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專題七與三角形有關(guān)常用幾何模型一、角平分線模型例題1如圖,SKIPIF1<0ABC中,AC=BC,∠ACB=90°,AD平分∠BAC交BC于點(diǎn)D,過點(diǎn)B作BE⊥AD,交AD延長線于點(diǎn)E,F(xiàn)為AB的中點(diǎn),連接CF,交AD于點(diǎn)G,連接BG.(1)線段BE與線段AD有何數(shù)量關(guān)系?并說明理由;(2)判斷SKIPIF1<0BEG的形狀,并說明理由.練習(xí)題1.已知:SKIPIF1<0是SKIPIF1<0的角平分線,且SKIPIF1<0.(1)如圖1,求證:SKIPIF1<0;(2)如圖2,SKIPIF1<0,點(diǎn)E在SKIPIF1<0上,連接SKIPIF1<0并延長交SKIPIF1<0于點(diǎn)SKIPIF1<0,SKIPIF1<0交CA的延長線于點(diǎn)SKIPIF1<0,且SKIPIF1<0,連接SKIPIF1<0.①求證:SKIPIF1<0;②若SKIPIF1<0,且SKIPIF1<0,求SKIPIF1<0的長.2.在SKIPIF1<0中,BE,CD為SKIPIF1<0的角平分線,BE,CD交于點(diǎn)F.(1)求證:SKIPIF1<0;(2)已知SKIPIF1<0.①如圖1,若SKIPIF1<0,SKIPIF1<0,求CE的長;②如圖2,若SKIPIF1<0,求SKIPIF1<0的大?。?.如圖,△ABC中,AB=AC,∠BAC=90°,CD平分∠ACB,BE⊥CD,垂足E在CD的延長線上.求證:BE=SKIPIF1<0CD.4.在△ABC中,AD為△ABC的角平分線,點(diǎn)E是直線BC上的動點(diǎn).(1)如圖1,當(dāng)點(diǎn)E在CB的延長線上時(shí),連接AE,若∠E=48°,AE=AD=DC,則∠ABC的度數(shù)為.(2)如圖2,AC>AB,點(diǎn)P在線段AD延長線上,比較AC+BP與AB+CP之間的大小關(guān)系,并證明.(3)連接AE,若∠DAE=90°,∠BAC=24°,且滿足AB+AC=EC,請求出∠ACB的度數(shù)(要求:畫圖,寫思路,求出度數(shù)).5.如圖,在△ABC中,∠C=90°,AD是∠BAC的角平分線,交BC于點(diǎn)D,過D作DE⊥BA于點(diǎn)E,點(diǎn)F在AC上,且BD=DF.(1)求證:AC=AE;(2)若AB=7.4,AF=1.4,求線段BE的長.6.(1)如圖1,射線OP平分∠MON,在射線OM,ON上分別截取線段OA,OB,使OA=OB,在射線OP上任取一點(diǎn)D,連接AD,BD.求證:AD=BD.(2)如圖2,在Rt△ABC中,∠ACB=90°,∠A=60°,CD平分∠ACB,求證:BC=AC+AD.(3)如圖3,在四邊形ABDE中,AB=9,DE=1,BD=6,C為BD邊中點(diǎn),若AC平分∠BAE,EC平分∠AED,∠ACE=120°,求AE的值.7.已知:如圖,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0分別平分SKIPIF1<0和SKIPIF1<0,點(diǎn)E在SKIPIF1<0上.用等式表示線段SKIPIF1<0、SKIPIF1<0、SKIPIF1<0三者之間的數(shù)量關(guān)系,并證明.8.如圖,在SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的平分線,延長SKIPIF1<0至點(diǎn)SKIPIF1<0,SKIPIF1<0,試求SKIPIF1<0的度數(shù).9.在平面直角坐標(biāo)系中,點(diǎn)SKIPIF1<0,SKIPIF1<0,點(diǎn)C為x軸正半軸上一動點(diǎn),過點(diǎn)A作SKIPIF1<0交y軸于點(diǎn)E.(1)如圖SKIPIF1<0,若點(diǎn)C的坐標(biāo)為(3,0),試求點(diǎn)E的坐標(biāo);(2)如圖SKIPIF1<0,若點(diǎn)C在x軸正半軸上運(yùn)動,且SKIPIF1<0,其它條件不變,連接DO,求證:OD平分SKIPIF1<0(3)若點(diǎn)C在x軸正半軸上運(yùn)動,當(dāng)SKIPIF1<0時(shí),試探索線段AD、OC、DC的數(shù)量關(guān)系,并證明.10.四邊形SKIPIF1<0中,SKIPIF1<0,連接SKIPIF1<0.(1)如圖1,若SKIPIF1<0平分SKIPIF1<0,求證:SKIPIF1<0.(2)如圖2,若SKIPIF1<0,SKIPIF1<0,求證:SKIPIF1<0.(3)如圖3,在(2)的條件下,作SKIPIF1<0于點(diǎn)SKIPIF1<0,連接SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0的長度.二、一線三等角模型例題2(1)課本習(xí)題回放:“如圖①,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,垂足分別為SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.求SKIPIF1<0的長”,請直接寫出此題答案:SKIPIF1<0的長為________.(2)探索證明:如圖②,點(diǎn)SKIPIF1<0,SKIPIF1<0在SKIPIF1<0的邊SKIPIF1<0、SKIPIF1<0上,SKIPIF1<0,點(diǎn)SKIPIF1<0,SKIPIF1<0在SKIPIF1<0內(nèi)部的射線SKIPIF1<0上,且SKIPIF1<0.求證:SKIPIF1<0.(3)拓展應(yīng)用:如圖③,在SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0.點(diǎn)SKIPIF1<0在邊SKIPIF1<0上,SKIPIF1<0,點(diǎn)SKIPIF1<0、SKIPIF1<0在線段SKIPIF1<0上,SKIPIF1<0.若SKIPIF1<0的面積為15,則SKIPIF1<0與SKIPIF1<0的面積之和為________.(直接填寫結(jié)果,不需要寫解答過程)練習(xí)題1.如圖,點(diǎn)P,D分別是∠ABC邊BA,BC上的點(diǎn),且SKIPIF1<0,SKIPIF1<0.連結(jié)PD,以PD為邊,在PD的右側(cè)作等邊△DPE,連結(jié)BE,則△BDE的面積為(

)A.SKIPIF1<0 B.2 C.4 D.SKIPIF1<02.課間,小聰拿著老師的等腰直角三角板玩,不小心掉到兩墻之間(如圖),∠ACB=90°,AC=BC,從三角板的刻度可知AB=20cm,小聰想知道砌墻磚塊的厚度(每塊磚的厚度相等),下面為砌墻磚塊厚度的平方是(

).A.SKIPIF1<0cm2 B.SKIPIF1<0cm2 C.SKIPIF1<0cm2 D.SKIPIF1<0cm23.【問題解決】(1)已知△ABC中,AB=AC,D,A,E三點(diǎn)都在直線l上,且有∠BDA=∠AEC=∠BAC.如圖①,當(dāng)∠BAC=90°時(shí),線段DE,BD,CE的數(shù)量關(guān)系為:______________;【類比探究】(2)如圖②,在(1)的條件下,當(dāng)0°<∠BAC<180°時(shí),線段DE,BD,CE的數(shù)量關(guān)系是否變化,若不變,請證明:若變化,寫出它們的關(guān)系式;【拓展應(yīng)用】(3)如圖③,AC=BC,∠ACB=90°,點(diǎn)C的坐標(biāo)為(-2,0),點(diǎn)B的坐標(biāo)為(1,2),請求出點(diǎn)A的坐標(biāo).4.(1)如圖1,在△ABC中,∠BAC=90°,AB=AC,直線m經(jīng)過點(diǎn)A,BD⊥直線m,CE⊥直線m,垂足分別為點(diǎn)D、E.求證:△ABD≌△CAE;(2)如圖2,將(1)中的條件改為:在△ABC中,AB=AC,D、A、E三點(diǎn)都在直線m上,并且有∠BDA=∠AEC=∠BAC=α,其中α為任意銳角或鈍角.請問結(jié)論△ABD≌△CAE是否成立?如成立,請給出證明;若不成立,請說明理由.(3)拓展應(yīng)用:如圖3,D,E是D,A,E三點(diǎn)所在直線m上的兩動點(diǎn)(D,A,E三點(diǎn)互不重合),點(diǎn)F為∠BAC平分線上的一點(diǎn),且△ABF和△ACF均為等邊三角形,連接BD,CE,若∠BDA=∠AEC=∠BAC,求證:△DEF是等邊三角形.5.已知△ABC中,∠ACB=90°,AC=BC.BE、AD分別與過點(diǎn)C的直線垂直,且垂足分別為D,E.學(xué)習(xí)完第十二章后,張老師首先讓同學(xué)們完成問題1:如圖1,若AD=2.5cm,DE=1.7cm,求BE的長;然后,張老師又提出問題2:將圖1中的直線CE繞點(diǎn)C旋轉(zhuǎn)到△ABC的外部,BE、AD與直線CE的垂直關(guān)系不變,如圖2,猜想AD、DE、BE三者的數(shù)量關(guān)系,并給予證明.6.感知:(1)數(shù)學(xué)課上,老師給出了一個(gè)模型:如圖1,SKIPIF1<0,由SKIPIF1<0,SKIPIF1<0,可得SKIPIF1<0;又因?yàn)镾KIPIF1<0,可得SKIPIF1<0,進(jìn)而得到SKIPIF1<0______.我們把這個(gè)模型稱為“一線三等角”模型.應(yīng)用:(2)實(shí)戰(zhàn)組受此模型的啟發(fā),將三等角變?yōu)榉侵苯?,如圖2,在SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,點(diǎn)P是BC邊上的一個(gè)動點(diǎn)(不與B、C重合),點(diǎn)D是AC邊上的一個(gè)動點(diǎn),且SKIPIF1<0.①求證:SKIPIF1<0;②當(dāng)點(diǎn)P為BC中點(diǎn)時(shí),求CD的長;拓展:(3)在(2)的條件下如圖2,當(dāng)SKIPIF1<0為等腰三角形時(shí),請直接寫出BP的長.7.在△ABC中,∠ACB=90°,AC=BC,且AD⊥MN于D,BE⊥MN于E.(1)直線MN繞點(diǎn)C旋轉(zhuǎn)到圖(1)的位置時(shí),求證:DE=AD+BE;(2)當(dāng)直線MN繞點(diǎn)C旋轉(zhuǎn)到圖(2)的位置時(shí),試問DE、AD、BE具有怎樣的等量關(guān)系?請直接寫出這個(gè)等量關(guān)系(不寫證明過程);(3)當(dāng)直線MN繞點(diǎn)C旋轉(zhuǎn)到圖(3)的位置時(shí),試問DE、AD、BE具有怎樣的等量關(guān)系?請直接寫出這個(gè)等量關(guān)系(不寫證明過程).8.如圖,在SKIPIF1<0中,SKIPIF1<0.(1)如圖①所示,直線SKIPIF1<0過點(diǎn)SKIPIF1<0,SKIPIF1<0于點(diǎn)SKIPIF1<0,SKIPIF1<0于點(diǎn)SKIPIF1<0,且SKIPIF1<0.求證:SKIPIF1<0.(2)如圖②所示,直線SKIPIF1<0過點(diǎn)SKIPIF1<0,SKIPIF1<0交SKIPIF1<0于點(diǎn)SKIPIF1<0,SKIPIF1<0交SKIPIF1<0于點(diǎn)SKIPIF1<0,且SKIPIF1<0,則SKIPIF1<0是否成立?請說明理由.9.問題背景:(1)如圖①,已知SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,直線m經(jīng)過點(diǎn)A,SKIPIF1<0直線m,SKIPIF1<0直線m,垂足分別為點(diǎn)D,E,易證:SKIPIF1<0______+______.(2)拓展延伸:如圖②,將(1)中的條件改為:在SKIPIF1<0中,SKIPIF1<0,D,A,E三點(diǎn)都在直線m上,并且有SKIPIF1<0,請求出DE,BD,CE三條線段的數(shù)量關(guān)系,并證明.(3)實(shí)際應(yīng)用:如圖③,在SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,點(diǎn)C的坐標(biāo)為SKIPIF1<0,點(diǎn)A的坐標(biāo)為SKIPIF1<0,請直接寫出B點(diǎn)的坐標(biāo).10.探究:(1)如圖(1),已知:在△ABC中,∠BAC=90°,AB=AC,直線m經(jīng)過點(diǎn)A,BD⊥直線m,CE⊥直線m,垂足分別為點(diǎn)D、E.請直接寫出線段BD,DE,CE之間的數(shù)量關(guān)系是.拓展:(2)如圖(2),將探究中的條件改為:在△ABC中,AB=AC,D、A、E三點(diǎn)都在直線m上,并且有∠BDA=∠AEC=∠BAC=α,其中α為任意銳角或鈍角.請問探究中的結(jié)論是否成立?如成立,請你給出證明;若不成立,請說明理由.應(yīng)用:(3)如圖(3),D、E是D、A、E三點(diǎn)所在直線m上的兩動點(diǎn)(D、A、E三點(diǎn)互不重合),點(diǎn)F為∠BAC平分線上的一點(diǎn),且△ABF和△ACF均為等邊三角形,連接BD、CE,若∠BDA=∠AEC=∠BAC,請直接寫出△DEF的形狀是.三、手拉手模型例題3如圖,在SKIPIF1<0、SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,設(shè)SKIPIF1<0.連接SKIPIF1<0,以SKIPIF1<0、SKIPIF1<0為鄰邊作SKIPIF1<0,連接SKIPIF1<0.(1)若SKIPIF1<0,當(dāng)SKIPIF1<0、SKIPIF1<0分別與SKIPIF1<0、SKIPIF1<0重合時(shí)(圖1),易得SKIPIF1<0.當(dāng)SKIPIF1<0繞點(diǎn)SKIPIF1<0順時(shí)針旋轉(zhuǎn)到(圖2)位置時(shí),請直接寫出線段SKIPIF1<0、SKIPIF1<0的數(shù)量關(guān)系________;(2)若SKIPIF1<0,當(dāng)SKIPIF1<0繞點(diǎn)SKIPIF1<0順時(shí)針旋轉(zhuǎn)到(圖3)位置時(shí),試判斷線段SKIPIF1<0、SKIPIF1<0的數(shù)量關(guān)系,并證明你的結(jié)論;(3)若SKIPIF1<0為任意角度,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0繞點(diǎn)SKIPIF1<0順時(shí)針旋轉(zhuǎn)一周(圖4),當(dāng)SKIPIF1<0、SKIPIF1<0、SKIPIF1<0三點(diǎn)共線時(shí),請直接寫出SKIPIF1<0的長度.練習(xí)題1.如圖,△ABC中,∠C=90°,AC=BCSKIPIF1<0,將△ABC繞點(diǎn)A順時(shí)針方向旋轉(zhuǎn)60°到△AB'C'的位置,連接BC',BC'的延長線交AB'于點(diǎn)D,則BD的長為_____.2.已知,如圖,等腰?ABC中,∠A=30°,AB=AC=8,D是AB上一點(diǎn),且AD=6,E為AC邊上一動點(diǎn),以DE為邊向右側(cè)作等邊三角形DEF.(1)當(dāng)F在AC邊上時(shí),AF長為______;(2)連結(jié)BF,則BF的取值范圍為______.3.已知:如圖,在△ABC中,AB=AC,在△ADE中,AD=AE,且∠BAC=∠DAE,連接BD,CE交于點(diǎn)F,連接AF.(1)求證:△ABD≌△ACE;(2)求證:FA平分∠BFE.4.如圖,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,連接BD,CE,BD與CE交于點(diǎn)O,BD與AC交于點(diǎn)F.(1)求證:BD=CE.(2)若∠BAC=48°,求∠COD的度數(shù).(3)若G為CE上一點(diǎn),GE=OD,AG=OC,且AG∥BD,求證:BD⊥AC.5.【理解概念】當(dāng)一個(gè)凸四邊形的一條對角線把原四邊形分成兩個(gè)三角形.若其中有一個(gè)三角形是等腰直角三角形,則把這條對角線叫做這個(gè)四邊形的“等腰直角線”,把這個(gè)四邊形叫做“等腰直角四邊形”,當(dāng)一個(gè)凸四邊形的一條對角線把原四邊形分成兩個(gè)三角形.若其中一個(gè)三角形是等腰直角三角形,另一個(gè)三角形是等腰三角形,則把這條對角線叫做這個(gè)四邊形的“真等腰直角線”,把這個(gè)四邊形叫做“真等腰直角四邊形”.(1)【鞏固新知】如圖①,若AD=3,AD=DB=DC,BC=3SKIPIF1<0,則四邊形ABCD______(填“是”或“否”)真等腰直角四邊形.(2)【深度理解】在圖①中,如果四邊形ABCD是真等腰直角四邊形,且∠BDC=90°,對角線BD是這個(gè)四邊形的真等腰直角線,當(dāng)AD=4,AB=3時(shí),則邊BC的長是______.(3)如圖②,四邊形ABCD與四邊形ABDE都是等腰直角四邊形,且∠BDC=90°,∠ADE=90°,BD>AD>AB,對角線BD、AD分別是這兩個(gè)四邊形的等腰直角線.求證:AC=BE.(4)【拓展提高】在圖3中,已知:四邊形ABCD是等腰直角四邊形,對角線BD是這個(gè)四邊形的等腰直角線.若BD正好是分得的等腰直角三角形的一條直角邊,且AD=3,AB=4,∠BAD=45°,求AC的長.6.如圖,已知點(diǎn)P在矩形ABCD外,∠APB=90°,PA=PB,點(diǎn)E、F分別在AD、BC上運(yùn)動,且∠EPF=45°,連接EF.(1)求證:△APE∽△BFP;(2)若△PEF是等腰直角三角形,求SKIPIF1<0的值;(3)試探究線段AE、BF、EF之間滿足的等量關(guān)系,并證明你的結(jié)論.7.如圖,在等腰直角三角形ABC和ADE中,AC=AB,AD=AE,連接BD,點(diǎn)M、N分別是BD,BC的中點(diǎn),連接MN.(1)如圖1,當(dāng)頂點(diǎn)D在邊AC上時(shí),請直接寫出線段BE與線段MN的數(shù)量關(guān)系是,位置關(guān)系是.(2)當(dāng)△ADE繞點(diǎn)A旋轉(zhuǎn)時(shí),連接BE,上述結(jié)論是否依然成立,若成立,請就圖2情況給出證明;若不成立,請說明理由.(3)當(dāng)AC=8時(shí),在△ADE繞點(diǎn)A旋轉(zhuǎn)過程中,以D,E,M,N為頂點(diǎn)可以組成平行四邊形,請直接寫出AD的長.8.在SKIPIF1<0中,SKIPIF1<0,D為BC延長線上一點(diǎn),點(diǎn)E為線段AC,CD的垂直平分線的交點(diǎn),連接EA,EC,ED.(1)如圖1,當(dāng)SKIPIF1<0時(shí),則SKIPIF1<0_______°;(2)當(dāng)SKIPIF1<0時(shí),①如圖2,連接AD,判斷SKIPIF1<0的形狀,并證明;②如圖3,直線CF與ED交于點(diǎn)F,滿足SKIPIF1<0.P為直線CF上一動點(diǎn).當(dāng)SKIPIF1<0的值最大時(shí),用等式表示PE,PD與AB之間的數(shù)量關(guān)系為_______,并證明.9.如圖,SKIPIF1<0為等邊三角形,D為AC邊上一點(diǎn),連接BD,M為BD的中點(diǎn),連接AM.(1)如圖1,若AB=2SKIPIF1<0+2,∠ABD=45°,求SKIPIF1<0的面積;(2)如圖2,過點(diǎn)M作SKIPIF1<0與AC交于點(diǎn)E,與BC的延長線交于點(diǎn)N,求證:AD=CN;(3)如圖3,在(2)的條件下,將SKIPIF1<0沿AM翻折得SKIPIF1<0,連接B'N,當(dāng)B'N取得最小值時(shí),直接寫出SKIPIF1<0的值.

10.【學(xué)習(xí)概念】有一組對角互余的凸四邊形稱為對余四邊形,連接這兩個(gè)角的頂點(diǎn)的線段稱為對余線.【理解運(yùn)用】(1)如圖1,對余四邊形中,AB=5,BC=6,CD=4,連接AC,若AC=AB,則cos∠ABC=___________,sin∠CAD=__________.(2)如圖2,凸四邊形中,AD=BD,AD⊥BD,當(dāng)2CD2+CB2=CA2時(shí),判斷四邊形ABCD是否為對余四邊形,證明你的結(jié)論.【拓展提升】(3)在平面直角坐標(biāo)中,A(-1,0),B(3,0),C(1,2),四邊形ABCD是對余四邊形,點(diǎn)E在對余線BD上,且位于△ABC內(nèi)部,∠AEC=90°+∠ABC.設(shè)SKIPIF1<0=u,點(diǎn)D的縱坐標(biāo)為t,請?jiān)谙路綑M線上直接寫出u與t的函數(shù)表達(dá),并注明t的取值范圍____________________________.四、旋轉(zhuǎn)模型例題4【課題研究】旋轉(zhuǎn)圖形中對應(yīng)線段所在直線的夾角(小于等于90°的角)與旋轉(zhuǎn)角的關(guān)系.【問題初探】線段AB繞點(diǎn)O順時(shí)針旋轉(zhuǎn)得到線段CD,其中點(diǎn)A與點(diǎn)C對應(yīng),點(diǎn)B與點(diǎn)D對應(yīng),旋轉(zhuǎn)角的度數(shù)為α,且0°<α<180°.(1)如圖①,當(dāng)α=60°時(shí),線段AB、CD所在直線夾角(銳角)為;(2)如圖②,當(dāng)90°<α<180°時(shí),直線AB與直線CD所夾銳角與旋轉(zhuǎn)角α存在怎樣的數(shù)量關(guān)系?請說明理由;【形成結(jié)論】旋轉(zhuǎn)圖形中,當(dāng)旋轉(zhuǎn)角小于平角時(shí),對應(yīng)線段所在直線的夾角與旋轉(zhuǎn)角.【運(yùn)用拓廣】運(yùn)用所形成的結(jié)論解決問題:(3)如圖③,四邊形ABCD中,∠ABC=60°,∠ADC=30°,AB=BC,CD=3,BD=SKIPIF1<0,求AD的長.練習(xí)題1.如圖,等邊SKIPIF1<0中,SKIPIF1<0分別交SKIPIF1<0、SKIPIF1<0于點(diǎn)SKIPIF1<0、SKIPIF1<0.(1)求證:SKIPIF1<0是等邊三角形;(2)將SKIPIF1<0繞點(diǎn)SKIPIF1<0順時(shí)針旋轉(zhuǎn)SKIPIF1<0(SKIPIF1<0),設(shè)直線SKIPIF1<0與直線SKIPIF1<0相交于點(diǎn)SKIPIF1<0.①如圖,當(dāng)SKIPIF1<0時(shí),判斷SKIPIF1<0的度數(shù)是否為定值,若是,求出該定值;若不是,說明理由;②若SKIPIF1<0,SKIPIF1<0,當(dāng)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0三點(diǎn)共線時(shí),求SKIPIF1<0的長.2.如圖1,在SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,點(diǎn)SKIPIF1<0,SKIPIF1<0分別在邊SKIPIF1<0,SKIPIF1<0上,SKIPIF1<0,連接SKIPIF1<0,點(diǎn)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0分別為SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的中點(diǎn).(1)觀察猜想:圖1中,線段SKIPIF1<0與SKIPIF1<0的數(shù)量關(guān)系是______,位置關(guān)系是______.(2)探究證明:把SKIPIF1<0繞點(diǎn)SKIPIF1<0逆時(shí)針方向旋轉(zhuǎn)到圖2的位置,連接SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,判斷SKIPIF1<0的形狀,并說明理由;(3)拓展延伸:把SKIPIF1<0繞點(diǎn)SKIPIF1<0在平面內(nèi)自由旋轉(zhuǎn),若SKIPIF1<0,SKIPIF1<0,請直接寫出SKIPIF1<0面積的最大值.3.在SKIPIF1<0ABC和SKIPIF1<0CDE中,∠ACB=∠DCE=90°,AC=BC,CD=CE,點(diǎn)D在邊AC上,點(diǎn)E在邊BC上,如圖1將SKIPIF1<0CDE繞點(diǎn)C按順時(shí)針方向旋轉(zhuǎn),旋轉(zhuǎn)角為α(0°<α≤90°).(1)連接AD,BE.求證:AD=BE,AD⊥BE;(2)當(dāng)旋轉(zhuǎn)至圖2位置時(shí),點(diǎn)A,D,E在一條直線上,連接BD,BE,若AD=2SKIPIF1<0,CD=1,則BD=;(3)當(dāng)α=90°時(shí),如圖3,連接AD,BE,延長AD交BE于點(diǎn)F,連接CF,若DF=1.EF=SKIPIF1<0.則CF=.4.如圖,在直角SKIPIF1<0中,SKIPIF1<0,點(diǎn)D是SKIPIF1<0上一點(diǎn),連接SKIPIF1<0,把SKIPIF1<0繞點(diǎn)A逆時(shí)針旋轉(zhuǎn)90°,得到SKIPIF1<0,連接SKIPIF1<0交SKIPIF1<0于點(diǎn)M.(1)如圖1,若SKIPIF1<0,求SKIPIF1<0的長;(2)如圖2,若SKIPIF1<0,點(diǎn)N為SKIPIF1<0上一點(diǎn),SKIPIF1<0,求證:SKIPIF1<0;(3)如圖3,若SKIPIF1<0,點(diǎn)D為直線SKIPIF1<0上一動點(diǎn),直線SKIPIF1<0與直線SKIPIF1<0交于點(diǎn)M,當(dāng)SKIPIF1<0為等腰三角形時(shí),請直接寫出此時(shí)SKIPIF1<0的度數(shù).5.綜合與實(shí)踐問題情境:一次數(shù)學(xué)課上,老師出示了課本中的一道復(fù)習(xí)題:如圖,SKIPIF1<0和SKIPIF1<0都是等邊三角形,SKIPIF1<0、SKIPIF1<0分別是SKIPIF1<0、SKIPIF1<0上的點(diǎn),且SKIPIF1<0,連接SKIPIF1<0、SKIPIF1<0.初步探究:(1)試判斷SKIPIF1<0與SKIPIF1<0的數(shù)量關(guān)系,并說明理由;(2)求證:四邊形SKIPIF1<0是平行四邊形;深入探究:(3)如圖2,四邊形SKIPIF1<0和四邊形SKIPIF1<0都是正方形,SKIPIF1<0、SKIPIF1<0分別是SKIPIF1<0、SKIPIF1<0上的點(diǎn),且SKIPIF1<0,連接SKIPIF1<0、SKIPIF1<0,試判斷四邊形SKIPIF1<0的形狀,并說明理由;拓展延伸:(4)如圖3,四邊形SKIPIF1<0和四邊形SKIPIF1<0都是菱形,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0是SKIPIF1<0上一點(diǎn),連接SKIPIF1<0、SKIPIF1<0,延長SKIPIF1<0交SKIPIF1<0于SKIPIF1<0,若四邊形SKIPIF1<0是平行四邊形,請直接寫出SKIPIF1<0的長.6.在SKIPIF1<0ABC中,AB=AC,點(diǎn)D是直線BC上一點(diǎn)(不與B、C重合),以AD為一邊在AD的右側(cè)作SKIPIF1<0ADE,使AD=AE,∠DAE=∠BAC,連接CE.(1)如圖1,當(dāng)點(diǎn)D在線段BC上,如果∠BAC=90°,則∠BCE=度;(2)設(shè)SKIPIF1<0,SKIPIF1<0.①如圖2,當(dāng)點(diǎn)在線段BC上移動,則SKIPIF1<0,SKIPIF1<0之間有怎樣的數(shù)量關(guān)系?請說明理由;②當(dāng)點(diǎn)在直線BC上(線段BC之外)移動,則SKIPIF1<0,SKIPIF1<0之間有怎樣的數(shù)量關(guān)系?請直接寫出你的結(jié)論.7.如圖①,在Rt△ABC中,AB=AC,D為BC邊上一點(diǎn)(不與點(diǎn)B,C重合),將線段AD繞點(diǎn)A逆時(shí)針旋轉(zhuǎn)90°得到AE,連接EC(1)試探索線段BC,DC,EC之間滿足的等量關(guān)系,并證明你的結(jié)論.(2)如圖②,在Rt△ABC與Rt△ADE中,AB=AC,AD=AE,將△ADE繞點(diǎn)A旋轉(zhuǎn),使點(diǎn)D落在BC邊上,試探索線段AD,BD,CD之間滿足的等量關(guān)系,并證明你的結(jié)論.8.如圖1,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0、SKIPIF1<0相交于點(diǎn)SKIPIF1<0,連接SKIPIF1<0.(1)求證:SKIPIF1<0,并用含SKIPIF1<0的式子表示SKIPIF1<0的度數(shù);(2)當(dāng)SKIPIF1<0時(shí),取SKIPIF1<0,SKIPIF1<0的中點(diǎn)分別為點(diǎn)SKIPIF1<0、SKIPIF1<0,連接SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,如圖2,判斷SKIPIF1<0的形狀,并加以證明.9.(1)如圖①,在四邊形SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0分別是邊SKIPIF1<0,SKIPIF1<0上的點(diǎn),且SKIPIF1<0.請直接寫出線段SKIPIF1<0,SKIPIF1<0,SKIPIF1<0之間的數(shù)量關(guān)系:__________;(2)如圖②,在四邊形SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0分別是邊SKIPIF1<0,SKIPIF1<0上的點(diǎn),且SKIPIF1<0,(1)中的結(jié)論是否仍然成立?請寫出證明過程;(3)在四邊形SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0分別是邊SKIPIF1<0,SKIPIF1<0所在直線上的點(diǎn),且SKIPIF1<0.請畫出圖形(除圖②外),并直接寫出線段SKIPIF1<0,SKIPIF1<0,SKIPIF1<0之間的數(shù)量關(guān)系.10.四邊形SKIPIF1<0是由等邊SKIPIF1<0和頂角為SKIPIF1<0的等腰SKIPIF1<0排成,將一個(gè)SKIPIF1<0角頂點(diǎn)放在SKIPIF1<0處,將SKIPIF1<0角繞SKIPIF1<0點(diǎn)旋轉(zhuǎn),該SKIPIF1<0交兩邊分別交直線SKIPIF1<0、SKIPIF1<0于SKIPIF1<0、SKIPIF1<0,交直線SKIPIF1<0于SKIPIF1<0、SKIPIF1<0兩點(diǎn).(1)當(dāng)SKIPIF1<0、SKIPIF1<0都在線段SKIPIF1<0上時(shí)(如圖1),請證明:SKIPIF1<0;(2)當(dāng)點(diǎn)SKIPIF1<0在邊SKIPIF1<0的延長線上時(shí)(如圖2),請你寫出線段SKIPIF1<0,SKIPIF1<0和SKIPIF1<0之間的數(shù)量關(guān)系,并證明你的結(jié)論;(3)在(1)的條件下,若SKIPIF1<0,SKIPIF1<0,請直接寫出SKIPIF1<0的長為.五、相似子母圖模型例題5如圖,在Rt△ABC中,∠ACB=90°,點(diǎn)D在AB上,且SKIPIF1<0=SKIPIF1<0.(1)求證△ACD∽△ABC;(2)若AD=3,BD=2,求CD的長.練習(xí)題1.如圖,在三角形ABC中,AB=8cm,BC=16cm,點(diǎn)P從點(diǎn)A開始沿邊AB運(yùn)動,速度為2cm/s,點(diǎn)Q從點(diǎn)B開始沿BC邊運(yùn)動,速度為4cm/s,如果點(diǎn)P、Q兩動點(diǎn)同時(shí)運(yùn)動,何時(shí)SKIPIF1<0QBP與SKIPIF1<0ABC相似?2.如圖,銳角△ABC中,CD,BE分別是AB,AC邊上的高,垂足為D,E.(1)求證:△ACD∽△ABE;(2)若將點(diǎn)D,E連接起來,則△AED和△ABC能相似嗎?說說你的理由.3.如圖,在△ABC中,D是BC上的點(diǎn),E是AD上一點(diǎn),且SKIPIF1<0,∠BAD=∠ECA.(1)求證:AC2=BC?CD;(2)若AD是△ABC的中線,求SKIPIF1<0的值.4.如圖,直線AB經(jīng)過⊙O上的點(diǎn)C,并且OA=OB,CA=CB,直線OB交⊙O于點(diǎn)E、D,連接EC、CD.(1)試判斷直線AB與⊙O的位置關(guān)系,并加以證明;(2)求證:SKIPIF1<0;(3)若SKIPIF1<0,⊙O的半徑為3,求OA的長.5.SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,點(diǎn)E為SKIPIF1<0的中點(diǎn),連接SKIPIF1<0并延長交SKIPIF1<0于點(diǎn)F,且有SKIPIF1<0,過F點(diǎn)作SKIPIF1<0于點(diǎn)H.(1)求證:SKIPIF1<0;(2)求證:SKIPIF1<0;(3)若SKIPIF1<0,求SKIPIF1<0的長.6.如圖,已知矩形SKIPIF1<0的兩條對角線相交于點(diǎn)O,過點(diǎn)SKIPIF1<0作SKIPIF1<0分別交SKIPIF1<0、SKIPIF1<0于點(diǎn)SKIPIF1<0、SKIPIF1<0.(1)求證:SKIPIF1<0;(2)連接SKIPIF1<0,若SKIPIF1<0.求證:SKIPIF1<0.7.如圖:在矩形ABCD中,SKIPIF1<0,SKIPIF1<0,動點(diǎn)Р以SKIPIF1<0的速度從A點(diǎn)出發(fā),沿AC向C點(diǎn)移動,同時(shí)動點(diǎn)Q以SKIPIF1<0的速度從點(diǎn)C出發(fā),沿CB向點(diǎn)B移動,設(shè)P、Q兩點(diǎn)移動的時(shí)間為t秒SKIPIF1<0.(1)SKIPIF1<0______m,SKIPIF1<0______m,SKIPIF1<0_____m(用含t的代數(shù)式表示)(2)t為多少秒時(shí),以P、Q、C為頂點(diǎn)的三角形與SKIPIF1<0相似?(3)在P、Q兩點(diǎn)移動過程中,四邊形ABQP與SKIPIF1<0CPQ的面積能否相等?若能,求出此時(shí)t的值;若不能,請說明理由.8.如圖1,四邊形SKIPIF1<0內(nèi)接于SKIPIF1<0是SKIPIF1<0的直徑,SKIPIF1<0.延長SKIPIF1<0交SKIPIF1<0的延長線于點(diǎn)SKIPIF1<0.(1)證明:SKIPIF1<0.(2)當(dāng)SKIPIF1<0時(shí),①求SKIPIF1<0的長度.②如圖2,作SKIPIF1<0平分SKIPIF1<0交SKIPIF1<0于點(diǎn)SKIPIF1<0,連結(jié)SKIPIF1<0,求SKIPIF1<0的面積.9.如果兩個(gè)相似三角形的對應(yīng)邊存在2倍關(guān)系,則稱這兩個(gè)相似三角形互為母子三角形.(1)如果SKIPIF1<0與SKIPIF1<0互為母子三角形,則SKIPIF1<0的值可能為(

)A.2

B.SKIPIF1<0

C.2或SKIPIF1<0(2)已知:如圖1,SKIPIF1<0中,SKIPIF1<0是SKIPIF1<0的角平分線,SKIPIF1<0.求證:SKIPIF1<0與SKIPIF1<0互為母子三角形.(3)如圖2,SKIPIF1<0中,SKIPIF1<0是中線,過射線SKIPIF1<0上點(diǎn)SKIPIF1<0作SKIPIF1<0,交射線SKIPIF1<0于點(diǎn)SKIPIF1<0,連結(jié)SKIPIF1<0,射線SKIPIF1<0與射線SKIPIF1<0交于點(diǎn)SKIPIF1<0,若SKIPIF1<0與SKIPIF1<0互為母子三角形.求SKIPIF1<0的值.

10.在矩形SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0是SKIPIF1<0邊上一點(diǎn),SKIPIF1<0交SKIPIF1<0于點(diǎn)SKIPIF1<0,過點(diǎn)SKIPIF1<0作SKIPIF1<0,交射線SKIPIF1<0于點(diǎn)SKIPIF1<0,交射線SKIPIF1<0于點(diǎn)SKIPIF1<0.(1)如圖SKIPIF1<0,當(dāng)點(diǎn)SKIPIF1<0與點(diǎn)SKIPIF1<0重合時(shí),求SKIPIF1<0的長.(2)如圖SKIPIF1<0,當(dāng)點(diǎn)SKIPIF1<0在線段SKIPIF1<0上時(shí),設(shè)SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0與SKIPIF1<0之間的函數(shù)關(guān)系式,并寫出它的定義域.(3)連接SKIPIF1<0,當(dāng)SKIPIF1<0與SKIPIF1<0相似時(shí),求線段SKIPIF1<0的長.六、旋轉(zhuǎn)相似模型例題6如圖,正方形ABCD,對角線AC,BD相交于O,Q為線段DB上的一點(diǎn),SKIPIF1<0,點(diǎn)M、N分別在直線BC、DC上.(1)如圖1,當(dāng)Q為線段OD的中點(diǎn)時(shí),求證:SKIPIF1<0;(2)如圖2,當(dāng)Q為線段OB的中點(diǎn),點(diǎn)N在CD的延長線上時(shí),則線段DN、BM、BC的數(shù)量關(guān)系為;(3)在(2)的條件下,連接MN,交AD、BD于點(diǎn)E、F,若SKIPIF1<0,SKIPIF1<0,求EF的長.練習(xí)題1.在同一平面內(nèi),如圖①,將兩個(gè)全等的等腰直角三角形擺放在一起,點(diǎn)A為公共頂點(diǎn),SKIPIF1<0.如圖②,若△ABC固定不動,把△ADE繞點(diǎn)A逆時(shí)針旋轉(zhuǎn),使AD、AE與邊BC的交點(diǎn)分別為M、N點(diǎn)M不與點(diǎn)B重合,點(diǎn)N不與點(diǎn)C重合.2.如圖,在正方形ABCD中,點(diǎn)P在對角線BD上,直線AP交CD于E,PF⊥AE交BC于點(diǎn)F,連接AF交BD于M.(1)判斷△APF的形狀,并說明理由;(2)連接EF,求EF:PM的值.3.(1)【問題發(fā)現(xiàn)】:如圖1在Rt△ABC中,AB=AC,∠BAC=90°,點(diǎn)D為BC的中點(diǎn),以CD為一邊作正方形CDEF,點(diǎn)E與點(diǎn)A重合,易知△ACF∽△BCE.線段BE與AF有怎樣的數(shù)量關(guān)系?請直接寫出.(2)【拓展研究】:在(1)的條件下,將正方形CDEF繞點(diǎn)C旋轉(zhuǎn)至如圖2所示的位置,連接BE,CE,AF.請猜想線段BE和AF的數(shù)量關(guān)系,并證明你的結(jié)論;(3)【結(jié)論運(yùn)用】:在(1)(2)的條件下,若△ABC的面積為8時(shí),當(dāng)正方形CDEF旋轉(zhuǎn)到B、E、F點(diǎn)共線時(shí),請直接寫出線段AF的長.4.如圖,SKIPIF1<0和SKIPIF1<0是有公共頂點(diǎn)直角三角形,SKIPIF1<0,點(diǎn)P為射線SKIPIF1<0,SKIPIF1<0的交點(diǎn).(1)如圖1,若SKIPIF1<0和SKIPIF1<0是等腰直角三角形,求證:SKIPIF1<0;(2)如圖2,若SKIPIF1<0,問:(1)中的結(jié)論是否成立?請說明理由.(3)在(1)的條件下,SKIPIF1<0,SKIPIF1<0,若把SKIPIF1<0繞點(diǎn)A旋轉(zhuǎn),當(dāng)SKIPIF1<0時(shí),請直接寫出SKIPIF1<0的長度5.在△ABC中,AB=AC,∠BAC=α,點(diǎn)P為線段CA延長線上一動點(diǎn),連接PB,將線段PB繞點(diǎn)P逆時(shí)針旋轉(zhuǎn),旋轉(zhuǎn)角為α,得到線段PD,連接DB,DC.(1)如圖1,當(dāng)α=60°時(shí),求證:PA=DC;(2)如圖2,當(dāng)α=120°時(shí),猜想PA和DC的數(shù)量關(guān)系并說明理由.(3)當(dāng)α=120°時(shí),若AB=6,BP=SKIPIF1<0,請直接寫出點(diǎn)D到CP的距離.6.在SKIPIF1<0和SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,點(diǎn)E在SKIPIF1<0的內(nèi)部,連接EC,EB,EA和BD,并且SKIPIF1<0.【觀察猜想】(1)如圖①,當(dāng)SKIPIF1<0時(shí),線段BD與CE的數(shù)量關(guān)系為__________,線段EA,EB,EC的數(shù)量關(guān)系為__________.【探究證明】(2)如圖②,當(dāng)SKIPIF1<0時(shí),(1)中的結(jié)論是否依然成立?若成立,請給出證明,若不成立,請說明理由;【拓展應(yīng)用】(3)在(2)的條件下,當(dāng)點(diǎn)E在線段CD上時(shí),若SKIPIF1<0,請直接寫出SKIPIF1<0的面積.7.一次小組合作探究課上,老師將兩個(gè)正方形按如圖所示的位置擺放(點(diǎn)E、A、D在同一條直線上),發(fā)現(xiàn)SKIPIF1<0且SKIPIF1<0.小組討論后,提出了下列三個(gè)問題,請你幫助解答:(1)將正方形SKIPIF1<0繞點(diǎn)A按逆時(shí)針方向旋轉(zhuǎn)(如圖1),還能得到SKIPIF1<0嗎?若能,請給出證明,請說明理由;(2)把背景中的正方形分別改成菱形SKIPIF1<0和菱形SKIPIF1<0,將菱形SKIPIF1<0繞點(diǎn)A按順時(shí)針方向旋轉(zhuǎn)(如圖2),試問當(dāng)SKIPIF1<0與SKIPIF1<0的大小滿足怎樣的關(guān)系時(shí),SKIPIF1<0;(3)把背景中的正方形分別改寫成矩形SKIPIF1<0和矩形SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0(如圖3),連接SKIPIF1<0,SKIPIF1<0.試求SKIPIF1<0的值(用a,b表示).8.?dāng)?shù)學(xué)課上,老師拿出兩塊不同大小的含30度角的三角板讓同學(xué)們在不同位置嘗試操作.(1)如圖1擺放,當(dāng)點(diǎn)SKIPIF1<0在SKIPIF1<0上,點(diǎn)SKIPIF1<0在SKIPIF1<0上,得知SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0的長.(2)如圖2,在(1)的條件下,連結(jié)SKIPIF1<0,求SKIPIF1<0的面積.(3)如圖3擺放,把這同樣的兩塊三角板的直角頂點(diǎn)互相重合放置,小三角板SKIPIF1<0繞著點(diǎn)SKIPIF1<0旋轉(zhuǎn),連結(jié)SKIPIF1<0、SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),求SKIPIF1<0的值.(4)SKIPIF1<0不變,當(dāng)SKIPIF1<0的三邊長擴(kuò)大一倍后,繞點(diǎn)SKIPIF1<0旋轉(zhuǎn)一周,直線SKIPIF1<0與SKIPIF1<0交于點(diǎn)SKIPIF1<0,請你直接寫出點(diǎn)SKIPIF1<0所經(jīng)過的運(yùn)動路徑.9.在△ABC中,AB=AC,∠BAC=α,點(diǎn)P是△ABC外一點(diǎn),連接BP,將線段BP繞點(diǎn)P逆時(shí)針旋轉(zhuǎn)α得到線段PD,連接BD,CD,AP.觀察猜想:(1)如圖1,當(dāng)α=60°時(shí),SKIPIF1<0的值為,直線CD與AP所成的較小角的度數(shù)為°;類比探究:(2)如圖2,當(dāng)α=90°時(shí),求出SKIPIF1<0的值及直線CD與AP所成的較小角的度數(shù);拓展應(yīng)用:(3)如圖3,當(dāng)α=90°時(shí),點(diǎn)E,F(xiàn)分別為AB,AC的中點(diǎn),點(diǎn)P在線段FE的延長線上,點(diǎn)A,D,P三點(diǎn)在一條直線上,BD交PF于點(diǎn)G,CD交AB于點(diǎn)H.若CD=2+SKIPIF1<0,求BD的長.10.某校數(shù)學(xué)活動小組在一次活動中,對一個(gè)數(shù)學(xué)問題作如下探究:(1)問題發(fā)現(xiàn):如圖1,在等邊SKIPIF1<0中,點(diǎn)SKIPIF1<0是邊SKIPIF1<0上任意一點(diǎn),連接SKIPIF1<0,以SKIPIF1<0為邊作等邊SKIPIF1<0,連接CQ,BP與CQ的數(shù)量關(guān)系是________;(2)變式探究:如圖2,在等腰SKIPIF1<0中,SKIPIF1<0,點(diǎn)SKIPIF1<0是邊SKIPIF1<0上任意一點(diǎn),以SKIPIF1<0為腰作等腰SKIPIF1<0,使SKIPIF1<0,SKIPIF1<0,連接SKIPIF1<0,判斷SKIPIF1<0和SKIPIF1<0的數(shù)量關(guān)系,并說明理由;(3)解決問題:如圖3,在正方形SKIPIF1<0中,點(diǎn)SKIPIF1<0是邊SKIPIF1<0上一點(diǎn),以SKIPIF1<0為邊作正方形SKIPIF1<0,SKIPIF1<0是正方形SKIPIF1<0的中心,連接SKIPIF1<0.若正方形SKIPIF1<0的邊長為5,SKIPIF1<0,求正方形SKIPIF1<0的邊長.七、K字型相似例題7已知正方形SKIPIF1<0的邊長為4,一個(gè)以點(diǎn)A為頂點(diǎn)的45°角繞點(diǎn)A旋轉(zhuǎn),角的兩邊分別與邊SKIPIF1<0、SKIPIF1<0的延長線交于點(diǎn)E、F,連接SKIPIF1<0.設(shè)SKIPIF1<0.(1)如圖1,當(dāng)SKIPIF1<0被對角線SKIPIF1<0平分時(shí),求a、b的值;(2)當(dāng)SKIPIF1<0是直角三角形時(shí),求a、b的值;(3)如圖3,探索SKIPIF1<0繞點(diǎn)A旋轉(zhuǎn)的過程中,SKIPIF1<0的面積是否發(fā)生變化?請說明理由.練習(xí)題1.在矩形SKIPIF1<0中,點(diǎn)SKIPIF1<0是SKIPIF1<0邊上一點(diǎn),將SKIPIF1<0沿SKIPIF1<0折疊,使點(diǎn)SKIPIF1<0恰好落在SKIPIF1<0邊上的點(diǎn)SKIPIF1<0處.(1)如圖1,若SKIPIF1<0,求SKIPIF1<0的值;(2)如圖2,在線段SKIPIF1<0上取一點(diǎn)SKIPIF1<0,使SKIPIF1<0平分SKIPIF1<0,延長SKIPIF1<0,SKIPIF1<0交于點(diǎn)SKIPIF1<0,若SKIPIF1<0,求SKIPIF1<0的值.2.如圖,在矩形SKIPIF1<0中,SKIPIF1<0是SKIPIF1<0上一點(diǎn),SKIPIF1<0于點(diǎn)SKIPIF1<0,設(shè)SKIPIF1<0.(1)若SKIPIF1<0,求證:SKIPIF1<0;(2)若SKIPIF1<0,且SKIPIF1<0在同一直線上時(shí),求SKIPIF1<0的值.3.某數(shù)學(xué)興趣小組在學(xué)習(xí)了尺規(guī)作圖、等腰三角形和相似三角形的有關(guān)知識后,在等腰△ABC中,其中SKIPIF1<0,如圖1,進(jìn)行了如下操作:第一步,以點(diǎn)A為圓心,任意長為半徑畫弧,分別交BA的延長線和AC于點(diǎn)E,F(xiàn),如圖2;第二步,分別以點(diǎn)E,F(xiàn)為圓心,大于SKIPIF1<0EF的長為半徑畫弧,兩弧相交于點(diǎn)D,作射線AD;第三步,以D為圓心,DA的長為半徑畫弧,交射線AE于點(diǎn)G;(1)填空;寫出∠CAD與∠GAD的大小關(guān)系為___;(2)①請判斷AD與BC的位置關(guān)系,并說明理由.②當(dāng)SKIPIF1<0時(shí),連接DG,請直接寫出SKIPIF1<0___;(3)如圖3,根據(jù)以上條件,點(diǎn)P為AB的中點(diǎn),點(diǎn)M為射線AD上的一個(gè)動點(diǎn),連接PM,PC,當(dāng)

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