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廣西玉林市玉州區(qū)2019屆九年級(jí)數(shù)學(xué)第一次模擬試題(含參照答案)廣西玉林市玉州區(qū)2019屆九年級(jí)數(shù)學(xué)第一次模擬試題(含參照答案)13/13廣西玉林市玉州區(qū)2019屆九年級(jí)數(shù)學(xué)第一次模擬試題(含參照答案)玉林市玉州區(qū)2019屆九年級(jí)數(shù)學(xué)第一次模擬試題注意事項(xiàng):本試卷滿分120分。考試時(shí)間為120分鐘。選擇題每題選出答案后,用2B鉛筆把答題卡上對(duì)應(yīng)題目的選項(xiàng)標(biāo)號(hào)涂黑。非選擇是,用直徑0.5毫米黑色墨水署名筆在答題卡上各題的答題區(qū)地域內(nèi)作答,答在式試卷上無(wú)效??荚嚱Y(jié)束,將本試卷和答題卡一并交回。一、選擇題:本大題共12小題,每題3分,共36分。在每題給出的四個(gè)選項(xiàng)中,只有一項(xiàng)為哪一項(xiàng)符合題目要求的,把正確答案的標(biāo)號(hào)填(涂)在答題卡內(nèi)相應(yīng)的地點(diǎn)上。1.1的倒數(shù)等于()2A.2B.2C.1D.1222.以下四個(gè)圖形中,既是軸對(duì)稱圖形又是中心對(duì)稱圖形的是()ABCD國(guó)家開(kāi)發(fā)銀行2018年有力有序落實(shí)“一帶一路”2500億元專項(xiàng)貸款,落實(shí)“十三五”規(guī)劃,全面提高國(guó)際發(fā)展質(zhì)量。此中2500億用科學(xué)記數(shù)法表示為()A.251010B.2.51010C.2.51011D.0.2510124.使分式x1值為零的x的值為()x1A.1B.0C.1D.25.從一副撲克牌中隨機(jī)抽出一張牌,獲取方塊或許A的概率是()A.17B.17C.8D.16525427526.以以下圖,將RtABC繞點(diǎn)A按順時(shí)針旋轉(zhuǎn)必定角度獲取RtADE,點(diǎn)B的對(duì)應(yīng)點(diǎn)D恰巧落在BC邊上,若AB1,C30,則CD的長(zhǎng)為()第6題圖A.1B.1.5C.2D.2217.一組的眾數(shù)、中位數(shù)、方差分別是()A.4,3,0.2B.3,3,0.4C.3,4,0.2D.3,2,0.48.以下計(jì)算中,正確的選項(xiàng)是()A.2a2b2B.a6a3a3abC.2x2y36x6y3D.2369.如圖,在RtABC中,C90,AB5,BC4,則以下三角函數(shù)表示正確的選項(xiàng)是()第9題圖A.tanA3B.tanB43D.cosA34C.sinA53510.中國(guó)“一帶一路”戰(zhàn)略沿線國(guó)家和地域帶來(lái)很大的經(jīng)濟(jì)效益,沿線某地域居民2017年人均收入為300美元,估計(jì)2019年人均收入將達(dá)到1200美元,設(shè)2017年到2019年該地域居民年人均收入均勻增加率為x,可列方程為()A.30012x1200C.3001x21200

B.3001x21200D.3002x120011.如圖,將O沿弦MN折疊,圓弧恰巧經(jīng)過(guò)圓心O,點(diǎn)A劣弧MN上一點(diǎn),則MAN的度數(shù)為()A.150B.135C.120D.10512.y24(h為常數(shù)),在自變量x的值知足1≤x≤4的狀況下,與其對(duì)應(yīng)的函已知二次函數(shù)xh數(shù)值y的最大值為0,則h的值為()A.1和6B.2和6C.1和3D.2和3二、填空題:本大題共6小題,每題3分,共18分,把答案填在答題卡的橫線上。13.使二次根式x2在實(shí)數(shù)范圍內(nèi)存心義的x的取值范圍是;14.分解因式:2xy218x;215.假如a2b1c32bc;0,那么a16.假如點(diǎn)A1,4,Bm,4在拋物線yax12;h上,那么m的值為17.如圖,母線長(zhǎng)為33的圓錐的側(cè)面張開(kāi)圖是一個(gè)扇形,若圓錐的底面圓半徑是3,則張開(kāi)圖扇形的圓心角底數(shù)為;第17題圖18.如圖,正方形ABCD的邊長(zhǎng)為10,點(diǎn)M在AD上,AM8,過(guò)M作MN∥AB,分別交AC、BC于H、N兩點(diǎn),若E、F分別為CH、BM的中點(diǎn),則EF的長(zhǎng)為第18題圖三、解答題:本大題共8小題,滿分66分,解答過(guò)程寫在答題卡上,解答寫出文字說(shuō)明,證明過(guò)程或演算步驟。1119.(6分)計(jì)算:02019259120.(6分)化簡(jiǎn)x1x1x1x2xx

2,并從1,0,1,2中選擇一個(gè)適合的數(shù)求代數(shù)式值。21.(6分)如圖,ABC三個(gè)極點(diǎn)的坐標(biāo)分別為A1,1,B4,2,C3,4.(1)請(qǐng)畫出ABC向左平移6個(gè)單位長(zhǎng)度后獲取的A1B1C1;(2)請(qǐng)畫出A1B1C1對(duì)于原點(diǎn)對(duì)稱的A2B2C2;(3)請(qǐng)x軸上求作一點(diǎn)D,使DA1B1的周長(zhǎng)最小,請(qǐng)畫出DA1B1,并直接寫出D的坐標(biāo).322.(8分)某班為認(rèn)識(shí)學(xué)生每周進(jìn)行體育鍛煉的時(shí)間狀況,對(duì)全班60名學(xué)生進(jìn)行檢查,按每周進(jìn)行體育鍛煉的時(shí)間t(單位:小時(shí)),將學(xué)生疏成五類:A類0≤t≤2,B類2t≤4,C類4t≤6,D類6t≤8,E類t8.繪制成尚不圓滿的條形統(tǒng)計(jì)圖如圖.依據(jù)以上信息,解答以下問(wèn)題:(1)E類學(xué)生有人,補(bǔ)全條形統(tǒng)計(jì)圖;(2)D類學(xué)生人數(shù)占被檢查總?cè)藬?shù)的%;(3)從該班每周進(jìn)行體育鍛煉時(shí)間在0≤t≤4的學(xué)生中任選人2人,求這2人每周進(jìn)行體育鍛煉時(shí)間都在2t≤4中的概率.23.(8分)如圖,已知AB是O的直徑,AC是O切線,連結(jié)BC交O于點(diǎn)P,且P為BC中點(diǎn)。1)求證:ABAC;2)若O的直徑長(zhǎng)為8,①求弧BP的長(zhǎng);②求暗影部分的面積.24.(10分)蔬菜基地栽種了娃娃菜和油菜兩種蔬菜共30畝,設(shè)栽種娃娃菜x畝,總利潤(rùn)為y萬(wàn)元,相關(guān)數(shù)據(jù)見(jiàn)下表:4成本(單位:萬(wàn)元/畝)銷售額(單位:萬(wàn)元/畝)娃娃菜2.43油菜22.5(1)求y對(duì)于x的函數(shù)關(guān)系式(利潤(rùn)=銷售額–成本);(2)若計(jì)劃投入的總成本不超出70萬(wàn)元,要使獲取的總利潤(rùn)最大,基地應(yīng)栽種娃娃菜和油菜各多少畝?(3)已知娃娃菜每畝地需要化肥400kg,油菜每畝地需要化肥600kg,依據(jù)(2)中的栽種畝數(shù),基地計(jì)劃運(yùn)送所需所有化肥,為了提高效率,實(shí)質(zhì)每次運(yùn)送化肥的總量是原計(jì)劃的1.25倍,結(jié)果運(yùn)送圓滿部化肥的次數(shù)比原計(jì)劃少1次,求基地原計(jì)劃每次運(yùn)送多少化肥.(10分)如圖1,在正方形ABCD中,E,F(xiàn)分別為BC,CD的中點(diǎn),連結(jié)AE,EF,交點(diǎn)為G.若正方形的邊長(zhǎng)為4.圖1(1)求證:AEBF;(2)將BCF沿BF對(duì)折,獲取BPF(如圖2),延伸FP交BA的延伸線于點(diǎn)Q,求AQ的長(zhǎng);圖2(3)將ABE繞點(diǎn)A逆時(shí)針?lè)较蛐D(zhuǎn),使邊AB正好落在AE上,獲取AHM(如圖3),若AM和BF訂交于點(diǎn)N,求四邊形MNGH面積.圖326.(12分)已知:如圖,直線y1xb與x軸負(fù)半軸交于點(diǎn)A,與y軸正半軸交于點(diǎn)B,線段OA的長(zhǎng)25是方程x27x80的一個(gè)根,請(qǐng)解答以下問(wèn)題:(1)求點(diǎn)B的坐標(biāo);(2)雙曲線ykk0,x0與直線AB交于點(diǎn)C,且AC55,求k的值;x(3)在(2)的條件下,點(diǎn)E在線段AB上,AE55,直線ly軸,垂足為P0,7,點(diǎn)M在直線l上,在直線AB上的坐標(biāo)平面內(nèi)能否存在點(diǎn)N,使以點(diǎn)C、E、M、N為極點(diǎn)的四邊形是矩形?若存在,懇求出點(diǎn)N的坐標(biāo);若不存在,請(qǐng)說(shuō)明原因。2019年玉州區(qū)第一次中考模擬試題數(shù)學(xué)參照答案一、ACCACABBDBCA二、13.x≥214.2xy3y315.216.317.12018.4118題解答過(guò)程:過(guò)F作FGBC于點(diǎn)G,過(guò)E作EPBC于點(diǎn)P,EHFG于點(diǎn)H∵四邊形ABCD是正方形∴AD∥BC,BC10MN∥AB∴四邊形ABNM是矩形∴BNAM8,MN10∴CN2∵AC是正方形ABCD的對(duì)角線∴CHNHCN45m]MNCN2∵E、F分別為CH、BM的中點(diǎn)6又∵FGBC,EPBC,EHFG∴EQEP1,F(xiàn)G5,BGNG4∴GHEP1,QHNG4∴EHEQQH5,F(xiàn)HFGGH4在RtEFH中,EFEH2FH2425241三、19.解:原式2191·····················································4分2131·····················································5分·····························································6分x1x220.解:11x2xxxx1xx1xx1x21x21xxx1x1

2

····························································2分x1x1xxx1x1

2

·······················································3分1·······································································4分x1∵x0,且x10,且x10∴x0,且x1,且x1∴在1,0,1,2中,x的值只好取2∴原式211·······························································6分1321.(1)以以下圖,A1B1C1為所求作的三角形·········································2分(2)以以下圖,A2B2C2所求作的三角形············································4分(3)以以下圖,DA1B1為所求作的三角形,點(diǎn)D坐標(biāo)為(4,0)························6分722.解:(1)15,補(bǔ)全圖形以下:···················································2分(2)30·········································································4分(3)∵每周進(jìn)行體育鍛煉時(shí)間在0≤t≤2內(nèi)的兩人記為甲、乙,在2<t≤4內(nèi)的3人記為A、B、C,從中任選兩人有:甲乙、甲A、甲B、甲C、乙A、乙B、乙C、AB、AC、BC這10種可能結(jié)果,此中2人每周進(jìn)行體育鍛煉時(shí)間都在2<t≤4中的有AB、AC、BC這3種結(jié)果∴這2人每周進(jìn)行體育鍛煉時(shí)間都在2<t≤4中的概率為3······························8分10(1)證明:連結(jié)APAB是O的直徑∴APB90∴APBCP為BC中點(diǎn)∴AP垂直均分BC∴ABAC········································································3分(2)①連結(jié)PO]∵AC是O的切線,AB是O的直徑∴ABACCAB90∵ABAC,APBC∴PAB145CAB28POB2PAB90O的直徑長(zhǎng)為8O的半徑長(zhǎng)為4∴弧BP的長(zhǎng)2···································································6分②∵POB90,OBOP4∴SPOB8,S扇形POB4∴暗影扇形POBSPOB48························································8分SS24.解:(1)由題意得y(32.4)x(2.52)(30x)0.1x15;·························3分(2)由題意知2.4x2(30x)≤70,解得x≤25·······································5分對(duì)于y0.1x15,∵0.10,∴y隨x的增大而增大,∴當(dāng)x25時(shí),所獲總利潤(rùn)最大,此時(shí)30x5.答:基地應(yīng)栽種娃娃菜25畝,栽種油菜5畝;·············································6分(3)設(shè)原計(jì)劃每次運(yùn)送化肥zkg,實(shí)質(zhì)每次運(yùn)送1.25zkg,需要運(yùn)送的化肥總量是40025600513000(kg),由題意可························································8分z1.25z解得z2600.經(jīng)查驗(yàn),z2600是原分式方程的解.答:基地原計(jì)劃每次運(yùn)送化肥2600kg···················································10分解:(1)證明:如圖1,∵E,F(xiàn)分別是正方形ABCD邊BC,CD的中點(diǎn),CFBE,在RtABE和RtBCF中,ABBCABEBCF,BECF∴RtABE≌RtBCF(SAS),·······················································2分BAECBF,又∵BAEBEA90,9∴CBFBEA90,BGE90,∴AEBF.······································································3分圖1(2)解:如圖2,依據(jù)題意得,F(xiàn)PFC,PFBBFC,F(xiàn)PB90CD∥AB,∴CFBABF,∴ABFPFB,QFQB,∵PFFC2,PBBC4,·····················································5分在RtBPQ中,設(shè)QBx,∴x2242,(x-2)x5,∴AQBQAB541.·························································6分圖2(3)解:∵正方形邊長(zhǎng)為4,∵BAEEAM,AEBF,∴ANAB4,AHM90,GN∥HM,·····································································8分AGN∽AHM10SS

2AGNANAHMAM2∴SAGN244516∴SAGN,5∴S四邊形GHMNSAHMSAGN4164,55∴四邊形GHMN的面積是4.························································10分526.解:(1)解方程x27x80得x8或x-1.∵線段OA的長(zhǎng)是方程x27x80的一個(gè)根,OA的長(zhǎng)是正數(shù)∴OA8,∴A8,0.將A8,0代入y=1x+b,得4b0,2∴b4,∴B0,4.············································································3分(2)在RtAOB中,OA8,OB4,∴AB45.圖1如圖①,過(guò)點(diǎn)C作CHx軸于點(diǎn)H,則CH∥OB,11AOB∽AHC·····································································5分∴OBABOA即4458CHACOHCH55AH解得CH5,AH10,∴OH1082,∴C2,5.∵雙曲線(ykk0,x0)經(jīng)過(guò)點(diǎn)C,x∴k2510························

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