2022年山東省淄博市中考數(shù)學(xué)試題及參考答案_第1頁
2022年山東省淄博市中考數(shù)學(xué)試題及參考答案_第2頁
2022年山東省淄博市中考數(shù)學(xué)試題及參考答案_第3頁
2022年山東省淄博市中考數(shù)學(xué)試題及參考答案_第4頁
2022年山東省淄博市中考數(shù)學(xué)試題及參考答案_第5頁
已閱讀5頁,還剩8頁未讀, 繼續(xù)免費閱讀

下載本文檔

版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進行舉報或認領(lǐng)

文檔簡介

2022年山東省淄博市中考數(shù)學(xué)試題及參考答案年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第9頁。數(shù)學(xué)試題參考答案及評分標準2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第9頁。一、選擇題:本大題共12個小題,每小題5分,共60分。題目123456789101112題號ADCDBACCDBAB二、填空題:本大題共5個小題,每小題4分,共20分。13.a(chǎn)≥514.x(x+3)(x-3)15.(1,3)16.-217.(-2023,2022)三、解答題:本大題共7個小題,共70分。18.(本題滿分8分)解:整理方程組得,···················2分①×2—②得—7y=7,y=1,············································4分把y=1代入①得x—2=3,解得x=5,·············································6分∴方程組的解為.············································8分19.(本題滿分8分)證明:∵△ABC是等腰三角形∴∠EBC=∠DCB,·······················································2分在△EBC與△DCB中∴BE=CD,BC=CB∴△EBC≌△DCB(SAS),··················································6分∴BD=CE;······························································8分20.(本題滿分10分)解:(1)將點A(1,2)代入y=,得m=2,∴雙曲線的表達式為:y=,···········································1分把A(1,2)和B(4,0)代入y=kx+b得:y=,解得:,·········································3分2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第10頁?!嘀本€的表達式為:y=x+;·········································4分2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第10頁。(2)聯(lián)立,解得,或··························5分∵點A的坐標為(1,2),∴點B的坐標為(3,),···············································6分∵S△AOB=S△AOB-S△AOB=OC·—OC·=×4×2—×4×=,∴△AOB的面積為;·······································8分(3)1<m<3····························································10分21.(本題滿分10分)解:(1)12099························································4分(2)如圖:··············8分(3)把“禮儀”“陶藝”“園藝”“廚藝”及“編程”等五門校本課程分別記為A、B、C、D、E,畫樹狀圖如下:2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第11頁。2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第11頁。共有25種等可能的結(jié)果,其中小剛和小強兩人恰好選到同一門課程的結(jié)果有5種,∴小剛和小強兩人恰好選到同—門課程的概率P=············································10分22.(本題滿分10分)解:小明能運用以上數(shù)據(jù),得到綜合樓的高度,理由如下:作EG⊥AB,垂足為G,作AH⊥CD,垂足為H,如圖:····················2分由題意知,EG=BF=40米,EF=BG=12.88米,∠HAE=16°=∠AEG=16°,∠CAH=9°,在Rt△AEG中,tan∠AEG=,∴tan16°=,即0.287≈,············································4分∴AG=40×0.287=11.48(米),∴AB=AG+BG=11.48+12.88=24.36(米),····································6分∴HD=AB=24.36米,在Rt△ACH中,AH=BD=BF+FD=80米,tan∠CAH=,∴tan9°=,即0.158≈,··········································8分∴CH=80×0.158=12.64(米),∴CD=CH+HD=12.64+24.36=37.00(米),則綜合樓的高度約是37.00米.·············································10分2022年山東省淄博市中考數(shù)學(xué)試題及參考答案全文共12頁,當前為第12頁。

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責。
  • 6. 下載文件中如有侵權(quán)或不適當內(nèi)容,請與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論