數(shù)學(xué)必修一課后習(xí)題答案

未知驅(qū)動探索，專注成就專業(yè)數(shù)學(xué)必修一課后習(xí)題答案第一章有理數(shù)1.1有理數(shù)的概念和運算習(xí)題1.1計算下列各題：$(-\\frac{5}{6})+\\frac{2}{3}=-\\frac{5}{6}+\\frac{4}{6}=-\\frac{1}{6}$$(-\\frac{1}{2})+(\\frac{2}{5})=-\\frac{5}{10}+\\frac{4}{10}=-\\frac{1}{10}$$-\\frac{7}{8}+(-\\frac{1}{16})=-\\frac{7}{8}-\\frac{1}{16}=-\\frac{14}{16}-\\frac{1}{16}=-\\frac{15}{16}$$-\\frac{5}{9}+(-\\frac{1}{3})=-\\frac{5}{9}-\\frac{3}{9}=-\\frac{8}{9}$將下列有理數(shù)按從小到大的順序排列：$-\\frac{2}{5},\\-\\frac{3}{4},\\-\\frac{7}{6},\\\\frac{1}{3},\\frac{5}{12}$從小到大的順序為：$-\\frac{7}{6},\\-\\frac{3}{4},\\-\\frac{2}{5},\\\\frac{5}{12},\\\\frac{1}{3}$習(xí)題1.2將下列有理數(shù)化為最簡形式：$\\frac{45}{75}=\\frac{3}{5}$$\\frac{42}{14}=3$$\\frac{35}{14}=\\frac{5}{2}$$\\frac{24}{12}=2$計算下列各題：$(-\\frac{4}{5})\\times\\frac{3}{2}=-\\frac{4}{5}\\times\\frac{3}{2}=-\\frac{12}{10}=-\\frac{6}{5}$$(-\\frac{2}{3})\\times(-\\frac{3}{4})=\\frac{2}{3}\\times\\frac{3}{4}=\\frac{2}{4}=\\frac{1}{2}$$(-\\frac{9}{5})\\div(-\\frac{3}{4})=\\frac{9}{5}\\div\\frac{3}{4}=\\frac{12}{5}$$(-\\frac{2}{3})+(\\frac{7}{6})\\times(-\\frac{3}{2})=-\\frac{2}{3}+\\frac{7}{6}\\times-\\frac{3}{2}=-\\frac{2}{3}+(-\\frac{7}{4})=-\\frac{2}{3}-\\frac{7}{4}=-\\frac{35}{12}$第二章整式及其運算2.1整式的概念和運算習(xí)題2.1計算下列各題：((((將下列各式化為最簡形式：4769習(xí)題2.2計算下列各題：$(3x+4y)(2x-3y)=3x\\times2x+3x\\times-3y+4y\\times2x+4y\\times-3y=6x^2-9xy+8xy-12y^2=6x^2-xy-12y^2$$(2a-b)(3a+2b)=2a\\times3a+2a\\times2b-b\\times3a-b\\times2b=6a^2+4ab-3ab-2b^2=6a^2+ab-2b^2$$(4x-3y)^2=(4x-3y)(4x-3y)=4x\\times4x+4x\\times-3y-3y\\times4x-3y\\times-3y=16x^2-12xy-12xy+9y^2=16x^2-24xy+9y^2$$(2a+3b)^2=(2a+3b)(2a+3b)=2a\\times2a+2a\\