高二理科數(shù)學(xué)期中測試題及答案

1(x)xbln(x在)2若fb）2第I卷[1,)(1,)(,(,,共55Pyx2lnx,Pyx2（）()2i22２22１、i2、2i2i、、iRf(1)0f（x）22）'3f)x22111333第Ⅱ卷,共f'xf'x，且3設(shè)aR，函數(shù)fxeae的導(dǎo)函數(shù)為是奇函數(shù)，則a為（）xx5A．0,[0,1]xxf(x)()2fx=1(2)xx2,定積分xe的值為（）0x01A．2eee2erab）S；112312＋＋Nkn*21n，S，S，SS；12341(1項k項)2－項2項kk12＝iz＋x-y2xx）x1a．3232m3(m2m15)i實數(shù)m取怎樣的值時，復(fù)數(shù)z（1）實數(shù)？（2）虛數(shù)？（3）純虛數(shù)？是：2(x)xaxbxa1(,)f322在xab為（）））((）或(x)x3xf.3x()23(x)[3,]在f)22f(x)P(2,6)yf(x)f(x,f1（）(））xNfxf(x)24212f(x)；f(x)；f(x)；f(x).22x1x12x1xaS39811(3)18,(1)2,(1)2,()ffff，,2nSa2annnnnx3f(x)18當(dāng)x1()2fx分,a,aa；minmax123(x,x3x)(3)3(1)()Qyxxxxx3o3o2oooooa6(3)3(1)(2)nP，xxxx，o3o22oo(x)xaxbxcx與x1f32在0x3x或3y624(x2)即y3oo,bf(x)ax[1,2]f(x)c2c(x)2x3x3.3xy0xy0或分f32yf(x)x2a2a32am0xfx有三個不同的實根，求實數(shù)m分分1232axgxxxa0nN)fx，．a(chǎn)nn*xnx1hxfxgxa1a101n,xe1x（efx≥gxa1212nkakk1k1111則nk1a(a)()SSa2ak2ak1k1k1kkk1k1111115(a)(kk1)()k,a2a22k11k1a1k6－1,7)R（SSS+S）k1k1312342ka10ak1k.a2k1,2m150，即m或時，復(fù)數(shù)Z分）3m5（1）當(dāng)m2k1k1即nk1*nNann1.分n（2）當(dāng)m2m15035，即m且m時，復(fù)數(shù)Z分）222150,且m-30m3（3）當(dāng)mm，即時，復(fù)數(shù)Z分）(x)xaxbxc,f(x)3x2axbf32'2f'(x)3(xx，21241()ab0f(1)32ab0a,b2'，'由f得393233[x]或f'(x)0[3,1],[1,]，f(x)當(dāng)xf'(x)3xx2(3x2)(x1)2f(x)222232當(dāng)x(f'(x)0，[f(x)(,)()33fhxa，22xxf(x)x22(31∴hxa2(x)(,))與2f分．3xx210令hxa2202xxa0．22122(x)xx2xc,x[1,2]xf()cx2xffc322331a0∵2，2cf2cf(x)c,x[1,2]118a2118a22∴hx0xx，4412f(2)2cc或c22分當(dāng)xhx，hxxx,x222()66,(2)12,(2)7,xffxx2f分0＋—f(x)x2在y7x，即xy0分y(x)2x3xm3,g(x)6x6x6x(x1)g322hxZ]()0令gxx或分則x,g(xg(x)(0)x1118a21a23，004g(x)Z]Zg(x)mxg(x)g(0)0m2.當(dāng)x分03．∵aa,，e都,，efx≥gxxx1（2xx由g(x),12122g(1)0fxgx有≥．minm即30,3m2m20110當(dāng)x，gxe．g(x)Axf(x)m(Ay分xxegx在a2，2xxhxgxgee1x∴．1xaxa∴hxa22a∵fx2．10e，a．xxx2x2x21013a0．∵xhx2xaxa0a1且x，efx0，03．∵aax21hx3axa2fxx，ex3∴a．fxf11a∴2.1a2e10a1a由又≥a≥e，≤a≤exaxa≤x＜afx0，x2xaxa若a＜x≤efx0．x2ea2x1,afx在xfxfa2a∴由.mine1