新高考數(shù)學(xué)一輪復(fù)習(xí)講練測第3章第03講 極值與最值（練習(xí)）（原卷版）

第03講極值與最值（模擬精練+真題演練）1．（2023·廣西南寧·武鳴縣武鳴中學(xué)?？既＃┖瘮?shù)SKIPIF1<0的極小值點為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2023·遼寧葫蘆島·統(tǒng)考二模）已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0有一個極值點B．SKIPIF1<0有兩個零點C．點（0，1）是曲線SKIPIF1<0的對稱中心D．直線SKIPIF1<0是曲線SKIPIF1<0的切線3．（2023·貴州貴陽·校聯(lián)考模擬預(yù)測）若SKIPIF1<0在SKIPIF1<0和SKIPIF1<0處有極值，則函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2023·寧夏銀川·六盤山高級中學(xué)?？家荒＃┮阎瘮?shù)SKIPIF1<0的極值點為SKIPIF1<0，函數(shù)SKIPIF1<0的最大值為SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2023·河北·校聯(lián)考模擬預(yù)測）已知SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2023·廣西南寧·南寧三中校考模擬預(yù)測）當(dāng)SKIPIF1<0時，函數(shù)SKIPIF1<0取得最小值SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2023·內(nèi)蒙古阿拉善盟·統(tǒng)考一模）已知e是自然對數(shù)函數(shù)的底數(shù)，不等于1的兩個正數(shù)m，t滿足SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的最小值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2023·山東煙臺·統(tǒng)考二模）若函數(shù)SKIPIF1<0有兩個極值點SKIPIF1<0，且SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．（多選題）（2023·海南省直轄縣級單位·校聯(lián)考二模）函數(shù)SKIPIF1<0的定義域為R，它的導(dǎo)函數(shù)SKIPIF1<0的部分圖象如圖所示，則下面結(jié)論正確的是（

）A．在SKIPIF1<0上函數(shù)SKIPIF1<0為增函數(shù) B．在SKIPIF1<0上函數(shù)SKIPIF1<0為增函數(shù)C．在SKIPIF1<0上函數(shù)SKIPIF1<0有極大值 D．SKIPIF1<0是函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的極小值點10．（多選題）（2023·廣東汕頭·統(tǒng)考三模）設(shè)函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0是函數(shù)SKIPIF1<0的極值點C．SKIPIF1<0存在兩個零點 D．SKIPIF1<0在(1，+∞)上單調(diào)遞增11．（多選題）（2023·山西運城·統(tǒng)考三模）已知函數(shù)SKIPIF1<0，則下列說法正確的是（

）A．曲線SKIPIF1<0在SKIPIF1<0處的切線與直線SKIPIF1<0垂直B．SKIPIF1<0在SKIPIF1<0上單調(diào)遞增C．SKIPIF1<0的極小值為SKIPIF1<0D．SKIPIF1<0在SKIPIF1<0上的最小值為SKIPIF1<012．（多選題）（2023·遼寧·校聯(lián)考三模）已知函數(shù)SKIPIF1<0，若SKIPIF1<0有兩個不同的極值點SKIPIF1<0，且當(dāng)SKIPIF1<0時恒有SKIPIF1<0，則SKIPIF1<0的可能取值有（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<013．（2023·甘肅蘭州·蘭化一中?？寄M預(yù)測）函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)有極小值，則SKIPIF1<0的一個可能取值為______．14．（2023·云南紅河·統(tǒng)考二模）若SKIPIF1<0是函數(shù)SKIPIF1<0的極小值點，則函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為______．15．（2023·河南·校聯(lián)考模擬預(yù)測）已知函數(shù)SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0與SKIPIF1<0中恰有一個函數(shù)無極值，則SKIPIF1<0的取值范圍是______．16．（2023·湖南·校聯(lián)考模擬預(yù)測）已知函數(shù)SKIPIF1<0，對于任意SKIPIF1<0，都有SKIPIF1<0，則實數(shù)SKIPIF1<0的取值范圍為______.17．（2023·陜西寶雞·統(tǒng)考二模）已知函數(shù)SKIPIF1<0，且f（x）在SKIPIF1<0內(nèi)有兩個極值點SKIPIF1<0（SKIPIF1<0）．(1)求實數(shù)a的取值范圍；(2)求證：SKIPIF1<0．18．（2023·寧夏石嘴山·平羅中學(xué)校考模擬預(yù)測）已知函數(shù)SKIPIF1<0.(1)求SKIPIF1<0的極值；(2)若SKIPIF1<0恒成立，求SKIPIF1<0的取值范圍.19．（2023·全國·模擬預(yù)測）已知函數(shù)SKIPIF1<0.(1)若曲線SKIPIF1<0在SKIPIF1<0處的切線與直線SKIPIF1<0相互垂直，探究函數(shù)SKIPIF1<0的單調(diào)性；(2)若函數(shù)SKIPIF1<0有唯一的極值0，求SKIPIF1<0的值.20．（2023·四川成都·三模）已知函數(shù)SKIPIF1<0，其中SKIPIF1<0．(1)當(dāng)SKIPIF1<0時，求曲線SKIPIF1<0在點SKIPIF1<0處的切線方程；(2)若SKIPIF1<0是函數(shù)SKIPIF1<0的極小值點，求SKIPIF1<0的取值范圍．21．（2023·北京房山·統(tǒng)考二模）已知函數(shù)SKIPIF1<0．(1)求曲線SKIPIF1<0在SKIPIF1<0處的切線方程；(2)當(dāng)SKIPIF1<0時，求函數(shù)SKIPIF1<0的最小值；(3)證明：SKIPIF1<022．（2023·陜西西安·長安一中?？级＃┮阎猄KIPIF1<0．(1)求SKIPIF1<0在SKIPIF1<0處的切線方程；(2)若SKIPIF1<0，記SKIPIF1<0為函數(shù)g(x)的兩個極值點，求SKIPIF1<0的取值范圍．1．（2017·全國·高考真題）若SKIPIF1<0是函數(shù)SKIPIF1<0的極值點，則SKIPIF1<0的極小值為．A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2012·重慶·高考真題）設(shè)函數(shù)SKIPIF1<0在R上可導(dǎo)，其導(dǎo)函數(shù)為SKIPIF1<0，且函數(shù)SKIPIF1<0的圖像如題（8）圖所示，則下列結(jié)論中一定成立的是A．函數(shù)SKIPIF1<0有極大值SKIPIF1<0和極小值SKIPIF1<0B．函數(shù)SKIPIF1<0有極大值SKIPIF1<0和極小值SKIPIF1<0C．函數(shù)SKIPIF1<0有極大值SKIPIF1<0和極小值SKIPIF1<0D．函數(shù)SKIPIF1<0有極大值SKIPIF1<0和極小值SKIPIF1<03．（2013·浙江·高考真題）已知e為自然對數(shù)的底數(shù),設(shè)函數(shù)SKIPIF1<0,則．A．當(dāng)k=1時,f(x)在x=1處取到極小值 B．當(dāng)k=1時,f(x)在x=1處取到極大值C．當(dāng)k=2時,f(x)在x=1處取到極小值 D．當(dāng)k=2時,f(x)在x=1處取到極大值4．（2022·全國·統(tǒng)考高考真題）已知SKIPIF1<0和SKIPIF1<0分別是函數(shù)SKIPIF1<0（SKIPIF1<0且SKIPIF1<0）的極小值點和極大值點．若SKIPIF1<0，則a的取值范圍是____________．5．（2021·全國·統(tǒng)考高考真題）函數(shù)SKIPIF1<0的最小值為______.6．（2018·全國·高考真題）已知函數(shù)SKIPIF1<0，則SKIPIF1<0的最