因車子是用均速行駛_第1頁
因車子是用均速行駛_第2頁
因車子是用均速行駛_第3頁
因車子是用均速行駛_第4頁
因車子是用均速行駛_第5頁
已閱讀5頁,還剩1頁未讀, 繼續(xù)免費閱讀

下載本文檔

版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進行舉報或認領(lǐng)

文檔簡介

1、Physics Answer1.) (i) As the car is moving at a constant velocity (i.e a=0), the horizontal forces must be equal and opposite i.e F=500N 因車子是用均速行駛 ( a= 0) ,橫向的力一定相等及相對 i.e F=500N(ii) 1) As a the car has no vertical acceleration, the vertical force must be equal and opposite. P+Q = 15000N(1 mark) 因車子

2、沒有垂直加速,所以垂直方向的力一定相等及相對。 P+Q = 15000N 2i) P = 2Q (P is twice the size of Q)( P是Q的兩倍)P+Q=1500N2Q+Q=15000N3Q=15000NQ=5000N(1 mark)P=10000N(1 mark)(iii ) The car would decelerate(1 mark)because the frictional force is greater than the driving force (1 mark)車子減速因磨擦力大過推動力考試技巧:l 留意F = ma 的是指剩力( net force )

3、,有剩力才有加速。因汽車要保持constant velocity,剩力 =0.l 留意垂直方向沒有加速,因此剩力 =0,所以向上力和向下力相等,因此P + Q = 15000N.2. (a) The efficiency decreases.(1 mark) 效率降低。 For a constant energy output (i.e PE gained = Mgh), the longer the plank, the more energy is used to overcome friction. This means that more input energy is supplie

4、d by Peter, so that the efficiency decreases.(2 mark) 因能量輸出是不變 ( PE 增長= Mgh ) ,用較長斜板需要多些能量去 克服磨擦力。這即是比得要多些能量輸入,因此效率降低。(b) This statement is false.(1mark)句子是不對的。 The downward component of weight parallel to the plank is smaller and so the applied force needed is smaller. (1 mark)由箱子重量分出來的分力 ( 與斜板成平行的

5、分力 ) 是較小的,所以應(yīng)用力較小??荚嚰记?l = 因斜板增長,所以耍用多些能量去對消friction,因此Work input 增加,從而使效率減少。l Applied force mgsin h l因斜板長度增加 , 減少。所以 applied force = mgsin 減少。3. i. 2S=Vt2S=(1500)(0.2)(1 mark)2S=300mS=150m(1 mark) ii. No (1 mark)不能 It is because the angle of reflection of sound wave must equal the angle of incidenc

6、e. This means that the reflected ray would miss the receiver on the ship. ( 1 mark )因為入射角一定要與反射角相等。這表示反射波不會反射至船身。iii The method of sonar is not suitable for aircrafts because they travel much faster than sound and would therefore miss the reflected ray(1 mark) 這種聲波方法不適合用作量度飛機高度是因飛機飛行速度較聲波快。考試技巧:l 使用

7、 v = 時,留意distance = 聲波來回距離。l 這個測度距離方法不能用於飛機的情況下,因飛機的速度比聲波快。4. a.i. When an alternating current flows through the primary coil , a changing magnetic flied is produced . ( 1 mark )當(dāng)交流電經(jīng)過第一組綫圈,有改變磁塲產(chǎn)生。The changing magnetic field links with the secondary coil. ( 1 mark )這改變磁塲牽引致第二組綫圈An induced a.c. volt

8、age is produced in the secondary coil ( 1 mark )感應(yīng)電壓在第二組綫圈產(chǎn)生due to electromagnetic induction. ( 1 mark )基於電磁感應(yīng)Since the number of turns in the secondary coil is less than that in the primary coil , the voltage is stepped down. ( 1 mark )因在第二組綫圈的綫圈較少,所以可將輸入電壓降低。ii. ( 1 mark )b) i. ( 1 )ii. (1 )iii. (

9、2 )c) Factors lead to heat lost能量流失原因Remedies解決方法Ohmic lost in the electrical wire due to heating effect of current in the wire因電綫有電阻,所似當(dāng)電流流過,就產(chǎn)生能量流失Low resistance ( thicker ) copper wire is used用低電阻電綫Magnetic flied leakage磁場流失A closed core is used用封閉式芯Reversal magnetization of the core將變壓器磁作A soft

10、iron is used用軟鉄芯Eddy current in the core渦流電A laminated core is used.將軟鐵芯切片 ( Any 3) ( 3 marks )d) At high voltage, the same electrical power can be transmitted at smaller currents. This reduce the power loss in the cables and the thinner cables can be used to save cost. ( 2 marks ) 在長距離電力傳送,多用高電壓傳送,這可使在電纜中減少,因此在纜中能 量流失減少。考試技巧:l 交流電可產(chǎn)生改變磁塲l 變壓器可分加壓及減壓兩

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論