新高考數(shù)學(xué)一輪復(fù)習(xí)講練測第2章第07講 函數(shù)與方程（講義）（原卷版）

第07講函數(shù)與方程一、函數(shù)的零點(diǎn)對(duì)于函數(shù)SKIPIF1<0，我們把使SKIPIF1<0的實(shí)數(shù)SKIPIF1<0叫做函數(shù)SKIPIF1<0的零點(diǎn).二、方程的根與函數(shù)零點(diǎn)的關(guān)系方程SKIPIF1<0有實(shí)數(shù)根SKIPIF1<0函數(shù)SKIPIF1<0的圖像與SKIPIF1<0軸有公共點(diǎn)SKIPIF1<0函數(shù)SKIPIF1<0有零點(diǎn).三、零點(diǎn)存在性定理如果函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的圖像是連續(xù)不斷的一條曲線，并且有SKIPIF1<0，那么函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)有零點(diǎn)，即存在SKIPIF1<0，使得SKIPIF1<0也就是方程SKIPIF1<0的根.四、二分法對(duì)于區(qū)間SKIPIF1<0上連續(xù)不斷且SKIPIF1<0的函數(shù)SKIPIF1<0，通過不斷地把函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間一分為二，使區(qū)間的兩個(gè)端點(diǎn)逐步逼近零點(diǎn)，進(jìn)而得到零點(diǎn)的近似值的方法叫做二分法.求方程SKIPIF1<0的近似解就是求函數(shù)SKIPIF1<0零點(diǎn)的近似值.五、用二分法求函數(shù)SKIPIF1<0零點(diǎn)近似值的步驟（1）確定區(qū)間SKIPIF1<0，驗(yàn)證SKIPIF1<0，給定精度SKIPIF1<0.（2）求區(qū)間SKIPIF1<0的中點(diǎn)SKIPIF1<0.（3）計(jì)算SKIPIF1<0.若SKIPIF1<0則SKIPIF1<0就是函數(shù)SKIPIF1<0的零點(diǎn)；若SKIPIF1<0，則令SKIPIF1<0（此時(shí)零點(diǎn)SKIPIF1<0）.若SKIPIF1<0，則令SKIPIF1<0（此時(shí)零點(diǎn)SKIPIF1<0）（4）判斷是否達(dá)到精確度SKIPIF1<0，即若SKIPIF1<0，則函數(shù)零點(diǎn)的近似值為SKIPIF1<0（或SKIPIF1<0）；否則重復(fù)第（2）—（4）步.用二分法求方程近似解的計(jì)算量較大，因此往往借助計(jì)算完成.【解題方法總結(jié)】函數(shù)的零點(diǎn)相關(guān)技巧:①若連續(xù)不斷的函數(shù)SKIPIF1<0在定義域上是單調(diào)函數(shù)，則SKIPIF1<0至多有一個(gè)零點(diǎn).②連續(xù)不斷的函數(shù)SKIPIF1<0，其相鄰的兩個(gè)零點(diǎn)之間的所有函數(shù)值同號(hào).③連續(xù)不斷的函數(shù)SKIPIF1<0通過零點(diǎn)時(shí)，函數(shù)值不一定變號(hào).④連續(xù)不斷的函數(shù)SKIPIF1<0在閉區(qū)間SKIPIF1<0上有零點(diǎn)，不一定能推出SKIPIF1<0.【典例例題】題型一：求函數(shù)的零點(diǎn)或零點(diǎn)所在區(qū)間【例1】（2023·廣西玉林·博白縣中學(xué)?？寄M預(yù)測）已知函數(shù)SKIPIF1<0是奇函數(shù)，且SKIPIF1<0，若SKIPIF1<0是函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)，則SKIPIF1<0（

）A．SKIPIF1<0 B．0 C．2 D．4【對(duì)點(diǎn)訓(xùn)練1】（2023·吉林·通化市第一中學(xué)校校聯(lián)考模擬預(yù)測）已知SKIPIF1<0是函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練2】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的零點(diǎn)依次為SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練3】（2023·全國·高三專題練習(xí)）已知SKIPIF1<0，若SKIPIF1<0是方程SKIPIF1<0的一個(gè)解，則SKIPIF1<0可能存在的區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【解題總結(jié)】求函數(shù)SKIPIF1<0零點(diǎn)的方法：（1）代數(shù)法，即求方程SKIPIF1<0的實(shí)根，適合于宜因式分解的多項(xiàng)式；（2）幾何法，即利用函數(shù)SKIPIF1<0的圖像和性質(zhì)找出零點(diǎn)，適合于宜作圖的基本初等函數(shù).題型二：利用函數(shù)的零點(diǎn)確定參數(shù)的取值范圍【例2】（2023·山西陽泉·統(tǒng)考三模）函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0存在零點(diǎn)．則實(shí)數(shù)m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練4】（2023·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)在區(qū)間SKIPIF1<0內(nèi)，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練5】（2023·河北·高三學(xué)業(yè)考試）已知函數(shù)SKIPIF1<0是R上的奇函數(shù)，若函數(shù)SKIPIF1<0的零點(diǎn)在區(qū)間SKIPIF1<0內(nèi)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練6】（2023·浙江紹興·統(tǒng)考二模）已知函數(shù)SKIPIF1<0，若SKIPIF1<0在區(qū)間SKIPIF1<0上有零點(diǎn)，則SKIPIF1<0的最大值為__________.【對(duì)點(diǎn)訓(xùn)練7】（2023·上海浦東新·高三上海市進(jìn)才中學(xué)校考階段練習(xí)）已知函數(shù)SKIPIF1<0在SKIPIF1<0上有零點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍___________.【解題總結(jié)】本類問題應(yīng)細(xì)致觀察、分析圖像，利用函數(shù)的零點(diǎn)及其他相關(guān)性質(zhì)，建立參數(shù)關(guān)系，列關(guān)于參數(shù)的不等式，解不等式，從而獲解.題型三：方程根的個(gè)數(shù)與函數(shù)零點(diǎn)的存在性問題【例3】（2023·黑龍江哈爾濱·哈爾濱三中校考模擬預(yù)測）已知實(shí)數(shù)SKIPIF1<0，SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0________.【對(duì)點(diǎn)訓(xùn)練8】（2023·新疆·校聯(lián)考二模）已知函數(shù)SKIPIF1<0，若SKIPIF1<0存在唯一的零點(diǎn)SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的取值范圍是________．【對(duì)點(diǎn)訓(xùn)練9】（2023·天津?yàn)I海新·統(tǒng)考三模）已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0在SKIPIF1<0上恰有三個(gè)不同的零點(diǎn)，則SKIPIF1<0的取值范圍是________．【對(duì)點(diǎn)訓(xùn)練10】（2023·江蘇·校聯(lián)考模擬預(yù)測）若曲線SKIPIF1<0有兩條過SKIPIF1<0的切線，則a的范圍是______.【對(duì)點(diǎn)訓(xùn)練11】（2023·天津北辰·統(tǒng)考三模）設(shè)SKIPIF1<0，對(duì)任意實(shí)數(shù)x，記SKIPIF1<0．若SKIPIF1<0有三個(gè)零點(diǎn)，則實(shí)數(shù)a的取值范圍是________．【對(duì)點(diǎn)訓(xùn)練12】（2023·廣東·統(tǒng)考模擬預(yù)測）已知實(shí)數(shù)m，n滿足SKIPIF1<0，則SKIPIF1<0___________.【解題總結(jié)】方程的根或函數(shù)零點(diǎn)的存在性問題，可以依據(jù)區(qū)間端點(diǎn)處函數(shù)值的正負(fù)來確定，但是要確定函數(shù)零點(diǎn)的個(gè)數(shù)還需要進(jìn)一步研究函數(shù)在這個(gè)區(qū)間的單調(diào)性，若在給定區(qū)間上是單調(diào)的，則至多有一個(gè)零點(diǎn)；如果不是單調(diào)的，可繼續(xù)分出小的區(qū)間，再類似做出判斷.題型四：嵌套函數(shù)的零點(diǎn)問題【例4】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，若關(guān)于SKIPIF1<0的方程SKIPIF1<0有且只有三個(gè)不同的實(shí)數(shù)解，則正實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練13】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，則關(guān)于SKIPIF1<0的方程SKIPIF1<0有SKIPIF1<0個(gè)不同實(shí)數(shù)解，則實(shí)數(shù)SKIPIF1<0滿足（

）A．SKIPIF1<0且SKIPIF1<0 B．SKIPIF1<0且SKIPIF1<0C．SKIPIF1<0且SKIPIF1<0 D．SKIPIF1<0且SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練14】（2023·四川資陽·高三統(tǒng)考期末）定義在R上函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0關(guān)于點(diǎn)SKIPIF1<0對(duì)稱，且SKIPIF1<0則關(guān)于x的方程SKIPIF1<0(SKIPIF1<0)有n個(gè)不同的實(shí)數(shù)解，則n的所有可能的值為A．2 B．4C．2或4 D．2或4或6【對(duì)點(diǎn)訓(xùn)練15】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，設(shè)關(guān)于SKIPIF1<0的方程SKIPIF1<0有SKIPIF1<0個(gè)不同的實(shí)數(shù)解，則SKIPIF1<0的所有可能的值為A．SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0 C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<0或SKIPIF1<0【解題總結(jié)】2、二次函數(shù)作為外函數(shù)可以通過參變分離減少運(yùn)算，但是前提就是函數(shù)的基本功要扎實(shí)．題型五：函數(shù)的對(duì)稱問題【例5】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的圖象上存在點(diǎn)P，函數(shù)g（x）=ax-3的圖象上存在點(diǎn)Q，且P，Q關(guān)于原點(diǎn)對(duì)稱，則實(shí)數(shù)a的取值范圍是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練16】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，函數(shù)SKIPIF1<0與SKIPIF1<0的圖象關(guān)于直線SKIPIF1<0對(duì)稱，若SKIPIF1<0無零點(diǎn)，則實(shí)數(shù)k的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練17】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的圖象上存在點(diǎn)SKIPIF1<0，函數(shù)SKIPIF1<0的圖象上存在點(diǎn)SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0關(guān)于SKIPIF1<0軸對(duì)稱，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練18】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0為自然對(duì)數(shù)的底數(shù)）與SKIPIF1<0的圖象上存在關(guān)于SKIPIF1<0軸對(duì)稱的點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0【解題總結(jié)】題型六：函數(shù)的零點(diǎn)問題之分段分析法模型【例6】（2023·浙江寧波·高三統(tǒng)考期末）若函數(shù)SKIPIF1<0至少存在一個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練19】（2023·湖北·高三校聯(lián)考期中）設(shè)函數(shù)SKIPIF1<0，記SKIPIF1<0，若函數(shù)SKIPIF1<0至少存在一個(gè)零點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍是A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練20】（2023·福建廈門·廈門外國語學(xué)校?？家荒＃┤糁辽俅嬖谝粋€(gè)SKIPIF1<0，使得方程SKIPIF1<0成立．則實(shí)數(shù)SKIPIF1<0的取值范圍為A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練21】（2023·湖南長沙·高三長沙一中校考階段練習(xí)）設(shè)函數(shù)SKIPIF1<0（其中SKIPIF1<0為自然對(duì)數(shù)的底數(shù)），若函數(shù)SKIPIF1<0至少存在一個(gè)零點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【解題總結(jié)】分類討論數(shù)學(xué)思想方法題型七：唯一零點(diǎn)求值問題【例7】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0有唯一零點(diǎn)，則實(shí)數(shù)SKIPIF1<0（

）A．1 B．SKIPIF1<0 C．2 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練22】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0有唯一零點(diǎn)，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練23】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，SKIPIF1<0分別是定義在SKIPIF1<0上的偶函數(shù)和奇函數(shù)，且SKIPIF1<0，若函數(shù)SKIPIF1<0有唯一零點(diǎn)，則實(shí)數(shù)SKIPIF1<0的值為A．SKIPIF1<0或SKIPIF1<0 B．1或SKIPIF1<0 C．SKIPIF1<0或2 D．SKIPIF1<0或1【對(duì)點(diǎn)訓(xùn)練24】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0有唯一零點(diǎn)，則負(fù)實(shí)數(shù)SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<0【解題總結(jié)】利用函數(shù)零點(diǎn)的情況求參數(shù)的值或取值范圍的方法：（1）利用零點(diǎn)存在性定理構(gòu)建不等式求解.（2）分離參數(shù)后轉(zhuǎn)化為函數(shù)的值域(最值)問題求解.（3）轉(zhuǎn)化為兩個(gè)熟悉的函數(shù)圖像的上、下關(guān)系問題，從而構(gòu)建不等式求解.題型八：分段函數(shù)的零點(diǎn)問題【例8】（2023·天津南開·高三南開中學(xué)?？计谀┮阎瘮?shù)SKIPIF1<0，若函數(shù)SKIPIF1<0有兩個(gè)零點(diǎn)，則m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練25】（2023·全國·高三專題練習(xí)）已知SKIPIF1<0，函數(shù)SKIPIF1<0恰有3個(gè)零點(diǎn)，則m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練26】（2023·陜西西安·高三統(tǒng)考期末）已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0，則函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為（

）A．1 B．3 C．4 D．5【對(duì)點(diǎn)訓(xùn)練27】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0SKIPIF1<0，若函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)恰有5個(gè)零點(diǎn)，則a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【解題總結(jié)】已知函數(shù)零點(diǎn)個(gè)數(shù)(方程根的個(gè)數(shù))求參數(shù)值(取值范圍)常用的方法：（1）直接法：直接求解方程得到方程的根，再通過解不等式確定參數(shù)范圍；（2）分離參數(shù)法：先將參數(shù)分離，轉(zhuǎn)化成求函數(shù)的值域問題加以解決；（3）數(shù)形結(jié)合法：先對(duì)解析式變形，進(jìn)而構(gòu)造兩個(gè)函數(shù)，然后在同一平面直角坐標(biāo)系中畫出函數(shù)的圖象，利用數(shù)形結(jié)合的方法求解.題型九：零點(diǎn)嵌套問題【例9】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0有三個(gè)不同的零點(diǎn)SKIPIF1<0.其中SKIPIF1<0，則SKIPIF1<0的值為（

）A．1 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練28】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，有三個(gè)不同的零點(diǎn)，（其中SKIPIF1<0），則SKIPIF1<0的值為A．SKIPIF1<0 B．SKIPIF1<0 C．-1 D．1【對(duì)點(diǎn)訓(xùn)練29】（2023·遼寧·校聯(lián)考二模）已知函數(shù)SKIPIF1<0有三個(gè)不同的零點(diǎn)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的值為（

）A．81 B．﹣81 C．﹣9 D．9【對(duì)點(diǎn)訓(xùn)練30】（2023·重慶南岸·高三重慶市第十一中學(xué)校?？茧A段練習(xí)）設(shè)定義在R上的函數(shù)SKIPIF1<0滿足SKIPIF1<0有三個(gè)不同的零點(diǎn)SKIPIF1<0且SKIPIF1<0則SKIPIF1<0的值是（

）A．81 B．-81 C．9 D．-9【解題總結(jié)】解決函數(shù)零點(diǎn)問題，常常利用數(shù)形結(jié)合、等價(jià)轉(zhuǎn)化等數(shù)學(xué)思想.題型十：等高線問題【例10】（2023·全國·高三專題練習(xí)）設(shè)函數(shù)SKIPIF1<0①若方程SKIPIF1<0有四個(gè)不同的實(shí)根SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的取值范圍是SKIPIF1<0②若方程SKIPIF1<0有四個(gè)不同的實(shí)根SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的取值范圍是SKIPIF1<0③若方程SKIPIF1<0有四個(gè)不同的實(shí)根，則SKIPIF1<0的取值范圍是SKIPIF1<0④方程SKIPIF1<0的不同實(shí)根的個(gè)數(shù)只能是1，2，3，6四個(gè)結(jié)論中，正確的結(jié)論個(gè)數(shù)為（

）A．1 B．2 C．3 D．4【對(duì)點(diǎn)訓(xùn)練31】（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有四個(gè)不同的解SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練32】（2023·四川瀘州·高一四川省瀘縣第四中學(xué)?？茧A段練習(xí)）已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有四個(gè)不同的實(shí)根SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，滿足SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練33】（2023·全國·高三專題練習(xí)）已知函數(shù)f(x)＝SKIPIF1<0，若互不相等的實(shí)數(shù)x1，x2，x3滿足f（x1）＝f（x2）＝f（x3），則SKIPIF1<0的取值范圍是（

）A．（SKIPIF1<0） B．（1，4） C．（SKIPIF1<0，4） D．（4，6）【解題總結(jié)】數(shù)形結(jié)合數(shù)學(xué)思想方法題型十一：二分法【例11】（2023·遼寧大連·統(tǒng)考一模）牛頓迭代法是我們求方程近似解的重要方法．對(duì)于非線性可導(dǎo)函數(shù)SKIPIF1<0在SKIPIF1<0附近一點(diǎn)的函數(shù)值可用SKIPIF1<0代替，該函數(shù)零點(diǎn)更逼近方程的解，以此法連續(xù)迭代，可快速求得合適精度的方程近似解．利用這個(gè)方法，解方程SKIPIF1<0，選取初始值SKIPIF1<0，在下面四個(gè)選項(xiàng)中最佳近似解為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【對(duì)點(diǎn)訓(xùn)練34】（2023·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的一個(gè)正數(shù)零點(diǎn)附近的函數(shù)值用二分法逐次計(jì)算，參考數(shù)據(jù)如下：SKIPIF1<0

SKIPIF1<0

SKIPIF1<0SKIPIF1<0