C第8次實(shí)驗(yàn)報(bào)告匯總

1、C 語言程序設(shè)計(jì)課程實(shí)驗(yàn)報(bào)告（第次）學(xué) 院：數(shù)學(xué)與計(jì)算機(jī)學(xué)院姓 名：張?jiān)軐W(xué) 號(hào)： 201510804033專 業(yè)：軟件工程班 級(jí)： 1 班同 組 人：實(shí)驗(yàn)地點(diǎn)： 6A-2實(shí)驗(yàn)時(shí)間：指導(dǎo)教師：實(shí)驗(yàn)名稱：多態(tài)性與虛函數(shù)所使用的開發(fā)工具及環(huán)境：硬件PC -l實(shí)驗(yàn)?zāi)康模?1) 了解多態(tài)性的概念。(2) 了解虛函數(shù)的作用及使用方法。(3) 了解靜態(tài)關(guān)聯(lián)和動(dòng)態(tài)關(guān)聯(lián)的概念和川法。(4) 了解純虛函數(shù)和抽象類的概念和用法。實(shí)驗(yàn)內(nèi)容:1、分析程序運(yùn)行結(jié)果，掌握虛函數(shù)的使用。程序一：#in elude using n amespace std;class ONE public:virtual void f()c

2、outONEe ndl;class TWO:public ONE public:TWO()coutTWOe ndl;class THREE:public TWO public:virtual void f()TWO:f(); coutf();/ONE THREEcoute ndl;程序二：#in clude using n amespace std;class Base public:virtual void fn() cout In Base Classn;；class SubClass :public Base public:virtual void fn() cout fn();/l n

3、 Base Classp=≻p-fn();/In Sub Class2、 實(shí)現(xiàn)一個(gè)類 A，在A中有兩個(gè)私有的整型變量a和b,定義構(gòu)造函數(shù)對(duì) a和b進(jìn)行初始化，并實(shí)現(xiàn)成員函數(shù)geta ()取得a的值和getb ()取b的值。實(shí)現(xiàn)類 B從A繼承，覆蓋geta()，使其返回a的2倍。主函數(shù)中聲明類B對(duì)象，調(diào)用類B中的geta ()并將結(jié)果輸出。3、設(shè)計(jì)一個(gè)計(jì)算圖形面積的類庫。它的頂層是一個(gè)抽象類，并且提供相應(yīng)的接口函數(shù)。抽象基類Shape，派生出Point類、矩形Rectangle、正方形Square， Point類派生出圓 形Circle 。 要求：(1) 每個(gè)類有構(gòu)造函數(shù)、析構(gòu)函數(shù)，并有相

4、應(yīng)的輸出語句，如：“正在構(gòu)造圓形”(2) 能顯示每個(gè)類的信息，如：輸出“我是圓形”(3) 能計(jì)算面積、周長(4) 定義一個(gè)基類 Shape類型的指針，實(shí)現(xiàn)動(dòng)態(tài)多態(tài)(5) 動(dòng)態(tài)創(chuàng)建一個(gè)圓形對(duì)象，賦值給基類Shape類型的指針變量，程序最后delete該指針，保證析構(gòu)函數(shù)的正確調(diào)用(提示：虛析構(gòu)函數(shù))(6 )在主函數(shù)測(cè)試。4、 設(shè)計(jì)一個(gè)基類 Base，其作用是計(jì)算一個(gè)圖形的面積，它只有一個(gè)公有的函數(shù)成員虛函數(shù)area。再從Base 類公有派生一個(gè)三角形類Triangle和一個(gè)圓類 Circle，在類Triangle和類Circle中分別定義自己的area 函數(shù)，用于計(jì)算各自的面積。在主函數(shù)中設(shè)計(jì)一

5、個(gè)Base類的對(duì)象指針，分別指向類Triangle 和類Circle 的對(duì)象，調(diào)用各自的area 函數(shù)顯示相應(yīng)對(duì)象的面積。分析：用虛函數(shù)實(shí)現(xiàn)多態(tài)。5 將上題中的Base類改為抽象類，應(yīng)用抽象類，求矩形、圓形的周長和面積。分析：將Base類的其成員函數(shù) area 和perimeter 聲明為純虛函數(shù)，Base就成為 一個(gè)抽 象類。然后再從Base派生矩形類和圓形類，分別實(shí)現(xiàn)Base中純虛函數(shù)的功 能結(jié)果與分析：Sy8-1:程序一：i-7 F：C+習(xí)lDebug：L 心eTWO TWOONE THREE程序二:Sy8-2:#in cludeusing n amespace std;class Ap

6、ublic:A(int a,int b):a(a),b(b) virtual int geta()return a; frie nd class B;private:int a;int b;class B:public Apublic:B(int a,int b):A(a,b) int geta()retur n 2*a;int mai n()A *p=new B(2,3); coutgeta()e ndl;system(pause);return 0;l F：K+8.Sy8-2Y3?bLig5y8-Z.exeSy8-3:#in cludeusing n amespace std;con st

7、 double Pl=3.1415926;class Shapepublic:Shape()coutC on struct ing Shape.e ndl; virtual Shape()coutDestruct ing Shape.e ndl; virtual void Name()coutSharee ndl; virtual double Area()=0;virtual double C()=0;class Point: public Shapepublic:Point()coutConstructing Point.endl; Poi nt()coutDestructi ng Poi

8、 nt.e ndl; virtual void Name()coutPo in te ndl; double Area()retur n 0; double C()return 0;class Recta ngle:public Shape public:Rectangle(int l,int w):length(l),width(w)coutConstructing Rectangle.endl;Rectangle()coutDestructing Rectangle.endl;double Area()retur n len gth*width;double C()return (le n

9、gth+width)*2;void Name()coutRecta nglee ndl;private:double len gth;double width;class Squre:public Shapepublic:Squre(i nt l):L(l)coutC on struct ing Squre.e ndl; Squre()coutDestruct ing Squre.e ndl; void Name()coutSquree ndl; double Area()retur n L*L;double C()return 4*L;private:double L;；class Circ

10、le: public virtual Pointpublic:Circle(double r):radious(r)coutConstructing Circle.endl;Circle()coutDestructing Circle.endl;void Name()coutvCirclevName();coutC()ve ndl;coutArea()vName();coutC()ve ndl;coutArea()vName();coutC()ve ndl;coutArea()vName();coutC()ve ndl;coutArea()ve ndl;delete p;system(paus

11、e);Constructin Shape* ConstFuct iny Rec tangle-. Rec tanc| leC = 10Aiea = EDestructing RectDes tmict lnj( S hctpe -.iwBUMSy8-4:#in cludeusing n amespace std;con st double Pl=3.1415926;class Basepublic:Base()coutC on struct ing Base.e ndl;virtual Base()coutDestructed Base.e ndl;virtual double Area()=

12、0;class Trian gle:public Basepublic:Tria ngle(double a,double b,double c):a(a),b(b),c(c)coutC on structi ng Tria ngle.e ndl;Tria ngle()coutDestructed Trian gle.e ndl;double Area()return sqrt(0.5*(a+b+c)*(0.5*(a+b+c)-a)*(0.5*(a+b+c)-b)*(0.5*(a+b+c)-c); private:double a,b,c;class Circle:public Basepub

13、lic:Circle(double r):radious(r)coutConstructing Circle.endl; Circle()coutDestructed Circle.e ndl;double Area()retur n Pl*radious*radious;private:double radious;int mai n()Base *p;p=new Trian gle(3,4,5);coutArea()ve ndl;delete p;coute ndl;p=new Circle(4);coutArea()ve ndl;delete p;coute ndl;system(pau

14、se);return 0;-F：C+SSy8-4DebugSyS-41exeConstruct ing Base Cons七1*1:1;insr Triangle A re a ： 6Destructed Triangfle. Destructed Base-Construct ins Base . Construjct ing Circle -. AreaDestructed Circle Destructed Base-Sy8-5:#in cludeusing n amespace std; const double Pl=3.1415926; class Basepublic:Base(

15、)coutC on struct ing Base.e ndl;virtual Base()coutDestructed Base.e ndl;virtual double Area()=0;virtual double Perimeter()=0;/ 周長;class Trian gle:public Basepublic:Tria ngle(double a,double b,double c):a(a),b(b),c(c)coutC on structi ng Tria ngle.e ndl; Triangle()coutDestructed Triangle.endl;double A

16、rea()return sqrt(0.5*(a+b+c)*(0.5*(a+b+c)-a)*(0.5*(a+b+c)-b)*(0.5*(a+b+c)-c); double Perimeter()retur n a+b+c;private:double a,b,c;class Circle:public Basepublic:Circle(double r):radious(r)coutConstructing Circle.endl;Circle()coutDestructed Circle.endl;double Area()retur n PI*radious*radious;double Perimeter()retur n 2*PI*radious;private:double radious;int mai n()Base *p;p=new Trian gle(3,4,5);coutArea()ve ndl;coutPerimeter()ve ndl;delete p;coute ndl;p=new Circle(4);coutArea()ve ndl;coutPerimeter()ve ndl;delete p;coute ndl;system