畢業(yè)設計（論文）：無線通信系統(tǒng)中接納控制協議的評估

畢業(yè)設計（論文）課題名稱：無線通信系統(tǒng)中接納控制協議的評估專業(yè)：信息與計算科學姓名：學號：指導教師：數理學院年月本科畢業(yè)設計（論文）XLVI6)];upp9=[zeros(1,28),lamdaf*ones(1,8),lamdah*ones(1,9),zeros(1,k-9-45)];upp10=[zeros(1,36),lamdaf*ones(1,9),lamdah*ones(1,10),zeros(1,k-10-55)];upp11=[zeros(1,45),lamdaf*ones(1,10),lamdah*ones(1,11),zeros(1,k-11-66)];upp12=[zeros(1,55),lamdaf*ones(1,11),lamdah*ones(1,12),zeros(1,k-12-78)];upp13=[zeros(1,66),lamdaf*ones(1,12),lamdah*ones(1,13),zeros(1,k-13-91)];upp14=[zeros(1,78),lamdaf*ones(1,13),lamdah*ones(1,14),zeros(1,k-14-105)];upp15=[zeros(1,91),lamdaf*ones(1,14),lamdah*ones(1,15),zeros(1,k-15-120)];upp16=[zeros(1,105),lamdaf*ones(1,15),lamdah*ones(1,16),zeros(1,k-16-136)];upp17=[zeros(1,120),lamdaf*ones(1,16),lamdah*ones(1,17),zeros(1,k-17-153)];upp18=[zeros(1,136),lamdaf*ones(1,17),lamdah*ones(1,18),zeros(1,k-18-171)];upp19=[zeros(1,153),lamdaf*ones(1,18),lamdah*ones(1,19),zeros(1,k-19-190)];upp20=[zeros(1,171),lamdaf*ones(1,19),lamdah*ones(1,20),zeros(1,k-20-210)];upp21=[zeros(1,190),lamdaf*ones(1,20),lamdah*ones(1,105)];%矩陣A的上三角down1=[miu,zeros(1,k-1-1)];down2=[miu,2*miu,miu,zeros(1,k-2-3)];down3=[zeros(1,1),miu*[1:3],miu*[2:-1:1],zeros(1,k-3-6)];down4=[zeros(1,3),miu*[1:4],miu*[3:-1:1],zeros(1,k-4-10)];down5=[zeros(1,6),miu*[1:5],miu*[4:-1:1],zeros(1,k-5-15)];down6=[zeros(1,10),miu*[1:6],miu*[5:-1:1],zeros(1,k-6-21)];down7=[zeros(1,15),miu*[1:7],miu*[6:-1:1],zeros(1,k-7-28)];down8=[zeros(1,21),miu*[1:8],miu*[7:-1:1],zeros(1,k-8-36)];down9=[zeros(1,28),miu*[1:9],miu*[8:-1:1],zeros(1,k-9-45)];down10=[zeros(1,36),miu*[1:10],miu*[9:-1:1],zeros(1,k-10-55)];down11=[zeros(1,45),miu*[1:11],miu*[10:-1:1],zeros(1,k-11-66)];down12=[zeros(1,55),miu*[1:12],miu*[11:-1:1],zeros(1,k-12-78)];down13=[zeros(1,66),miu*[1:13],miu*[12:-1:1],zeros(1,k-13-91)];down14=[zeros(1,78),miu*[1:14],miu*[13:-1:1],zeros(1,k-14-105)];down15=[zeros(1,91),miu*[1:15],miu*[14:-1:1],zeros(1,k-15-120)];down16=[zeros(1,105),miu*[1:16],miu*[15:-1:1],zeros(1,k-16-136)];down17=[zeros(1,120),miu*[1:17],miu*[16:-1:1],zeros(1,k-17-153)];down18=[zeros(1,136),miu*[1:18],miu*[17:-1:1],zeros(1,k-18-171)];down19=[zeros(1,153),miu*[1:19],miu*[18:-1:1],zeros(1,k-19-190)];down20=[zeros(1,171),miu*[1:20],miu*[19:-1:1],zeros(1,k-20-210)];down21=[zeros(1,190),miu*[1:21],miu*[20:-1:1],miu*[22:-1:2],miu*[23:-1:3],miu*[24:-1:4],miu*[25:-1:5]];%矩陣A的下三角A=A+diag(upp1,1)+diag(upp2,2)+diag(upp3,3)+diag(upp4,4)+diag(upp5,5)+diag(upp6,6)+diag(upp7,7)+diag(upp8,8)+diag(upp9,9)+diag(upp10,10)+diag(upp11,11)+diag(upp12,12)+diag(upp13,13)+diag(upp14,14)+diag(upp15,15)+diag(upp16,16)+diag(upp17,17)+diag(upp18,18)+diag(upp19,19)+diag(upp20,20)+diag(upp21,21);A=A+diag(down1,-1)+diag(down2,-2)+diag(down3,-3)+diag(down4,-4)+diag(down5,-5)+diag(down6,-6)+diag(down7,-7)+diag(down8,-8)+diag(down9,-9)+diag(down10,-10)+diag(down11,-11)+diag(down12,-12)+diag(down13,-13)+diag(down14,-14)+diag(down15,-15)+diag(down16,-16)+diag(down17,-17)+diag(down18,-18)+diag(down19,-19)+diag(down20,-20)+diag(down21,-21);d=sum(A');%對A轉置，然后對轉置矩陣每行豎向相加，求每一列的和，結果為行向量A=A-diag(d);%把行向量加到矩陣A的對角線上A(:,1)=[];%把A矩陣每行第一列數取空A=[ones(k,1)A];%用k行一列的全為1的列矩陣代替A的第一列b=zeros(1,k);%b為