海南師范大學(xué)《線性代數(shù)》2018-2019學(xué)年期末試卷B

????????????????線???????????封??????????????????密???????????????????????????????????線???????????封??????????????????密???????????????????級班業(yè)專系號學(xué)名姓???????????????????????????題???????不?內(nèi)?線?封?密?EQ\*jc3\*hps31\o\al(\s\up7(?),?)?????????????????????????○EQ\*jc3\*hps31\o\al(\s\up8(○),密)2.所有答案請直接答在試卷上封評卷人------------------------斷下列命題是否正確,正確的在其后面括號內(nèi)填上“V封評卷人------------------------EQ\*jc3\*hps31\o\al(\s\up6(○),裝)評卷人每小題列出的四個(gè)選項(xiàng)中只有一個(gè)是符合題目要求的，請將其代碼○復(fù)查人填在題后的括號內(nèi)。錯選或未選均無分）T2--------------------------○答案直接填入括號內(nèi)）評卷人EQ\*jc3\*hps36\o\al(\s\up15(2),4)EQ\*jc3\*hps36\o\al(\s\up15(1),3)-1EQ\*jc3\*hps36\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up9(0),1)EQ\*jc3\*hps35\o\al(\s\up9(2),2)EQ\*jc3\*hps35\o\al(\s\up9(2),0)22（7分）（7分）○評卷人○密0-2-2-4+10-2-0-2-2-2-20-2-2（4分）（4分）-2-20-2-2-20（7分）（7分）|2EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up13(2),3)EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(0),1)EQ\*jc3\*hps35\o\al(\s\up13(4),2)EQ\*jc3\*hps35\o\al(\s\up13(2),4)EQ\*jc3\*hps35\o\al(\s\up13(4),6)EQ\*jc3\*hps35\o\al(\s\up13(6),3)○訂「9|訂「9|54（4分）（4分）|○AB=|211-1021-1-2]○(a(a|EQ\*jc3\*hps35\o\al(\s\up15(a),2)EQ\*jc3\*hps35\o\al(\s\up15(1),0)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(+),3)（5分）（7分）（7分）「10-2]「10-2]「10-2]EQ\*jc3\*hps36\o\al(\s\up16(6),3)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(0),2)EQ\*jc3\*hps36\o\al(\s\up16(0),8)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(2),0)EQ\*jc3\*hps36\o\al(\s\up16(8),0)○評卷人評卷人1η○η密13|||,3|||,求該方程組的通解.------------------1試確定實(shí)數(shù)a的取值范圍,使相應(yīng)的二次型f正定.