廣東省廣州市xx中學(xué)2022-2023學(xué)年高一上學(xué)期期末數(shù)學(xué)試題（原卷版）

高一上學(xué)期期末數(shù)學(xué)試題第I卷一?單選題：本大題共8小題，每小題3分，滿分24分.在每小題給出的四個(gè)選項(xiàng)中，只有一項(xiàng)符合題目要求.1.已知集合SKIPIF1<0，集合SKIPIF1<0，則SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.“SKIPIF1<0”是“SKIPIF1<0”的()A.充分不必要條件 B.必要不充分條件C.充分必要條件 D.既不充分也不必要條件3.命題“SKIPIF1<0，SKIPIF1<0，”的否定是()ASKIPIF1<0，SKIPIF1<0 B.SKIPIF1<0，SKIPIF1<0C.SKIPIF1<0，SKIPIF1<0 D.SKIPIF1<0，SKIPIF1<04.不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知二次函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)是單調(diào)函數(shù)，則實(shí)數(shù)a的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.磚雕是我國古建筑雕刻中的重要藝術(shù)形式，傳統(tǒng)磚雕精致細(xì)膩、氣韻生動(dòng)、極富書卷氣．如圖所示，一扇環(huán)形磚雕，可視為將扇形SKIPIF1<0截去同心扇形SKIPIF1<0所得圖形，已知SKIPIF1<0，則該扇環(huán)形磚雕的面積為()SKIPIF1<0．A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.已知角SKIPIF1<0的終邊過點(diǎn)SKIPIF1<0，則SKIPIF1<0的值為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.已知函數(shù)SKIPIF1<0是SKIPIF1<0上奇函數(shù)，且SKIPIF1<0時(shí)，SKIPIF1<0，則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二?多選題：本大題共4小題，每小題3分，滿分12分.在每小題給出的四個(gè)選項(xiàng)中，有多項(xiàng)符合要求，全部選對(duì)得3分，選對(duì)但不全的得1分，有選錯(cuò)的得0分.9.下列命題中正確的是()A.SKIPIF1<0時(shí)，SKIPIF1<0的最小值是2B.存在實(shí)數(shù)SKIPIF1<0，使得不等式SKIPIF1<0成立C.若SKIPIF1<0，則SKIPIF1<0D.若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<010.下列結(jié)論正確的是()A.函數(shù)SKIPIF1<0且SKIPIF1<0的圖像必過定點(diǎn)SKIPIF1<0B若SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0C.已知函數(shù)SKIPIF1<0，則方程SKIPIF1<0的實(shí)數(shù)解為SKIPIF1<0D.對(duì)任意SKIPIF1<0，都有SKIPIF1<011.下列等式成立的是()A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<012.已知函數(shù)SKIPIF1<0，則方程SKIPIF1<0實(shí)根個(gè)數(shù)可能為()A.8 B.7 C.6 D.5第II卷三?填空題：本大題共4小題，每小題3分，滿分12分.13.函數(shù)SKIPIF1<0的定義域?yàn)開___________.(用區(qū)間表示)14.已知SKIPIF1<0，則SKIPIF1<0__________.15.如果光線每通過一塊玻璃其強(qiáng)度要減少10%，那么至少需要將____________塊這樣的玻璃重疊起來，才能使通過它們的光線強(qiáng)度低于原來的0.5倍．(參考數(shù)據(jù)：SKIPIF1<0．)16.若SKIPIF1<0，不等式SKIPIF1<0恒成立，則實(shí)數(shù)SKIPIF1<0的取值范圍是__________.四?解答題：本大題共6小題，滿分52分.解答應(yīng)寫出文字說明?證明過程或演算過程.17.(1)求值：SKIPIF1<0；(2)設(shè)SKIPIF1<0，且SKIPIF1<0，求SKIPIF1<0的值.18.已知函數(shù)SKIPIF1<0.(1)求SKIPIF1<0的單調(diào)遞增區(qū)間；(2)若SKIPIF1<0在區(qū)間SKIPIF1<0上的值域?yàn)镾KIPIF1<0，求SKIPIF1<0的取值范圍.19.在密閉培養(yǎng)環(huán)境中，某類細(xì)菌的繁殖在初期會(huì)較快，隨著單位體積內(nèi)細(xì)菌數(shù)量的增加，繁殖速度又會(huì)減慢.在一次實(shí)驗(yàn)中，檢測到這類細(xì)菌在培養(yǎng)皿中的數(shù)量SKIPIF1<0(單位：百萬個(gè))與培養(yǎng)時(shí)間SKIPIF1<0(單位：小時(shí))的關(guān)系為：SKIPIF1<0234568SKIPIF1<0SKIPIF1<0SKIPIF1<04SKIPIF1<0SKIPIF1<0SKIPIF1<0根據(jù)表格中的數(shù)據(jù)畫出散點(diǎn)圖如下：為了描述從第2小時(shí)開始細(xì)菌數(shù)量隨時(shí)間變化的關(guān)系，現(xiàn)有以下三種模型供選擇：①SKIPIF1<0，②SKIPIF1<0，③SKIPIF1<0.(1)選出你認(rèn)為最符合實(shí)際的函數(shù)模型，并說明理由；(2)利用SKIPIF1<0和SKIPIF1<0這兩組數(shù)據(jù)求出你選擇的函數(shù)模型的解析式，并預(yù)測從第2小時(shí)開始，至少再經(jīng)過多少個(gè)小時(shí)，細(xì)菌數(shù)量達(dá)到6百萬個(gè).20.已知兩個(gè)變量SKIPIF1<0且SKIPIF1<0滿足關(guān)系式SKIPIF1<0，且SKIPIF1<0是SKIPIF1<0的函數(shù).(1)寫出該函數(shù)的表達(dá)式SKIPIF1<0，值域和單調(diào)區(qū)間(不必證明)；(2)在坐標(biāo)系中畫出該函數(shù)的圖象(直接作圖，不必寫過程及理由).21.已知函數(shù)SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的最小正周期；(2)令SKIPIF1<0，求SKIPIF1<0的最小值.22.給定常數(shù)SKIPIF1<0，定義在SKIPIF1<0上的函數(shù)SKIPIF1