高中化學(xué)魯科版第三章自然界中的元素 2023版第3章章末知識網(wǎng)絡(luò)構(gòu)建

章末知識網(wǎng)絡(luò)構(gòu)建一、碳的多樣性過程①～?的化學(xué)方程式分別為：①______________________________________________________________②______________________________________________________________③______________________________________________________________④______________________________________________________________⑤______________________________________________________________⑥______________________________________________________________⑦______________________________________________________________⑧______________________________________________________________⑨______________________________________________________________⑩______________________________________________________________?______________________________________________________________二、氮的循環(huán)過程①～?的化學(xué)方程式分別為：①______________________________________________________________②______________________________________________________________③______________________________________________________________④______________________________________________________________⑤______________________________________________________________⑥______________________________________________________________⑦______________________________________________________________⑧______________________________________________________________⑨______________________________________________________________⑩______________________________________________________________?______________________________________________________________三、硫的轉(zhuǎn)化過程①～?的化學(xué)方程式分別為：①______________________________________________________________②______________________________________________________________③______________________________________________________________④______________________________________________________________⑤______________________________________________________________⑥______________________________________________________________⑦______________________________________________________________⑧______________________________________________________________⑨______________________________________________________________⑩______________________________________________________________?______________________________________________________________?______________________________________________________________四、海水中的元素過程①～?的化學(xué)方程式分別為：①______________________________________________________________②______________________________________________________________③______________________________________________________________④______________________________________________________________⑤______________________________________________________________⑥______________________________________________________________⑦______________________________________________________________⑧______________________________________________________________⑨______________________________________________________________⑩______________________________________________________________?______________________________________________________________?______________________________________________________________?______________________________________________________________一、①2Mg＋CO2eq\o(②C＋O2eq\o(=,\s\up14(點燃))CO2③Na2CO3＋2HCl=2NaCl＋H2O＋CO2↑④Na2CO3＋CO2＋H2O=2NaHCO3⑤NaHCO3＋NaOH=Na2CO3＋H2O⑥2CO2＋2Na2O2=2Na2CO3＋O2⑦CaCO3＋2HCl=CaCl2＋H2O＋CO2↑⑧CaCO3＋CO2＋H2O=Ca(HCO3)2⑨2CO＋O2eq\o(=,\s\up14(點燃))2CO2⑩CO2＋Ceq\o(=,\s\up14(高溫))2CO?3CO＋Fe2O3eq\o(=,\s\up14(高溫))2Fe＋3CO2二、①N2＋O2eq\o(=,\s\up14(放電))2NO②2NO＋O2=2NO2③3NO2＋H2O=2HNO3＋NO④Cu＋4HNO3(濃)=Cu(NO3)2＋2NO2↑＋2H2O⑤3Cu＋8HNO3(稀)=3Cu(NO3)2＋2NO↑＋4H2O⑥N2＋3H2eq\o(,\s\up14(高溫、高壓),\s\do10(催化劑))2NH3⑦4NH3＋5O2eq\o(=,\s\up14(高溫),\s\do10(催化劑))4NO＋6H2O⑧NH3＋HCl=NH4Cl⑨2NH4Cl＋Ca(OH)2eq\o(=,\s\up7(△))CaCl2＋2NH3↑＋2H2O⑩NH4Cleq\o(=,\s\up7(△))NH3↑＋HCl↑?N2＋3Mgeq\o(=,\s\up14(點燃))Mg3N2三、①S＋H2eq\o(=,\s\up14(△))H2S②S＋O2eq\o(=,\s\up14(點燃))SO2③2H2S＋SO2=3S↓＋2H2O④2SO2＋O2eq\o(,\s\up14(催化劑),\s\do10(△))2SO3⑤Na2SO4＋BaCl2=BaSO4↓＋2NaCl⑥SO3＋H2O=H2SO4⑦Cu＋2H2SO4(濃)eq\o(=,\s\up14(△))CuSO4＋SO2↑＋2H2O⑧2H2SO3＋O2=2H2SO4⑨SO2＋2NaOH=Na2SO3＋H2O⑩Na2SO3＋H2SO4=Na2SO4＋H2O＋SO2↑?S＋2Cueq\o(=,\s\up14(△))Cu2S?Fe＋Seq\o(=,\s\up14(△))FeS四、①Mg＋2HCl=MgCl2＋H2↑②Mg＋Cl2eq\o(=,\s\up14(點燃))MgCl2③MgCl2(熔融)eq\o(=,\s\up14(通電))Mg＋Cl2↑④3Mg＋N2eq\o(=,\s\up14(點燃))Mg3N2⑤2Mg＋O2eq\o(=,\s\up14(點燃))2MgO⑥2