數(shù)理統(tǒng)計(jì)參考答案A

經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁(yè)眉頁(yè)腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請(qǐng)聯(lián)系刪除，謝謝！2013-2014數(shù)理統(tǒng)計(jì)期末試題A卷參考答案與評(píng)分標(biāo)準(zhǔn)一、選擇題（2X5=10分）BDCAB二、填空題（3X5=15分）116I78F(2,10)9[4.71,5.69]10n1n12(0x1)三、計(jì)算題11EX11（1）EXxxdxxdx（3分）111EX00X?所以的矩估計(jì)為11X（2）似然函數(shù)為nnL)(;)px(xxxx)1n1ii12ni1i1nln(L))nlnlnx3ii1ln(L))nnlnx0ii1n?所以的似然估計(jì)為3nxii1（3）根據(jù)似然估計(jì)的不變性nx11??ig)的似然估計(jì)為?))gg（3分）i1n1111（4）E(lnx)lnxxdxlnxdxlnxx|xdx01113000nx1n1in(?()))ExEgEgi1nii1nlnx1的無(wú)偏估計(jì)（3分）i?()gg是)i1n12(1)總體X~N(,1.2)2H:100vsH:10001X又已知，所以檢驗(yàn)統(tǒng)計(jì)量為u22/9拒絕域?yàn)閧|uu}{|uu}{|u1.96}/20.97599.5100|1.251.9661.2/3當(dāng)平均質(zhì)量為99時(shí)，犯第二類錯(cuò)誤的概率為XX1||P||{PuP/3/3X1/31.22~N)X~N)X2)9:1.2vsH:1.2）H2201s2檢驗(yàn)統(tǒng)計(jì)量為21.22拒絕域：{(91)}{(8)}{2.7326}222220.052又1.2261.22{7.347}0.5,(~(8))P=P222Hpp00H)（3）當(dāng)總體不再是正態(tài)分布的時(shí)候13H0H:ppp,i1,2,j1,20ijijB14836B2合計(jì)13638452088348436合計(jì)84原假設(shè)成立的情況下?136/5200.2615,?384/5200.7385pp25?84/5200.1615,?436/5200.8385p1p3???,1,2,1,2ijnpnppijijB121.9608114.01920.261562.0192322.00080.73850.16150.8385122222rc2,(rc1)1,2(1)3.841550.250.95514（1）方差分析表來(lái)源平方和105.542.75148.25自由度均方52.754.75F比11.1052p值因子A誤差e總和T2911(2,9)4.2611.1052>F(2,9)4.26F，0.950.95S(3)?2efe（4）44?的yyt1220.975】,1122,x,,x和y,y,,y分別是來(lái)自N(,)和N(,)的樣本，且兩x2212n12m12個(gè)樣本相互獨(dú)立2222x~N(,~)xN~(,~)yN，yN1n1n2n2m492(x)3(y)~N(0,()x)y)~N22，314912nmnm(ms2(ns2~(n1),~(m1)22yx22則（3分）(ms2(ns2~(2