版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡介
1、1 .聲明動(dòng)態(tài)數(shù)組,根據(jù)用戶輸入值n重定義數(shù)組元素個(gè)數(shù);利用 rnd為該數(shù)組元 素賦值為兩位的隨機(jī)整數(shù),將數(shù)組元素顯示到listl中; 單擊“逆序按鈕,實(shí)現(xiàn)數(shù)組逆序,將逆序 結(jié)果顯示到list2中。Opti on ExplicitOption Base 1Dim a(), b(), n As In teger, i As In tegerPrivate Sub Comma nd1_Click()n = InputBox("請(qǐng)")ReDim a(n)End SubPrivate Sub Comma nd2_Click()For i = 1 To na(i) = In t(R
2、nd * 100 + 1)Listl.Addltem a(i)Next iEnd SubPrivate Sub n ixu_Click()ReDim b(n)For i = LBou nd(b) To UBou nd(b)b(i) = a(n + 1 - i)List2.AddItem b(i)Next iEnd Sub2.從數(shù)組中刪除一個(gè)數(shù)。先定義一個(gè)一維數(shù)組,大小、數(shù)組的值自定。從鍵盤上 輸入一個(gè)數(shù),假設(shè)這個(gè)數(shù)在數(shù)組當(dāng)中,就把它 刪除;假設(shè)這個(gè)數(shù)不在數(shù)組中,提示“該數(shù)不 在數(shù)組中文檔來自于網(wǎng)絡(luò)搜索注意:1)如果數(shù)組中存在多個(gè)與該數(shù) 相同的元素,每一個(gè)都能刪除;2)能實(shí)現(xiàn)屢次刪除Privat
3、e Sub Comma nd1_Click()Dim m(1 To 10), mid%, top%, bot%, find, x%Fori = 1 To 10m(i) = a(i)Next ix = Val(Text1.Text): find = 0: top = 10: bot =1Do While top >= bot And find = 0mid = In t(bot + top) / 2)If x = m(mid) The nfind = 1For i = mid To 9m(i) = m(i + 1)Next iFori = 1 To 9List2.AddItem m(i)N
4、ext iElseIf x > m(mid) The nbot = mid + 1Elsetop = mid - 1End IfLoopIf find = 0 The n MsgBox Str(x) + " 不在數(shù) 組中End Sub3數(shù)組a中存放著升序排列的數(shù)據(jù), 使用array賦值,將inputbox輸入的新數(shù)插 入到數(shù)組中,插入后數(shù)組仍有序,將原數(shù)組 和插入后數(shù)組顯示到picture1中。資料個(gè)人收集整理,勿做商業(yè)用途注意:要求利用動(dòng)態(tài)數(shù)組,能夠?qū)崿F(xiàn)屢次插 入Private Sub Comma nd1_Click()x = Val(InputBox("請(qǐng)輸入一個(gè)
5、數(shù)",Int(Rnd * 100 + 1)ReDim d(UBou nd(a) + 1): c = -1For i = LBound(a) To UBound(a)d(i) = a(i)If x < a(i) The n Exit Forc = c + 1Next iFor i = c + 1 To UBou nd(a)d(i + 1) = a(i)Next id(c + 1) = xFor i = 0 To UBou nd(a) + 1Picture1.Pri nt d(i)Next iEnd Sub4. 6個(gè)評(píng)委為4位歌手打分,分?jǐn)?shù)介 于1-100之間。去掉一個(gè)最高分,一個(gè)
6、最低 分,求出每位選手的最后得分。將4位歌手得分從高到低排列輸出,同時(shí)輸出該選手的編號(hào)。資料個(gè)人收集整理,勿做商業(yè)用途如: 歌手3 95分歌手1 87分 歌手4 80分歌手270分Opti on ExplicitOption Base 1Dim a(4, 6) As In teger, aver As Si ngle Private Sub Comma nd1_Click()Dim n As In teger, i As In tegerFor n = 1 To 4Print"第 &n & 位選手得分為:;Fori = 1 To 6'a(n, i) = Int
7、(Rnd * 11 + 90)a(n, i) = InputBox("請(qǐng)第"& i & " 位評(píng)委 為第 &n & 位選手打分")資料個(gè)人收集整理, 勿做商業(yè)用途Do While a( n, i) < 1 Or a(n, i) > 100MsgBox "打分請(qǐng)?jiān)? 100之間a(n, i) = InputBox("請(qǐng)第"& i & " 位評(píng)委 為第 &n & 位選手打分")資料個(gè)人收集整理, 勿做商業(yè)用途LoopPrint a(n
8、, i);NextPrintNextComma nd2.E nabled = TrueComma nd3.E nabled = TrueEnd SubPrivate Sub Comma nd2_Click()'Me.ClsDim n As Integer, i As Integer, max As Integer, min As Integer, sum As Integer 資料個(gè)人收集整 理,勿做商業(yè)用途For n = 1 To 4max = a(n, 1)min = a(n, 1)sum = 0Fori = 1 To 6If a( n, i) > max The n max
9、 = a( n, i)If a(n, i) < min Then min = a(n, i)sum = sum + a(n, i)Nextaver( n) = (sum - max - min) / 4Print"第 &n & 位選手的最高得分是:"& maxPrint "最低得分是: & minPrint "去掉一個(gè)最高分,去掉一個(gè)最低 分,第 &n & 位選手的最終得分是: & aver( n)資料個(gè)人收集整理,勿做商業(yè)用途PrintNextEnd SubPrivate Sub Comma
10、 nd3_Click()Dim i As In teger, j As In teger, a(10) As In teger, n As Integer資料個(gè)人收集整理,勿做商業(yè)用途For i = 1 To 4Forj = 1 To 4a(i) = 1If aver(i) < aver(j) The n a(i) = a(i) + 1NextNexti = 1Do While i <= 4For n = 1 To 4If a(n) = i Then Print "第"& n & "位選手 "aver( n)Nexti = i
11、 + 1LoopEnd Sub5 .編寫函數(shù)求一元二次方程 ax2+bx+c=0 的解。注意:要求考慮方程解有如下情況a=0、有兩相等實(shí)根、有兩不等實(shí)根和 兩個(gè)虛根6.多行文本框中任意輸入多行文字, 統(tǒng)計(jì)并輸出每個(gè)字母和數(shù)字出現(xiàn)次數(shù)。 如字母AZ分別出現(xiàn)多少次,數(shù)字09分別出現(xiàn)多少次?要求用過程實(shí)現(xiàn)(大小寫不 敏感,即大寫 A和小寫a都記為字母 A)資 料個(gè)人收集整理,勿做商業(yè)用途Public Sub zifu(s, ByRef n1, ByRef n 2, ByRef n3)Dim s1 As Stri ng, i As In tegerFor i = 1 To Len(s)s1 = Mid
12、(s, i, 1)If Asc(s1) >= Asc(A)And Asc(s1) <= Asc(Z)The n n1 = n1 + 1 資料個(gè)人收集整理,勿 做商業(yè)用途If Asc(s1) >= Asc("a") And Asc(s1) <= Asc("z") The n n2 = n2 + 1 資料個(gè)人收集整理,勿 做商業(yè)用途If Asc(s1) >= Asc("0") And Asc(s1) <= Asc("9") The n n3 = n3 + 1 資料個(gè)人收集整理,勿 做
13、商業(yè)用途NextEnd SubPrivate Sub Comma nd1_Click()Dim s As String, n1 As Integer, n2 As Integer, n3 As Integer資料個(gè)人收集整理,勿做商業(yè)用途 s = Text1.Textzifu s, n1, n2, n3Text2.Text = 字符中含有大寫字母 & n1 & 個(gè); & 含有小寫字母 & n2 & 個(gè); & 含有數(shù)字"& n3 & "個(gè)"資料個(gè)人收集整理,勿做商 業(yè)用途End Sub7.隨機(jī)產(chǎn)生一個(gè)5
14、*5的矩陣,每個(gè)元 素值介于1099之間,將主對(duì)角線和次對(duì)角 線元素都置為1,矩陣顯示在 picture1中, 求出矩陣的四周元素之和,顯示在列表框 中。資料個(gè)人收集整理,勿做商業(yè)用途Opti on ExplicitDim a(5, 5) As In tegerPrivate Sub Comma nd1_Click()Dim i As In teger, j As In tegerFor i = 0 To 4Forj = 0 To 4If i = j Or i + j = 4 The na(i, j) = 1ElseRan domizea(i, j) = In t(R nd * 9 + 1)E
15、nd IfList1 .List(i) = List1.List(i) & a(i, j) & IINextNextEnd SubPrivate Sub Comma nd2_Click()Dim i As In teger, j As In teger, sum As In tegerFor i = 0 To 4sum = sum + a(i, 0) + a(i, 4)NextForj = 0 To 4sum = sum + a(0, j) + a(4, j)Nextsum = sum - a(0, 0) - a(4, 4) - a(0, 4) - a(4, 0) List1.
16、List(5)= 四周元素之和為: & sum End Sub&編寫一個(gè)函數(shù),能將字母按以下規(guī) 律譯成密碼:A<->Za<->zB<-> Yb<->y即第1個(gè)字母與第26個(gè)字 母互換,第i個(gè)字母與第(26-i+1) 個(gè)字母互換。在文本框中任意輸 入一個(gè)字符串,調(diào)用該函數(shù)將密 碼顯示在另一個(gè)文本框中。資料個(gè)人收集整理,勿做商業(yè)用途Opti on ExplicitDim str1 As Stri ng, str2 As Stri ng, array1(100)As String資料個(gè)人收集整理,勿做商業(yè)用途Dim i As In te
17、ger, n As In teger Private Sub Text1_Cha nge()str1 = Text1.Textn = Len( str1)For i = 1 To narray1(i) = Mid(str1, i, 1)If Asc(array1(i) >=97 AndAsc(array1(i) <= 122 Then資料個(gè)人收集整理,勿 做商業(yè)用途array1(i) =Chr(219-Asc(array1(i)ElseIf Asc(array1(i) >=65 AndAsc(array1(i) <= 90 The n 資料個(gè)人收集整理,勿 做商業(yè)用途a
18、rray1(i) =Chr(155-Asc(array1(i)End IfNext istr2 = Join(array1,"")Text2.Text = str2End Sub9編寫2個(gè)函數(shù),分別求兩個(gè)正整數(shù)的 最大公約數(shù)和最小公倍數(shù),用戶任意輸入兩個(gè)數(shù),采用函數(shù)嵌套調(diào)用,該函數(shù)將它們?cè)?窗體顯示。資料個(gè)人收集整理,勿做商業(yè)用途Opti on ExplicitPrivate Sub Form_Load()Textl = "": Text2 =""End SubPrivate Sub Text1_KeyPress(KeyAscii A
19、s In teger)If KeyAscii = 13 The n Text2.SetFocusEnd SubPrivate Sub Text2_KeyPress(KeyAscii As In teger)Dim p As In teger, q As In teger, xClsIf KeyAscii = 13 The np = Text1.Textq = Text2.TextIf p < 0 Or q < 0 The nx = MsgBox("請(qǐng)輸入正數(shù)", vbCritical + vbOKCa ncel)If x = vbCa ncel The nEnd
20、ElseText1 = "": Text2 =""Text1.SetFocusEnd IfElseCall gys(p, q)Print Text1.Text & "和"& Text2.Text & "的最大公約數(shù)是:"& gys(p, q) & gbs(p, q) 資料個(gè)人收集整理,勿做商業(yè)用途End IfEnd IfEnd SubPrivate Function gys(m, n) As In tegerDim x As Integer, r As Integer, t
21、As In tegerIf m < n The nt = m: m = n: n = tEnd Ifr = m Mod nWhile r <> 0m = n: n = r: r = m Mod nWendgys = nEnd FunctionPrivate Function gbs(m, n) As In tegerDim a As In teger, b As In tegera = Text1.Text gys(m, n): b = Text2.Text gys(m, n)資料個(gè)人收集整理,勿做商業(yè)用途gbs = a * b * gys(m, n)End Function
22、10. 編寫計(jì)算階乘的Function過程,利用ex的以下公式計(jì)算e (直到最后一項(xiàng)小 于10-6為止)的近似值。資料個(gè)人收集整理,勿做商業(yè)用途ex 1+x/1!+x 2/2!+x 3/3!+ +xn/n!Opti on ExplicitPrivate Sub Form_Load()ShowDim x As Integer, n As Integer, s As Double x = InputBox("請(qǐng)輸入一個(gè)數(shù):") n = 1: s = 1Dos = s + x A n / (jieche ng(n)n = n + 1Loop Un til x a n / (jie
23、che ng( n) < 10 a (-6)Print sEnd SubPublic Function jiecheng(n As Integer) AsDoubleDim i As In teger, s As Doubles = 1For i = 1 To ns = s * iNext ijieche ng = sEnd Function11. 輸入整數(shù)N,顯示具有N行的楊 輝三角形,要求按正三角形的形式在圖片框中顯示。Opti on ExplicitPrivate Sub Form_Load()Win dowState = 2ShowDim a(), n As Integer, i
24、 As Integer, j AsInteger, g As Integer, e As Integer 資料個(gè)人收集 整理,勿做商業(yè)用途n = InputBox("請(qǐng)輸入一個(gè)數(shù):")ReDim a(n, n)e = 80For i = 1 To ne = e - 5: g = eForj = 1 To nIf j > i The na(i, j) = 0ElseIf i = j The na(i, j) = 1Elsea(i, j) = a(i - 1, j) + a(i - 1, j - 1)End IfEnd IfIf a(i, j) = 0 The nExit
25、 ForElsePicture1.Pri nt Tab(g); a(i, j);g = g + 10End IfNext jPicture1.Pri ntNext iEnd Sub12. 編寫一個(gè)過程,輸出以下菱形圖形:Opti on ExplicitPrivate Sub Form_Load()Win dowState = 2ShowDim n As In tegern = InputBox("請(qǐng)輸入一個(gè)數(shù) (>=3的奇 數(shù)):")If n Mod 2 = 1 Then Call tuxing(n)End SubPublic Sub tux ing(n As In
26、teger)Dim i As In teger, j As In tegerFor i = 1 To (n + 1) / 2Print Tab(43 - i); String(2 * i - 1, Chr(Asc("A") - 1 + i)資料個(gè)人收集整理,勿做商業(yè) 用途Next iFor j = (n - 1) / 2 To 1 Step -1Print Tab(43 - j); String(2 * j - 1, Chr(Asc("A") - 1 + j)資料個(gè)人收集整理,勿做商業(yè) 用途NextEnd Sub13. 編寫一個(gè)將十進(jìn)制轉(zhuǎn)換為二進(jìn)制字符
27、串輸出的函數(shù)。調(diào)用函數(shù)計(jì)算用戶輸入一個(gè) 十進(jìn)制數(shù),在文本框中輸出二進(jìn)制值 資料個(gè)人 收集整理,勿做商業(yè)用途Opti on ExplicitPrivate Sub Form_Load()Dim x As In tegerx = InputBox("請(qǐng)輸入一個(gè)十進(jìn)制數(shù):")erjin zhi (x)If x < 0 The nText1.Text = "-" & erjin zhi(x)ElseText1.Text = erjin zhi(x)End IfEnd SubPublic Function erjinzhi(m As Integer)
28、 As Stri ngDim r As In teger, ss As Stringr = Abs(m) Mod 2Do While Abs(m) >= 1ss = Str(r) & ssm = m 2r = Abs(m) Mod 2Looperjin zhi = ssEnd Function14 .輸入一個(gè)整數(shù)N,產(chǎn)生N個(gè)隨機(jī)數(shù)(范圍1 10*N ),然后采用任何2種算法實(shí)現(xiàn)由小到大的排序。將排序前后的數(shù)據(jù)顯 示出來 資料個(gè)人收集整理,勿做商業(yè)用途Opti on ExplicitOptio n Base 1Dim n As In teger, a() As In tegerPr
29、ivate Sub Comma nd1_Click()Dim i As In teger, j As In teger, b As In tegerFor i = 1 To n - 1For j = i + 1 To nIf a(i) < a(j) Thenb = a(i)a(i) = a(j)a(j) = bEnd IfNextNextList2.Addltem ("用第一種排序法排序得:")For i = 1 To nList2.AddItem (a(i)NextEnd SubPrivate Sub Comma nd2_Click()Dim i As In teg
30、er, j As In teger, b As In tegerFor i = 1 To n - 1For j = 1 To n - iIf a(j) < a(j + 1) The nb = a(j)a(j) = a(j + 1)a(j + 1) = bEnd IfNextNextList3.AddItem ("用第二種排序法排序得: ")For i = 1 To nList3.AddItem (a(i)NextEnd SubPrivate Sub Comma nd3_Click()List1.Clearn = Val(Text1.Text)ReDim a(n)Dim
31、 i As In tegerRan domizeList1.AddItem ("原隨機(jī)數(shù)組為:")For i = 1 To na(i) = Int(Rnd * 10 * n + 1)List1.AddItem (a(i)NextEnd Sub15 .編寫程序,在窗體上輸出3100之間 的所有素?cái)?shù)。要求每行顯示4個(gè)數(shù)Private Sub Form_Load()ShowDim n As Integer, i As Integer, a As Integer, b As Integer, c As Integer資料個(gè)人收集整理,勿做 商業(yè)用途For n = 3 To 100
32、'for 循環(huán)For i = 2 To n - 1If n Mod i = 0 Then'驗(yàn)證素?cái)?shù)c = 0Exit ForElsec = nEnd IfNext iIf c <> 0 The n'打印素?cái)?shù),四個(gè)每行If a > 0 And a Mod 4 = 0 The n PrintPrint c;a = a + 1'素?cái)?shù)計(jì)數(shù)End IfNext nEnd Sub16. 設(shè)計(jì)程序,單擊“求素?cái)?shù)按鈕, 將2個(gè)文本框范圍內(nèi)的素?cái)?shù)添加到列表框 中。單擊“寫入文件按鈕,將列表框中所 有末位數(shù)字是9的數(shù)寫入到“從“ c:sushu9.txt 。中。界
33、面如下:資料個(gè)人收集整理,勿做商業(yè)用途Opti on ExplicitPrivate Sub Comma nd1_Click()Dim a As In teger, b As In teger, i As In teger,n As Integer資料個(gè)人收集整理,勿做商業(yè)用途a = Text1.Text: b = Text2.TextFor n = a To bFor i = 2 To n - 1If n Mod i = 0 Then Exit ForNext iIf i = n Then List1.AddItem nNext nEnd SubPrivate Sub Comma nd2_C
34、lick()Dim i As Integer, n As Integer, m As Integern = List1.ListCo untFor i = 1 To nm = Val(List1丄 ist(i)If (m + 1) Mod 10 = 0 The nOpe n "c:sushu9.txt" For Output As #1Print #1, m;Close #1End IfNext iEnd Sub17. 編寫2個(gè)函數(shù),分別采用遞歸法和遞 推法求斐波納契數(shù)列的第 n個(gè)月的兔子數(shù), n使用inputbox輸入,調(diào)用函數(shù)的結(jié)果在窗 體上顯示。資料個(gè)人收集整理,勿做
35、商業(yè)用途Opti on ExplicitPrivate Sub Comma nd1_Click()Dim n As Integer, a() As Integer, i As In tegerMe.Clsn = InputBox("請(qǐng)輸入n的值")ReDim a(n)a(1) = 1a(2) = 1For i = 3 To na(i) = a(i - 1) + a(i - 2)NextPrint"用遞歸法得數(shù)列:For i = 1 To nPrint a(i);NextPrintPrint"第n個(gè)月的兔子數(shù)為:;a(n)End SubPrivate Su
36、b Comma nd2_Click()Me.ClsDim n As Integer, a As Integer, b As Integer, c As Integer, i As Integer資料個(gè)人收集整理,勿做 商業(yè)用途n = InputBox("請(qǐng)輸入n的值")a = 1b = 1Print"用遞推法得數(shù)列:Print a; b;For i = 1 To n - 2c = a + ba = bb = cPrint c;NextPrintPrint "第n個(gè)月的兔子數(shù)為:"cEnd Sub18. 有一個(gè)數(shù)列:1,1,2,3,5,8,13,
37、 21,按規(guī)律計(jì)算出前40項(xiàng)的和,結(jié)果寫入到順序文件(out.txt)中。資料個(gè)人 收集整理,勿做商業(yè)用途界面設(shè)計(jì)見圖1,寫入結(jié)果的數(shù)據(jù)文件out.txt用“記事本翻開如圖2Opti on ExplicitOptio n Base 1Dim a(40) As Long, s As LongPrivate Sub Comma nd1_Click()Dim i As In tegera(1) = 1a(2) = 1s = a(1) + a(2)For i = 3 To 40a(i) = a(i - 1) + a(i - 2)s = s + a(i)NextEnd SubPrivate Sub Co
38、mma nd2_Click()Open "c:out.txt" For Output As #1Print #1,"數(shù)列1,1,2,3,5的總和 是:"sClose #1End Sub19. 單擊讀數(shù)按鈕從文件 in.txt中讀入 一個(gè)整數(shù)(先用記事本創(chuàng)立一個(gè) in.txt文件, 其中輸入任意一個(gè)素?cái)?shù), 如圖3中輸入的是 101 ),單擊計(jì)算按鈕那么計(jì)算出大于該數(shù)的第1個(gè)素?cái)?shù),單擊存盤將結(jié)果保存到文件 out.txt中,如圖5。資料個(gè)人收集整理,勿做商業(yè)用 途Opti on ExplicitDim a%Private Sub Comma nd1_Click()Ope n "C:i n.txt" For In put As #1In put #1, aClose #1Textl.Text = aEnd SubPrivate Sub Comma nd2_Click()a = Text1.TextDoa = a + 1Loop Un til isprime(
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 二零二五年度賓館酒店客房租賃及收益分成及品牌授權(quán)合同2篇
- 二零二五年房產(chǎn)租賃押金返還與住房按揭貸款保全合同3篇
- 二零二五年環(huán)保產(chǎn)業(yè)投資合作合同范本集2篇
- 二零二五年度綠色建筑安裝工程合同范本2篇
- 二零二五版教育局教師幼兒園勞動(dòng)合同履行評(píng)估標(biāo)準(zhǔn)3篇
- 二零二五年度板材行業(yè)風(fēng)險(xiǎn)管理與保險(xiǎn)合同2篇
- 展會(huì)參展商信息收集合同(2篇)
- 2025年度浙江房產(chǎn)市場風(fēng)險(xiǎn)防范7月1日實(shí)施合同3篇
- 二零二五版工業(yè)項(xiàng)目總承包監(jiān)理服務(wù)合同范本3篇
- 二零二五版混凝土工程數(shù)字化管理與優(yōu)化合同3篇
- 北京市朝陽區(qū)2024-2025學(xué)年高二上學(xué)期期末考試生物試卷(含答案)
- 2025年西藏拉薩市柳梧新區(qū)城市投資建設(shè)發(fā)展集團(tuán)有限公司招聘筆試參考題庫附帶答案詳解
- 2025年部編版一年級(jí)語文上冊(cè)期末復(fù)習(xí)計(jì)劃
- 2024年新高考II卷數(shù)學(xué)高考試卷(原卷+答案)
- 儲(chǔ)罐維護(hù)檢修施工方案
- 地理2024-2025學(xué)年人教版七年級(jí)上冊(cè)地理知識(shí)點(diǎn)
- 2024 消化內(nèi)科專業(yè) 藥物臨床試驗(yàn)GCP管理制度操作規(guī)程設(shè)計(jì)規(guī)范應(yīng)急預(yù)案
- 2024-2030年中國電子郵箱行業(yè)市場運(yùn)營模式及投資前景預(yù)測報(bào)告
- 基礎(chǔ)設(shè)施零星維修 投標(biāo)方案(技術(shù)方案)
- 人力資源 -人效評(píng)估指導(dǎo)手冊(cè)
- 大疆80分鐘在線測評(píng)題
評(píng)論
0/150
提交評(píng)論