525010031電大流體力學(xué)考試題小抄參考

1、專業(yè)好文檔流體力學(xué) 試題2008年7月試卷代號：7753 河南廣播電視大學(xué)20072008年學(xué)年度第二學(xué)期期末考試一、單選題1、在明渠均勻流中取一六面體，其所受的外力：作用在該六面體上有（ d ）a、 切向力、正壓力 b、正壓力 c、 正壓力、重力 d、正壓力、切向力、重力 2、在水箱上接出一條等直徑長細(xì)圓管，末端設(shè)有閥門以控制流量，若水箱內(nèi)水面不隨時間變化，當(dāng)閥門開度一定時，管中水流為（ a ）a、恒定均勻流 b、恒定非均勻流 c、非恒定均勻流 d、非恒定非均勻流3、 對實際流體，總水頭總是（ a ）a、沿程下降 b沿程升高c沿程可升可降 d沿程不升不降 4、按短管進(jìn)行水力計算的管路是（ a

2、 ）a、虹吸管 b、給水管路 c、 支狀管網(wǎng) d、環(huán)狀管網(wǎng)5、跌水的形成條件是（ c ）a、從急流過渡到急流 b、 從急流過渡到緩流 c、從緩流過渡到急流 d、從緩流過渡到緩流二、判斷題1.流體內(nèi)部切應(yīng)力的大小僅與流速梯度有關(guān)。( ）2.真空壓強(qiáng)是指沒有大氣存在時的壓強(qiáng)。（ ）3.均勻流一定是恒定流。（ ）4.動能修訂系數(shù)與斷面流速分布有關(guān) （ ）5.壁面光滑的管道一定是水力光滑管 （ ）6.若兩孔口形狀、尺寸完全相同，作用水頭相同，一個為自由出流，一個為淹沒出流，二者的流量是相同的（） 三、簡答題1流體靜壓強(qiáng)的兩個特征？答:1）垂直指向受壓面。2）某點壓強(qiáng)的大小與受壓面的方位無關(guān)（某點壓強(qiáng)的

3、大小僅與該點的淹沒深度有關(guān)）2、根據(jù)尼古拉茲試驗，說明紊流各區(qū)沿程阻力系數(shù) 與re和k/d的關(guān)系？答：（1）水力光滑區(qū)：f（re）（2）過渡粗糙區(qū)： f（re,k/d）(3)粗糙區(qū)： f（k/d03、為什么對于孔口淹沒出流無小孔口與大孔口的區(qū)別？答：在劃分小孔口和答孔口時，若h/d10,視為孔口各點的壓強(qiáng)僅似相等，定義為小孔口，對于孔口淹沒出流其作用水頭h為上下游水面差，孔口各點的壓強(qiáng)相等，故對于孔口淹沒出流無小孔口與大孔口之分。4、何種流動為恒定流？答：若流體中任一點的運(yùn)動要素與時間無關(guān)，或者說：流體中任一點的運(yùn)動要素不隨時間變化。5、圓管中層流與紊流，其斷面流速分布有什么不同？答：圓管中層

4、流斷面流速分布為拋物線狀，而圓管中紊流斷面流速分布為對數(shù)曲線，紊流的斷面流速分布均勻化了。流體力學(xué) 試題2008年1月試卷代號：7753 河南廣播電視大學(xué)2007-2008學(xué)年度第一學(xué)期期末考試一、單選題1在明渠均勻流中取一六面體，其所受的外力：作用在該六面體上有 （ d ）a.切向力、正壓力 b.正壓力 c.正壓力、重力 d. 正壓力、切向力、重力 2在水箱上接出一條等直徑長細(xì)圓管，末端設(shè)有閥門以控制流量，若水箱內(nèi)水面不隨時間變化，當(dāng)閥門開度一定時，管中水流為 ( a ）a.恒定均勻流 b.恒定非均勻流 c.非恒定均勻流 d.非恒定非均勻流3對實際流體，總水頭總是 ( a ）a.沿程下降 b

5、.沿程升高 c.沿程可升可降 d.沿程不升不降 4.按短管進(jìn)行水力計算的管路是 ( a ）a.虹吸管 b.給水管路 c. 支狀管網(wǎng) d.環(huán)狀管網(wǎng)5.跌水的形成條件是 (c）a.從急流過渡到急流 b.從急流過渡到緩流 c.從緩流過渡到急流 d.從緩流過渡到緩流二、判斷題1.流體內(nèi)部切應(yīng)力的大小僅與流速梯度有關(guān)。 ( ） 2.真空壓強(qiáng)是指沒有大氣存在時的壓強(qiáng)。（ ） 3.均勻流一定是恒定流。（ ） 4.動能修訂系數(shù)與斷面流速分布有關(guān)（ ） 5.壁面光滑的管道一定是水力光滑管（ ） 6.若兩孔口形狀、尺寸完全相同，作用水頭相同，一個為自由出流，一個為淹沒出流，二者的流量是相同的 （ ） 三、簡答題1

6、流體靜壓強(qiáng)的兩個特征？答：（1）垂直指向受壓面。（2）某點壓強(qiáng)的大小與受壓面的方位無關(guān)（某點壓強(qiáng)的大小僅與該點的淹沒深度有關(guān)）2、根據(jù)尼古拉茲試驗，說明紊流各區(qū)沿程阻力系數(shù) 與re和k/d的關(guān)系？答：（1）水力光滑區(qū)：f（re）（2）過渡粗糙區(qū)： f（re,k/d）(3)粗糙區(qū)： f（k/d03、為什么對于孔口淹沒出流無小孔口與大孔口的區(qū)別？答：在劃分小孔口和答孔口時，若h/d10,視為孔口各點的壓強(qiáng)僅似相等，定義為小孔口，對于孔口淹沒出流其作用水頭h為上下游水面差，孔口各點的壓強(qiáng)相等，故對于孔口淹沒出流無小孔口與大孔口之分。4、何種流動為恒定流？答：若流體中任一點的運(yùn)動要素與時間無關(guān)，或者說

7、：流體中任一點的運(yùn)動要素不隨時間變化。5、圓管中層流與紊流，其斷面流速分布有什么不同？答：圓管中層流斷面流速分布為拋物線狀，而圓管中紊流斷面流速分布為對數(shù)曲線，紊流的斷面流速分布均勻化了。流體力學(xué) 試題2008年1月土木工程專業(yè)試題試卷代號：1123中央廣播電視大學(xué)2007-2008學(xué)年度第一學(xué)期“開放本科期末考試(半開卷)一、選擇題1在靜水中取一六面體，分析其所受的外力：作用在該六面體上的力有( c )。a切向力、正壓力 b正壓力c正壓力、重力 d正壓力、切向力、重力2在水箱上接出一條逐漸收縮錐形管道，末端設(shè)有閥門已控制流量，當(dāng)水箱內(nèi)水面不變、閥門開度一定時，管中水流為( d )。a恒定均勻

8、流 b恒定非均勻流c非恒定均勻流 d非恒定非均勻流3按短管進(jìn)行水力計算的管路是( a )a虹吸管 b給水管路 c支狀管網(wǎng) d環(huán)狀管網(wǎng)4外延管嘴的正常工作條件是( d )。 a管長等于34倍的管徑 b作用水頭小于9米水柱 c管長ln2)，其他參數(shù)相同(i，b，m，q)，則h01h02 b底坡不同(i1i2)，其他參數(shù)相同(n，b，m，q)，則h01h02 c底寬不同(b1b2)，其他參數(shù)相同(i，n，m，q)，則h01h02 d邊坡系數(shù)不同(m1m2)，其他參數(shù)相同(i，n,b，q)，則h01h02二、判斷題1非均勻流一定是非恒定流。 () 2流體內(nèi)部切應(yīng)力的大小僅與流速梯度有關(guān)。 () 3壁面

9、光滑的管道一定是水力光滑管 () 4流體中某點的靜壓強(qiáng)大小與受壓面方位無關(guān)()5明渠水流從急流過渡到緩流，發(fā)生跌水(水跌)。 ( )6明渠水流的測壓管水頭線不可能沿程上升。 ()三、簡答題1動力粘滯系數(shù)和運(yùn)動粘滯系數(shù)v布什么區(qū)別?答：兩者都反映流體的粘滯性，為動力量，v為運(yùn)動量，量綱不同。2繪出下圖平面ab上相對壓強(qiáng)翁布圖。2答：3簡述明渠恒定非均勻流的水力特征。答：過水?dāng)嗝婷娣ea，水深h，沿程改變。即底坡線，水面線，總線頭線三線不再平行，即。4如圖所示，平板閘門置于水中，當(dāng)上游水位均上升l米(虛線位置)時，試問：圖(a)(b)中閘門所受的靜水總壓力及作用點是否改變?(提示：畫壓強(qiáng)分布圖分析)

10、答：(1)圖(a)中閘門所受的靜水總壓力及作用點改變。靜水總壓力變大，作用點升高。(2)圖(b)中閘門所受的靜水總壓力及作用點不變。四、計算題 1如圖所示，容器中盛有水，右側(cè)為一測壓管；左側(cè)為一u形測壓管，管中為水銀。已知：，求右側(cè)測壓管中水面高度h1=? 1解：(1)畫出兩個等壓面(通過a點畫一個，通過u形測壓管中水銀液面畫一個)(2)列方程：將(1)式帶人(2)整理得：答：右側(cè)測壓管中水面高度h。一222m。2圖示為一平板ab，寬l米，傾角a=45o，左側(cè)水深為3米，右側(cè)水深為2米，求靜水總壓力及其作用點的位置? 2解：(1)求兩側(cè)靜水壓力及靜水總壓力：(方向向右)右側(cè)靜水壓力作用點距8點

11、的距離為(方向向左)左側(cè)靜水壓力作用點距8點的距離為(方向向右)(2)求作用點位置：(設(shè)靜水總壓力作用點距8點的距離為e)答：靜水總壓力p=3465kn，作用點距b點的距離為e一179m。 3如圖所示一虹吸管，上下有水位差為h=25m，虹吸管頂部與上游水面高差為h1=20m，虹吸管頂部前，管長為50 m，虹吸管頂部后，管長為100 rn，管徑d=02m，管道沿程阻力系數(shù)a=002，進(jìn)口(帶有蓮蓬頭)局部阻力系數(shù)每個彎管局部阻力系數(shù)(1)流量q=?(2)虹吸管最大真空值3解：(1)以上游水面為基準(zhǔn)面，列能量方程：(2)以上游水面為基準(zhǔn)面，列上游過流斷面和頂部22段間的能量方程：(水柱)答：(i)

12、流量(2)虹吸管最大真空值發(fā)生在頂部，最大真空值為3428m(水柱)流體力學(xué)土木工程專業(yè)2007年7月試題試卷代號：1123扣央廣播電視大學(xué)20062007學(xué)年度第二學(xué)期“開放本科”期末考試(半開卷) 一、選擇題1在靜水中取一六面體，分析其所受的外力：作用在該六面體上的表面力有( b )a切向力、正壓力 b正壓力c正壓力、重力 d切向力、重力2在水箱上接出一條逐漸收縮錐形管道，末端設(shè)有閥門以控制流量，當(dāng)水箱內(nèi)水面不變、閥門開度一定時，管中水流為( b )a恒定均勻流 b恒定非均勻流c非恒定均勻流 d非恒定非均勻流3等直徑圓管中層流的過流斷面流速分布是( a )a呈拋物線分布 b呈對數(shù)線分布c呈

13、橢圓曲線分布 d呈雙線分布4流體內(nèi)部某點壓強(qiáng)為2個工程大氣壓，用液柱高度為( c )a10米水柱 b22米水柱c20米水柱 d25米水柱5總水頭線與測壓管水頭線的基本規(guī)律之一，是：( b )a總水頭線總是沿程升高b總水頭線總是在測壓管水頭線的上方c測壓管水頭線沿程升高 d. 測壓管水頭線總是沿程下降的二、判斷題1理想流體與實際流體的區(qū)別僅在于，理想流體具有不可壓縮性。( )2無論流體作何種運(yùn)動，流體內(nèi)任何一個水平面都是等壓面。( )3在恒定流情況下，流線與跡線重合。( )4對于漸變流，過流斷面上動水壓強(qiáng)分布符合靜水壓強(qiáng)分布規(guī)律( )5壁面粗糙的管道一定是水力粗糙管。( )6在進(jìn)行水力計算時，短

14、管是指管道幾何長度較短的管道。( ) 三、簡答題1等壓面是水平面的條件有哪些?答：(1)必須是同一種流體。(2)必須是連續(xù)流體。 (3)必須是單一重力作用條件下。(4)必須為靜止流體。2管道內(nèi)流態(tài)為紊流時，水力光滑與水力粗糙是如何定義的?答：固體邊界表面存在當(dāng)量粗糙度k，流體運(yùn)動時在固體邊界存在粘性底層艿；(1)當(dāng)粘性底層艿遠(yuǎn)遠(yuǎn)大于當(dāng)量粗糙度k(k-6)，稱為水力粗糙。3寫出管流和明渠水流雷諾數(shù)的表達(dá)式，并說明其層流、紊流的判別標(biāo)準(zhǔn)?答：管流 re：2000(紊流)re500(紊流)re500(層流)。4如圖所示，平板閘門置于水中，當(dāng)上游水位均上升1米(虛線位置)時，試問：圖(a)(b)中閘門

15、所受的靜水總壓力及作用點是否改變?(提示：畫壓強(qiáng)分布圖分析)(a)(b)答：(1)圖(a)中閘門所受的靜水總壓力及作用點改變。靜水總壓力變大，作用點升高。(2)圖(b)中閘門所受的靜水總壓力及作用點不變。四、計算題1在封閉水箱中，h=1.5m z=05m(如圖)，壓力表讀數(shù)為49knm2，求水面相對壓強(qiáng)及其真空度。1解：(1)將壓力表讀數(shù)換算為水柱高：p=4998=05m(2)列方程pq+pghpgz+p=一49kn=-05m水柱(3)pk一05m水柱答：水箱中水面相對壓強(qiáng)：p。一-49knm2，其真空度為pk205m水柱。2水閘寬度b=2m，兩側(cè)都有水，左側(cè)水深h1=3m，右側(cè)水深h2=2m

16、，試求作用在閘門上的靜水總壓力及作用點的位置?2(1)畫出靜壓強(qiáng)分布圖。(2)計算兩側(cè)靜水壓力及靜水總壓力： (3)求靜水總壓力的作用點。(設(shè)作用點距渠底的距離為e)答：靜水總壓力夕=392kn，方向向右。靜水總壓力的作用點在閘門的對稱軸上，距渠底的距離e=126m。 3如圖所示，左側(cè)為密閉水箱，水通過一管道流人右側(cè)水箱，已知左水箱內(nèi)自由表面相對壓強(qiáng)p=294kpa，兩水箱液面高差h=20m，管長l=5m，管徑d=020m，管路沿程水頭損失系數(shù)=002，在恒定流情況下，求通過流量。 3解：以右水箱水面為基準(zhǔn)面，取a=10，管道進(jìn)口局部損失1=o5，管道出口局部損失島=10，管中流速可(1)把左

17、水箱內(nèi)自由表面壓強(qiáng)換算成液柱高度水柱)(2)列能量方程： (3)流量：答：通過流量winger tuivasa-sheck, who scored two tries in the kiwis 20-18 semi-final win over england, has been passed fit after a lower-leg injury, while slater has been named at full-back but is still recovering from a knee injury aggravated against usa.both sides boas

18、t 100% records heading into the encounter but australia have not conceded a try since josh charnleys effort in their first pool match against england on the opening day.aussie winger jarryd hayne is the competitions top try scorer with nine, closely followed by tuivasa-sheck with eight.but it is rec

19、ently named rugby league international federation player of the year sonny bill williams who has attracted the most interest in the tournament so far.the kiwi - with a tournament high 17 offloads - has the chance of becoming the first player to win the world cup in both rugby league and rugby union

20、after triumphing with the all blacks in 2011.id give every award back in a heartbeat just to get across the line this weekend, said williams.the (lack of) air up there watch mcayman islands-based webb, the head of fifas anti-racism taskforce, is in london for the football associations 150th annivers

21、ary celebrations and will attend citys premier league match at chelsea on sunday.i am going to be at the match tomorrow and i have asked to meet yaya toure, he told bbc sport.for me its about how he felt and i would like to speak to him first to find out what his experience was.uefa hasopened discip

22、linary proceedings against cskafor the racist behaviour of their fans duringcitys 2-1 win.michel platini, president of european footballs governing body, has also ordered an immediate investigation into the referees actions.cska said they were surprised and disappointed by toures complaint. in a sta

23、tement the russian side added: we found no racist insults from fans of cska. baumgartner the disappointing news: mission aborted.the supersonic descent could happen as early as sunda.the weather plays an important role in this mission. starting at the ground, conditions have to be very calm - winds

24、less than 2 mph, with no precipitation or humidity and limited cloud cover. the balloon, with capsule attached, will move through the lower level of the atmosphere (the troposphere) where our day-to-day weather lives. it will climb higher than the tip of mount everest (5.5 miles/8.85 kilometers), dr

25、ifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilometers) and into the stratosphere. as he crosses the boundary layer (called the tropopause),e can expect a lot of turbulence.the balloon will slowly drift to the edge of space at 120,000 feet ( then, i would as

26、sume, he will slowly step out onto something resembling an olympic diving platform.they blew it in 2008 when they got caught cold in the final and they will not make the same mistake against the kiwis in manchester.five years ago they cruised through to the final and so far history has repeated itse

27、lf here - the last try they conceded was scored by englands josh charnley in the opening game of the tournament.that could be classed as a weakness, a team under-cooked - but i have been impressed by the kangaroos focus in their games since then.they have been concentrating on the sort of stuff that

28、 wins you tough, even contests - strong defence, especially on their own goal-line, completing sets and a good kick-chase. theyve been great at all the unglamorous stuff that often goes unnoticed in the stands but not by your team-mates.it is as though their entire tournament has been preparation fo

29、r the final.in johnathan thurston, cooper cronk, cameron smith and either billy slater or greg inglis at full-back they have a spine that is unmatched in rugby league. they have played in so many high-pressure games - a priceless asset going into saturday.the kiwis are a lot less experienced but win

30、ning a dramatic match like their semi-final against england will do wonders for their confidence.they defeated australia in the four nations final in 2010 and the last world cup, and know they can rise to the big occasion. 保護(hù)與報警定值與結(jié)果保護(hù)與報警定值與結(jié)果過載大于110%報警，大于120%延時5秒跳閘出口電壓高卸載大于108%短路200%，延時0.08秒跳閘出口電壓低

31、卸載低于85%電流不平衡不平衡電流大于20%，延時5秒跳閘電壓高跳閘大于110%漏電電流大于30%，延時10秒三相電壓不平衡電壓差大于10%逆功率大于8%，延時0.5秒過頻率大于110%超速大于115%，延時5秒跳閘低頻率小于85%蓄電池電壓低小于21v蓄電池電壓高大于30v差動保護(hù)0秒跳閘失磁保護(hù)跳閘單相接地保護(hù)跳閘過電流保護(hù)跳閘潤滑油壓低跳閘三次自起動失敗發(fā)信并閉鎖自起動冷卻水溫高發(fā)信潤滑油溫度高發(fā)信機(jī)油油壓過低跳閘機(jī)油油壓低發(fā)信冷卻水?dāng)嗨l燃油量過低發(fā)信油箱油位低發(fā)信冷卻水水位低發(fā)信3主要技術(shù)指標(biāo)（表一）靈敏度100lx(0=550nm)1.5s2.55s輸 出ac220v 50hz

32、1a ， dc24v 1a模擬量輸出420madc 15vdc工作方式環(huán)境溫度探 -2環(huán)境濕度;入口ac220v 50hz功耗15wa*cz7h$dq8kqqfhvzfedswsyxty#&qa9wkxfyeq!djs#xuyup2knxprwxma&ue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvk

33、um>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2

34、zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ng#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx

35、2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%m

36、z849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z8vg#tym*jg&6a*c

37、z7h$dq8kqqfhvzfedswsyxty#&qa9wkxfyeq!djs#xuyup2knxprwxma&ue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxg89amue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpaza

38、dnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6

39、x4ngpp$vstt#&ksv*3tngk8!z8vg#tym*jg&6a*cz7h$dq8kqqfhvzfedswsyxty#&qa9wkxfyeq!djs#xuyup2knxprwxma&ue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tn

40、gk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*

41、3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qype

42、h5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ng

43、pp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%m

44、z849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!

45、z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum

46、>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcv

47、r9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxg

48、jqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5u

49、xgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xr

50、m6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpaz

51、adnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpaz

52、adnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jn

53、d6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8

54、!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#