大學(xué)物理教程(上)課后習(xí)題答案

----物理部分課后習(xí)題答案（標(biāo)有紅色記號(hào)的為老師讓看的題）27頁(yè)1-12質(zhì)點(diǎn)的運(yùn)動(dòng)方程為xt2,y(t2，x,yt位，求：（）質(zhì)點(diǎn)的運(yùn)動(dòng)軌跡；（）從t到t2s質(zhì)點(diǎn)的位移的大小；

（）t2s時(shí)，質(zhì)點(diǎn)的速度和加速度。謝謝閱讀）由運(yùn)動(dòng)方程消去時(shí)間t可得軌跡方程，將tx代入，有精品文檔放心下載y(x2或yx1（）將t和t2sr1，r21jrr2r1j位移的大小r2210m（）vxvy2(tv2ti2(t1)jaxx2，a2yya2i2j當(dāng)t2s時(shí)，速度和加速度分別為v2jm/sa2i2jm/s21-4設(shè)質(zhì)點(diǎn)的運(yùn)動(dòng)方程為rRcostiRsintj(SI)R、均為常感謝閱讀量。求（）速率的變化率。word可編輯.----解（）質(zhì)點(diǎn)的速度為vdrRsintiRcostj（）質(zhì)點(diǎn)的速率為vvv22xy速率的變化率為0R質(zhì)點(diǎn)沿半徑為R32t2(SI)t精品文檔放心下載時(shí)刻的法向加速度a的大小和角加速度的大

小。n解由于d4t質(zhì)點(diǎn)在t時(shí)刻的法向加速度a的大小為naR2n16Rt2角加速度d4rad/s277頁(yè)2-15,2-30，2-34，2-15mF3(SI)謝謝閱讀0到2.0sF謝謝閱讀解Is3t)20002-21飛謝謝閱讀fkv（kt0，初速度為v，0謝謝閱讀vt2）0到t精品文檔放心下載解精品文檔放心下載fkv

mk即vmvt2-31m謝謝閱讀word可編輯.----22RRGM精品文檔放心下載））.解(1)精品文檔放心下載Mmv2Gm(3R)3R2Ek1GMmmv226REpGMm3Rvtk0v0m2-37Mm2g500m/s謝謝閱讀/s20cm感謝閱讀））解mv1mv2Mu1Mgs0Mu2

2得(1)m2(vv)2(2103)2100)2122Mgs219.80.16(2)1EEm(v22vk1k2212)114頁(yè)3-11，，例3-2A、BmA、mBCmC，RBA、BBLword可編輯.例圖----J12mR2。（2A、B謝謝閱讀atR。T1T。2AT1mAaBmgTmaB2B11Tm)RJ

RmC222''21CCmg解）aB。1mm

m2ABC1(mm）T)g1mg2m，T。ACAB112mm

mmm

m22ABCABCBvv2202mvB1mm

m2ABC例3-4R謝謝閱讀μω0謝謝閱讀1JmR2m精品文檔放心下載2謝謝閱讀r精品文檔放心下載mg2rR

rdr

2MR23mgR0word可編輯.----MJ0感謝閱讀2M22

0Jn，則轉(zhuǎn)角2n謝謝閱讀J3R22n004M16πg(shù)3-2：如題3-2圖所示，兩個(gè)圓柱形輪子內(nèi)外半徑分別為R和R精品文檔放心下載12為M和M。二者同軸固結(jié)在一起組成定滑輪，可繞一水平軸自由轉(zhuǎn)動(dòng)。今在兩謝謝閱讀12輪上各繞以細(xì)繩，細(xì)繩分別掛上質(zhì)量為m和m的兩個(gè)物體。求在重力作用下，謝謝閱讀12定滑輪的角加速度。m：T11m：m22mgma111gTma222T1T1R1R2T2T2RTRTJ221111R2R2JMM221122aam11R1(M12R2(mm)gRR2211/2m)R(M/2m)R2211222m2,ym(x11vvivj,x負(fù)xyf精品文檔放心下載:

rxiyj11ffiLrmv(xi)m(vivj)(xiy0111xyy0111y1x)kword可編輯.----Mrf(xiyj)(fi)y0111fkmlO感謝閱讀.:l1則(ml2)β233g11

l(ml)ωsinθ022232題3-11圖3gsinlMR并以角速度m3謝謝閱讀精品文檔放心下載?:v0Rhv題3-13圖精品文檔放心下載v2v02gh2令v01v2HR0222g2gJ1MR1

2J'2222ω謝謝閱讀JωJ'ωmvR0word可編輯.----11MR2(2mR2)mvR22011(MR2mR2)(MR2mR2)22得)1(MR2mR2)2謝謝閱讀精品文檔放心下載Ek11(MR2mR2)222258頁(yè)8-2,8-12,8-178-7q精品文檔放心下載PP.解P謝謝閱讀dq4R0xR，22PdEdq與POx∥在PdE⊥解圖感謝閱讀XE=E=dEcos0dqxqx4022∥q4x2R2x12R22xR32>0<0.精品文檔放心下載8-12R和RRRq和q，謝謝閱讀122112rRRR3R感謝閱讀1122r解精品文檔放心下載(1)當(dāng)R1EcosdSE4rE0e2E(2)當(dāng)RR12EE4r2qeqE14r02(3)當(dāng)R210,ＯR12r解8-12圖場(chǎng)強(qiáng)隨r的變化曲線(xiàn)word可編輯.----eEE4r2q1q20Eq4

qr21208-13λ.謝謝閱讀.解l謝謝閱讀精品文檔放心下載λ.精品文檔放心下載感謝閱讀R謝謝閱讀erlEdSE0dS00E2E0；E當(dāng)R2rlel,E.2r008-15將-8CAB5.0-6JABBA感謝閱讀感謝閱讀解WWA、BBWAA外5.010J；6UUABWWWW5.0106V<0，ABABqqq2.510822.0∴BV.BUA2.0102謝謝閱讀8-17.q解R4R0.謝謝閱讀）當(dāng)R1:Uq140R14q2R02；:Uq140）當(dāng)R＜R12:U4q1q2r400rqq124r0當(dāng)R2r4q2R02；word可編輯.----當(dāng)2:Uq140r4q20rqq124r0285頁(yè)9-3,9-49-3．ROaA感謝閱讀B=B感謝閱讀B.BqEEBpEB41r04r39.3圖01(ar)03Bq感謝閱讀VVBB4q0ro感謝閱讀VBV0V04qa0o感謝閱讀oVV00qVV4B0a0BVB4qa09-4R1=6.0cmAB.謝謝閱讀word可編輯.----BR=8.0R=10.0AQ=-8，23A球殼BQ=-81BAB殼BB，AAB謝謝閱讀AB.精品文檔放心下載1QABQAQABQAQBE0(rR),E21E30(R12rR),EQrA(RR4r210QQB(rR)34A4r202)39.4圖EV和VABAV為A．3drEdrEdrE感謝閱讀VERRR12Ar1R2R3R4123QQ

QAdrBdrR2A4r2

4r2R

R10031QQQQ()AAAB4RRR0123BVB為3EdrE精品文檔放心下載VRB34rR3QQQQR3ABAB4r24R0032和精品文檔放心下載1和4精品文檔放心下載.word可編輯.----感謝閱讀精品文檔放心下載精品文檔放心下載精品文檔放心下載023；302P210()()()0222000由2得143.=-5C.-2εr=2.0DE感謝閱讀和P.精品文檔放心下載r1r（r）rPE(r０Drr1且P,D,Eword可編輯.----R1為εr.R±2.）精品文檔放心下載精品文檔放心下載強(qiáng)E10，rR1E22r，R2Rr1E3R0r2uR2R1E2dlRRlnrln2

222RR0101

rr）E2r0rrDP(0rEr2rr0(r2rrword可編輯.----329頁(yè)10-9,10-10lm場(chǎng)B3j1.5k)TyB.OllxSl2BS(6i3j1.5k)(0.15i)2感謝閱讀zl習(xí)題圖10-6B0d謝謝閱讀精品文檔放心下載r1r3解PB和B感謝閱讀12BPB1PB2P設(shè)P1rB1PI，B2R2P2IdrBPII2r2dr）d2Ir，B2d）ldr感謝閱讀word可編輯.----mSBdSrrII12r12r2drIlrrIldrIldr㏑+㏑㏑12112r2r

drr1121acPB的精品文檔放心下載習(xí)題圖10-10.PP謝謝閱讀度l0.15myB

B3j1.5k)T感謝閱讀.OllxSl2zl習(xí)題圖10-6BII(coscos)0(cos9004r4a21ocos180o)I[0(1)]04aIBS(6i3j1.5k)(0.15i)精品文檔放心下載04aB0d感謝閱讀感謝閱讀r1r3word可編輯.----解PB和B12BPB1PB2P設(shè)P1rB1PI，B2R2PI2drBIIP2r2dr）rd

2I，B2

d）ldr謝謝閱讀mSBdSr1r1r2r1IIldr2r2drIlrrIldrIl

dr㏑+㏑㏑12112r2drrr1121cPB的

.謝謝閱讀習(xí)題圖10-10word可編輯.----PP謝謝閱讀度BIIo(coscos)0

cos180o)(cos9004r4a21[0

I(1)]04aI04a.P感謝閱讀BBBB1B232BII(coscos)004r2r221r900;0;感謝閱讀21IIIIB2[0(1)]00004a2r22a4r謝謝閱讀.BB1B2B1333B1rh3B93II0.04h2a(cosI04r2cos)1.A精品文檔放心下載S，如圖所示感謝閱讀S精品文檔放心下載.rB則習(xí)題圖10-14BI,0IIr2R2Ir2r2I;B2rI0R00R22IrB002R2RIBdsIlrldr0000s02R22R2410711.01064R0rdrIl004word可編輯.----即S1.0Wb.6.P謝謝閱讀B1B2B32B1B32II(coscos)004r2r221r900;0;精品文檔放心下載21IIIIB2[0(1)]00004a2r22a4r精品文檔放心下載.BBBBB1233B1rh393BII0.04h2a13(cosI04r2cos)1.精品文檔放心下載S.謝謝閱讀線(xiàn)S精品文檔放心下載.rB則謝謝閱讀習(xí)題圖10-14word可編輯.----IIIBr2I,R20r2r2I;B2rI0R0R022IrB002R2RIBdsIlrldr0000s02R22R2410711.01064R0rdrIl004即S1.0Wb.6367頁(yè)11-1,11-5１INLv感謝閱讀感謝閱讀解IABCD謝謝閱讀感謝閱讀vt謝謝閱讀dSx感謝閱讀BB=0I2xdI02xtIIdbvtbvt

00avt2x2xavtword可編輯.----=Ilbvt0㏑

2a

vtNdEN精品文檔放心下載0aavbt2ba2lINav

b0vba2vt令t=感謝閱讀ENdt0lIvN0211NlIvba0ab2EBB率=КК感謝閱讀R,lE；V）ab,bc解精品文檔放心下載為rrR精品文檔放心下載LEVdBdSmtSEV2rr2r2有EVr2rROa,Ob和OcOabO精品文檔放心下載word可編輯.--