![新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專(zhuān)題28 體積法求點(diǎn)面距離(原卷版)_第1頁(yè)](http://file4.renrendoc.com/view14/M08/08/36/wKhkGWdSSfuAYGPAAAFQwWPufsA010.jpg)
![新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專(zhuān)題28 體積法求點(diǎn)面距離(原卷版)_第2頁(yè)](http://file4.renrendoc.com/view14/M08/08/36/wKhkGWdSSfuAYGPAAAFQwWPufsA0102.jpg)
![新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專(zhuān)題28 體積法求點(diǎn)面距離(原卷版)_第3頁(yè)](http://file4.renrendoc.com/view14/M08/08/36/wKhkGWdSSfuAYGPAAAFQwWPufsA0103.jpg)
![新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專(zhuān)題28 體積法求點(diǎn)面距離(原卷版)_第4頁(yè)](http://file4.renrendoc.com/view14/M08/08/36/wKhkGWdSSfuAYGPAAAFQwWPufsA0104.jpg)
![新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專(zhuān)題28 體積法求點(diǎn)面距離(原卷版)_第5頁(yè)](http://file4.renrendoc.com/view14/M08/08/36/wKhkGWdSSfuAYGPAAAFQwWPufsA0105.jpg)
版權(quán)說(shuō)明:本文檔由用戶(hù)提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
專(zhuān)題28體積法求點(diǎn)面距離一、多選題1.在正方體ABCD-A1B1C1D1中,E,F(xiàn),G分別為BC,CC1,BB1的中點(diǎn),則()A.D1D⊥AFB.A1G∥平面AEFC.異面直線(xiàn)A1G與EF所成角的余弦值為SKIPIF1<0D.點(diǎn)G到平面AEF的距離是點(diǎn)C到平面AEF的距離的2倍2.在正方體SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0、SKIPIF1<0分別為SKIPIF1<0、SKIPIF1<0中點(diǎn),SKIPIF1<0是SKIPIF1<0上的動(dòng)點(diǎn),則下列說(shuō)法正確的有()A.SKIPIF1<0B.三棱錐SKIPIF1<0的體積與點(diǎn)SKIPIF1<0位置有關(guān)系C.平面SKIPIF1<0截正方體SKIPIF1<0的截面面積為SKIPIF1<0D.點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離為SKIPIF1<03.已知三棱錐SKIPIF1<0中,SKIPIF1<0為SKIPIF1<0中點(diǎn),SKIPIF1<0平面SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則下列說(shuō)法中正確的是()A.若SKIPIF1<0為SKIPIF1<0的外心,則SKIPIF1<0B.若SKIPIF1<0為等邊三角形,則SKIPIF1<0C.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0與平面SKIPIF1<0所成角的范圍為SKIPIF1<0D.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0為平面SKIPIF1<0內(nèi)動(dòng)點(diǎn),若SKIPIF1<0平面SKIPIF1<0,則SKIPIF1<0在三角形SKIPIF1<0內(nèi)的軌跡長(zhǎng)度為SKIPIF1<0二、單選題4.如圖,在正方體SKIPIF1<0中,棱長(zhǎng)為1,SKIPIF1<0分別為SKIPIF1<0與SKIPIF1<0的中點(diǎn),SKIPIF1<0到平面SKIPIF1<0的距離為()
A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.如圖,正方體SKIPIF1<0的棱長(zhǎng)為1,線(xiàn)段SKIPIF1<0上有兩個(gè)動(dòng)點(diǎn)SKIPIF1<0,且SKIPIF1<0,給出下列四個(gè)結(jié)論錯(cuò)誤的選項(xiàng)是()A.SKIPIF1<0B.點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離為SKIPIF1<0C.SKIPIF1<0在底面SKIPIF1<0內(nèi)的正投影是面積不是定值的三角形D.在平面SKIPIF1<0內(nèi)存在無(wú)數(shù)條與平面SKIPIF1<0平行的直線(xiàn)6.正三棱柱SKIPIF1<0的所有定點(diǎn)均在表面積為SKIPIF1<0的球SKIPIF1<0的球面上,SKIPIF1<0,則SKIPIF1<0到平面SKIPIF1<0的距離為()A.1 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.如圖,正四棱錐SKIPIF1<0的高為SKIPIF1<0,且底面邊長(zhǎng)也為SKIPIF1<0,則點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離為()
A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.已知在正四棱柱SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0為SKIPIF1<0的中點(diǎn),則點(diǎn)SKIPIF1<0與平面SKIPIF1<0的距離為()A.2 B.SKIPIF1<0 C.SKIPIF1<0 D.19.直三棱柱SKIPIF1<0的側(cè)棱SKIPIF1<0,底面SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,則點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.已知正方體SKIPIF1<0的棱長(zhǎng)為1,給出下列四個(gè)命題:①對(duì)角線(xiàn)SKIPIF1<0被平面SKIPIF1<0和平面SKIPIF1<0、三等分;②正方體的內(nèi)切球、與各條棱相切的球、正方體的外接球的表面積之比為SKIPIF1<0;③以正方體的頂點(diǎn)為頂點(diǎn)的四面體的體積都是SKIPIF1<0;④正方體與以SKIPIF1<0為球心,1為半徑的球的公共部分的體積是SKIPIF1<0.其中正確的序號(hào)是()A.①② B.②④ C.①②③ D.①②④11.如圖,在正四棱柱SKIPIF1<0中,SKIPIF1<0,則點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0三、解答題12.已知四棱錐SKIPIF1<0中,底面SKIPIF1<0為矩形,平面SKIPIF1<0平面SKIPIF1<0,平面SKIPIF1<0平面SKIPIF1<0.(1)求證:SKIPIF1<0平面SKIPIF1<0;(2)若SKIPIF1<0,求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.13.在多面體SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,平面SKIPIF1<0平面SKIPIF1<0.(1)證明:SKIPIF1<0;(2)求直線(xiàn)SKIPIF1<0與平面SKIPIF1<0所成角的正弦值.14.如圖,直二面角SKIPIF1<0中,四邊形SKIPIF1<0是邊長(zhǎng)為SKIPIF1<0的正方形,SKIPIF1<0,SKIPIF1<0為SKIPIF1<0上的點(diǎn),且SKIPIF1<0平面SKIPIF1<0.(1)求證:SKIPIF1<0平面SKIPIF1<0;(2)求二面角SKIPIF1<0的大?。唬?)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.15.如圖,四棱錐SKIPIF1<0的底面SKIPIF1<0為正方形,平面SKIPIF1<0平面SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0.(1)證明:SKIPIF1<0平面SKIPIF1<0;(2)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.16.如圖,圓柱的軸截面SKIPIF1<0是正方形,點(diǎn)SKIPIF1<0是底面圓周上異于SKIPIF1<0的一點(diǎn),SKIPIF1<0,SKIPIF1<0是垂足.(1)證明:SKIPIF1<0;(2)若SKIPIF1<0,當(dāng)三棱錐SKIPIF1<0體積最大時(shí),求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.17.如圖,在四棱錐SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0平面SKIPIF1<0,SKIPIF1<0為SKIPIF1<0的中點(diǎn).(Ⅰ)證明:SKIPIF1<0平面SKIPIF1<0;(Ⅱ)若SKIPIF1<0,求點(diǎn)SKIPIF1<0以平面SKIPIF1<0的距離.18.如圖,多面體SKIPIF1<0中,四邊形SKIPIF1<0是菱形,SKIPIF1<0,SKIPIF1<0平面SKIPIF1<0,SKIPIF1<0(1)求二面角SKIPIF1<0的大小的正切值;(2)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離;(3)求直線(xiàn)SKIPIF1<0與平面SKIPIF1<0所成的角的正弦值.19.如圖,在四棱錐SKIPIF1<0中,SKIPIF1<0平面SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.20.棱長(zhǎng)為SKIPIF1<0的正方體SKIPIF1<0中,SKIPIF1<0、SKIPIF1<0分別是棱SKIPIF1<0、SKIPIF1<0中點(diǎn),求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.21.在棱長(zhǎng)為SKIPIF1<0的正方體SKIPIF1<0中求出下列距離:(1)點(diǎn)SKIPIF1<0到面SKIPIF1<0的距離;(2)線(xiàn)段SKIPIF1<0到面SKIPIF1<0的距離;(3)點(diǎn)SKIPIF1<0到面SKIPIF1<0的距離;(4)SKIPIF1<0到平面SKIPIF1<0的距離.22.如圖,四邊形SKIPIF1<0是正方形,SKIPIF1<0平面SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0(1)求證:SKIPIF1<0平面SKIPIF1<0;(2)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.23.如圖,在平行六面體SKIPIF1<0中,以頂點(diǎn)SKIPIF1<0為端點(diǎn)的三條棱長(zhǎng)都是SKIPIF1<0,且它們彼此的夾角都是SKIPIF1<0,SKIPIF1<0為SKIPIF1<0與SKIPIF1<0的交點(diǎn).若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,設(shè)平面SKIPIF1<0的法向量SKIPIF1<0(1)用SKIPIF1<0表示SKIPIF1<0;(2)求SKIPIF1<0及SKIPIF1<0的長(zhǎng)度;(3)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離24.如圖,在四棱柱SKIPIF1<0中,SKIPIF1<0平面SKIPIF1<0,底面SKIPIF1<0滿(mǎn)足SKIPIF1<0且SKIPIF1<0.(1)求證:SKIPIF1<0平面SKIPIF1<0;(2)求直線(xiàn)SKIPIF1<0與平面SKIPIF1<0所成角的正弦值;(3)求點(diǎn)SKIPIF1<0到平面SKIPIF1<0的距離.25.如圖,已知PA⊥平面ABCD,ABCD為矩形,M、N分別為AB、PC的中點(diǎn),SKIPIF1<0.(1)求證:平面MPC⊥平面PCD;(2)求三棱錐SKIPIF1<0的高.26.如圖所示,在三棱錐SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,O為SKIPIF1<0的中點(diǎn).(1)證明:SKIPIF1<0平面SKIPIF1<0;(2)若點(diǎn)M為棱SKIPIF1<0的中點(diǎn),求點(diǎn)C到平面SKIPIF1<0的距離.27.如圖,在四棱錐SKIPIF1<0中,底面SKIPIF1<0為菱形,SKIPIF1<0平面SKIPIF1<0,E為SKIPIF1<0上的動(dòng)點(diǎn).(1)確定E的位置,使SKIPIF1<0平面SKIPIF1<0;(2)設(shè)SKIPIF1<0,SKIPIF1<0,根據(jù)(1)的結(jié)論,求點(diǎn)E到平面SKIPIF1<0的距離.28.如圖,在五面體ABCDEF中,面SKIPIF1<0是正方形,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0.(1)求證:SKIPIF1<0平面SKIPIF1<0;(2)求直線(xiàn)BD與平面ADE所成角的正弦值;(3)
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶(hù)所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶(hù)上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶(hù)上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶(hù)因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 修建大橋勞務(wù)合同范本
- 個(gè)人山林入股合同范本
- 2025-2030年廚電產(chǎn)品租賃分期行業(yè)跨境出海戰(zhàn)略研究報(bào)告
- 保密工種聘用合同范本
- 事業(yè)編聘任合同范本
- 2025-2030年口腔清新維C片行業(yè)深度調(diào)研及發(fā)展戰(zhàn)略咨詢(xún)報(bào)告
- 2025-2030年在線(xiàn)健身指導(dǎo)平臺(tái)行業(yè)深度調(diào)研及發(fā)展戰(zhàn)略咨詢(xún)報(bào)告
- 2025-2030年廚電直播帶貨節(jié)企業(yè)制定與實(shí)施新質(zhì)生產(chǎn)力戰(zhàn)略研究報(bào)告
- 2025-2030年手表禮盒個(gè)性化定制行業(yè)深度調(diào)研及發(fā)展戰(zhàn)略咨詢(xún)報(bào)告
- 2025-2030年散熱風(fēng)扇智能控制企業(yè)制定與實(shí)施新質(zhì)生產(chǎn)力戰(zhàn)略研究報(bào)告
- 服裝廠(chǎng)安全生產(chǎn)培訓(xùn)
- 城市隧道工程施工質(zhì)量驗(yàn)收規(guī)范
- 2025年湖南高速鐵路職業(yè)技術(shù)學(xué)院高職單招高職單招英語(yǔ)2016-2024年參考題庫(kù)含答案解析
- 五 100以?xún)?nèi)的筆算加、減法2.筆算減法 第1課時(shí) 筆算減法課件2024-2025人教版一年級(jí)數(shù)學(xué)下冊(cè)
- 2025年八省聯(lián)考陜西高考生物試卷真題答案詳解(精校打印)
- 2025脫貧攻堅(jiān)工作計(jì)劃
- 借款人解除合同通知書(shū)(2024年版)
- 《血小板及其功能》課件
- 沐足店長(zhǎng)合同范例
- 《既有軌道交通盾構(gòu)隧道結(jié)構(gòu)安全保護(hù)技術(shù)規(guī)程》
- 初中物理22-23人大附中初三物理寒假作業(yè)及答案
評(píng)論
0/150
提交評(píng)論