C語言編程實(shí)驗(yàn)8

1、實(shí)驗(yàn)8 指針（P148-P158）說明： 完成以下實(shí)驗(yàn)內(nèi)容后，將本文檔改名為“實(shí)驗(yàn)8_班級_學(xué)號_姓名.doc”，并按規(guī)定提交。 第一部分：練習(xí)題練習(xí)題1用一維數(shù)組和指針變量作為函數(shù)參數(shù)，編程打印某班一門課程的最高分?jǐn)?shù)及其學(xué)號。程序代碼#include<stdio.h>#define ARR_SIZE 40int FindMax(int score, long num,int n,long *pMaxNum);void main()int scoreARR_SIZE,maxScore,n,i;long numARR_SIZE,maxNum;printf("Please e

2、nter total number:");scanf("%d",&n);printf("Please enter the number and score:n");for (i=0;i<n;i+)scanf("%ld%d",&numi,&scorei);maxScore=FindMax(score,num,n,&maxNum);printf("maxScore=%d,maxNum=%ldn",maxScore,maxNum);int FindMax(int score

3、,long num,int n,long *pMaxNum)int i;int maxScore;maxScore=score0;*pMaxNum=num0;for (i=1;i<n;i+)if (scorei>maxScore)maxScore=scorei;*pMaxNum=numi;return(maxScore);程序運(yùn)行截圖練習(xí)題2用二維數(shù)組和指針變量作為函數(shù)參數(shù)，編程打印3個(gè)班學(xué)生的某門課程成績的最高分，并指出具有該最高分成績的學(xué)生是第幾個(gè)班的第幾個(gè)學(xué)生。程序代碼#include<stdio.h>#define CLASS 3#define STU 10#d

4、efine ARR_SIZE 40int FindMax(int scoreCLASSARR_SIZE, int m,int n,int *pRow,int *pCol);void main()int scoreCLASSARR_SIZE,maxScore,n,i,j,row,col;printf("Please enter student number in a class:");scanf("%d",&n);printf("Please enter score:n");for (i=0;i<CLASS;i+)for(

5、j=0;j<n;j+) scanf("%d",&scoreij); maxScore=FindMax(score,n,CLASS,&row,&col);printf("maxScore=%d,class=%d,number=%dn",maxScore,row+1,col+1);int FindMax(int scoreARR_SIZE,int n,int m,int *pRow,int *pCol) int i,j,maxScore;maxScore=score00;*pRow=0;*pCol=0;for (i=0;i<

6、;m;i+)for(j=0;j<n;j+)if(scoreij>maxScore)maxScore=scoreij;*pRow=i;*pCol=j;return(maxScore);程序運(yùn)行截圖問題解答思考題1能否使用二維數(shù)組或者而為數(shù)組的行指針作為函數(shù)參數(shù)進(jìn)行編程實(shí)現(xiàn)呢？可以，兩者都可以作為指針指向函數(shù)，從而進(jìn)行地址傳遞思考題2利用動(dòng)態(tài)內(nèi)存分配，編寫計(jì)算任意m行n列二維數(shù)組中最大值的函數(shù)。程序代碼#include <stdio.h>#include <stdlib.h>int m;int n;int main() int *p; int *q; print

7、f("輸入行數(shù)m列數(shù)n: "); scanf("%d %d",&m,&n); p=(int*)calloc(m,n); q=p; printf("輸入數(shù)組n"); for(int i=0;i<m;i+) for(int j=0;j<n;j+) scanf("%d",p+); int max =*q; for(int k=0;k<m*n;k+) if(*(q+k)>max) max=*(q+k); printf("max=%dn",max); return

8、0;程序運(yùn)行截圖練習(xí)題4編寫返回字符指針函數(shù)搜尋一個(gè)字符串中第一個(gè)字符d，找到返回d的地址，在主函數(shù)內(nèi)用*代替d，然后打印該字符串。程序代碼#include <stdio.h>#define EMPTY 0char* findfirst(char *, char);int main() char string="do you study math today?" char *ptr; printf("%sn",string); ptr=EMPTY; ptr=findfirst(string, 'd'); if(ptr!=EMP

9、TY) *ptr='*' printf("%sn",string); return 0;char *findfirst(char *s,char d) while(*s!=d)&&(*s!='0') s+; if(*s=d) return s; else return EMPTY;程序運(yùn)行截圖問題解答思考題1若將函數(shù)findfirst中while語句改為：while(*s!=d)&&(*s!=0);可以嗎？不可以思考題2修改主程序?qū)⒆址械淖址鹍全部替換為*，應(yīng)如何編程實(shí)現(xiàn)。程序代碼#include <

10、stdio.h>#define EMPTY 0char* find(char *, char);int main() char string="do you study math today?" char *ptr; printf("%sn",string); ptr=EMPTY; do ptr=find(string, 'd'); if(ptr!=EMPTY) *ptr='*' while(ptr!=0); printf("%sn",string); return 0;char *find(ch

11、ar *s,char d) while(*s!=d)&&(*s!='0') s+; if(*s=d) return s; else return EMPTY;程序運(yùn)行截圖練習(xí)題5編寫函數(shù)求從1-n倒數(shù)的累加和，要求使用只想函數(shù)的指針。程序代碼#include <stdio.h>double sur(double);double sqrt(double);double cube(double);double sum(int,double(*p)(double);void main()double(*ptr)(double );int s=0;ptr=s

12、ur;printf("sum=%.2lfn",sum(4,ptr);double sum(int n,double(*p)(double)double s=0;int k;for(k=1;k<=n;k+)s+=(*p)(k);return s;double sur(double x)return(1.0/x);程序運(yùn)行截圖問題解答思考題1根據(jù)用戶需求選擇求平方累加和、立方累加和或倒數(shù)累加和。程序代碼#include <stdio.h>double x(double);double pf(double);double lf(double);double su

13、m(int,double(*p)(double);int main() double(*p)(double); int l; printf("倒數(shù)和輸入1，平方和輸入2，立方和輸入3:"); scanf("%d",&l); switch(l) case 1: p = x;break; case 2: p = pf;break; case 3: p = lf;break; default: break; int n; printf("輸入n:"); scanf("%d",&n); printf(&qu

14、ot;sum = %.2lfn",sum(n,p); return 0;double x(double i) return 1/i;double pf(double i) return (i*i);double lf(double i) return (i*i*i);double sum(int n, double(*p)(double) double s = 0; for(int k = 1; k <= n; k+) s += (*p)(double)k); return s;程序運(yùn)行截圖練習(xí)題6輸入三個(gè)數(shù)利用指針存入臨時(shí)動(dòng)態(tài)分配的變量中，并按從小到大的順序輸出。要求不能交換

15、無名變量中的數(shù)據(jù)，通過改變指針的指向完成排序。程序代碼#include <stdio.h>#include <stdlib.h>int main() float *pa; float *pb; float *pc; float *pt; if(pa=(float*)malloc(sizeof(float) scanf("%f",pa); else printf("malloc for pa is failed!n"); if(pb=(float*)malloc(sizeof(float) scanf("%f",

16、pb); else printf("malloc for pb is failed!n"); if(pc=(float*)malloc(sizeof(float) scanf("%f",pc); else printf("malloc for pc is failed!n"); if(*pa>*pb) pt=pa; pa=pb; pb=pt; if(*pa>*pc) pt=pa; pa=pc; pc=pt; if(*pb>*pc) pt=pb; pb=pc; pc=pt; printf("%.2f %.2f

17、 %.2fn",*pa,*pb,*pc); return 0;程序運(yùn)行截圖第二部分：自測練習(xí)自測練習(xí)2輸入一個(gè)3*4的數(shù)組，先找出每一行中的最大元素，在分別除改行中的所有元素，最后輸出數(shù)組。要求定義函數(shù)形參時(shí)，如果把二維數(shù)組定義為指針，調(diào)用時(shí)要用一級指針的地址。程序代碼#include <stdio.h>#include <string.h>float* func(float s134,float *p1)int m,n;float st;for(m=0;m<3;m+)for(n=0;n<4;n+)if(*p1>s1mn);elsep1=&a

18、mp;s1mn;st=*p1;p1=&s1m+10;for(n=0;n<4;n+)s1mn=s1mn/st;return &s100;int main(void)float s34,*p,*q;int i,j,k;for(i=0;i<12;i+)scanf("%d",&si/4i%4);p=&s00;q=func(s,p);for(j=0;j<3;j+)for(k=0;k<4;k+)printf("%0.2f ",*q);q+;printf("n");return 0;程序運(yùn)行截

19、圖自測練習(xí)4編程把命令行中的字符串（由數(shù)字字符組成）轉(zhuǎn)換成整數(shù)并累加輸出。程序代碼#include <stdio.h>#include <string.h>#include <math.h>#define N 100int main(void)char sN,*p=NULL;int i,j,k,len,sum,numN;j=0,k=0,sum=0;for(i=0;i<N;i+)numi=0;gets(s);len=strlen(s);p=&sN-1;for(i=0;i<N;i+)if(*p>='0')&(*p

20、<='9')numj+=(pow(10,k)*(*p)-'0');k+;if(*p=' ')j+;k=0;p-; for(i=0;i<N;i+)sum+=numi;printf("%dn",sum);return 0;程序運(yùn)行截圖自測練習(xí)5程序代碼#include <stdio.h>float matrix(float (*a)3,int n)int i,j;float sum=0;for(i=0;i<3;i+)for(j=0;j<3;j+)if(i=j)sum=sum+*(*(a+i)+j);if(j=2-i && i!=j)sum=sum+*(*