面向對象程序設計卷答案

1、2010 年2011 年第二學期 面象程序設計期末試題B 卷一、填空題（每空 1 分，共 10 分）1.public 2.能 不能 不能this3. 104. Student:Student();5. 1 個6.X:X(const X& x);7.268.二、選擇題（每題 1 分，共 10 分）1. C2. B3.A4.C5.A6. C7.A8. D9.D10.D三、寫出下列程序的運行結果（共 25 分）1、-9 3 56 78 0 12 55 77 2 902、10/13/200512/30/200510/1/20051/1/20053、35:035:14、 num:1001 name:Li

2、 score:87.5 num:2001 name:wang score:98.5 pay=1200四、分析題（共 15 分）五、程序設計題（共 40 分）1、void inputData(a,n)for(i = 0; i ai;void outputData(a,n)for(i = 0; i n; i+) cout ai t;void moveDate(*a,n,m)for (i = 1; i a; p-)*p = *(p - 1);*a = temp;main(argc, char* argv)a10;inputData(a, 10);moveDate (a, 10, 4); output

3、Data(a,10); return 0;2、class Popublic:Po(float x=0,float y=0);friend ostream & operator(ostream &,const Po protected:float x,y;&);Po:Po(float a,float b)x=a;y=b;ostream & operator(ostream &outponst Po&p)outputp.x,p.yendl; return output;class Circle:public Popublic:Circle(float x=0,float y=0,float r=0

4、);friend ostream &operator(ostream &,const Circle &); private:float radius;Circle:Circle(float a,float b,float r):Po ostream &operator(ostream &outpoutput Center= c.x c.area( )endl; return output;(a,b),radius(r) onst Circle &c), c.y ,r= c.radius ,area= class Cylindpublic:ublic CircleCylinder (float

5、x=0,float y=0,float r=0,float h=0);friend ostream& operator(ostream&,const Cylinder&); protected:float height;Cylinder:Cylinder(float a,float b,float r,float h):Circle(a,b,r),height(h)ostream &operator(ostream &outponst Cylinder& cy)outputCenter=cy.x,cy.y,r=cy.radius,h=cy.heightnarea=cy.area( ), volume=cy.volume( )endl; return output;main( )Cylinder cy1(3.5,6.4,5.2,10); coutcylinder:ncy1;Po&pRe