一二進制數轉換為ASC碼

1、一二進制數轉換為ASC碼將一個字節(jié)的二進制數轉換為兩位16進制數的ASC碼main:mova,0x9f;二進制數為0x9f mov0x30,a;二進制數存入0x30mova,0x02mov0x10,a;0x10中存放轉換次數mova,0x31mov0x04,a;0x04中為轉換后數據存放地址mova,0x30B1:anda,0x0f;取a低4位mov0x00,asuba,0x09;低4位大于9跳往B2jbs0x03,0jmpB2mova,0x00;低4位不大于9則加0x30adda,0x30mov0x00,a;將ASC碼存入0X04所指單元jmpB3B2:mova,0x00;大于9則加0X37

2、adda,0x37mov0x00,aB3:swapa0x30;將0X30高4位換入A低4位inc0x04;存儲地址加1djz0x10;循環(huán)次數減1,為0則返回jmpB1;不為0繼續(xù)轉換self:jmpselfeop二多字節(jié)二進制加法0X20,0X21中的二進制無符號數與0X22,0X23中的二進制無符號數相加,結果放在0X24,0X25,0X26中,低地址中放低字節(jié)數據。Main：mov a，0x78;賦值mov0x20,amova,0xc6mov0x21,amova,0x86mov0x22,amova,0x9emov0x23,amova,0x0;0x26單元清0mov0x26,amova,0

3、x21adda,0x23mov0x25,a;高字節(jié)相加,結果送0x25jbc0x03,0inc0x26; 有進位則0x26加1mova,0x20adda,0x22mov0x24,a;低字節(jié)相加,結果送0x24jbs0x03,0jmp self;無進位跳selfinc0x25;有進位0x25加1jbc0x03,0inc0x26; 有進位0x26加1self:jmpselfeop三多字節(jié)二進制減法0x20,0x21中的二進制無符號數減0x22,0x23中的二進制無符號數, 低地址中放低字節(jié)數據。假設被減數大于減數。注意：（1）sub指令減出結果為正時，c標志置1。 （2）sub指令減出結果為0時，

4、c標志也置1。即，sub指令執(zhí)行后，c標志清0表示結果為負。main：mova，0x67;賦值mov0x20,amova,0xffmov0x21,amova,0xe8mov0x22,amova,0x44mov0x23,a; 高字節(jié)相減suba,0x21mov0x25,a;結果存0x25mova,0x22;低字節(jié)相減suba,0x20mov0x24,ajbs0x03,0dec0x25;有借位則0x25減1self:jmpselfeop四二進制乘法運算EM78單片機沒有乘法指令,所以乘法運算需要轉化為加法運算。0X20單元數據乘以0X21單元數據，結果放在0X22，0X23中。main:mova,

5、0x0;0x22,0x23單元清0mov0x22,amov0x23,amova,0x3f;賦值mov0x20,amova,0x22mov0x21,amul1:mova,0x20；0x20與0x22內容相加add0x22,ajbc0x03,0inc0x23;有進位0x23加1djz0x21;0x21中次數減到0則結束jmpmul1;沒減到0則繼續(xù)self:jmpselfeop五二進制除法運算多字節(jié)二進制除法被除數為3個字節(jié)，在0x20、0x21、0x22單元中，0x22.7為最高位，0x20.0為最低位。除數為2個字節(jié)，在0x30、0x31中。算法：EM78單片機沒有除法指令，而且本例中除法為多

6、字節(jié)除法，可采用如下算法。將被除數擴充一個字節(jié)0X23，0X23清0。被除數左移1位，0X23、0X22中數據減去0X31、0X30中數據，夠減則減且0X20.0置1，減出結果存入0X23、0X22；不夠減則0X23、0X22保持不變，0X20.0清0。然后被除數再左移1位，重復上述過程。共循環(huán)16次，最后0X23、0X22中得相減余數，0X21、0X20中得商。注意，若被除數左移后C標志為1，則不比較0X23、0X22與0X31、0X30數據大小關系而直接相減。main：mova,0x55;被除數賦值mov0x20,amov0x21,amov0x22,amova,0x0;被除數擴充1字節(jié)并清

7、0mov0x23,amova,0x12;除數賦值mov0x30,amov0x31,amova,0x10;循環(huán)次數為16mov0x32,aagain:callrt_sub;調移位除法子程djz0x32;16次循環(huán)完成則結束jmpagain;未完成則繼續(xù)self:jmpselfrt_sub:bc0x03,0;c標志清0rlc0x20;被除數左移1位rlc0x21rlc0x22rlc0x23jbc0x03,0jmprt3;c標志為1則直接相減mova,0x23;c標志為0則先比較大小mov0x25,amova,0x22mov0x24,amova,0x31;先比較高位sub0x25,ajbc0x03,

8、2jmprt1;高位相等跳rt1比較低位jmprt2;高位不等跳rt2rt1:mova,0x30;比較低位sub0x24,ajbc0x03,2jmprt3;低位也相等則跳rt3,相減,上1rt2:jbs0x03,0ret;減數大則返回,減數小則相減,上1rt3:bs0x20,0;上1callsub_2b;調2字節(jié)減法子程retsub_2b:mova,0x31;高字節(jié)相減sub0x23,amova,0x30;低字節(jié)相減sub 0x22,ajbc0x03,2ret;低字節(jié)相等,無借位,返回jbc0x03,0ret;無借位,返回dec0x23;低字節(jié)相減有借位,高字節(jié)結果減1reteop六BCD數轉

9、換為二進制數兩字節(jié)壓縮BCD碼轉換為兩字節(jié)二進制數。算法如下：BCD碼abcd=1000a+100b+10c+d=101010a+b+c+d，將各位BCD碼分離出之后，即可根據此式轉換為二進制數。涉及到乘法運算和多字節(jié)加法運算。0X20，0X21中為BCD碼，0X21高4位為最高位。轉換結果放在0X30，0X31中。main：mova，0x79mov0x20,amova,0x54mov0x21,a;賦值mova,0x20anda,0x0fmov0x22,aswapa0x20anda,0x0fmov0x23,amova,0x21anda,0x0fmov0x24,aswapa0x21anda,0x

10、0fmov0x25,a;BCD碼展開后存于0X22,0X23,0X24,0X25mova,0x25,;0X25為最高位mov0x30,amova,0x0;多字節(jié)加法高位為0mov0x31,amova,0x24mov0x32,acalla_b;調子程mova,0x23mov0x32,acalla_bmova,0x22mov0x32,acalla_bself:jmpselfa_b:mova,0x0;0X34,0X35存儲中間結果mov0x34,amov0x35,amova,0x0a;實現乘10mov0x33,aa1:mova,0x35;兩字節(jié)二進制加法,在本例中高字節(jié)肯定無進位adda,0x31m

11、ov0x35,amova,0x34adda,0x30mov0x34,ajbc0x03,0inc0x35djz0x33jmpa1mova,0x32add0x34,ajbc0x03,0inc0x35mova,0x34mov0x30,amova,0x35mov0x31,areteop七二進制數轉換為BCD碼本例為單字節(jié)二進制數(0X20)轉換為非壓縮BCD碼,存在0X25,0X24,0X23中,0X25為百位,0X23為個位。main:mova,0xa4;賦值mov0x20,amov0x21,amov0x22,amova,0x0;0x23,0x24,0x25單元清0mov0x23,amov0x24,amov0x25,amova,0x64;對100的個數計數mov0x26,amova,0x25;百位存在0x25中mov0x04,acalla0;調計數子程mova,0x0a;對10的個數計數mov0x26,adec0x04;個位存在0x24中calla0mova,0x22;除去百位,十位,余下的即個位,存入0x23mov0x23,aself:jmpselfa0:;計數子程mova,0x26sub0x22,ajbs0x03,2jmpa1inc0x00;無