計(jì)算機(jī)二級(jí)C語(yǔ)言題庫(kù)之程序填空

1、計(jì)算機(jī)二級(jí)C語(yǔ)言題庫(kù)之程序填空 找Armstrong（水仙花）數(shù)：371=3*3*3+7*7*7+1*1*1#include <stdio.h>#include<math.h>void main() int i,a,b,c;for(i=100;i<=999;i+) a=i/100;_1_ / b=i%100/10;c=i%10;if (_2_) / a*a*a+b*b*b+c*c*c = = i printf("%d is a Armstrong number!n",i);輸入1個(gè)整數(shù)后，

2、輸出該數(shù)的位數(shù)。（例：輸入3214則輸出4，輸入-23156則輸出5）。#include <stdio.h>void main() int n,k=0;scanf("%d",&n);while( _1_ ) / n!=0k+;_2_; / n=n/10printf("%dn",k);求輸入的整數(shù)各位數(shù)字之和，如輸入234則輸出9，輸入-312則輸出6。#include <stdio.h>#include <math.h>vo

3、id main()int n,s=0;scanf("%d",&n);_ 1 _ / if (n<0) n=-n;while(n!=0) _ 2 _ / s+=n%10;n=n/10;printf("%dn",s);調(diào)用函數(shù)f，將一個(gè)整數(shù)首尾倒置。例如：若程序輸入12345，則輸出54321；若程序輸入-34567，則輸出-76543。#include <stdio.h>#include <math.h>long f(long n) lon

4、g m,y=0; m=fabs(n);while(m!=0) y=y*10+m%10; _1_ / m=m/10 ；if(n>=0) return y;else _2_ / return -y ;void main()printf("%ldt",f(12345); printf("%ldn",f(-34567);調(diào)用函數(shù)f，從字符串中刪除所有的數(shù)字字符。#include <stdio.h>#include <string.h>#include &

5、lt;ctype.h>void f(char *s) int i=0;while(si!='0')if(isdigit(si) _1_(s+i,s+i+1); / strcpy_2_ i+; / elsevoid main() char str80; gets(str); f(str); puts(str);調(diào)用find函數(shù)在輸入的字符串中查找是否出現(xiàn)"the"這個(gè)單詞。如果查到返回出現(xiàn)的次數(shù)，如果未找到返回0。#include <stdio.h>int find(char *str)

6、 char *fstr="the"int i=0,j,n=0; while (stri!='0')for(_1_) / j=0; j<3; j+if (strj+i!=fstrj) break;if (_2_) n+; / j>=3i+;return n;void main() char a80;gets(a);printf("%d",find(a);輸入的一個(gè)小寫(xiě)字母，將字母循環(huán)后移5個(gè)位置后輸出。例如："a"變成&q

7、uot;f"，"w"變成"b"。#include <stdio.h>void main() char c;c=getchar();if(_1_) / c>='a'&&c<='u'c=c+5;elseif (c>='v' && c<='z&#3

8、9;)_2_ / c=(c-'a'+5)%26+'a'putchar(c);將字符串s中所有的字符'c'刪除。#include <stdio.h>void main() char s80;int i,j;gets(s);for(i=j=0; _1_; i+) / si != '0'if(si != 'c') sj=si;_2_ / j+; sj='0'puts(s);對(duì)x=1，

9、2，10，求f(x)=x*x-5*x+sin(x)的最大值。#include <stdio.h>#include <math.h>#define f(x) x*x-5*x+sin(x)void main() int x; float max;_1_ / max=f(1);for(x=2;x<=10;x+)_2_ / if (f(x)>max) max=f(x);printf("%fn",max);輸入三個(gè)整數(shù)，按由小到大的順序輸出這三個(gè)數(shù)。#include <s

10、tdio.h>void swap(_1_) / int *pa, int *pb /*交換兩個(gè)數(shù)的位置*/int temp;temp = *pa;*pa = *pb;*pb = temp;void main() int a,b,c,temp;scanf("%d%d%d",&a,&b,&c);if(a>b)swap(&a,&b);if(b>c)swap(&b,&c);if(_2_) / if ( a&

11、gt;b )swap(&a,&b);printf("%d,%d,%d",a,b,c);調(diào)用函數(shù)f，去除數(shù)組中的負(fù)數(shù)，輸入數(shù)組x7，輸出結(jié)果為：1 3 4 6#include <stdio.h> / 數(shù)組元素的刪除void f(int *a,int *m) int i, j ;for(i=0;i<*m;i+)if(ai<0) for(j=i-;j<*m-1;j+) aj=aj+1;_1_; / *m = *m-1;void main() int i,n=7,x

12、7=1,-2,3,4,-5,6,-7;_2_; / f (x, &n) ;for(i=0;i<n;i+) printf("%5d",xi);printf("n");調(diào)用函數(shù)f計(jì)算代數(shù)多項(xiàng)式1.1+2.2*x+3.3*x*x+4.4*x*x*x+5.5*x*x*x*x當(dāng)x=1.7時(shí)的值。#include <stdio.h>float f(float, float*, int);void main() float b5=1.1, 2.2, 3.3, 4.4, 5.5 ;

13、printf("%fn", f(1.7,b,5) );float f( _1_ ) / float x, float *a, int n float y=a0, t=1; int i;for(i=1; i<n; i+) t=t*x; y=y+ai*t; _2_ / return y;分別統(tǒng)計(jì)字符串中英文字母、數(shù)字、和其他字符出現(xiàn)的次數(shù)。#include <stdio.h>#include <ctype.h>void main() char a80; int n3=0, i; gets(a)

14、 ;_1_ / for ( i=0; ai!='0' i+)if (tolower(ai)>='a' && tolower(ai)<='z') /*統(tǒng)計(jì)字母?jìng)€(gè)數(shù)*/n0+; else if (_2_) /*統(tǒng)計(jì)數(shù)字個(gè)數(shù)*/ / ai>='0' && ai<='9'n1+;elsen2+;for(i=0;i&lt

15、;3;i+) printf("%dn",ni);將輸入的十進(jìn)制整數(shù)n通過(guò)函數(shù)DtoH函數(shù)轉(zhuǎn)換為十六進(jìn)制數(shù)，并將轉(zhuǎn)換結(jié)果以字符串形式輸出。（例如：輸入十進(jìn)制數(shù)79，將輸出十六進(jìn)制4f。）# include <stdio.h># include <string.h>char trans(int x)if(x<10) return '0'+x;else _1_ / return 'a'+x-10;int DtoH(int n,cha

16、r *str)int i=0;while(n!=0)_2_ / stri=trans(n%16);n/=16;i+; return i-1;void main()int i,k,n;char *str; scanf("%d",&n);k=DtoH(n,str);for (i=0;i<=k;i+) printf("%c",strk-i);將輸入的十 進(jìn)制正整數(shù)n通過(guò)函數(shù)Dec2Bin轉(zhuǎn)換為二進(jìn)制數(shù)，并將轉(zhuǎn)換結(jié)果輸出。#include <stdio.h>void Dec

17、2Bin(int m)int bin32,j;for(j=0;m!=0;j+)binj= _1_; / m%2m=m/2;for( ; j!=0; j- )printf("%d", _2_ ); / binj-1void main()int n;scanf("%d",&n);Dec2Bin(n);數(shù)列的第1、2項(xiàng)均為1，此后各項(xiàng)值均為該項(xiàng)前二項(xiàng)之和。計(jì)算數(shù)列第30項(xiàng)的值。#include <stdio.h>_1_ / long f(int n); 或者 long f(int);v

18、oid main() printf("%ldn",f(30) ;long f(int n) if( _2_ ) / n=1 | n=2return 1;elsereturn f(n-1)+f(n-2);該程序計(jì)算四位學(xué)生的平均成績(jī)，保存在結(jié)構(gòu)中，然后列表輸出這些學(xué)生的信息。#include <stdio.h>struct STUDENT char name16;int math;int english;int computer;int average;void GetAverage(struct STUDENT *pst) /*

19、計(jì)算平均成績(jī) */ int sum=0;sum = _1_; / pst->math+pst->english+pst->computerpst->average = sum/3;void main() int i;struct STUDENT st4="Jessica",98,95,90,"Mike",80,80,90,"Linda",87,76,70,"Peter",90,100,99;for

20、(i=0;i<4;i+) GetAverage(_2_); / st + iprintf("NametMathtEnglishtComputAveragen");for(i=0;i<4;i+) printf("%st%dt%dt%dt%dn",,sti.math,sti.english,puter,sti.average);輸入m、n（要求輸入數(shù)均大于0）。輸出它們的最大公約數(shù)。#include<stdio.h>void main() int m, n, k;while ( scanf("%d%d", &m, &n), _1_ ); / m<=0|n<=0for (_2_ ; n%k!=0 | m%k!=0 ; k-) ; / k=m>n?n:mprintf("%dn"