主減速器齒輪計(jì)算載荷的確定

主減速器齒輪計(jì)算載荷的確定通常將發(fā)動(dòng)機(jī)最大轉(zhuǎn)矩配以傳動(dòng)系最低擋傳動(dòng)比時(shí)和驅(qū)動(dòng)車輪在良好路面上開始滑轉(zhuǎn)時(shí)這兩種情況下作用在主減速器從動(dòng)齒輪上的轉(zhuǎn)矩(Tje和Tj少)的較小者，作為載貨汽車和越野汽車在強(qiáng)度計(jì)算中用以驗(yàn)算主減速器從動(dòng)齒輪最大應(yīng)力的計(jì)算載荷，即T=T iKn/njeemaxTL0TTj@=G2^rr/(nLBiLB)式中：T 是發(fā)動(dòng)機(jī)的最大轉(zhuǎn)矩，T =200NXmemax emaxiTL由發(fā)動(dòng)機(jī)至所計(jì)算的主減速器從動(dòng)齒輪之間的傳動(dòng)系最低TL擋傳動(dòng)比，iTL=6.5；nT傳動(dòng)系上述傳動(dòng)部分的傳遞效率，取nt=0.85K0由于“猛接合”離合器產(chǎn)生沖擊載荷時(shí)的超載系數(shù)，對(duì)于一般載荷汽車K0=ln汽車驅(qū)動(dòng)橋數(shù)目；n=1G2汽車滿載時(shí)一個(gè)驅(qū)動(dòng)橋給水平地面的最大載荷15600N少輪胎對(duì)地面的附著系數(shù)，取0.85r輪胎的滾動(dòng)半徑，r=0.2985m；rrnTB，iTB分別為由所計(jì)算的主減速器從動(dòng)齒輪到驅(qū)動(dòng)輪之間的LBLB傳遞效率和傳動(dòng)比n=0.95i=1TB ，TBT=TiKn/njeemaxTT0T=200*6.5*1*0.85/1=1105N*mTj<p=Gcpr/ni)2rLBLB=15600*0.85*0.2985/1/0.95=4166.44N*m3．2．3主減速器齒輪基本參數(shù)的選擇T.=(G+Gt)r(fR+t+f)/(nLBiBn)N*mjm aTrRHp LBLBG滿載總重量，G=24000N;a aGT所牽引的掛車的滿載總重量，N,=0勒道路滾動(dòng)阻力系數(shù)=0.018fH汽車正常使用時(shí)的平均爬坡能力系數(shù)，通常0.07fp汽車的性能系數(shù)pf=[16－0.195(G+G)/T ]/100p aTemax0.195(G+G)/T >16,取f=0aTemax p所以fp=0pT=(G+G)r(f+f+f)/(ninjmaTrRHp LBLB=(24000+0)*0.2985*(0.018+0.07+0)=663.613N*m主減速器主從動(dòng)齒輪的齒數(shù)，根據(jù)加工原則和推薦值z(mì)1=9，z2=46主減速器雙曲面從動(dòng)齒輪節(jié)圓直徑由經(jīng)驗(yàn)公式：d=K(T)1/32d2jKd2直徑系數(shù)，取15T.計(jì)算轉(zhuǎn)矩N*m取min(T.和Tjp)j je從動(dòng)錐齒輪節(jié)圓直徑確定后，按m=d2/z2計(jì)算大端端面模數(shù)m=217.7/46=4.732且按下面公式校核m=K(T)1/3mjK模數(shù)系數(shù)，取0.3-0.4m3．2．4主減速器圓弧及延伸外擺線齒螺旋錐齒輪與雙曲面齒輪的幾何尺寸計(jì)算z19z246(1)/(2)0.195652F大齒輪齒面寬F=0.155d2；F<=10m40E33d2217.7r=[2KKAA-AA(2-sin0 sin0八 00mm 2 L2)]o.5+Amsin02114.30l'=25o+5o[power(z2/Z],0.5)]+90oE/d250tanR]'1.1918cotY=1?2(3)2i0.2348sinY2i0.97353Rm=[(6)-(4)*(11)]/2104.154sins'i等于(5)(11)/(12)0.30845

cos￡，i 0.95124(14)+(9)*(13)1.3189(3)*(12)20.387Rm1=(15)*(16)26.877Tr=0.02(1)+1.061.24(12)/(10)+(17)470.463tann=(5)/(19)(21)0.07[1+(20)(20)]0.51.0024sinn=(20)/(21)0.0698n4.00436sins2=[(5)-(17)(22)]/(12)0.2988tans20.3131tanY1n=(22)/(25)0.2229cosy]][0.976sins2'=(24)/(27)0.306coss2'0.952tanp1n=[(15)-(29)]/(28)1.199(28)[(9)-(30)]-0.0022(3)(31)-0.00043sins1=(24)-(22)(32)0.2988tans10.328tanY1=(22)/(34) 0.2128Y112.01cosy10.978sins=(33)/(37)0.3055￡1'17.79cose1'0.9522tan01=[(15)+(31)-(40)]/(38)1.1930150.03COS010.642802=(42)-(39)32.21cos020.8461tan020.63cotY2=(22)/(33)0.2336Y276.85sinY20.9738cosy20.2274[(17)+(12)(32)]/(37)27.4358(12)/(50)458.021(51)+(52)485.4568(12)(45)/(49)90.4957(43)(51)/(35)82.8747

負(fù)-tana0]=[(41)(55)-(46)(54)]/(53) 0.086負(fù)-a丿014.928C0Sa010.9963(41)(56)/(51)0.00374(46)(56)/(52)0.0001183(54)(55)7499.804[(54)-(55)]/(61)0.001016(59)+(60)+(62)0.0048743[(41)-(46)]/(63)115.504rd，=(64)/(58)115.033(7)/(56)0.9859⑶(50);1.0-(3)左左0.0445；0.80435(5)/(34)-(17)(35);(35)(37)94.89；0.2081(37)+(40)(67)左左1.0204zm=(49)(51)26.717z=(12)(47)-(70)-2.387Am=(12)/(49)106.956A0=0.5(6)/(49)111.779(73)-(72)4.823h=k(12)(45)/(2)gm7.28(12)(46)/(7)0.574

(49)/(45)-(76) 0.577ai40sinai0.6428ai/2=(78)/220cos(ai/2)0.9397tan(ai/2)0.364(77)/(82)1.5852E6d=10560(83)/(2)363.9068，Ka0.17Kb=1.150-(85)0.98人口2=(75)(85)1.2376h，，m2=(75)(86)+0.057.1844雙重收縮齒：02=(84)(85)單位分1.03sin020.018雙重收縮齒：52=(84)-(89)單位分230.936，sinS20.0671h，2=(87)+(74)(90)1.3244h，，2=(88)+(74)(92)7.508C=0.150(75)+0.051.142h=(93)+(94)8.8324hg=(96)-(95)7.6904

Y02=(48)+(89)(89項(xiàng)單位為分) 77.88UZ/SinY020.9777C0SY020.21YR2=(48)-(91)(91項(xiàng)單位為分).R2.73.001SinY.R2.0.9563C0SY.R2.0.2924COtY.R2.0.3057d°2=2(93)(50)+(6)218.3(70)+(74)(50)27.814x02=(106)-(93)(49)26.5243[(72)(90)-(87)]/(99)0.7033[(72)(92)-(88)]/(102)-0.008z0=(71)-(108)-3.0903Zr=(71)+(109)-2.395(12)+(70)(104)112.321sins=(5)/(112)0.2938cosw=[1-(113)2]i/20.9559tans=(113)/(114)0.3074sinY01=(103)(104)0.2795Y0i16.2307cosy010.9601

tanY01 0.2911[(102)(111)+(95)]/(103)-3.9273G°=[(5)(113)-(120)]/(114)14.2512tan九'=(38)(67)/(69)左0.0133九'；cos"0.7633;0.999911△"=(39)-(123);cos△“左17.0267;0.9561901=(117)-(36);cosO14.2207;0.99729±(113)(67)右-(68)右石 石0.02821;-0.4444(123)右/(124)石石 石1.0457(68)左+(87)(68)左左 左95.1475(118)/(125)石石0.9627(74)(127)5.0434B0=(128)+(130)(129)+(75)(126)左100.208(4)(127)-(130)36.7846B=(128)-(132)(129)+(75)(126)1 右56.4997(121)+(131)114.4595d01=(119)(134)/0.566.638(70)(100)/(99)+(12)109.893sins0=(5)/(136)0.3￡017.