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1、2013-2014學(xué)年安徽省宿州市泗縣中學(xué)七年級(下)第一次月考試卷一、選擇題(每小題3分,共30分)1下列運(yùn)算正確的是()aa2a3=a6b(x5)2=x7c(-3c)2=9c2d(a-2b)2=a2-2ab+4b2顯示解析2下列式子中,不成立的是()a2x23x=6x3b(-6x4)(3x2)=-18x6c(2x+1)(2x-1)=2x2-1d(12ab2c3)214a2b4c6顯示解析3若a2b214,ab12,則a+b的值為()a12b12c1d2顯示解析4計(jì)算:(19)201392014=()a19b9c1d94027顯示解析5利用平方差公式計(jì)算20122-20132011的結(jié)果是(
2、)a-1b1c-2d2顯示解析6已知(x+a)(x+b)=x2-11x+18,則a+b的值是()a-11b11c-18d18顯示解析7方程x(x-3)+2(x-3)=x2-8的解為()ax=2bx=-2cx=4dx=-4顯示解析8將正方形的邊長由acm增加6cm,則正方形的面積增加了()a36cm2b12acm2c(36+12a)cm2d以上都不對顯示解析9已知x+1x2,則下列等式成立的有()x2+1x22;x4+1x42;x8+1x82;x1x0abcd顯示解析10如圖在邊長為a的正方形中挖掉一個(gè)邊長為b的小正方形(ab),把剩下的部分拼成一個(gè)矩形,通過計(jì)算兩處圖形的面積,驗(yàn)證了一個(gè)等式,
3、此等式是()aa2-b2=(a+b)(a-b)b(a+b)2=a2+2ab+b2c(a-b)2=a2-2ab+b2d(a+2b)(a-b)=a2+ab+b2顯示解析二、填空題(每小題3分,共24分)11有一道計(jì)算題:(-a4)2,李老師發(fā)現(xiàn)全班有以下四種解法,(-a4)2=(-a4)(-a4)=a4a4=a8;(-a4)2=-a42=-a8;(-a4)2=(-a)42=(-a)8=a8;(-a4)2=(-1a4)2=(-1)2(a4)2=a8;你認(rèn)為其中完全正確的是(填序號)顯示解析12若(am+1bn+2)(a2n-1b2m)=a3b5,則m+n的值是顯示解析13如果單項(xiàng)式-4x2ay2與1
4、4x4y3a2b是同類項(xiàng),則這兩個(gè)單項(xiàng)式的積為顯示解析14已知長方體長為4102毫米,寬為3102毫米,高為2102毫米,這個(gè)長方體的體積是立方毫米顯示解析15已知10m=2,10n=3,則103m+2n=顯示解析16若m+4n-2=0,則3m81n=顯示解析17已知2x+y=1,代數(shù)式(y+1)2-(y2-4x)的值為顯示解析18如圖所示,正方形abcd和正方形cefg的邊長分別為a、b,如果a+b=17,ab=60,那么陰影部分的面積是顯示解析三、解答題(共66分)19計(jì)算(1)(a-2)2+4(a-1)(2)(a+2)(a+2)-a(a+1)(3)(a-b-1)(a+b-1)(4)(x+
5、2y)2(x-2y)顯示解析20解下列方程(組)(x+3)2-2(x-3)(x+2)+(x-2)2=5顯示解析21化簡,求值(1)先化簡,再求值:(x+3)(x-3)-x(x-2),其中x=4;(2)先化簡,再求值:(2a-b)2-b2,其中a=2,b=3;(3)已知210=a2=4b,化簡(14a+15b)(14a15b)(14a+15b)2,并求值顯示解析22已知x3m=4,y3n=5,求:(x2m)3+(yn)3-x2mynx4my2n的值顯示解析23(1)多項(xiàng)式a2+b2-4a+6b+13=0,求a+b值(2)已知(x+y)2=25,(x-y)2=9,求xy與x2+y2的值顯示解析24
6、觀察下列等式:32-12=8=81;52-32=16=82;72-52=24=83;92-72=32=84這些等式反映了正整數(shù)的某種規(guī)律(1)設(shè)n為正整數(shù),試用含m的式子,表示你發(fā)現(xiàn)的規(guī)律;(2)驗(yàn)證你發(fā)現(xiàn)規(guī)律的正確性,并用文字歸納出這個(gè)規(guī)律顯示解析25小明將一個(gè)底為正方形,高為m的無蓋盒子展開,如圖所示,測得其邊長為n,(1)請你計(jì)算無蓋紙盒的表面展開圖的面積s1(即圖中陰影部分的面積)(2)將陰影部分拼成一個(gè)長方形如圖所示,這個(gè)長方形的長和寬分別是多少?面積s2是多少?(3)比較(1)、(2)的結(jié)果,你得出什么結(jié)論?顯示解析26下列運(yùn)算正確的是()a3x-2x=1b(-2a+1)2=4a2
7、+4a+1c(-a)2a3=a6d(-a2)3=-a6顯示解析27下列各式中,與(a-1)2相等的是()aa2-1ba2-2a+1ca2-2a-1da2+1顯示解析28下列運(yùn)算正確的是()ax3x4=x12b(-6x6)(-2x2)=3x3c2a-3a=-ad(x-2)2=x2-4顯示解析29計(jì)算(-x)2x3所得的結(jié)果是()ax5b-x5cx6d-x6顯示解析30計(jì)算(ab2)3的結(jié)果是()aab5bab6ca3b5da3b6顯示解析31下列式子中是完全平方式的是()aa2+ab+b2ba2+2a+2ca2-2b+b2da2+2a+1顯示解析32下列各式計(jì)算正確的是()a2a2+a3=3a5
8、b(3xy)2(xy)=3xyc(2b2)3=8b5d2x3x5=6x6顯示解析333(x3)2(y2)3(13xy)=顯示解析34若a2+a=0,則2a2+2a+2007的值為顯示解析35一個(gè)長方形的面積是(x2-9)平方米,其長為(x+3)米,用含有x的整式表示它的寬為米顯示解析36先化簡,再求值:(a+b)(a-b)+b(b-2),其中a=-1,b=1顯示解析37若a0且ax=2,ay=3,則ax-y的值為()a-1b1c23d32顯示解析38已知x+y=-5,xy=6,則x2+y2的值是()a1b13c17d25顯示解析39定義.abcd.=ad-bc,上述記號就叫做2階行列式若.x+
9、1x11xx+1.=6,x=顯示解析40計(jì)算:(-2a-2)3b22a-8b-3顯示解析41如圖,正方形卡片a類,b類和長方形卡片c類若干張,如果要拼一個(gè)長為(a+2b),寬為(a+b)的大長方形,則需要c類卡片張qcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka
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17、cudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawger4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wg
18、qv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkkn
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20、i92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32w
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24、uwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawger4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fh
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