高等數(shù)學(xué)A1學(xué)習(xí)通超星期末考試答案章節(jié)答案2024年

高等數(shù)學(xué)A1學(xué)習(xí)通超星期末考試章節(jié)答案2024年/star3/origin/e9f9d1c1d1c0495edeae6164328fd8a7.png

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答案:0/star3/origin/57398ce5c0dfec2d5fc7cc07d05de923.png

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答案:錯/star3/origin/3790cba875d7947c64c5f14ffd0c47a9.png

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答案:錯/star3/origin/392c9ff1ae08cc104b25536e3b1c1988.png

答案:0/star3/origin/d4f31afdd9c04f1d9c6acd731c2690d6.png

答案:錯/star3/origin/a5ab97db159b58f379d8219ebc531ffc.png

答案:錯/star3/origin/292cea7cf254d07a154efa975229d543.png

答案:對/star3/origin/e5841be97ef9b9a4abc340ddb274dd1f.png

答案:0/star3/origin/d671649fcbb1ea4865118a9bc526fbe5.png

答案:0/star3/origin3e4361f20e31650145e7.png

答案:錯/star3/origin/f65c54b4eae83127b1faa7300839d5ef.png

答案:錯/star3/origin/92c63f9e2500403d4dab757d3fa16ef1.png

答案:0/star3/origin/ce00e9fd632bb7c35787889eaee462aa.png

答案:0.01/star3/origin/bfe96380db3e07f94950e09c5774ff47.png

答案:0/star3/origin/d7760e592cd8a565c3afd1538c8cc321.png

答案:e-1/star3/origin/ebec143b5c5dcd3177c234113d457fc2.png

答案:解:因?yàn)?所以該函數(shù)為偶函數(shù)。/star3/origin/151db3e8317407beea1787f178634e28.png

答案:因?yàn)?所以該函數(shù)為奇函數(shù)。/star3/origin/3e28dd0ea58753dbf611bc575acd72e2.png

答案:要使函數(shù)有意義,只需即,所以該函數(shù)的定義域。/star3/origin/c61d31f10c079593bc3a70ce40f7f04a.png

答案:要使函數(shù)有意義,只需即,所以該函數(shù)的定義域?yàn)椤?star3/origin/7ad8477e241de60eb32a1c3485fc1d51.png

答案:D/star3/origin/581aefe60c466c41caf3525f57654f96.png

答案:D/star3/origin/bb9fcd99bdd72bfb249ef4d88a6c01e5.png

答案:錯/star3/origin/d93c4836fd00beed0cb1c45c49105a78.png

答案:對/star3/origin/ded28324db862b15e3e7176d68cbef51.png

答案:b/star3/origin/32bac785da4abd7fcda0304e34c38684.png

答案:因?yàn)橛薪?所以,,;又因?yàn)?所以,,時(shí),有;即,故。/star3/origin/0f0ec6b469cb4b9e83b516a773c03658.png

答案:,時(shí),有,而,故。反過來未必成立:令,則,而不存在。/star3/origin/2121f3dd33a6b7258a687b08939077b0.png

答案:a;b/star3/origin/9c49bcd165448e2bbd00a9a5a4f1eb94.png

答案:必要條件/star3/origin/3de64918b0d3f27b3211f94c8c55e596.png

答案:因?yàn)?,所以;因?yàn)?,所以不存在。/star3/origin/841809f586c15eb2c11fab22a268d95e.png

答案:原式===。/star3/origin/ef6964170f9c7d8843054efa679d2f42.png

答案:原式=。/star3/origin/dbf451e1baa8890886686c63b3051277.png

答案:原式=/star3/origin/bb017943892805c7e2f365a382ea9381.png

答案:原式=。/star3/origin/15cf565bc95b9ea52eb4febb9072f90c.png

答案:原式=。/star3/origin/009d46d9c15f60c2f3d81b30966af88c.png

答案:原式=/star3/origin/3c7f561a384bf51cf446f74d4e676f92.png

答案:原式=/star3/origin/f2390e5e61b3266d3daec574e1bed259.png

答案:大/star3/origin/fd111fbaebb89731919101a904940b03.png

答案:小/star3/origin/f18975c442af9e194707cd513e1cc98a.png

答案:1/star3/origin/56d9b75d99c433137a0194e51581cef4.png

答案:0/star3/origin/768f8c5d20cd2ffa4d7d89514630854f.png

答案:1/star3/origin/71d29f620b88692d8ac2658b5980f8f8.png

答案:0/star3/origin/83fc3521272e5488934ece01eeba2c2b.png

答案:2/star3/origin/6ec5756c0f206c5021f6093cefe20406.png

答案:同階/star3/origin/d1fdb3ebb8fc4fd69588115b488aefc6.png

答案:等價(jià)/star3/origin/f4e014033d49bd3e0103ce6145b63143.png

答案:設(shè),則在上上連續(xù),且,若,則即為根,若,則由零點(diǎn)定理,在存在點(diǎn),使,故程,其中,至少有一個正根,并且它不超過/star3/origin/d7bab1d874fc1c132d3e6fadf0a8e695.png

答案:原式==。/star3/origin/73404b108389d58558157044bafb4006.png

答案:因?yàn)?所以。/star3/origin/fcbfb4b2a51618dee3b9a7ad16347cdb.png

答案:連續(xù)/star3/origin/841eea44608829f23308bc13c5b7a42f.png

答案:,因?yàn)?,所以。/star3/origin/c11224d617503153e7e06239b25c0fe8.png

答案:原式=/star3/origin/ac2acdbf629148fb56b3a397679e179f.png

答案:原式=/star3/origin/f0bfc95de9f1d5429ea0af4f33c3f7ed.png

答案:原式==。/star3/origin/c2a4d59844eb6735eca42a4d2ddcc649.png

答案:B/star3/origin/e7347fabdc8acc66de0fd4fe5b72e715.png

答案:與同階但不等價(jià)的無窮小/star3/origin/2dba835983d72dc9344f751f4f97e485.png

答案:極限不存在/star3/origin/3d2187c191e34a6b7db39e84556a6743.png

答案:可去間斷點(diǎn)/star3/origin/d18dab1b6591012fb643cb78352b82f8.png

答案:1/3【單選題】無窮多個無窮小量之和().

答案:是無窮小,或是無窮大,或有可能是有界量/star3/origin/b0dce5102b9740fa3605123416461856.png

答案:0/star3/origin/0c77193601f86e9def01eb43cf53bd21.png

答案:解:因?yàn)?所以又因?yàn)?所以,即,,,,所以,所以,即/star3/origin/0acd8d52ab21c8cb542da45a25705ee9.png

答案:解:因?yàn)?切線:,即法線:,即/star3/origin/08fdeb013601e61e5afdf67104e26f92.png

答案:解:因?yàn)?所以。/star3/origin/e7ca3b183b05d736017548db0cccdf12.png

答案:解:因?yàn)?所以。/star3/origin/4c8f0b11b8709343dc88b75cf58e7750.png

答案:1;1/star3/origin/ad3e6ce976e6592e67d4c71673a1ff3e.png

答案:連續(xù),但不可導(dǎo)。/star3/origin/7a5266a03b935587cac741340aba4d5c.png

答案:(1,0)/star3/origin/c672cd7b4f5f7e817aff2967064e9a2e.png

答案:解:。/star3/origin/dafbf76883b8b1d90d4931ff5f182997.png

答案:解:。/star3/origin/a60a9386396c2d4278a80053ddc799dd.png

答案:解:。/star3/origin/6eec4037a955f6dcba896a8f29f84549.png

答案:解:。/star3/origin/76d3118688eeecd77da010dd4d2a5c32.png

答案:解:/star3/origin/832bc5479feadfb51dacdc411ad92eae.png

答案:解:/star3/origin/73254e62e08922e5dff910cdfb6c58f4.png

答案:解:。/star3/origin/02acad4a98ce7511b9a28b4a8f874e14.png

答案:解:/star3/origin/e954c229cddf7ec82112bb857c259a08.png

答案:(1;(2;(3;(4;(5;(6;(7;(8;(9;(10)(10);(11)(11);(12)(12);(13)(13);(14)(14);(15);(16);(17)(15)/star3/origin/2d61bffa0e7ef01cd2c95f39d8889c7a.png

答案:解:,,,,,。/star3/origin/57a8fcf680282e2bda0377daf3d3cffb.png

答案:答案:（1),

;(2);。/star3/origin/b3048d8c2bbe74ff01f7d3c8915bfdef.png

答案:方程兩端同時(shí)對求導(dǎo)數(shù)得。/star3/origin/d32bc6f169cc7a7e36ee43f3d12a7ca3.png

答案:1/star3/origin/9106a4e86dcba6b776c1ea6b46d12143.png

答案:。/star3/origin/7865100b61353396e70a554dc4277fd7.png

答案:18;11/star3/origin/f513513ffd53e33a68225cbfa7d825f0.png

答案:。/star3/origin/aae7161c9d428778c22bc7e00e8b9340.png

答案:因?yàn)?,所以在處不可導(dǎo);又,,即所以在處連續(xù)。/star3/origin/a65281e4579b21c6ccbf44e871cf872b.png

答案:設(shè)點(diǎn),由,切線斜率,即;又;所以。/star3/origin/ca6906c7daa6a604769272613b49d470.png

答案:由,有,即;由,有,即。/star3/origin/d4b2a5b9e09df0ccbd63f009911e2837.png

答案:由存在,有在連續(xù),,,即;,,即,所以。/star3/origin/7da2f1cd7a56633379600f92402eb53c.png

答案:1/star3/origin/7c6d30ec9cd89684b2989929865ecb71.png

答案:設(shè),顯然在上連續(xù),在內(nèi)可導(dǎo)且,應(yīng)用柯西中值定理,存在,使得,即。/star3/origin/69c71ecd200e5500cda04467c5368ef9.png

答案:設(shè),,顯然在區(qū)間上連續(xù),在內(nèi)可導(dǎo),應(yīng)用拉格朗日中值定理,存在,使得,即,故。/star3/origin/024f21e3a81553dea807dfcc9ea0946f.png

答案:設(shè),因?yàn)?,所以即。/star3/origin/51f76bec6ed331618c4f4b1bb30e499e.png

答案:原式=。/star3/origin/1b42c4387626a19476d1b7e181093589.png

答案:原式=。/star3/origin/97d7e9c40145d1195c6e138bcef314a8.png

答案:原式=/star3/origin/8f3663fc0298c60526b7555708fed36f.png

答案:原式=。/star3/origin/02945b1bd99b2c947acc370771056159.png

答案:原式=/star3/origin/15139d943d68cf13341e20f946cd9d3a.png

答案:錯/star3/origin/0caf39ffaf4d2f4bbb75491a3fd33c5e.png

答案:錯/star3/origin/ab16984f70b305aa857723148790ae5c.png

答案:3/star3/origin/7114396b79b44a117fcf92fa0b975ac8.png

答案:9/2/star3/origin/6317ba8f91f86e925d2e137f40b068b4.png

答案:1/star3/origin/f21e857fb2f838c93033d65e4b2ac21b.png

答案:原式=。/star3/origin/7ac876bae3a9d575d99a1a39369ab343.png

答案:由,所以;或。/star3/origin/c143e85ad0cba9c69495e720786c2303.png

答案:A/star3/origin/ad0c4f306ead8c66b18dca21270b9b7b.png

答案:A/star3/origin/ea7a8aa6ba4de515433831b7bef42be3.png

答案:3;-1【單選題】下面結(jié)論正確的是()。

答案:可導(dǎo)函數(shù)的極值點(diǎn)一定是駐點(diǎn)/star3/origin/32d26cc8e0689f93fa590fb3faa51a60.png

答案:2【單選題】設(shè)f(x)和g(x)都在x=a處取得極大值,F(x)=f(x)g(x),則F(x)在x=a();

答案:不能確定是否取得極值/star3/origin/e66d081d36778d9ee8d36195c534dd0f.png

答案:函數(shù)的定義域?yàn)?,令,,當(dāng)時(shí),不存在,令,,當(dāng)時(shí),不存在,不存在00不存在拐點(diǎn)拐點(diǎn)極小值/star3/origin/dbe19d169ff43271a1415235687ad050.png

答案:函數(shù)的定義域?yàn)?令,,令,,000極小值1拐點(diǎn)極大值5/star3/origin/4aa5aba2ecfe97348bcb110a015d5e53.png

答案:因?yàn)?所以,由,得,故所求曲線方程為。/star3/origin/7c27cc29243357aaf455ea2327f59f5e.png

答案:,由,得,所以。/star3/origin/699dd97bfae13182fd8eef2bd27529e9.png

答案:原式。/star3/origin/bbf6c05a6ef9e9730d0925e190dbd7d4.png

答案:原式。/star3/origin/682906acaedfd52b5475811c031580d5.png

答案:原式。/star3/origin/ad7c2e1b50469943187ee83cad9f80a4.png

答案:原式。/star3/origin/fa996c2f70a1e776755e2538f75f8bb6.png

答案:原式。/star3/origin/f78817cd2a89b43e1a94c0d5ce2c6d9b.png

答案:原式。/star3/origin/4d4ac27c4154c859daa03292d932ba49.png

答案:對/star3/origin/65e02c48333315a7719b997acf7e6fdb.png

答案:對/star3/origin/538295afefb0dc166b8d14e1ee790cb8.png

答案:對/star3/origin/974c943bd3d35b6deaac7ad862bd17ac.png

答案:錯/star3/origin/65babca7f4e31dc469e04483cfd5c0b9.png

答案:錯/star3/origin/3a907301d6d844c2501b02ac94d48cbd.png

答案:對/star3/origin/e5c6888c822c31be723f0a2523567aac.png

答案:原式

。/star3/origin/349feb28f728c6cb81ac5db0b8e7bb65.png

答案:原式

。/star3/origin/beff1e6a1a6793d0bb5660d52df3b52d.png

答案:原式

。/star3/origin/78a84aee19843ad62d6f49ca7bfb7aeb.png

答案:原式

。/star3/origin/8304f36a84a22f1460e55b66b647e700.png

答案:原式

。/star3/origin/ce8adc63c34df4a3526ff8170c2b5131.png

答案:原式

。/star3/origin/4d4df35a02826e9064a3673470c437fc.png

答案:原式

。/star3/origin/b49fff93523f22324a80e68b3d537bd6.png

答案:對/star3/origin/28235b745b4f4d09d9f879c4aca3d874.png

答案:對/star3/origin/73b1697409ba1d9276e0c09b04c1338f.png

答案:原式

。/star3/origin/d9f7e87931c450cbaecf2483d405d619.png

答案:原式

。/star3/origin/47c856013d8f84581d749f02cd8d7786.png

答案:原式

。/star3/origin/ee84e8e8cd1c62a5a38e66b78308e02f.png

答案:原式

。/star3/origin/d743587c47868f44df94d5471c295a53.png

答案:原式。

原式

?！九袛囝}】第二類換元法最后一步不需要將中間變量代換回原來的變量。

答案:錯/star3/origin/1f89b0d8f7722af72b15b1877142cd3e.png

答案:(1)解:原式(2)解:原式。。(3)原式(4)原式。所以原式。(5)解:因?yàn)樗栽?6)解:原式。/star3/origin/3330383cbb40d67f81dea68e214712d8.png

答案:(1)解:原式。(2)解:原式。(3)解:原式。(4)解:原式。(5)解:原式。(6)解:原式。/star3/origin/d841cdab07658939396dfe5f002a1485.png

答案:錯【判斷題】有理函數(shù)的積分,需要先拆項(xiàng)化成簡單形式()。

答案:對/star3/origin/0f589fec5a5745f0c72acbb4d2da4956.png

答案:和/star3/origin/1c5baecf7429aa8a08a630fc81c77bef.png

答案:解:原式,,由,得,所以原式。/star3/origin/cb21ca415352c2e3ac41780a577e574d.png

答案:(1)解:原式。(2)解:原式。/star3/origin/abe87491984c96bff3838d3b7ba092b9.png

答案:因?yàn)?,所以。,/star3/origin/588a33f95eae66588095abe0f36946fc.png

答案:>/star3/origin/f48ae7d256652f60d93343bd86135639.png

答案:</star3/origin/76b2d0e91520f4afc4d039e5c9be392b.png

答案:</star3/origin/3ab48a3f36285ccee290aacf53f8054e.png

答案:1/star3/origin/8fa3a3a8bb4c520543c6dea521020552.png

答案:。/star3/origin/1009e4b9635aba39583e5246f3a439a4.png

答案:原式。/star3/origin/7084d3485ae73834216d17dbd62c3a33.png

答案:原式。/star3/origin/b5031036e3d788d348c2d8a67a384449.png

答案:原式。/star3/origin/57bd1fb5a5444012a072e648e090d016.png

答案:;/star3/origin/d4871904e0f9ee68e1d346ab6e0dd3ad.png

答案:3/star3/origin/8713fe7936cb2e675a0424f8645a920a.png

答案:1)原式。2)原式。/star3/origin/7611607311679eab0eec0e25149f2154.png

答案:原式。/star3/origin/c7cd2e1e4a77cf6e22eecde2f49b091f.png

答案:原式。/star3/origin/3031a41bbbd6e7219a5c65e0024068c6.png

答案:原式。/star3/origin/adc7b0b1cfa1093a6f6fb4dd9dbe3c4d.png

答案:原式。/star3/origin/d674ed798e2679e3a5f336c15d38e85e.png

答案:1)原式。2)原式。3)原式。/star3/origin/f59f8b1ec1e71ad6ab33d0b539f490e7.png

答案:原式。/star3/origin/0655d5e48b8d3b1e5e796608960ef820.png

答案:原式。/star3/origin/770f9343fa7d59b60a0fd71c36906d41.png

答案:原式。/star3/origin/4d9fb839eff87f5f9e4e9037b39b22f1.png

答案:原式。/star3/origin/7555909261c5d143676b9e8aed6247b8.png

答案:原式。/star3/origin/9fdb8c21af59a6156e471c5d92ef6518.png

答案:原式。/star3/origin/5f4493cd97847a5720b1c5e7fb4ad7d5.png

答案:原式。/star3/origin/224e3c1e5c3faf4da153f877b59faf01.png

答案:0/star3/origin/fee2e140f950783dbfa4b03cd5f8f4f6.png

答案:原式。/star3/origin/fc8b8e7eb1363b9cee770b9452fc30a1.png

答案:解法一:原式。解法二:原式。/star3/origin/495c65ce85fa9292f9c92118ca7c8bb7.png

答案:原式。/star3/origin/b5b9cf30ce2d1af3fdb34fd3d0475990.png

答案:所以,原式/star3/origin/fec848af5016db4d30ff3c228b58c502.png

答案:原式/star3/origin/98644ed416814117ef5efbc4b224826f.png

答案:。/star3/origin/482aaa33ca472c3b15b2d4fcf4b5a252.png

答案:因?yàn)?所以的值只與有關(guān),與無關(guān)。/star3/origin/ce4ca7b594b1091f5eb6609ced1cc40c.png

答案:令,因?yàn)?所以原式=0。/star3/origin/276120b7db122bf66d08e3ffae6529e9.png

答案:原式/star3/origin/d39f38a1486ec0b01a9adcb365c423bd.png

答案:0;0;;;1;0;;;1;(10)4/star3/origin/439774ae485f8cdd33037ec8d6a0750f.png

答案:因只要求出該柱體的底面積即可。法一:如圖,將S拆分為4個部分,則有而法二:如圖,將S拆分為2個部分,則有法三:先考慮單位圓的情形,則有對圖形做橫向拉伸a,縱向拉伸b,則:/star3/origin/39a5924035749fab70585d19094f147f.png

答案:答案:。/star3/origin/c769e59f0f3fa49fac0f4f611ce6a685.png

答案:;。/star3/origin/880d049709c96cd605368396ee87400b.png

答案:答案:。/star3/origin/bf977826079bf5351903d80abb6b993e.png

答案:答案:。/star3/origin/36ab49ef6c8d644bcc29d76ca5d5731f.png

答案:1/star3/origin/9caec9612bd3cc5cbe80e22e1b47a5f9.png

答案:;/star3/origin/a8e6fb8482dc5d36c785ac0c0b7ee55f.png

答案:;/star3/origin/d04c0a496cd3d617c70cf5410a865e9f.png

答案:2;/star3/origin/d90de6ed4a8ab565d69bceae32302db4.png

答案:分離變量得,,,兩端同時(shí)積分得,由,得,特解。/star3/origin/0473c1c2f23e537172162a597d3b56ae.png

答案:分離變量得,,,方程兩端同時(shí)積分得,,通解。/star3/origin/38fcecdba8559ecafce3a3631bd0e75e.png

答案:分離變量得,,,方程兩端同時(shí)積分得通解,,。/star3/origin/3e6adfbf11c333524797ce72a4a42c92.png

答案:分離變量得,,,方程兩端同時(shí)積分得,,通解。/star3/origin/73b0619f44b9662095172b1522e36e45.png

答案:分離變量得,,,方程兩端同時(shí)積分得,,通解。/star3/origin/32a1c9e5140bba25ed5271fef8e6e7bd.png

答案:方程變形得,令,則,再令,得,分離變量得,變形得,,方程兩端同時(shí)積分得,,,通解。/star3/origin/38a79c8624e8e42f4bfe5200bbe75110.png

答案:令,則/star3/origin/c4130d2960bc49a0a513e234387e11eb.png

答案:方程變形得,令,則,,,,兩端同時(shí)積分得,通解。/star3/origin/75a07371a4814cc4a6955812451627d9.png

答案:方程變形得,令,則,,,,兩端同時(shí)積分得,通解。。/star3/origin/53090907e7ed97a44dd9fa9942cd2c82.png

答案:方程變形得,,,通解。方法二:,,,,。/star3/origin/7b6e435a35f335d5e8a6414abb912440.png

答案:方程變形得,,,通解。方法二:,,,。/star3/origin/9fff29ec6350c44a2fec3ba81590416e.png

答案:方程變形得,,,通解。/star3/origin/8bc734d0a1afb481f6df88e184f9dddd.png

答案:方程變形得,,,通。方法二:,。/star3/origin/33d574039c7e70e6e13bc70f6f131775.png

答案:.;答案:/star3/origin/ad9d865bf2b952ebf52500ee90750613.png

答案:令,則,,,由,得,所以,,由,得,故。/star3/origin/45ac41e6f229901661a30129c95a9fc4.png

答案:令,則,,,,,由,得,,,,由,得,故。/star3/origin/55a8678dd0187472de1c81fc154c9611.png

答案:,/star3/origin/217674e0369c11dadc911c3db345bb37.png

答案:,,。/star3/origin/5e53c6748912291814177d7233a2df4b.png

答案:。;答案:/star3/origin/53a4b8ca4d3cf916f239c898f7d15eb5.png

答案:無;相;無/star3/origin/6e3a2c3236f2fd00c3abde36a3e6f9dd.png

答案:特征方程為,特征根為,,特解形式。/star3/origin/33225af0c420625fc1709c95e64d1c09.png

答案:特征方程為,特征根為,不是特征方程的根,設(shè)為原非齊次方程的特解,代入非齊次方程使方程兩端恒等化解為:,所以通解。/star3/origin/4c9547c7808c64d4c0030d5e2624edf9.png

答案:特征方程為,特征根為,不是特征方程的根,設(shè)為原非齊次方程的特解,代入非齊次方程使方程兩端恒等化解為:,所以通解。/star3/origin/d55aff230ad312162a4969a857716078.png

答案:特征方程為,特征根為,,是特征方程的單根,設(shè)為原非齊次方程的特解,代入非齊次方程使方程兩端恒等化解為:,所以,,通解。/star3/origin/b8b861cf36b63c09c3dd810814e415b9.png

答案:特征方程為,特征根為,是特征方程的重根,設(shè)為原非齊次方程的特解,代入非齊次方程使方程兩端恒等化解為:,所以,,通解。/star3/origin/3740b18e2891d237ed0f28796e6eda1f.png

答案:答案:特征方程為,特征根為,,特解形式。/star3/origin/49dba01928c09273dd0a14675f37b181.png

答案:。/star3/origin/5d94ea2d279c904214ca7182b59cb136.png

答案:;/star3/origin/c27a7047e40c1061e46bc19b679b41ad.png

答案:;/star3/origin/5f3bb4fb39301d7ee9be8bfde51d82bd.png

答案:方法一:令,則,,,,,,,,,,通解。方法二:,。/star3/origin/d5c25fa4e4f460c5f80e0fca041d3cea.png

答案:方法一:方程變形得一階線性非齊次形式,,,通解。方法二:,,。/star3/origin/83f78aa20ca5b32244587653d7fd65b2.png

答案:特種方程為,特征根為,不是特征根,設(shè),代入原方程得,通解。/star3/origin/d181edffa0453a1593d005c207868c59.png

答案:,,,。/star3/origin/773388666c60f0d4f23f3f11bd92b825.png

答案:,,/star3/origin/b1bb07ad0e1ed40fa12c5eb2122a4d2a.png

答案:./star3/origin/a16a1d88796b3357f504ec0e14073cac.png

答案:相關(guān)/star3/origin/17f8057840569b2d48140bf8a0c47186.png

答案:二階/star3/origin/64fb83ce1ee471dd857cb976575209bd.png

答案:必要條件下列命題不正確的是()

答案:有界數(shù)列一定收斂/star3/origin/d5eb198aa6a58a3f601e84506096fa46.png

答案:與有關(guān),但給定時(shí)N并不唯一確定/star3/origin/d43cc54100507a1fb456c6ddec0f9b37.png

答案:對/star3/origin/bdb704cef0e5805f9caaf76594a76634.png

答案:錯/star3/origin/b558329ff2116d2f3cbe523f400ad3a9.png

答案:對/star3/origin/61d8e06037b605ff2d99ac008f38a76e.png

答案:ⅹ下列命題正確的是()。

答案:若存在,則極限唯一/star3/origin/2b028af555678e88864e8dc9ebd8af59.png

答案:充分必要條件;/star3/origin/fff37afeb090e2ca889f1ad1f307acd4.png

答案:錯/star3/origin/5d451741ad0a9aadc1647aa5b589f399.png

答案:錯/star3/origin/9b867db09e1591b5dbe2bd53dc748196.png

答案:錯/star3/origin/363926048f76b132d571f1770794bd17.png

答案:錯/star3/origin/a76f00d33a11975aade60d05f05dc7a9.png

答案:錯/star3/origin/312f7a1c6a2c13970539d75834f9ff0e.png

答案:對/star3/origin/5427664a538e9fca95c384ed93f038c7.png

答案:錯/star3/origin/d340ad130c434384fb5bc054c81f7bac.png

答案:對/star3/origin/7ae892b0d5dd8d9f3ca6d967c7274827.png

答案:對/star3/origin/998013355e886ff5cda38d076aef4e7d.png

答案:不存在A.B.C.D.不存在/star3/origin/2b403c1d316fdd64bb3d5496a831d90d.png

答案:e/star3/origin/f714a6c69a11adca93f8f025253a2378.png

答案:易知,又.由夾逼準(zhǔn)則,可得/star3/origin/6bcab731e7fce5505a696c040233fb3e.png

答案:由于,,故,從而不存在./star3/origin/a58ff107fe5dc976afbfdd4ced8b960e.png

答案:;0/star3/origin/c4a30d28ba1ab3837168bdeaf1f4f73c.png

答案:;-1/star3/origin/b9fd60ed6588594f381772fdd157bb31.png

答案:；1/2/star3/origin/3296b624c64556cc7a9687e219467d01.png

答案:1/star3/origin/ac384767a4fbd6bee6de212f1029a88b.png

答案:；1/star3/origin/daf6ac4e608be1b95563ca43191a4327.png

答案:-1；/star3/origin/29b58fa9a69fdbc54ca0d35ab031a37f.png

答案:;1/star3/origin/47ac309a3ee352e099f38b81c0fdd07c.png

答案:在處連續(xù)/star3/origin/e8cedc270c608052ba9b6adc6b8e3a04.png

答案:必要條件/star3/origin/6b32945a9522bb2f943e4ec08237cfef.png

答案:為其可去間斷點(diǎn)/star3/origin/632dc70d756345c74ac9ee9f37aa6ac1.png

答案:無窮間斷點(diǎn)/star3/origin/f25e18f05ed375311c5c50c0860979e0.png

答案:對/star3/origin/77fa4c92b26eca41ed2c7c55d9b97a19.png

答案:對/star3/origin/8b5aaef3b87e01c448336e6981ae9039.png

答案:錯不連續(xù)函數(shù)平方后仍為不連續(xù)函數(shù).()

答案:錯/star3/origin/a744adaf7878594e188b2951378eda84.png

答案:對/star3/origin/6882471ec4e2eac1f78541c9596fa5d5.png

答案:錯/star3/origin/a1659b31f486a174d3b34d3224afc30d.png

答案:對函數(shù)在一點(diǎn)處的導(dǎo)數(shù)就是該曲線在該點(diǎn)處切線的斜率.()

答案:對/star3/origin/e1ec6ea52bc13c6ae40b04a3968a1189.png

答案:連續(xù)但不可導(dǎo)/star3/origin/bb69f5ec5e3525bb89b1447c4fe8d293.png

答案:連續(xù)但不可導(dǎo)/star3/origin/57371f12cb4b38c6bd158c4456f6d76d.png

答案:不存在/star3/origin/ac712f30c38059e9f97642d1f53ee682.png

答案:./star3/origin/80373eb4bd28bee37980456b0b8d6f4d.png

答案:./star3/origin/8be789ea5730f146772337310194736a.png

答案:.

當(dāng)時(shí),

,

,

,所求切線方程為

,即;

所求法線方程為

,即./star3/origin/67245cc2137cc4550d18c2f4677f8eb3.png

答案:,

./star3/origin/0a6e02e78f30d3e742900f7ba3e38107.png

答案:,

./star3/origin/7dfa4423c4f6fe757fb130a6e644e792.png

答案:,

./star3/origin/8de75276820d1618d9213d4fc9ef63b8.png

答案:./star3/origin/24db8142c77c34b3e96f37d90d5c822e.png

答案:兩邊取對數(shù)得

,

兩邊求導(dǎo)得

,

于是/star3/origin/0d2c4c57366c7476c055eba56052a765.png

答案:對方程兩邊關(guān)于求導(dǎo)數(shù)

于是

解得

.對方程兩邊關(guān)于求導(dǎo)數(shù)

./star3/origin/06274e96bbc9de012295b7f759e6d894.png

答案:對方程兩邊關(guān)于求導(dǎo)數(shù)

于是

解得/star3/origin/6bf558c2d6edb3c5e53f3c21f1c7390f.png

答案:錯/star3/origin/3780953b78638ac4e2f51d7d9ed56fa3.png

答案:對/star3/origin/cef6fa84ff2ba7a23bd4bff0adf3214d.png

答案:-3/star3/origin/a41af5ea46f8bf77b191d930de6b8dd9.png

答案:為的線性函數(shù)/star3/origin/73aa16fe1dd2778c6d7e9a16d5eac47b.png

答案:高階無窮小/star3/origin/149329ce587055d940ee63a9f7dfd8b7.png

答案:錯/star3/origin/9a8a1f8759d1dcf3e55b1af719e87ae8.png

答案:對/star3/origin/73feac00d2553ed9ca7f505060b7052c.png

答案:錯/star3/origin/1a0bdc714df8ad73d99c3dbc199d9166.png

答案:對/star3/origin/5c2478e69247ac536b6f7f977050d786.png

答案:對/star3/origin/c48ef286bc2566cf73844bf6a57a84b6.png

答案:錯/star3/origin/781b7913ca86ebf670abce77493924c3.png

答案:錯/star3/origin/e021f0c82be0e40bf99443ac6d302484.png

答案:在上羅爾定理成立下列各式中正確運(yùn)用羅必塔法則求極限的是()

答案:=/star3/origin/693d136f2fc5584529d0713b2c9057c2.png

答案:充分條件/star3/origin/02a3d51e721c7223c94fabd0dea7a83b.png

答案:原式/star3/origin/5c8596f3aacaed22e6f7e4688e09857b.png

答案:對任意,有(是任意常數(shù))/star3/origin/8f9b428ab4200513fea0071bc686c96f.png

答案:有且僅有一個實(shí)根/star3/origin/d3532a59ec3032c65967c2854c808d3d.png

答案:因?yàn)?

而

,

所以

./star3/origin/0f07a24fbbb3505b96ee6b0eb0b70f08.png

答案:,極限是存在的.

但不存在,不能用洛必達(dá)法則./star3/origin/a34657a02efae5e520f45e68c9805bd2.png

答案:證明設(shè),則在閉區(qū)間上連續(xù),在區(qū)間內(nèi)可導(dǎo),由拉格朗日中值定理,至少存在一點(diǎn),使

即.

因?yàn)?所以,即

,即./star3/origin/3ccccf6806deed530700208a027e27cb.png

答案:解:/star3/origin/93e207c543eb26f4921e92c3fd309add.png

答案:./star3/origin/7f557d7fd99e440343ac8f771af08ef5.png

答案:.無窮大量必是無界變量.()

答案:對兩個無窮小之積仍是無窮小.()

答案:對/star3/origin/dfe28e7aa1d9c87deb2bf0390160a13a.png

答案:對兩個無窮小之和仍是無窮小.()

答案:對兩個無窮大之和仍是無窮大.()

答案:錯/star3/origin/3ad059faa17d80aa60074ad305b9c6a3.png

答案:錯零是無窮小.()

答案:對無界變量必是無窮大量.()

答案:錯/star3/origin/b44186aa1ffaed19916968701f45a65e.png

答案:無窮小;無窮大/star3/origin/5e995de8cefd2d318e872201f5b828ba.png

答案:無窮小/star3/origin/5e139dfa06b75808713c6d730a8d7495.png

答案:無窮大;無窮小/star3/origin/8a0649847ac94a69dfce1f787dd74f78.png

答案:無窮大;無窮小若x是無窮小,下面說法錯誤的是()

答案:x-0.0001是無窮小;/star3/origin/be027bc6efafa155f3dac35e7201a577.png

答案:0下面命題中正確的是()

答案:無窮大必是無界變量在x→0時(shí),下面說法中錯誤的是()

答案:sin是無窮大;/star3/origin/3de0c0e3e90ef16a58f5e39b540ce61f.png

答案:原式=。/star3/origin/2c03e020be06d004c27abaeed628f3ca.png

答案:原式=。/star3/origin/cfd11622b83c97521779c5d45eff9137.png

答案:原式=/star3/origin/6bfd66773f0a37db68e312c36f947714.png

答案:原式=。/star3/origin/7c07a5b7d2f52c505f70e3e5b17c0232.png

答案:原式==/star3/origin/dfee816e039ebc965dd91770c079