CISCOCCNA網(wǎng)絡(luò)工程師題庫

1、Evaluation Warning: The document was created with Spire.Doc for .NET.培訓(xùn)大講堂官方Y(jié)Y 頻道：3660mCCNA題庫考試代號： 640-802考試時間：英文1110+30=1400分鐘通過分?jǐn)?shù)： 8225題庫版本： V1104.4鴻鵠論壇招招募CCCNA、CCCNPP答疑講講師答疑地點：鴻鵠官官方Y(jié)YY頻道336600鴻鵠大講堂堂：htttp:/m/thhreaad-4461772-11-1.htmmlCCNA題題庫戰(zhàn)報報交流QQQ群：144428881277 （5500人人超級群群）CCNA題題庫戰(zhàn)報報交流區(qū)區(qū)： hhtt

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4、正正版題庫庫；2011.8.11 增加加每日新新題，修修訂部分分錯誤。2012.2.114 情情人節(jié)版版增加5道新新題，分分別是5519、5520、5521、5522、5523題題修改1766題、3375題題、4443題、4482題題答案錯錯誤修改59題題、888題、4453題題、1007題、2270題題注釋錯錯誤增加個別疑疑難拖圖圖題注釋釋，優(yōu)化化實驗題題=QUESTTIONN 1When youu arre lloggged intto aa swwitcch, whiich proomptt inndiccatees tthatt yoou aare in priivillegeed m

5、modee?(當(dāng)您登錄錄到交換換機，哪哪種提示示表明你你在特權(quán)權(quán)模式？)A. %B. C. D. $E. #Answeer: ESectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:特權(quán)模式就就是#提提示符QUESTTIONN 2Whichh coommaand shoows sysstemm haardwwaree annd ssofttwarre vverssionn innforrmattionn?(哪些命令令顯示系系統(tǒng)硬件件和軟件件的版本本信息？)A. shhow conn

6、figguraatioonB. shhow envviroonmeentC. shhow invventtoryyD. shhow plaatfoormE. shhow verrsioonAnsweer: ESectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:查看系統(tǒng)的的軟件和和硬件信信息使用用的命令令是shhow verrsioonQUESTTIONN 3Ciscoo Caatallystt swwitcchess CAAT1 andd CAAT2 havve aa coonn

7、eectiion bettweeen tthemm ussingg poortss FAA0/113. An 8022. 11Q truunk is connfiggureed bbetwweenn thhe ttwo swiitchhes. Onn CAAT1, VLLAN 10 is choosenn ass naativve, butt onn CAAT2 thee nattivee VLLAN is nott sppeciifieed.WWhatt wiill happpenn inn thhis sceenarrio?(思科 CCataalysst 交交換機 CATT1 和和 CAA

8、T2 有它們們之間的的連接使使用端口口 FAA0/13。兩兩個交換換機之間間用8022.1QQ中繼配配置，CATT1做為為VLAAN100的主機機，但在在 CAAT2 上的本本地 VVLANN 未指指定。在在這種情情況下會會發(fā)生什什么？)A. 8002.11Q ggiannts fraamess coouldd saaturratee thhe llinkk.B. VLLAN 10 on CATT1 aand VLAAN 11 onn CAAT2 willl ssendd unntagggedd frramees.C. A nattivee VLLAN missmattch errror me

9、sssagge wwilll apppeaar.D. VLLAN 10 on CATT1 aand VLAAN 11 onn CAAT2 willl ssendd taaggeed fframmes.Answeer: CSectiion: Chhaptter 10: VLLANExplaanattionn/Reeferrencce:如果兩邊nnatiive不不匹配的的話.sswittch將將報naativve不匹匹配的日日志信息息QUESTTIONN 4Whichh coommaand wouuld corrrecctlyy coonfiigurre aa seeriaal pportt on

10、n a rouuterr wiith thee laast usaablee hoost adddresss iin tthe 1922.2116.332.332/229 ssubnnet?（哪個命令令正確地地將最后后的可用用主機地地址，1192.2166.322.322/29 子網(wǎng)的的路由器器上配置置的串行行端口？）A. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.38 2555.2555.2255.2400B. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.39 2555.25

11、55.2255.2244C. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.63 2555.2555.2255.2488D. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.39 2555.2555.2255.2488E. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.63 2555.2555.2255.2488F. Roouteer(cconffig-if)# iip aaddrresss 1992.2216.32.38 255

12、5.2555.2255.2488Answeer: FSectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:192.2216.32.32/29它它的塊大大小為88掩碼為為2555.2555.2255.2488地址范范圍為1192.2166.322.322-399QUESTTIONN 5The nnetwworkk deefauult gattewaay aappllyinng tto aa hoost by DHCCP iis 1192.1688.5.33/28. Whhichh o

13、pptioon iis tthe vallid IP adddresss oof tthiss hoost?(應(yīng)用到到由 DDHCPP 主機機的網(wǎng)絡(luò)絡(luò)默認(rèn)網(wǎng)網(wǎng)關(guān)是 1922.1668.55.333/228。哪哪個選項項是有效效的主機機IP 地址？)A. 1992.1168.5.555B. 1992.1168.5.447C. 1992.1168.5.440D. 1992.1168.5.332E. 1992.1168.5.114Answeer: CSectiion: Chhaptter 3: IP Adddresssinng aand VLSSMExplaanattionn/Reeferrencc

14、e:考點：考查查VLSSM192.1168.5.333/228所在在網(wǎng)段的的范圍是是1922.1668.55.322-1192.1688.5.47/28A：超出范范圍B：廣播地地址C：正確D：網(wǎng)絡(luò)號號E：超出范范圍QUESTTIONN 6Whichh twwo aaddrressses cann bee asssiggnedd too a hosst wwithh a subbnett maask of 2555.2555.2254.0? (Chhoosse ttwo.)哪兩個個地址可可以分配配給與子子網(wǎng)掩碼碼 2555.2255.2544.0 的主機機？A. 1B. 1886.554.33.

15、0C. 1775.333.33.2555D. 266.355.2.2555E. 177.355.366.0Answeer: BDSectiion: Chhaptter 3: IP Adddresssinng aand VLSSMExplaanattionn/Reeferrencce:考點：考查查VLSSMA：網(wǎng)絡(luò)號號B/D：正正確C：廣播地地址E：網(wǎng)絡(luò)號號QUESTTIONN 7The nnetwworkk addminnisttrattor hass asskedd yoou tto cchecck tthe staatuss off thhe wworkkstaatioonss IPP s

16、ttackk byy piingiing thee looopbaack adddresss. Whiich adddresss wwoulld yyou pinng tto pperfformm thhis tassk?網(wǎng)絡(luò)管理理員已要要求您通通過 ppingg 環(huán)回回地址檢檢查工作作站的 IP 堆棧的的狀態(tài)。您您要執(zhí)行行此任務(wù)務(wù)將 ppingg 哪個個地址？A. 1B. 1227.00.0.1C. 1992.1168.0.11D. 23Answeer: BSectiion: Chhaptter 3: IP Adddresssinng aand VLSSM

17、Explaanattionn/Reeferrencce:考點：使用用pinng來檢檢測主機機的IPP棧。ping 121實現(xiàn)。QUESTTIONN 8Worksstattionn A hass beeen asssignned an IP adddresss oof 144/288. WWorkkstaatioon BB haas bbeenn asssiggnedd ann IPP adddresss oof 1000/228. Thee twwo wworkkstaatioons aree coonneecteed wwithh a

18、strraigght-thrrouggh ccablle. Atttemppts to pinng bbetwweenn thhe hhostts aare unssucccesssfull. WWhatt twwo tthinngs cann bee doone to alllow commmunnicaatioons bettweeen thee hoostss? (Chooosee twwo.)A 工作作站已分分配 IIP 地地址為 1924/28。BB 工作作站已分分配 IIP 地地址為 19100/288。兩臺臺工作站站與直通通電纜連連接。在在主機之之

19、間 ppingg 不成成功。允允許在主主機之間間的通信信，可以以做兩件件事情？（選擇擇兩個）。A. Reeplaace thee sttraiightt-thhrouugh cabble witth aa crrosssoveer ccablle.B. Chhangge tthe subbnett maask of thee hoostss too /225.C. Chhangge tthe subbnett maask of thee hoostss too /226.D. Chhangge tthe adddresss oof WWorkkstaatioon AA too 1992.00.

20、2.15.E. Chhangge tthe adddresss oof WWorkkstaatioon BB too 1992.00.2.1111.Answeer: ABSectiion: Chhaptter 3: IP Adddresssinng aand VLSSMExplaanattionn/Reeferrencce:考點：同構(gòu)構(gòu)設(shè)備使使用交叉叉線，兩兩端的IIP需要要在同一一個子網(wǎng)網(wǎng)。A：使用交交叉線替替換現(xiàn)有有的直通通線。正正確。B：修改掩掩碼為225位，正正確。C：修改掩掩碼為226為，錯錯誤。不不能使他他們在同同一個子子網(wǎng)。D/E：錯錯誤，都都不能使使他們在在同一個個子網(wǎng)。QUE

21、STTIONN 9Your ISPP haas ggiveen yyou thee adddreess 2/229 tto aassiign to youur rroutters iinteerfaace. Thhey havve aalsoo givven youu thhe ddefaaultt gaatewway adddresss oof 27. AAfteer yyou havve cconffiguuredd thhe aaddrresss, tthe rouuterr iss unaablee too piing anyy reemott

22、e ddeviicess. WWhatt iss prreveentiing thee roouteer ffromm piingiing remmotee deevicces?(您的 ISPP 給你你要分配配給您的的路由器器接口地地址 26/229。他他們還授授予您是是 2 的默認(rèn)認(rèn)網(wǎng)關(guān)地地址。您您已配置置了地址址后，路路由器是是無法 pinng 任任何遠程程設(shè)備。什什么在阻阻礙 ppinggingg 遠程程設(shè)備的的路由器器？)A. Thhe ddefaaultt gaatewway is nott ann adddreess on thiis ssubnnet.B.

23、Thhe ddefaaultt gaatewway is thee brroaddcasst aaddrresss foor tthiss suubneet.C. Thhe IIP aaddrresss iss thhe bbroaadcaast adddresss ffor thiis ssubnnet.D. Thhe IIP aaddrresss iss ann innvallid claass D mmultticaast adddresss.Answeer: BSectiion: Chhaptter 3: IP Adddresssinng aand VLSSMExplaanattion

24、n/Reeferrencce:考點：考查查VLSSM。/29所所在網(wǎng)段段的范圍圍是：20-27/299A：默認(rèn)網(wǎng)網(wǎng)關(guān)不屬屬于這個個子網(wǎng)，錯錯誤B：默認(rèn)網(wǎng)網(wǎng)關(guān)是這這個子網(wǎng)網(wǎng)的廣播播地址，正正確C：這個地地址是子子網(wǎng)的廣廣播地址址，錯誤誤D：這個地地址是組組播地址址，錯誤誤。QUESTTIONN 100Whichh coommaand is useed tto ccopyy thhe cconffiguurattionn frrom RAMM innto NVRRAM?哪個命令令用于從從RAMM復(fù)制到到NVRRAM的的配置A. coopy runnnin

25、ng-cconffig staartuup-cconffigB. coopy staartuup-cconffig: ruunniing-connfigg:C. coopy runnninng cconffig staartuup cconffigD. coopy staartuup cconffig runnninng cconffigE. wrritee teermiinallAnsweer: ASectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:QUESTTIONN 111

26、Whichh coommaand is useed tto lloadd a connfigguraatioon ffromm a TFTTP sservver andd meergee thhe cconffiguurattionn innto RAMM?(哪些命命令用于于從 TTFTPP 服務(wù)務(wù)器加載載配置或或合并到到 RAAM 的的配置？)A. coopy runnninng-cconffig: TFFTP:B. coopy TFTTP: runnninng-cconffigC. coopy TFTTP: staartuup-cconffigD. coopy staartuup-ccon

27、ffig: TFFTP:Answeer: BSectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:QUESTTIONN 122A sysstemm addminnisttrattor typpes thee coommaand to chaangee thhe hhosttnamme oof aa roouteer. Wheere on thee Ciiscoo IFFS iis thaat cchannge stooredd?A. NVVRAMMB. RAAMC. FLLASHH

28、D. ROOME. PCCMCIIAAnsweer: BSectiion: Chhaptter 4: Inttrodducttionn too Ciiscoo IOOSExplaanattionn/Reeferrencce:runniing-connfigg保存在在RAMM中starttup-connfigg保存在在NVRRAM中中QUESTTIONN 133Whichh coommaand is useed tto cconffiguure a ddefaaultt rooutee?A. ipp rooutee 17 2555.2555.2255.0 00B. ipp roou

29、tee 17 2555.2555.2255.0 11C. ipp rooutee 0.0.00.0 2555.2555.2255.0 11D. ipp rooutee 0.0.00.0 0.00.0.0 11Answeer: DSectiion: Chhaptter 6: IP RouutinngExplaanattionn/Reeferrencce:QUESTTIONN 144If IPP rooutiing is enaableed, whiich twoo coommaandss seet tthe gattewaay oof

30、llastt reesorrt tto tthe deffaullt ggateewayy?（如果啟啟用了 IP 路由，哪哪兩個命命令設(shè)置置網(wǎng)關(guān)的的最后到到默認(rèn)網(wǎng)網(wǎng)關(guān)？）(Chooose twoo.)A. ipp deefauult-gattewaay 00B. ipp rooutee 17 0.00.0.0 00C. ipp deefauult-nettworrk 00D. ipp deefauult-rouute 0.00.0.0 00 17E. ipp rooutee 0.0.00.0 0.00.0.0 11An

31、sweer: CESectiion: Chhaptter 6: IP RouutinngExplaanattionn/Reeferrencce:產(chǎn)生默認(rèn)網(wǎng)網(wǎng)關(guān)的兩兩種方式式ip deefauult-nettworrkip roouteeQUESTTIONN 155Whichh coommaand wouuld youu coonfiigurre gglobballly oon aa Ciiscoo roouteer tthatt woouldd allloww yoou tto vvieww diirecctlyy connnecctedd Ciiscoo deevicces?(該命令令將全局

32、局上配置置使您可可以直接接查看的的 Ciiscoo 路由由器連接接 Ciiscoo 設(shè)備備嗎？)A. ennablle ccdpB. cddp eenabbleC. cddp rrunD. ruun ccdpAnsweer: CSectiion: Chhaptter 5: Mannagiing Cissco IOSSExplaanattionn/Reeferrencce:QUESTTIONN 166Whichh coommaand is useed tto ssee thee paath takken by paccketts aacrooss an IP nettworrk?(哪些命令令用于

33、看看到通過過 IPP 網(wǎng)絡(luò)絡(luò)數(shù)據(jù)包包所采取取的路徑徑？)A. shhow ip rouuteB. shhow rouuteC. trraceerouuteD. trracee ipp roouteeAnsweer: CSectiion: Chhaptter 2: TCPP/IPPExplaanattionn/Reeferrencce:哪條命令用用于查看看數(shù)據(jù)包包轉(zhuǎn)發(fā)所所經(jīng)過的的路徑A:查看路路由表B：沒有這這條命令令C：正確D：沒這條條命令QUESTTIONN 177Whichh coommaand is useed tto ddebuug aa piing commmannd?哪些命令令用于

34、調(diào)調(diào)試 ppingg 命令令？A. deebugg iccmpB. deebugg ipp iccmpC. deebugg tccpD. deebugg paackeetAnsweer: BSectiion: Chhaptter 5: Mannagiing Cissco IOSSExplaanattionn/Reeferrencce:ping調(diào)調(diào)用了iicmpp協(xié)議，而而icmmp數(shù)據(jù)據(jù)包封裝裝在ipp包中。QUESTTIONN 188Whichh coommaand dissplaays CPUU uttiliizattionn?哪個命令令顯示的的 CPPU 利利用率呢呢？A. shhow

35、prootoccolssB. shhow proocesssC. shhow sysstemmD. shhow verrsioonAnsweer: BSectiion: Chhaptter 5: Mannagiing Cissco IOSSExplaanattionn/Reeferrencce:查看CPUU利用率率。QUESTTIONN 199When connfigguriing a sseriial intterffacee onn a rouuterr, wwhatt iss thhe ddefaaultt enncappsullatiion?在配置一一個串行行接口的的路由器器，什么么是

36、默認(rèn)認(rèn)的封裝裝？A. attm-ddxiB. frramee-reelayyC. hddlcD. laapbE. ppppAnsweer: CSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:缺省封裝是是HDLLCQUESTTIONN 200What musst bbe sset corrrecctlyy whhen connfigguriing a sseriial intterffacee soo thhat higgherr-leevell prrotoocolls ccalc

37、culaate thee besst rroutte?什么時，必必須設(shè)置置正確配配置串行行接口，以以便更高高級別的的協(xié)議計計算最佳佳路線？A. baandwwidtthB. deelayyC. looadD. reeliaabillityyAnsweer: ASectiion: Chhaptter 6: IP RouutinngExplaanattionn/Reeferrencce:為了使高層層路由協(xié)協(xié)議計算算最佳路路由，串串口的什什么東西西必須被被設(shè)置正正確？在在接口下下，只有有帶寬是是可以配配置的。QUESTTIONN 211A commpanny iimpllemeentss viide

38、oo coonfeerenncinng ooverr IPP onn thheirr Ettherrnett LAAN. Thee usserss nooticce tthatt thhe neetwoork sloows dowwn, andd thhe vvideeo eeithher stuutteers or faiils commpleetelly. Whaat iis tthe mosst llikeely reaasonn foor thiis?公司對他他們的以以太網(wǎng) LANN ipp 實現(xiàn)現(xiàn)視頻會會議。用用戶注意意網(wǎng)絡(luò)變變慢，和和視頻斷斷斷續(xù)續(xù)續(xù)或完全全失敗。最最有可能能的原因

39、因是什么么？A. miinimmum celll rratee (MMCR)B. quualiity of serrvicce (QoSS)C. moodullatiionD. paackeet sswittchiing excchannge (PSSE)E. reeliaablee trranssporrt pprottocool (RTPP)Answeer: BSectiion: Chhaptter 9: SwiitchhinggExplaanattionn/Reeferrencce:考點：當(dāng)網(wǎng)網(wǎng)絡(luò)中使使用視頻頻會議后后發(fā)現(xiàn)網(wǎng)網(wǎng)絡(luò)非常常慢，什什么原因因引起的的？QoS：用用于定制制策略對對

40、不同流流量進行行控制。QUESTTIONN 222Whichh laayerr inn thhe OOSI reffereencee moodell iss reespoonsiiblee foor ddeteermiininng tthe avaailaabillityy off thhe rreceeiviing proograam aand cheeckiing to seee iff ennouggh rresoourcces exiist forr thhat commmunnicaatioon?OSI 參考模模型在哪哪一層負(fù)負(fù)責(zé)確定定接收程程序的可可用性和和檢查足足夠的資資源，是是

41、否存在在該通信信？A. trranssporrtB. neetwoorkC. prreseentaatioonD. seessiionE. apppliicattionnAnsweer: ESectiion: Chhaptter 1: InttrodducttionnExplaanattionn/Reeferrencce:哪一層確定定的接收收程序的的可用性性？應(yīng)用層提供供QUESTTIONN 233Data traansffer is sloow bbetwweenn thhe ssourrce andd deestiinattionn. TThe quaalitty oof sservvic

42、ee reequeesteed bby tthe traanspportt layyer in thee OSSI rrefeerennce moddel is nott beeingg maainttainned. Too fiix tthiss isssuee, aat wwhicch llayeer sshouuld thee trooublleshhoottingg prroceess beggin?數(shù)據(jù)傳輸輸速度慢慢的源和和目標(biāo)之之間。不不保持在在 OSSI 參參考模型型的傳輸輸層所要要求的服服務(wù)質(zhì)量量。要解解決此問問題，在在哪一層層應(yīng)故障障排除過過程開始始？A. prreseent

43、aatioonB. seessiionC. trranssporrtD. neetwoorkE. phhysiicallAnsweer: DSectiion: Chhaptter 1: InttrodducttionnExplaanattionn/Reeferrencce:解決網(wǎng)絡(luò)問問題，先先確保網(wǎng)網(wǎng)絡(luò)層通通信。QUESTTIONN 244Whichh prrotoocolls aare fouund in thee neetwoork layyer of thee OSSI rrefeerennce moddel andd arre rrespponssiblle ffor patth de

44、ttermminaatioon aand traaffiic sswittchiing?哪些協(xié)議議在網(wǎng)絡(luò)絡(luò)層 OOSI 參考模模型中找找到，負(fù)負(fù)責(zé)路徑徑測定和和交通切切換？A. LAANB. rooutiingC. WAAND. neetwoorkAnsweer: BSectiion: Chhaptter 1: InttrodducttionnExplaanattionn/Reeferrencce:OSI網(wǎng)絡(luò)絡(luò)層中什什么提供供了路徑徑選擇和和流量轉(zhuǎn)轉(zhuǎn)發(fā)？由路由協(xié)議議提供。通通過手工工或者動動態(tài)學(xué)習(xí)習(xí)路由條條目實現(xiàn)現(xiàn)。QUESTTIONN 255Whichh coommaand revveall

45、s tthe lasst mmethhod useed tto ppoweercyyclee a rouuterr?A. shhow relloaddB. shhow boootC. shhow runnninng-cconffigD. shhow verrsioonAnsweer: DSectiion: Chhaptter 5: Mannagiing Cissco IOSSExplaanattionn/Reeferrencce:哪一個命令令可以顯顯示最近近一次被被用來重重啟路由由器的方方法？QUESTTIONN 266Whichh thhreee opptioons aree vaalidd

46、 WAAN cconnnecttiviity metthodds? (Chhoosse tthreee.)A. PPPPB. WAAPC. HDDLCD. MPPLSE. L22TPvv3F. ATTMAnsweer: ACFFSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:哪三種封裝裝屬于WWAN鏈鏈路的?A:點到點點協(xié)議，正正確B：無線加加密技術(shù)術(shù)，錯誤誤C:思科缺缺省封裝裝格式，正正確。D：多協(xié)議議標(biāo)簽轉(zhuǎn)轉(zhuǎn)換，錯錯誤E：隧道協(xié)協(xié)議，錯錯誤F：正確。QUESTTIONN 277

47、Referr too thhe eexhiibitt. WWhicch WWAN prootoccol is beiing useed?A. ATTMB. HDDLCC. Frramee ReelayyD. PPPPAnsweer: CSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:由圖中的紅紅線可看看到發(fā)送送接受LLMI信信息。屬屬于FRR的數(shù)據(jù)據(jù)包。QUESTTIONN 288What is thee diiffeerennce bettweeen aa CSSU/DDSU a

48、ndd a moddem?【一個CSSU/DDSU和和調(diào)制解解調(diào)器之之間的區(qū)區(qū)別是什什么？】A. A CSUU/DSSU cconvvertts aanallog siggnalls ffromm a rouuterr too a leaasedd liine; a moddem connverrts anaalogg siignaals froom aa roouteer tto aa leeaseed llinee.B. A CSUU/DSSU cconvvertts aanallog siggnalls ffromm a rouuterr too a phoone linne; a mm

49、odeem cconvvertts ddigiitall siignaals froom aa roouteer tto aa leeaseed llinee.C. A CSUU/DSSU cconvvertts ddigiitall siignaals froom aa roouteer tto aa phhonee liine; a moddem connverrts anaalogg siignaals froom aa roouteer tto aa phhonee liine.D. A CSUU/DSSU cconvvertts ddigiitall siignaals froom

50、aa roouteer tto aa leeaseed llinee; aa moodemm coonveertss diigittal siggnalls froom aa roouteer tto aa phhonee liine.Answeer: DSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:CSU/DDSU一一般是專專線，MMODEEN是將將模擬信信號與數(shù)數(shù)字信號號轉(zhuǎn)換QUESTTIONN 299A nettworrk aadmiinisstraatorr muust

51、connfigguree 2000 sswittch porrts to accceptt trrafffic froom oonlyy thhe ccurrrenttly atttachhed hosst ddeviicess. WWhatt woouldd bee thhe mmostt effficciennt wway to connfigguree MAAC-lleveel ssecuuritty oon aall theese porrts?A. Viisuaallyy veeriffy tthe MACC adddreessees aand theen ttelnnet to t

52、hee swwitcchess too ennterr thhe sswittchpportt-poort seccuriity macc-adddreess commmannd.B. Haave endd usserss e-maiil ttheiir MMAC adddresssess. TTelnnet to thee swwitcch tto eenteer tthe swiitchhporrt-pportt seecurrityy macc-adddreess commmannd.C. Usse tthe swiitchhporrt pportt-seecurrityy MAAC a

53、addrresss sttickky ccommmandd onn alll tthe swiitchh poortss thhat havve eend devvicees cconnnectted to theem.有端設(shè)設(shè)備連接接到他們們的所有有交換機機端口上上使用交交換機端端口端口口安全 MACC 地址址粘滯命命令。D. Usse sshoww maac-aaddrresss-taablee too deeterrminne tthe adddresssess thhat aree asssocciatted witth eeachh poort andd thhen entter t

54、hee coommaandss onn eaach swiitchh foor MMAC adddresss pportt-seecurrityy.Answeer: CSectiion: Chhaptter 9: SwiitchhinggExplaanattionn/Reeferrencce:考點：有2200臺臺主機需需要接入入，采用用什么方方式來增增強網(wǎng)絡(luò)絡(luò)安全性性？A：先驗證證macc安全性性，然后后在交換換機上綁綁定。錯錯誤，工工作量太太大B：用戶發(fā)發(fā)送郵件件認(rèn)證再再在交換換機上配配置，錯錯誤，不不科學(xué)。C：使用pportt-seecurrityy，正確確。D：錯誤，工工作量太太大。QU

55、ESTTIONN 300When trooublleshhoottingg a Fraame Rellay connnecctioon, whaat iis tthe firrst steep wwhenn peerfoormiing a llooppbacck ttestt?【幀中繼繼連接故故障排除除時，執(zhí)執(zhí)行環(huán)回回測試時時的第一一步是什什么？】A. Seet tthe enccapssulaatioon oof tthe intterffacee too HDDLC.B. Pllacee thhe CCSU/DSUU inn loocall-looop modde.C. Ennablle

56、llocaal-lloopp moode on thee DCCE FFramme RRelaay rroutter.D. Veeriffy tthatt thhe eencaapsuulattionn iss seet tto FFramme RRelaay.Answeer: ASectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:在對FR進進行排錯錯的時候候，當(dāng)做做回環(huán)測測試的時時候，第第一步如如何處理理？A：講接口口配置成成HDLLC，正正確，F(xiàn)FR封裝裝下無法法正常ppingg自

57、己端端口QUESTTIONN 311What occcurss onn a Fraame Rellay nettworrk wwhenn thhe CCIR is excceedded?A. Alll TTCP traaffiic iis mmarkked disscarrd eeliggiblle.B. Alll UUDP traaffiic iis mmarkked disscarrd eeliggiblle aand a BBECNN iss seent.C. Alll TTCP traaffiic iis mmarkked disscarrd eeliggiblle aand a BB

58、ECNN iss seent.D. Alll ttraffficc exxceeedinng tthe CIRR iss maarkeed ddisccardd elligiiblee.Answeer: DSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:在FR網(wǎng)絡(luò)絡(luò)中，當(dāng)當(dāng)CIRR超過時時會發(fā)生生什么情情況？D：所有超超過的流流量都丟丟棄。QUESTTIONN 322What aree twwo ccharractteriistiics of Fraame Rellay poiin

59、t-to-poiint subbintterffacees? (Chhoosse ttwo.)A. Thhey creeatee spplitt-hoorizzon isssuess.B. Thhey reqquirre aa unniquue ssubnnet witthinn a rouutinng ddomaain.C. Thhey emuulatte lleassed linnes.D. Thhey aree iddeall foor ffulll-meesh toppoloogiees.E. Thhey reqquirre tthe usee off NBBMA opttionns

60、wwhenn ussingg OSSPF.Answeer: BCSectiion: Chhaptter 14: Wiide Areea NNetwworkk (WWAN)Explaanattionn/Reeferrencce:幀中繼點到到點子接接口的特特點？A：水平分分割，錯錯誤。B：每個子子接口需需要一個個獨立的的網(wǎng)段，正正確。C：類似專專線，正正確。D:全網(wǎng)互互聯(lián)是理理想拓?fù)鋼?，錯誤誤。通常常是huub-sspokkeE：NBMMA不支支持OSSPF，錯錯誤。QUESTTIONN 333Referr too thhe eexhiibitt. AAddrressses witthinn th