某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算

1、某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算電力系統(tǒng)綜合設(shè)計(jì) 任務(wù)書、設(shè)計(jì)題目：某化纖廠降壓變電所電氣設(shè)計(jì)二、設(shè)計(jì)要求：根據(jù)本廠用電負(fù)荷，并適當(dāng)考慮生產(chǎn)的發(fā)展，按安全可靠，技術(shù)先進(jìn)，經(jīng)濟(jì) 合理的要求，確定工廠變電所的位置與型式，通過負(fù)荷計(jì)算，確定主變壓器臺(tái)數(shù) 及容量，進(jìn)行短路電流計(jì)算，選擇變電所的主接線及高、低壓電氣設(shè)備，選擇整 定繼電保護(hù)裝置，最后按要求寫出設(shè)計(jì)計(jì)算說明書，繪出設(shè)計(jì)圖紙。三、設(shè)計(jì)資料設(shè)計(jì)工程項(xiàng)目情況如下（1）工廠總平面圖見圖1,辦公樓圖 1 某化學(xué)纖維廠總平面圖（1cm=200m）（2）工廠負(fù)荷數(shù)據(jù)：本工廠多數(shù)車間為3班制，年最大負(fù)荷利用小時(shí)數(shù)6400小時(shí)。本廠負(fù)荷統(tǒng)計(jì)

2、資料見表1，學(xué)生組合方案見表2。表 1某化學(xué)纖維廠負(fù)荷情況表序號(hào)車間設(shè)備名稱安裝容量（kW）Kdtancos計(jì)算負(fù)荷甲乙丙丁P（kW）Q （kvar） S（ kVA）1紡煉車間紡絲機(jī)1801502002200.800.780.7885筒絞機(jī)624030560.750.750.8000烘干機(jī)788085700.751.020.7001某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算脫水機(jī)201512180.600.800.7809通風(fēng)機(jī)2002201802400.700.750.8000淋洗機(jī)1456220.750.780.7885變頻機(jī)9008008409500.800.700.8192傳送

3、機(jī)423840300.800.700.8192小計(jì)16062原液車間照明10121040120011600.750.700.8192小計(jì)3酸站照 明3042602003100.650.700.8192小計(jì)4鍋爐房 照明2803202902700.750.750.8000小計(jì)5排毒車間照明1861601801400.700.600.8575小計(jì)6其他車間照明3802403002400.700.750.8000小計(jì)78910全廠計(jì) 算負(fù)荷 總計(jì)1112表 2學(xué)生組合方案序號(hào)紡煉車間原液車間酸站鍋爐房排毒機(jī)房其他附屬車間1ABCDEF2ABDEFC3ABEFCD4ABFCDE5BACDEF6BADE

4、FC7BAEFCD8BAFCDE某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算(3)供電電源情況：按與供電局協(xié)議，本廠可由東南方19公里處的城北變 電所110/38.5/11kV,50 MVA變壓器供電，供電電壓可任選。另外，與本廠相距5公里處的其他工廠可以引入10kV線路做備用電源，但容量只能滿足本廠負(fù)荷 的30%重要負(fù)荷，平時(shí)不準(zhǔn)投入，只在本廠主要電源故障或檢修時(shí)投入。（4）電源的短路容量 （城北變電所） ：35kV母線的出線斷路器斷流容量為1500MVA；10kV母線的出線斷路器斷流容量為350 MVA。（5） 供電局要求的功率因素：當(dāng)35kV供電時(shí)，要求工廠變電所高壓側(cè)cos0.9

5、;當(dāng)以10kV供電時(shí)，要求工廠變電所高壓側(cè)cos0.95。（6） 電費(fèi)制度：按兩部制電費(fèi)計(jì)算。變壓器安裝容量每1kVA為15元/月， 動(dòng)力電費(fèi)為0.3元/kWh，照明電費(fèi)為0.55元/（kWgh）。（7） 氣象資料：本廠地區(qū)最高溫度為38C，最熱月平均最高氣溫29C，最 熱月地下0.8m處平均溫度為22C，年主導(dǎo)風(fēng)向?yàn)闁|風(fēng)，年雷暴雨日數(shù)為20天。（8）地質(zhì)水文資料：本廠地區(qū)海拔60m，地層以砂黏土為主，地下水位為2m。四、設(shè)計(jì)任務(wù)（一） 設(shè)計(jì)計(jì)算說明書設(shè)計(jì)計(jì)算的內(nèi)容，可按下列建議的標(biāo)題及其順序，逐項(xiàng)計(jì)算并加以說明。在各一級(jí)標(biāo)題之下，根據(jù)內(nèi)容層次再擬定小標(biāo)題，組成一個(gè)合理的文本框架，例如:一、各

6、車間計(jì)算負(fù)荷和無功補(bǔ)償二、各車間變電所的設(shè)計(jì)選擇三、工廠總降壓變電所及接入系統(tǒng)設(shè)計(jì)四、短路電流計(jì)算五、變電所高低壓電氣設(shè)備的選擇六、繼電保護(hù)的配置七、收獲和體會(huì)八、參考文獻(xiàn)（二） 設(shè)計(jì)圖紙1、工廠變電所設(shè)計(jì)計(jì)算用電氣主接線簡圖2、變電所供電平面布置圖某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算某化纖降壓變電所電氣設(shè)計(jì)MATLAB計(jì)算程序(以第三組丁數(shù)據(jù)為例)clear all ;clc;pe=220;56;70;18;240;22;950;30;pe2=1160;310;270;140;240;PP30=0;QQ30=0;Kp=0.9;Kg=0.95;kd=0.8;0.75;0.75;0

7、.6;0.7;0.75;0.8;0.8;kd2=0.75;0.65;0.75;0.7;0.7;tan 1=0.780.75 1.02 0.8 0.75 0.78 0.7 0.7 ;ta n2=0.70.7 0.75 0.60cos 仁 cos(ata n(ta n1)cos2=cos(ata n(ta n2)P30=(pe.*kd)P302=(pe2.*kd2)Q30=(P30.*ta n1)Q302=(P302.*ta n2)for i=1:size(pe);PP30=PP30+P30(i); QQ30=QQ30+Q30(i);endFP=PP30*Kp;FQ=QQ30*Kg;SS1=(FP

8、A2+FQA2)A(1 /2);FP_FQ=FP FQF2P=P302F2Q=Q302%第二部分%1 紡織 2 原液 3 酸 4 鍋 5 排毒 6 其他%方案 A1 B2 C5 D6 E3 F4%變電所 1BF 變電所 2A 變電所 3CDEFP_ALL=FP F2P;FQ_ALL=FQ F2Q;cs1=0.7;FP_Psum=sum(FP_ALL);FP_Qsum=sum(FQ_ALL);FP_Ssum=sqrt(FP_Psum)A2+(FP_ Qsum)A2);%變電所 1BD1P30=Kp*(FP_ALL (2)+FP_ALL(4);BD1Q30=Kg*(FQ_ALL (2)+FQ_AL

9、L (4);BD1P30_BD1Q30=BD1P30 BD1Q30BD1QC_1=400;BD1QC1=BD1Q30-BD1QC_1;cosa1=BD1P30/sqrt(BD1P30)A2+(BD1QC1)A2);S 仁 sqrt(BD1P30)A2+(BD1QC1)A2);SNT1=cs1*S1;%選 S7_800/10BD1_deda_p0=1.54;BD1_deda_pk=9.9;BD1_Uk=4;BD1_l0=1.5; n=1;BD1_SN=800; BD1_S30=1/2*S1BD1_dedaPT=n*BD1_deda_p0+1/ n*BD1_deda_pk*(BD1_S30/BD1

10、_SN)A2;BD1_dedaQT=n*BD10/100*BD1_SN+1/ n*BD1_Uk/100*BD1_SN*(BD1_S30/BD1_SN)A2;BD1_dedaPT_BD1_dedaQT=BD1_dedaPT BD1_dedaQT%變電所 2BD2P30=FP_ALL(1);BD2Q30=FQ_ALL(1);format bankBD2P30_BD2Q30=(BD2P30 BD2Q30)0.75;某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算BD2QC_1=400; %補(bǔ)償為 400 % 常數(shù)選擇BD2QC1=BD2Q30-BD2QC_1;cosa2=BD2P30/sqrt(B

11、D2P30)A2+(BD2QC1f2);S2=sqrt(BD2P30)A2+(BD2QC1F2);SNT2=cs1*S2;%選 S7_1000/10BD2_deda_p0=1.8;BD2_deda_pk=11.6;BD2_Uk=4;BD2_I0=1.2;n=1;BD2_SN=1000;%常數(shù)選擇BD2_S30=1/2*S2BD2_dedaPT=n*BD2_deda_pO+1/ n*BD2_deda_pk*(BD2_S30/BD2_SNF2;BD2_dedaQT=n*BD2_I0/100*BD2_SN+1/n*BD2_Uk/100*BD2_SN*(BD2_S30/BD2_SN)A2;BD2_de

12、daPT_BD2_dedaQT=BD2_dedaPT BD2_dedaQT%變電所 3BD3P30=Kp*(FP_ALL(3)+FP_ALL(5)+FP_ALL(6);BD3Q30=Kg*(FQ_ALL(3)+FQ_ALL (5)+FQ_ALL(6);BD3P30_BD3Q30=BD3P30 BD3Q30BD3QC_1=200;BD3QC1=BD3Q30-BD3QC_1;cosa3=BD3P30/sqrt(BD3P30)A2+(BD3QC 1)A2);S3=sqrt(BD3P30)A2+(BD3QC1)A2); SNT3=cs1*S3;%選 S7_400/10BD3_deda_p0=0.92;

13、BD3_deda_pk=5.8;BD3_Uk=4;BD3_I0=1.9;n=1;BD3_SN=400;常數(shù)選擇BD3_S30=1/2*S3;BD3_dedaPT=n*BD3_deda_p0+1/n*BD3_deda_pk*(BD3_S30/BD3_SN)A2;BD3_dedaQT=n*BD3_I0/100*BD3_SN+1/n*BD3_Uk/100*BD3_SN*(BD3_S30/BD3_SN)A2;BD3_dedaPT_BD3_dedaQT=BD3_dedaPT BD3_dedaQT%第三部分總降壓BD4P30=2*BD1_dedaPT+BD1P30+2*BD2_dedaPT+BD2P30+

14、2*BD3_dedaPT+BD3P30;BD4Q30=BD1QC1+2*BD1_dedaQT+BD2QC1+2*BD2_dedaQT+BD3QC1+2*BD3_dedaQT;BD4P30_BD4Q30=BD4P30 BD4Q30 all_P=Kp*BD4P30;all_Q=Kg*BD4Q30; all_P_all_Q=all_P all_QBD4QC_1=0; %補(bǔ)償為 0 % 常數(shù)選擇cosa4=BD4P30/sqrt(all_P)A2+(all_Q-BD4QC_1)A2);S4=sqrt(all_P)A2+(all_Q-BD4QC_1)A2);SNTT=cs1*S4; BD4_S30=1/

15、2*S4;BD4_deda_p0=3.4;BD4_deda_pk=19.8;BD4_Uk=6.5;BD4_I0=1.1;n=1;BD4_SN=200 0; %常數(shù)選擇BD4_dedaPT=n*BD4_deda_p0+1/n*BD4_deda_pk*(BD4_S30/BD4_SN)A2;BD4_dedaQT=n*BD4_I0/100*BD4_SN+1/n*BD4_Uk/100*BD4_SN*(BD4_S30/BD4_SN)A2;BD4_dedaPT_BD4_dedaQT=BD4_dedaPT BD4_dedaQT s1_s2_s3_s4_cosa1_cosa2_cosa3_cosa4=S1S2

16、S3 S4 cosa1 cosa2 cosa3 cosa4%4.1 變電所線路選擇 line1P30=1/2*BD1P30;line1Q30=1/2*(BD1Q30-BD1QC_1);%選 S7_2000/10%BD1某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算BYA1_P30=line1P30+BD1_dedaPT;BYA1_Q30=line1Q30+BD2_dedaQT;BYA1_S=sqrt(BYA1_P30)A2+(BYA1_Q30)A2);BYA1_l30=BYA1_S/(sqrt(3)*10);Jec1=0.9;Aec1=BYA1_I30/Jec1;LJ_lai=170;LJ

17、_r0=0.96;LJ_x0=0.34;theta1=29;LJ_K=sqrt(70-theta1)/(70-25);LJ_llai=LJ_K*LJ_lailine1P30_Q30_BYA1P30_BYA1Q30_llai=line1P30LJ_llailine2P30=1/2*BD2P30;line2Q30=1/2*(BD2Q30-BD2QC_1);BYA2_P30=line2P30+BD2_dedaPT;BYA2_Q30=line2Q30+BD2_dedaQT;BYA2_S=sqrt(BYA2_P30)A2+(BYA2_Q30)A2);BYA2_I30=BYA2_S/(sqrt(3)*10

18、);line2P30_Q30_BYA2P30_BYA2Q30_l30=line2P30 line2Q30 BYA2_P30 BYA2_Q30 BYA2_I30Jec2=0.9;Aec2=BYA2_I30/Jec2;%選 LJ_35LJ2_Iai=170;LJ2_r0=0.96;LJ2_x0=0.34;theta2=29;L2=0.32;%常數(shù)選擇LJ2_K=sqrt(70-theta2)/(70-25);LJ2_IIai=LJ2_K*LJ2_Iai;RL2=LJ2_r0*L2;XL2=LJ2_x0*L2;line2_dedaPL2=3*(BYA2_I30)A2*RL2/1000;line2_d

19、edaQL2=3*(BYA2_I30)A2*XL 2/1000;first_line2P30=line2P30+line2_dedaPL2;first_line2Q30=line2Q30+line2_d edaQL2;line2dedaPL2_line2dedaQL2_firstline2P30_firstline2Q30=line2_dedaPL2line2_dedaQL2 first_line2P30 first_line2Q30%BD3 line3P30=1/2*BD3P30;line3Q30=1/2*(BD3Q30-BD3QC_1);BYA3_P30=line3P30+BD3_deda

20、PT;BYA3_Q30=line3Q30+BD3_dedaQT;BYA3_S=sqrt(BYA3_P30)A2+(BYA3_Q30)A2);BYA3_I30=BYA3_S/(sqrt(3)*10);line3P30_line3Q30_BYA3_P30_BYA3_Q30=line3P30 line3Q30 BYA3_P30BYA3_Q30Jec3=0.9;%常數(shù)選擇Aec3=BYA3_I30/Jec3;%選 LJ_35LJ3_Iai=135;LJ3_r0=1.33;LJ3_x0=0.35;theta3=29;L3=0.64;%常數(shù)選擇LJ3_K=sqrt(70-theta3)/(70-25);L

21、J3_IIai=LJ3_K*LJ3_Iai;%BYA3_I30RL3=1.33*L3;XL3=0.35*L3;line3_dedaPL3=3*(BYA3_I30)A2*RL3/1000;line3_dedaQL3=3*(BYA3_I30)A2*XL3/1000;first_line3P30=BYA3_P30+line3_dedaPL3;first_line3Q30=BYA3_Q30+line3_d edaQL3;line3deda_U3=(first_line3P30*LJ3_r0+first_line3Q30*LJ3_x0)/10*L3/1000line3deda_U3_baifen=lin

22、e3deda_U3/10*100;line3_dedaPL3_dedaQL3_firstline3P30_firstline3Q30_U3baifen=line3_ded aPL3 line3_dedaQL3first_line3P30 first_line3Q30 line3deda_U3_baifen %4.2 聯(lián)絡(luò)線 10kvlianluo_P30=FP_Psum*0.3;lianluo_Q30=FP_Qsum*0.3;lianluo_S=sqrt(lianl uo_P30F2+(lia nluo_Q30F2);lianluo_I=lianluo_S/(sqrt(3)*10);lianl

23、uo_Jec=0.9;%常數(shù)選擇lianluo_Aec=lianluo_I/lianluo_Jec;lianluo_r0=1.33;lianluo_x0=0.35;theta4=29;lianluo_Iai=135;L4=5;%常數(shù)選擇lianluo_K=sqrt(70-theta4)/(70-25);lianluo_IIai=lianluo_K*lianluo_Ia i;RL4=1.33*L4;XL4=0.35*L4;lian luo_dedaPL4=3*(lia nluoF2*RL4;lia nluo_dedaQL4=3*(lia nluoF2*XL4;first_lianluoP30=l

24、ianluo_P30+lianluo_dedaPL4;first_lianluoQ30=lianluo _Q30+lianluo_dedaQL4;%選 LJ_35%常數(shù)選擇%BYA1_l30line1Q30 BYA1_P30 BYA1_Q30%BD2某化纖廠降壓變電所電氣設(shè)計(jì)MATLAB全程輔助計(jì)算lianluodeda_U4=(lianluo_P30*lianluo_r0+lianluo_Q30*lianluo_x0)/(10)*L 4/1000;lianluodeda_U4_baifen=lianluodeda_U4/10*100;%4.3 35kv 線路選擇Line35kv_P=1/2*

25、all_P;Line35kv_Q=1/2*(all_Q-BD4QC_1);Line35kv_S=sqrt(Lin e35kv_P)A2+(Li ne35kv_QF2);Line35kv_dedaP=0.015*Line35kv_S;Line35kv_dedaQ=0.06*Line35kv_S;Line35kv_P2=Line35kv_P+Line35kv_dedaP;Line35kv_Q2=Line35kv_Q+Line35kv _dedaQ;Line35kv_S2=sqrt(Line35kv_P2)A2+(Line35kv_Q2)A2);Line35kv_I=Line35kv _S2/(sq

26、rt(3)*35);Line35kv_Jec=0.9;Line35kv_Aec=Line35kv_I/Line35kv_Jec;%常數(shù)選擇Line35kv_r0=0.91;Line35kv_x0=0.433;Line35kv_theta=29;Line35kv_Iai=170 ;Line35kv_L=19;Line35kv_K=sqrt(70-Line35kv_theta)/(70-25);Line35kv_IIai=Line35kv_K *Line35kv_Iai;Line35kv_RL=Line35kv_r0*Line35kv_L;Line35kv_XL=Line35kv_x0*Line3

27、5kv_LLine35kv_dedaPL=3*(Line35kv_I)A2*Line35kv_RL/1000;Line35kv_dedaQL=3*( Line35kv_I)A2*Line35kv_XL/1000;first_Line35kvP30=Line35kv_P2+Line35kv_dedaPL;first_Line35kvQ30=Line3 5kv_Q2+Line35kv_dedaQL;Line35kvdeda_U=(first_Line35kvP30*Line35kv_r0+first_Line35kvQ30*Line3 5kv_x0)/35*Line35kv_L/1000;Line

28、35kvdeda_U_baifen=Line35kvdeda_U/35*100;%5 短路電流計(jì)算 jiangya35kv_Sd=100;jiangya35kv_Uav=37;jiangya35kv_Soc=1500;jiangya35kv_Id=jiangya35kv_Sd/(sqrt(3)*jiangya35kv_Uav);jy35_X1=jiangya35kv_Sd/jiangya35kv_Soc;xian0_x=0.433;xian0_L=19;jy35_X2=xian0_x*xian0_L*jiangya35kv_Sd/(jiangya35kv_Uav)A2;jy35_X3=BD4_Uk/100*jiangya35kv_Sd/2;jy35_X4=BD3_Uk/100*jiangya35kv_Sd/0.8;jy35_Xall=jy35_X1+1/2*jy35_X2;jy35_Ik3=jiangya35kv_Id/jy35_Xall;jy35_ish3=2.55*jy35_Ik3;jy35_Ish3=1.51*jy35_Ik3;j