttodecodethebinarynumber0011withanactive-LOWdecoder.Themissinggateshouldbe(
).
A:aNANDgate
B:anORgate
C:
anANDgate
D:aNORgate
答案:aNANDgate
Toexpanda2-bitparalleladdertoa4-bitparalleladder,youmust(
).
A:usetwo2-bitaddersandconnectthesumoutputsofonetothebitinputsoftheother
B:usetwo2-bitadderswiththecarryoutputofoneconnectedtothecarryinputoftheother
C:usefour2-bitadderswithnointerconnections
D:usetwo2-bitadderswithnointerconnections
答案:usetwo2-bitadderswiththecarryoutputofoneconnectedtothecarryinputoftheother
Ifanhex-to-binarypriorityencoderhasits0,3,6,and14inputsattheactivelevel,theactive-HIGHbinaryoutputis(
).
A:0000
B:0011
C:0110
D:1110
答案:1110
ThecontinuousassignmentassignOUT=
select?A:B;specifiestheconditionthatOUT=
()
ifselect=
1,elseOUT=
()
ifselect=
0.
A:
A,B
B:1,0
C:B,A
D:
0,1
答案:
A,B
Considertheinitial
blockinthefollowing:initialbeginA=0;B=0;#10A=1;#20A=0;B=1;EndThenatt=30,Ais
changedto(
)andBto(
).
A:
1,1
B:0,1
C:1,0
D:0,0
答案:0,1
Theinitialstatementexecutesonlyonce,startingfrom
simulationtime0,andmaycontinuewithanyoperationsthataredelayedbyagiven
numberoftimeunits.
A:錯B:對
答案:對
InVerilogHDL,thedefinitionsofmodulesareallowedtobenested.
A:對B:錯
答案:錯
ThevaluezrepresentsanunknownlogicvalueinVerilogHDL.
A:對B:錯
答案:錯
InVerilogHDL,~(1010)is(0101),and!(1010)is0.
A:錯B:對
答案:對
第五章測試
TheoutputofaDlatchwillnotchangeif(
).
A:DisLOW
B:
theoutputisLOW
C:Enableisnotactive
D:alloftheabove
答案:Enableisnotactive
TheDflip-flopshownwill(
).
A:resetonthenextclockpulse
B:toggleonthenextclockpulse
C:setonthenextclockpulse
D:latchonthenextclockpulse
答案:toggleonthenextclockpulse
FortheJ-Kflip-flopshown,thenumberofinputsthatareasynchronousis(
).
A:3B:2C:1D:4
答案:2
AssumetheoutputisinitiallyHIGHonaleadingedgetriggeredJ-Kflipflop.Fortheinputsshown,theoutputwillgofromHIGHtoLOWonwhichclockpulse?
A:3B:2C:4D:1
答案:3
Thetimeintervalillustratediscalled(
).
A:holdtime
B:set-uptime
C:tPHL
D:tPLH
答案:tPLH
TheadvantageofdynamicRAMoverstaticRAMisthat(
).
A:alloftheaboveB:itissimplerandcheaperC:itismuchfasterD:itdoesnotrequirerefreshing
答案:itissimplerandcheaper
Anasynchronous
resetsignalwilloverridetheclockonaFF.
A:對B:錯
答案:對
InVerilogHDL,aninitialbehavioralstatementexecutesonlyonce.
A:錯B:對
答案:對
InaMoore
model,theoutputsofthesequentialcircuitarenotsynchronizedwiththe
clock.
A:對B:錯
答案:錯
TheoutputoftheMealy
machineisthevaluethatispresentimmediatelybeforethe
activeedgeoftheclock.
A:錯B:對
答案:對
第六章測試
TocauseaDflip-floptotoggle,connectthe(
).
A:clocktotheD
input
B:clocktothepresetinput
C:
Q
outputtotheD
input
D:
答案:
A4-bitbinarycounterhasaterminalcountof(
).
A:16B:15C:10D:4
答案:15
Assumetheclockfora4-bitbinarycounteris80kHz.Theoutputfrequencyofthefourthstage(Q3)is(
).
A:320kHz
B:10kHz
C:20kHz
D:5kHz
答案:5kHz
A4-bitparallel-in/parallel-outshiftregisterwillstoredatafor(
).
A:2clockperiods
B:3clockperiods
C:1clockperiod
D:4clockperiods
答案:1clockperiod
AnadvantageofaringcounteroveraJohnsoncounteristhattheringcounter(
).
A:isclearedaftereachcycle
B:allowsonlyonebittochangeatatime
C:isself-decoding
D:hasmorepossiblestatesforagivennumberofflip-flops
答案:isself-decoding
Apossiblesequencefora4-bitringcounteris(
).
A:…1111,1110,1101…
B:…0000,0001,0010…
C:
…1000,0100,0010…
D:
…0001,0011,0111…
答案:
…1000,0100,0010…
Adivide‐by‐N-counterisacounterthatgoesthrougharepeated
sequenceofNstates,anditisalsoknownasamodulo‐Ncounter.
A:錯B:對
答案:對
Forcounterswithunusedstates,itisnecessarytoensurethatthecircuiteventuallygoesintooneofthevalidstatessothatitcanresumenormaloperation.
A:錯B:對
答案:對
Fortransmission,datafromaUARTissentin
synchronousparallelform.
A:錯B:對
答案:錯
Themaximummodulusofacounteris,
wherenisthenumberofstages(flip-flops)inthecounter.
A:對B:錯
答案:錯
第七章測試
StaticRAMis(
).
A:volatilereadonlymemory
B:
nonvolatileread/writememory
C:volatileread/writememory
D:nonvolatilereadonlymemory
答案:volatileread/writememory
Anonvolatilememoryisonethat(
)
A:mustberefreshedregularly
B:
retainsdatawithoutpowerapplied
C:
requiresaclock
D:alloftheabove
答案:
retainsdatawithoutpowerapplied
TheadvantageofdynamicRAMoverstaticRAMisthat(
).
A:itissimplerandcheaper
B:itdoesnotrequirerefreshing
C:alloftheabove
D:itismuchfaster
答案:itissimplerandcheaper
A4-bitparallel-in/parallel-outshiftregisterwillstoredatafor(
).
A:3clockperiodB:2clockperiodC:4clockperiodD:1clockperiod
答案:1clockperiod
WhendataisreadfromRAM,thememorylocationis(
).
A:unchanged
B:settoall1’safterthereadoperation
C:destroyed
D:clearedafterthereadoperation
答案:unchanged
Thefirststepinareadorwriteoperationforarandomaccessmemoryisto(
).
A:placeavalidaddressontheaddressbus
B:enablethememory
C:
sendorobtainthedata
D:startarefreshcycle
答案:placeavalidaddressontheaddressbus
AddressmultiplexingcanreducethenumberofpinsintheICpackage.
A:錯B:對
答案:對
OneofthemajorapplicationsofSRAMsisincachememoriesincomputers.
A:對B:錯
答案:對
RAMisusedinacomputerto
storetheBIOS(BasicInput/Output
System.
A:錯B:對
答案:錯
Memoryexpansion
isaccomplishedbyaddinganappropriatenumberofmemorychipstotheaddress,data,
andcontrolbuses.
A:對B:錯
答案:對
第八章測試
Thenumberofcomparatorsrequiredina10-bitflashADCis(
).
A:511
B:1023
C:255
D:4095
答案:1023
Ifananti-aliasingfilterisnotusedindigitizingasignaltherecoveryprocess(
)
A:alloftheabove
B:isslowed
C:willhav
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