圓、環(huán)截面受彎構(gòu)件計(jì)算

圓形截面受彎構(gòu)件單筋、非均勻配筋--彎矩求配筋,,,,,,,,

輸入M=N·mm,459960000,,,,,,,

輸入半徑R=mm,400,,,,,,,

輸入混凝土fc=MPa,11.9,,,,,,,

縱筋強(qiáng)度fy=MPa,360,,,,,,,

計(jì)算k4=,-0.862770108,,,,,,,

計(jì)算q=,-0.53288742,,,,,,,

計(jì)算初始值α=,0.810734192,試算值α=,0.8967,（取α在初始值附近值使ε絕對(duì)值逼近0.001）,,,,

計(jì)算初始值ε=,-0.188773068,ε=α+（1/1.4)*sinα-0.5*sin2α-(1/4.2)*sin3α+k4,,,,,,

迭代求終值ε=,0.000434754,,受壓區(qū)扇形角度=°,,161.406,,,

計(jì)算受拉側(cè)As=mm2,2163.351394,,,,,,,

圓形截面受彎構(gòu)件單筋、非均勻配筋--配筋求承載彎矩,,,,,,,,

輸入M初=N·mm,268350000,,M0=,274177845.6,（取輸入M初在M0值附近值使ε絕對(duì)值逼近0.001,,,

輸入半徑R=mm,300,,,,,,,

輸入混凝土fc=MPa,9.6,,,,,,,

縱筋強(qiáng)度fy=MPa,310,,,,,,,

實(shí)配受拉側(cè)As=mm2,2000,,,,,,,

計(jì)算值α=,0.970295917,,受壓區(qū)扇形角度=°,,174.6532651,,,

計(jì)算H=,222.8244499,,,,,,,

計(jì)算ε=,0.001869264,（當(dāng)ε絕對(duì)值逼近0.001時(shí)，Mu=M初）,,,,,,

繼續(xù)試算,268350000,,,,,,,

圓形截面受彎構(gòu)件抗剪計(jì)算,,,,,,,,

輸入V設(shè)=N,710520,0.7ftbh0=,704704,,,,,

輸入半徑R=mm,500,,,,,,,

輸入混凝土ft=MPa,1.43,,,,,,,

箍筋強(qiáng)度fyv=MPa,270,,,,,,,

計(jì)算Asv/S=,0.026925926,構(gòu)造Min（Asv/S)=,1.118577778,,,,,

設(shè)S=mm,200,計(jì)算Asv=,223.7155556,,,,,

箍筋單肢As1=mm2,111.8577778,,,,,,,

環(huán)形截面受彎構(gòu)件均勻配筋--已知配筋求承載彎矩,,,,,環(huán)形截面受彎構(gòu)件均勻配筋--已知彎矩求配筋,,,

輸入外半徑r1=mm,500,輸入縱筋rs=r1-asmm,470,,輸入外半徑r1=mm,500,輸入縱筋rs=r1-asmm,450

輸入內(nèi)半徑r2=mm,400,環(huán)形截面積A=,282744,,輸入內(nèi)半徑r2=mm,300,環(huán)形截面積A=,502656

輸入混凝土fc=MPa,16.7,,,,輸入混凝土fc=MPa,16.7,,

縱筋強(qiáng)度fy=MPa,360,,,,縱筋強(qiáng)度fy=MPa,360,,

實(shí)配縱筋A(yù)s=mm2,3600,,,,設(shè)計(jì)彎矩M=Nmm,600000000,,

計(jì)算值α=,0.162776754,當(dāng)α＞0.6667時(shí)αt=0,,,輸入值α=,0.122962,應(yīng)α＜0.4，使ε絕對(duì)值接近10000，取值在0.13附近,

計(jì)算αt=,0.755834868,,,,計(jì)算ε=,263.4982927,受壓區(qū)扇形角度=°,44.26632

計(jì)算Mu=,560441461,受壓區(qū)扇形角度=°,58.59963158,,計(jì)算As=mm2,4139.771857,,

圓形截面受彎構(gòu)件均勻配筋--已知配筋求承載彎矩,,,,,,,,

輸入半徑r=mm,600,輸入縱筋rs=r-asmm,529,,,,,

輸入混凝土fc=MPa,16.7,,,,,,,

縱筋強(qiáng)度fy=MPa,310,,,,,,,

實(shí)配縱筋A(yù)s=mm2,11309.7,,,,,,,

輸入α=,0.25126105,應(yīng)α＜0.625，使ε絕對(duì)值小于100，取值在0.21附近,,,,,,

計(jì)算ε=,-7.458550587,,,,,,,

計(jì)算αt=,0.7474779,受壓區(qū)扇形角度=°,90.453978,,,,,

計(jì)算Mu=,1700198973,,,,,,,

圓形截面受彎構(gòu)件均勻配筋--已知彎矩求配筋,,,,,,,,

輸入半徑r=mm,500,輸入縱筋rs=r-asmm,430,,,,,

輸入混凝土fc=MPa,14.3,圓形截面積A=,785400,,,,,

縱筋強(qiáng)度fy=MPa,360,計(jì)算αt=,0.682444,,,,,

設(shè)計(jì)彎矩M=Nmm,1361140000,,,,,,,

輸入α=,0.283778,應(yīng)α＜0.6