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GMAT(QUANTITATIVE)數(shù)學(xué)練習(xí)試
卷1(共9套)
(共231題)
GMAT(QUANTITATIVE)數(shù)學(xué)練習(xí)試
卷第1套
一、單項(xiàng)選擇題(本題共30題,每題1.0分,共30
分。)
1、Ifthesmallerof2consecutiveoddintegersisamultipleof5,whichofthefollov/ing
couldNOTbethesumofthese2integers?
A、-8
B、12
C、22
D、52
E、252
標(biāo)準(zhǔn)答案:C
知識(shí)點(diǎn)解析:Sincethesmallerofthe2consecutiveoddintegersisamultipleof5,letit
berepresentedbySnforsomeintegern.Thcntheotheroddintegercanberepresentedby
5n+2.ThesumofthesetwointegersislOn+2.Thesumis-8whenn=-1and5n=(5)(-
1)isodd.Thesumis12whenn=1and5n=(5)(1)isodd.Thesumis22whenn=2,but
5n=(5)(2)isnotodd.ThereisnoneedtochecktheDandEbecauseithasbeen
determinedthat22cannoibethesumofthe2consecutiveoddintegers.For
completeness,thesumis52whenn=Sand5n=(5)(5)isodd.Thesumis252whenn=
25and5n=(5)(25)isodd.ThecorrectanswerisC.
2、A8inthefigureabove,iftrianglesABC,ACD,andADEare
isoscelesrighttrianglesandtheareaofAABCis6,thentheareaofAADEis
A、18
B、24
C、36
D、\2yf2
E、24戲36
標(biāo)準(zhǔn)答案:B
知識(shí)點(diǎn)解析:BecauseAABCisanisoscelesrighttrianglewithlegs新5d前,itfollows
thatAB=BCandtheareaofAABCis(AB)(BC)/2=(1/2)(AB)2.Itisgiventhatthearea
ofAABCis6,andthus(1/2)(AB-=6,or(AB)~=12,orAB=疝..Applyingthe
PythagoreantheoremtoAABCgives(AC)2=(AB)2+(BC)2,andhence(AC)2=
(何:
12+12=24,orACV24.1.BecauseAACDisanisoscelesrighttriangle
withlegs衣and歷.、andAC=日.itfollowsthatAC=CD=424..Applyingthe
777o
PythagoreantheoremtoAACDgives(AD)~=(AC)+(CD),andhence(AD)~=
(衣)+(舊)=24+24=48,orAD=聞..BecauseAADEisanisoscelesrighttriangle
withlegsADandDE,,(jAD=相,,it
an?***???,?i-t9followsthatAD=DE=andhencetheareaof
=屈)(屈)=24.加correctanswerisB.
Eachof27white1-centimetercubeswillhaveexactlyoneface
paintedred.Ifthese27cubesarejoinedtogethertoformonelargecube,asshownabove,
whatisthegreatestpossiblefractionofthesurfaceareathatcouldbered?
As11/27
B、13/27
C、1/2
D、5/9
E、19/27
標(biāo)準(zhǔn)答案:B
知識(shí)點(diǎn)解析:Allbutoneofthe1-centimetercubes,namelytheI-centimetercubeinthe
center,hasatleastonefacelyingonihesurfaceofthelargecube.Thegreatestpossible
fractionofthesurfaceofthelargecubewillberedwheneachofthese27-1=26non-
center1-centimetercubesisorientedsothatitsredfaceliesonthesurfaceofthelarge
cube.Sincethesurfaceofthelargecubehas6faces,eachconsistingof9facesfromthe
1-centimetercubes,thesurfaceofthelargecubeconsistsofatotalof(6)(9)=54faces
fromthe1-centimetercubes.Therefore,thegreatestpossiblefractionofthesurfacearea
thatcouldberedis26/54=13/27.ThecorrectanswerisB.
4、Thefigureaboveisconstructedbyseparatingacircular
regioninto6equalpartsandrearrangingthepartsasshown.Ifthediameterofthecircle
isd,whatistheperimeterofthefigureabove?
A、兀d
B>27rd
C、兀d+2
D、兀d+d
E、2nd+d
標(biāo)準(zhǔn)答案:D
矢口識(shí)點(diǎn)解析:Theperimeterconsistsof6arcsand2segments.Thetotallengthofthe6
arcsisthecircumferenceofthecircle,whichisnd.Eachsegmentisaradiusofthecircle
withlengthd/2.Thereforetheperimeterofthefigureisnd+2(d/2)=nd+d.Thecorrect
answerisD.
5、Onascaledrawingofatriangularpieceofland,thesidesofthetrianglehavelengths
5,12,and13centimeters.IfIcentimeteronthedrawingrepresents3meters,whatisthe
area,insquaremeters,ofthepieceofland?
A、90
B、180
C、240
D、270
E、540
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Since52+122=132,thepieceoflandisintheshapeofarighttriangle.
Thelengthsofthelegsofthepieceofland,inmeters,are(3)(5)=15and(3)(12)=36
since1centimeteronthedrawingrepresents3metersonthepieceofland.Therefore,the
area,insquaremeters,ofthepieceoflandis(1/2)(15)(36)=270squaremeters.The
correctanswerisD.
6、*怪"gurenocd"ssc*Whichofthefollowinggivesallpossiblevaluesofxinthe
figureabove?
A、1<x<4
1<x<7
C>3<x<5
D、4
E、5
標(biāo)準(zhǔn)答案:B
E、4r(n+4)
標(biāo)準(zhǔn)答案:B
知識(shí)點(diǎn)解析:Thefigureshowsthatthe(vertical)widthoftheracetrackisequaltothe
diameterofthesemicircles,whichis2r,andthusthe(horizontal)lengthoftheracetrack
is2(2r)=4r.Therefore,theperimeteroftheracetrack,whichconsistsoftwosemicircular
arcsandtwolengthsoftherectangle,is2(兀r)+2(4r)=2i?(兀+4).ThecorrectanswerisB.
Thefigureabove,whichisdividedinto6sectorsofequal
area,containsanarrowrepresentingaspinner.Ifthespinnerisrotated3,840degreesina
clockwisedirectionfromthepositionshown,whichofthefollowingindicatesthesector
(A)△
(B)口
(C)O
(D)
towhichthearrowonthespinnerwillpoint?o
A、
B、
C、
D、
E、
標(biāo)準(zhǔn)答案:B
知識(shí)點(diǎn)解析:Thespinnerrotates3840/360=32/3=,03revolutions,whichcanalsobe
seenbyobservingthat3,840degrees-3,600degrees=240degrees=2/3ofarevolution.
Aftermaking10revolutions,thespinnerisbacktothestartingpointandstillneedsto
rotate2/3ofthewayaroundthecircle.Sincerotating2/3ofthewayaroundthecircleis
equivalenttorotatingthrough4ofthe6sectorsofthecircle,thespinnerwillpointtothe
sectorwiththesquare.ThecorrectanswerisB.
11、Whenarectangularvatthatis3feetdeepisfilledto2/3ofitscapacity,itcontains
7I
60gallonsofwaler.If2gallonsofwaleroccupies1cubicfoolofspace,whalisthe
area,insquarefeet,ofthebaseofthevat?
A、4
B、8
C、12
D、150
E、225
標(biāo)準(zhǔn)答案:A
知識(shí)點(diǎn)解析:2Whenfilledto2/3capacity,thevatcontains60gallonsofwater(i.e.,
(2/3)(capacity)=60),andsowhenitisfilledtocapacityitcontains(2/3)(60)=90
gallonsofwater,whichoccupies90/7.5=12cubicfeet.IfArepresentstheareaofthe
baseofthevat,insquarefeet,thenthevolumeofthevatis3A=12cubicfeet,andhence
A=4.ThecorrectanswerisA.
12、Thefigureaboverepresentsanantennatowerwithtwoguy
wiresthatextendfrompointQ,40feetabovetheground,topointsPandRasshown.If
thetwowireshaveequallength,approximatelywhatisthetotallength,infeet,ofthetwo
wires?
A、60
B、80
C、100
D、120
E、180
標(biāo)準(zhǔn)答案:C
知識(shí)點(diǎn)解析:BecausePQ=QR.itfollowsthatAPQRisisoscelesandtheperpendicular
fromQtoPRbisectsPR?Therefore,eachoftherighttrianglesinthefigurehaslegs
J7()2+A()2
thatare30ftand40ft.BythePythagoreantheorem,PQ=*-ru=50andthe
totallengthofthetwoguywiresis2(50ft)=100ft.ThecorrectanswerisC.
13、Thefiguresaboveshowasealedcontainerthat
isarightcircularcylinderfilledwithliquidto1/2itscapacity.Ifthecontainerisplaced
onitsbase,thedepthoftheliquidinthecontaineris10centimetersandifthecontaineris
placedonitsside,thedepthoftheliquidis20centimeters.Howmanycubiccentimeters
ofliquidareinthecontainer?
A、4,000兀
2,000兀
C>1,000兀
D、400兀
E、200n
標(biāo)準(zhǔn)答案:A
知識(shí)點(diǎn)解析:Thefigureontheright,whichshowsthecylinderfilledto1/2itscapacity,
indicatesthattheradiusofthecylinderis20cm.Thefigureontheleftindicatesthatthe
heightoftheliquidis10cmUsingV=7tr2h,whereristheradiusandhistheheightof
theliquidinthecylinder,thevolumeofliquidinthecylindricalcontaineris兀(20)~(10)=
4,000兀cubiccentimeters.ThecorrectanswerisA.
Whatistheradius,inmeters,ofthetabletopwhenallfourleavesareup?
A、1/2
收
B、T
C、1
D、圾
E、2
標(biāo)準(zhǔn)答案:B
知識(shí).點(diǎn)解析/:O-----'Thefigureaboveshowsthecirculartabletopviewedfrom
above.Thediameterofthecircleisthediagonalofthesquare,whichis1meteronaside.
BythePythagoreantheorem,thediagonalis"+0五metersandtheradiusis2
meters.ThecorrectanswerisB.
15>Ifthediameterofacircularskatingrinkis60meters,theareaoftherinkis
approximatelyhowmanysquaremeters?
A、90
B、180
C、900
D、2,800
E、10,800
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Ifthediameterofthecircularskatingrinkis60meters,thentheradiusis
30metersandtheareais兀(30)=900兀squaremeters.Assumingthevalueof兀tobe
slightlygreaterthan3,therinkisapproximately2,800squaremeters.Thecorrectanswer
isD.
16、Whatisthegreatestnumberofblocks8centimetersby6centimetersby9
centimetersthatwillfitintoastoragespacethatis60centimetersby72centimetersby
96centimeters?
A、60
B、840
C、896
D、960
E、1,080
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Thevolumeofthestoragespaceis60x72x96andeachblockis6x8x
9,sothenumberofblocksthatwillfit
is=(60x72x96)/(6x8x9)=60/6x72/9x96/8=10x8x12=960.ThecorrectanswerisD.
17、ClosingPricesofStockXDuringaCertainWeek(indollars)
MondayTuesdayWednesdayThursdayFnday
21192223
-JAcertainfinancialanalystdefinesthe"volatility"
ofastockduringagivenweektobetheresultofthefollowingprocedure:findthe
absolutevalueofthedifferenceinthestock'sclosingpricefbreachpairofconsecutive
daysintheweekandthenfindtheaverage(arithmeticmean)ofthese4values.Whatis
thevolatilityofStockXduringtheweekshownintheTable?
A、2
B、3
C、4
D、6
E、7
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Theeasiestwaytodothisproblemmightbebyjustcountingeverythird
bulbgoingclockwisearoundthecirclestartingalBulb1,whichHashes,skipping2bulbs
andgettingtoBulb4,whichHashes,skipping2bulbsandgettingtoBulb7,which
flashes,skipping2bulbsandgettingtoBulb2,whichflashes,skipping2bulbsand
gettingtoBulb5,whichflashes,skipping2bulbsandgettingtoBulb8,whichflashes,
skipping2bulbsandgettingtoBulb3,whichflashes,andfinallyskipping2bulbsand
gettingtoBulb6,whichflashes.Now,all8bulbshaveflashedonceandthelastoneto
flashwasBulb6.ThecorrectanswerisD.
18、Acertainfinancialanalystdefinesthe"volatility"ofastockduringagivenweekto
betheresultofthefollowingprocedure:findtheabsolutevalueofthedifferenceinthe
stock'sclosingpricefbreachpairofconsecutivedaysintheweekandthenfindthe
average(arithmeticmean)ofthese4values.WhatisthevolatilityofStockXduringthe
weekshowninthetabic?
A、0.50
B、1.80
C、2.00
D、2.25
E、2.50
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:ThevolatilityofStockXduringtheweekistheaverageofthe4values
associatedwiththe4pairsofconsecutivedaysduringtheweek.
(Moo&Tue)-?(Ttte&WedH(Wal&cThu)-<-CnMi&Fri)
4
|19-21|+|22-19|+|M5-22|平3-245]
4
_|-2|+|3|+|2.5|+|-L5|2+3+25+1.5_922s
444ThecorrectanswerisD.
13*7
19>Ify=**2-3,forwhatvalueofxwillthevalueofybegreatest?
A、-5
B、-3/5
C、0
D、3/5
E、5/3
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:Sincetheabsolutevalueofanyrealnumberisgreaterthanorequalto
zero,itfollowsthat|3x-5|>0.Also,toranyrealnumberxwchavex->0,andhence-
x-<0.Subtracting3frombothsidesofthelastinequalitygives-x~-3<-3.Therefore,
thenumeratoroftheexpressionforyisgreaterthanorequaltozeroandthedenominator
oftheexpressionfbryisnegative.Itfollowsthatthevalueofycannotbegreaterthan0.
However,thevalueofyisequalto0when|3x-5|=0tor3x-5=0,orx=5/3.
Therefore,thevalueofxforwhichthevalueofyisgreatest(i.e.,wheny=0)isx=5/3.
ThecorrectanswerisE.
20>Whatvaluesofxhaveacorrespondingvalueofythatsatisfiesbothxy>0andxy=
x+y?
A、x<-l
B、-1
C、0<x<1
D^x>I
ExAllrealnumbers
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:First,usexy=x+ytosolveforyintermsofx.xy=x+ygivenxy-y=x
subtractyfrombothsidesy(x-1)=xfactory=x/(x-l)dividebothsidesbyx-1Note
thatthedivisionbyx-1requiresx/1,andthusx=lneedstobeconsideredseparately.
However,ifx=1,thenxy=x+ybecomesy=1+y,whichisnottrueforanyvalueofy.
Usingy=x/(x-l),itfollowsthattheinequalityxy>0isequivalenttox2/(x-l)>0.Since
x2>0foreachvalueofx,thequotientx2/(x-l)canonlybepositivewhenx/0andx-1
ispositive,orwhenx>1.Alternatively,thecorrectanswercanbefoundbyeliminating
theincorrectanswers,whichcanbeaccomplishedbyconsideringtheendpointsofthe
intervalsgivenintheanswerchoices.Case1:Ifx=-1,thenxy=x+ybecomes-y=-1+
y,ory=1/2.However,inthiscasexy=(-1)(1/2)isnegative,andthusxy>0isnottrue.
Therefore,theanswercannotbeAorE.Case2:Ifx=0,thenxy=0,andthusxy>0is
nottrue.Therefore,theanswercannotbeBorE.Case3:Ifx=1,thenxy=x+vbecomes
y=1+y,whichisnottruefbranyvalueofy.Therefore,theanswercannotbeCorE.
SincetheanswercannotbeA,B,C,orE,itfollowsthattheanswerisD.Thecorrect
answerisD.
21、EmployeeX'sannualsalaryis$12,000morethanhalfofEmployeeY'sannual
salary.EmployeeZ'sannualsalaryis$15,000morethanhalfofEmployeeX'sannual
salary.IfEmployeeX'sannualsalaryis$27,500,whichofthefollowingliststhesethree
peopleinorderofincreasingannualsalary?
A、Y,Z,X
B、Y,X,Z
C、Z,X,Y
D、X,Y,Z
E、X,Z,Y
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:Lettingx,y,andzrepresenttheannualsalary,indollars,ofEmployeeX,
EmployeeY,andEmployeeZ,respectively,thefollowinginformationisgiven:(1)x=
12,000+y/2(2)z=15,000+x/2(3)x=27,500From(1)and(3),itfollowsthat27,500
=12,000+y/2ory=2(27,500-12,000)=31,000.From(2)and(3),itfollowsthatz=
15,000+27500/2=28,750.Therefore,x<z<y.ThecorrectanswerisE.
C/0.10s,ifss60.000
22、-10.10"0.MAeo,ooo)/Sn60.000TheformulaabovegivesthecontributionC,in
dollars,toacertainprofit-sharingplanforaparticipantwithasalaryofsdollars.How
manymoredollarsisthecontributionforaparticipantwithasalaryof$70,000thanfora
participantwithasalaryof$50,000?
A、$800
B、$1,400
C、$2,000
D、$2,400
E、$2,800
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Foraparticipantwithasalaryof$70,000,C=0.1(S70,000)+
0.04($70,000-$60,000)=$7,000+$400=$7,400.Foraparticipantwithasalaryof
$50,000,C=0.1($50.0001=$5,000.Thedifferenceis$7,400-$5,000=$2,400.The
correctanswerisD.
23、Nextmonth,RonandCathywilleachbeginworkingpart-timeat3/5oftheir
respectivecurrentsalaries.IfthesumoftheirreducedsalarieswillbeequaltoCathy's
currentsalary,thenRon'scurrentsalaryiswhatfractionofCathy'scurrentsalary?
A、1/3
B、2/5
C、1/2
D、3/5
E、2/3
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:LettingRandC,respectively,representRon'sandCathy'scurrent
salaries,itisgiventhat3R/5+3C/5=C.Itfollowsthat3R/5=2C/5andR=3'5'3
ThecorrectanswerisE.
24、DavidandRonareorderingfoodforabusinesslunch.Davidthinksthatthere
shouldbetwiceasmanysandwichesastherearepastries,butRonthinksthenumberof
pastriesshouldbe12morethanone-fourthofthenumberofsandwiches.Howmany
sandwichesshouldbeorderedsothatDavidandRoncanagreeonthenumberofpastries
toorder?
A、12
B、16
C、20
D、24
E、48
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:LetSbethenumberofsandwichesthatshoulcbeorderedandletPbethe
numberofpastriesthatshouldbeordered.ThenDaviddesiresS=2PandRondesiresP=
12+S/4.S=2PgivenS=2(12+S/4)P=12+S/4S=24+S/2distributivelawS/2=24
subtractS/2frombothsidesS=48multiplybothsidesby2ThecorrectanswerisE.
25、Thecostofpurchasingeachboxofcandyfromacertainmailordercatalogisv
dollarsperpoundofcandy,plusashippingchargeofhdollars.Howmanydollarsdoesit
costtopurchase2boxesofcandy,onecontainingspoundsofcandyandtheother
containingtpoundsofcandy,fromthiscatalog?
A、h+stv
B、2h+srv
C>2hstv
D、2h+s+t+v
E、2h+v(s+t)
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:Thecost,indollars,topurchasethe2boxesofcandyisthesumof2
shippingchargesandthecostofs+tpoundsofcandy,cost=(2shippingcharges)+(v)(s
+/)cost=2(h)+(v)(s+t)cost=2h+v(s+i)ThecorrectanswerisE.
6/?31-8x-4
26、Ifxrl/2,then―2K.i
A、3X2+3X/2-8
B、3X2+3X/2-4
C、3x2-4
D、3x-4
E、3x+4
標(biāo)準(zhǔn)答案:C
6*'-8*-4=(6y'<-)—(8JT-?4)
2*+1=2x+lgroup
£七*+1)-42"1)
taclor
2x*l
(3-T3+1)
factor
cancdsince
知識(shí)點(diǎn)解析:Alternatively,sometimesitis
easierorquickertotestone-variableexpressionsforequalitybysubstitutingaconvenient
valueforthevariableandeliminatinganswerchoicesfbrwhichthevalueofthe
expressioninthatanswerchoicedoesnotequalthevalueofthegivenexpression.For
example,choosex=0,sincecalculationsforx=0areminimal.Then,asshowninthe
tablebelow,2x+11"but3x-+3x/2-8=-8and3x+4=4,neitherofwhich
equals-4,soanswerchoicesAandEcanbeeliminated.Anotherconvenientvalueto
choosefbrxisI.ThereisnoneedtoevaluateanswerchoicesAandEat1sincethey
+3*i_8jr_4.一]、
havealreadybeeneliminated.Asshown,whenx=I,A+i-'but3x~+3x/2-
4=l/2^-l,soanswerchoiceBcanbeeliminated.Athirdconvenientvalueforxis-1.
ThereisnoneedtoevaluateanswerchoicesA,B,andEat-1sincetheyhavealready
6x'?.........-...8..x-4a.
beenclimiiialcd.Asshuwn,whenx=-l,but3x-4=-7/-1,soanswer
choiceDcanbeeliminated.Notethat,ifx=-1hadbeenchoseninitially,A,B,D,andE
wouldhavebeeneliminatedimmediatelysince3x2+3x/2-8=62,3x2+3x/2-4=
zx-0x-1
+3/-8x-4T-1-1
2x>l
A-8
1
B短哮-4-4
2
C3x2~4-4-1-i
D3*-4-4-1-7
244
2±-\,3x-4=-7豐-1,and3x+4=1/-I.回_____/The
correctanswerisC.
27、Ifx2+bx+5=(x|內(nèi)ballnumbersx,wherebandcarepositiveconstants,
⑻而
(C)275
(DI2而
(E)10
whatisthevalueofb?
A、
B、
C、
D、
E、
標(biāo)準(zhǔn)答案:C
知識(shí)點(diǎn)解析:Giventhatx2+bx+5=(x+c)2,since(x+c)2=x2+2cx+c2,itfollows
that5=c2andb=2c.ThepossiblevaluesofcareYmd7s,butsincecispositive,c二6
andb=2c=26..ThecorrectanswerisC.
28、LastyearShannonlistenedtoacertainpublicradiostation10hoursperweekand
contributed$35tothestation.Ofthefollowing,whichisclosesttoShannon's
contributionperminuteoflisteningtimelastyear?
A、$0.001
B、$0.010
C、$0.025
D、$0.058
E、$0.067
標(biāo)準(zhǔn)答案:A
知識(shí)點(diǎn)解析:Sincethereare52weeksin1yearand60minutesin1hour,10hoursper
weekisequivalentto(10)(52)(60)=31,200minutesperyear.Shannon's35$35
contributionisthen35/31200dollarsperminute,whichisclosestto$0,001perminute.
ThecorrectanswerisA.
29、Eachofthe20employeesatCompanyJistoreceiveancnd-of-ycarbonusthisyear.
Agneswillreceivealargerbonusthananyotheremployee,butonly$500morethan
Cherylwillreceive.NoneoftheemployeeswillreceiveasmallerbonusthanCheryl.If
theamountofmoneytobedistributedinbonusesatCompanyJthisyeartotals$60,000,
whatisthelargestbonusAgnescanreceive?
A、$3,250
B、$3,325
C、$3,400
D、$3,475
E、$3,500
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:Sincethetotalamountofthebonusesisfixed,thelargestpossiblebonus
thatAgnescanreceivewilloccurwhenthetotalamountreceivedbythe19employees
otherthanAgnesisthesmallestpossible.LetAbethebonus,indollars,thatAgnes
receives.Then,indollars,Cherylwillreceive(A-500),andeachoftheremaining18
employeeswillreceivebetween(A-500)andA.Therefore,thetotalamountreceivedby
the19employeesotherthanAgnesissmallestwheneachofthese19employeesreceives
(A-500)dollars.19(A-500)+A=60,000totalof20bonusesis$60,00019A-9,500+A=
60,000distributivelaw20A-9,500=60,000combineliketerms20A=69,500add9.500
tobothsidesA=3,475dividebothsidesby20ThecorrectanswerisD.
30、Beth,Naomi,andJuanraisedatotalof$55forcharity.Naomiraised$5lessthan
Juan,andJuanraisedtwiceasmuchasBeth.HowmuchdidBethraise?
A、$9
B、$10
C、$12
D、$13
E、$15
標(biāo)準(zhǔn)答案:C
知識(shí)點(diǎn)解析:LetB,N,andJbetheamountsraised,respectivelyandindollars,byBeth,
Naomi,andJuan.B+N+J=55givenN=J-5givenJ=2BgivenJ=55-B-NsubtractB
+NfrombothsidesoffirstequationJ=55-B-(J-5)N=J-52B=55-B-(2B-5)J=2BB=
12solveforBThecorrectanswerisC.
GMAT(QUANTITATIVE)數(shù)學(xué)練習(xí)試
卷第2套
一、單項(xiàng)選擇題(本題共30題,每題7.0分,共30
分。)
1、Howmanyhourswerebudgetedforacertainjob?(1)Thenumberofhoursbudgeted
forthejobplustheactualnumberofhoursusedforthejobwas140.(2)Theactual
numberofhoursusedforthejobminusthenumberofhourbudgetedforthejobwas8.
A、Statement(1)ALONEissufficient,butstatement(4)aloneisnotsufficienttoanswer
thequestionasked.
B、Statement(2)ALONEissufficient,butstatement(3)aloneisnotsufficienttoanswer
thequestionasked.
C^BOTHstatement(I)and(4)TOGETHERaresufficienttoanswerthequestion
asked,butNEITHERstatementALONEissufficient.
D、EACHstatementALONEissufficienttoanswerthequestionasked.
E、Statement(1)and(4)TOGETHERareNOTsufficienttoanswerthequestionasked,
andadditionaldataspecifictotheproblemareneeded.
標(biāo)準(zhǔn)答案:C
知識(shí)點(diǎn)解析:假設(shè)Thenumberofhoursbudgetedforthejob為x,theactualnumber
ofhoursusedforthejob為y,那么得到:?jiǎn)为?dú)⑴x+y=140,一個(gè)方程兩個(gè)未知數(shù)有
無(wú)數(shù)解;單獨(dú)(2)y-x=8,一個(gè)方程兩個(gè)未知數(shù)有無(wú)數(shù)解;把⑴和⑵結(jié)合起來(lái)考
慮,兩個(gè)未知數(shù),兩個(gè)方程,可以求解,所以答案為C。
2、Isthepositiveintegermequaltothecubeofaninteger?(1)Foreveryprimenumber
q,ifqisafactorofm,thenq’isalsoadivisorofm.(2)以isaninteger.
A、Statement(1)ALONEissufficient,butstatement(12)aloneisnotsufficientto
answerthequestionasked.
B、Statement(2)ALONEissufficient,butstatement(11)aloneisnotsufficientto
answerthequestionasked.
C、BOTHstatement(1)and(12)TOGETHERarcsufficienttoanswerthequestion
asked,butNEITHERstatementALONEissufficient.
D、EACHstatementALONEissufficienttoanswerthequestionasked.
E、Statement(1)and(12)T0GETHERareNOTsufficienttoanswerthequestionasked,
andadditionaldataspecifictotheproblemareneeded.
標(biāo)準(zhǔn)答案:B
知識(shí)點(diǎn)解析:?jiǎn)为?dú)(1),q,q3是m的因子,m不一定是完全立方數(shù),比如m=q4同
樣能滿足q,q3是m的因子。單獨(dú)(2),而是整數(shù),滿足完全立方數(shù)的定義,所以
選擇Bo
3、Whatistheunitsdigitofpositiveintegerx?(l)xdividedby9hasaremainderof5.
(2)xdividedby3hasaremainderof2.
A、Statement(1)ALONEissufficient,butstatement(20)aloneisnotsufficientto
answerthequestionasked.
B、Statement(2)ALONEissufficient,butstatement(19)aloneisnotsufficientto
answerthequestionasked.
C、BOTHstatement(1)and(20)TOGETHERarcsufficienttoanswerthequestion
asked,butNEITHERstatementALONEissufficient.
D、EACHstatementALONEissufficienttoanswerthequestionasked.
E>Statement(1)and(20)TOGETHERareNOTsufficienttoanswerthequestionasked,
andadditionaldataspecifictotheproblemareneeded.
標(biāo)準(zhǔn)答案:E
知識(shí)點(diǎn)解析:Statement⑴中x=9n+5,隨著n的不同,x的個(gè)位數(shù)也不同,所以單
獨(dú)(I)無(wú)法回答問(wèn)題。Statement(2)^x=3m+2,隨著m的不同,x的個(gè)位數(shù)也不
同,單獨(dú)(2)也無(wú)法回答問(wèn)題。把(1)和(2)結(jié)合起來(lái),x=9n+5,除以3余2,所以結(jié)
合起來(lái)的性質(zhì)仍然等同于(1),無(wú)法回答問(wèn)題,所以E為正確答案。
4、Theaverage(arithmeticmean)ofMconsecutiveoddintegersis10.Whatisthe
smallestnumberinthesequence?(I)ThcrangeoftheMconsecutiveoddintegersis14.
(2)ThegreatestnumberoftheMconsecutiveoddintegersis15.
A、Statement(1)ALONEissufficient,butstatement(28)aloneisnotsufficientto
answerthequestionasked.
Statement(2)ALONEissufficient,butstatement(27)aloneisnotsufficientto
answerthequestionasked.
C、BOTHstatement(1)and(28)TOGETHERaresufficienttoanswerthequestion
asked,butNEITHERstatementALONEissufficient.
D、EACHstatementALONEissufficienttoanswerthequestionasked.
E^Statement(1)and(28iTOGETHERareNOTsufficienttoanswerthequestionasked,
andadditionaldataspecifictotheproblemarcneeded.
標(biāo)準(zhǔn)答案:D
知識(shí)點(diǎn)解析:設(shè)最小的奇數(shù)為ai,M個(gè)連續(xù)奇數(shù)是一個(gè)等差數(shù)列,公差為2,它們
的平均數(shù)為10,那么它們的和為10M,在Statement⑴中,am-ai=14,那么
M=7,知道了和、項(xiàng)數(shù)、公差,首項(xiàng)當(dāng)然可以求得,所以單獨(dú)(1)可以回答問(wèn)題。
在Statement⑵中,設(shè)am為原數(shù)列中最大的奇數(shù),則am=15,那么
S=10M=(ai+15)/215=ai+(M?l)x2從方程組里面能夠求得ai,也就是數(shù)列中的最小
值,所以單獨(dú)(2)也可以回答問(wèn)題。因此D為正確答案。
5、Ifrs=s,whatisthevalueofr+s?(1)r=4(2)5=0
A、Statement(1)ALONEissufficient,butstatemem(36)aloneisnotsufficientto
answerthequestionasked.
Statement(2)ALONEissufficient,butstatement(35)aloneisnotsufficientto
answerthequestionasked.
C、BOTHstatement(1)and(36)TOGETHERaresufficienttoanswerthequestion
asked,butNEITHERstatementALONEissufficient.
D、EACHstatementALONEissufficienttoanswerthequestionasked.
E、Statement(1)and(36)TOGETHERareNOTsufficienttoanswerthequestionasked,
andadditionaldataspecifictotheproblemarcneeded.
標(biāo)準(zhǔn)答案:A
知識(shí)點(diǎn)解析:對(duì)于Statement(1),r=4,要滿足4s=S,s必然為0,可以求得r+s。
對(duì)于Statement(2),s=0,那么「可以為任意值,所以r+s不確定,因此答案為A。
6、DoesthelineLpasscuadranlIV?(1)TheslopeofLisnegative.(2)y-inter
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