




版權(quán)說(shuō)明:本文檔由用戶(hù)提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
Contents§2.1DiscreteLTIsystems:theconvolutionsum§2.2ContinuousLTIsystems:theconvolutionintegral§2.3PropertiesofLTIsystems§2.4CausalLTIsystemsdescribedbydifferentialordifferenceequations§2.5SingularityfunctionsDiscreteLTIsystems:theconvolutionsumConsidersignalx[n]:Anarbitrarysequencecanberepresentedasalinearcombinationofshiftedunitimpulses[n-k],wheretheweightsinthislinearcombinationarex[k].Writeas:……-4-3-2-101234nx[n]DiscreteLTIsystems:theconvolutionsum
(siftingproperty—篩選性).....2]-[n
x[2]1]-[n
x[1]
][]0[]1[]1[]2[]2[....][+++++-++-+=dddddnxnxnxnxDiscreteLTIsystems:theconvolutionsumLeth[n]denotetheresponseoflinearsystemto[n].
i.e.
h[n]—theunitimpulseresponse.then,each[n]ofx[n]response:
….….DiscreteLTIsystems:theconvolutionsum
….….
Thisresultisreferredtoastheconvolutionsum,andtheoperationontheright-handsideofequationisknownastheconvolutionsumofx[n]andh[n].DiscreteLTIsystems:theconvolutionsumWerepresenttheoperationas
y[n]=x[n]h[n](2.7)Thesame,isreferredtoastheconvolutionsumofx[n]and[n].Somenotes:1)AnLTIsystemiscompletelycharacterizedbyitsh[n].DiscreteLTIsystems:theconvolutionsum2)Thegraphofconvolutionsum.Transformindependentvariable:
x[n],h[n]x[k],h[k]andh[k]
h[-k]Shifth[-k]nstepsh[n-k].Foranyn,x[k]multipliedbyh[n-k]andx[k]·h[n-k].DiscreteLTIsystems:theconvolutionsumExample2.2determiney[n]=x[n]h[n].Answer:(a)DiscreteLTIsystems:theconvolutionsum
(b)Shifth[-k]totheright(n>0)ortotheleft(n<0).n<0,y[n]=0n=0,y[0]=x[0]h[0]=0.51=0.5n=1,y[1]=x[0]h[1]+x[1]h[0]=0.5+2=2.5n=1n=2DiscreteLTIsystems:theconvolutionsum
(c)Foranyparticularvalueofn,wemultiplythesetwosignalsandsumoverallvaluesofk.n=2,y[2]=x[0]h[2]+x[1]h[1]=0.5+2=2.5n=3,y[3]=x[1]h[2]=2n4,y[n]=0n=3n=4n=2DiscreteLTIsystems:theconvolutionsumory[n]={0.5,2.5,2.5,2}n=0,1,2,3,Themainstepsofconvolutionsumgraph:
reversalshiftmultiplysum(3)Calculationofconvolutionsumcanbedonebyuprightmultiplication.DiscreteLTIsystems:theconvolutionsum
h[n]{0.52}(0)
x[n]{111}(0)0.520.520.52
y[n]{0.52.52.52}(0)DiscreteLTIsystems:theconvolutionsumExample2.3x[n]andh[n]givenbyDeterminey[n]=?Answer:forn0
(Seeproblem1.54)ContinuousLTIsystems:theconvolutionintegral
Webeginbyconsideringapulseor“staircase”approximation,x(t)toacontinuoussignalx(t).IfdefineThen,,andtheshadepulseis,isAs,writtenas……tkx(k)ContinuousLTIsystems:theconvolutionintegralContinuousLTIsystems:theconvolutionintegralConsequently—siftingpropertyofFortheexampleofx(t)=u(t),ContinuousLTIsystems:theconvolutionintegralLeth(t)astheresponseofLTIto
,thenconvolutionintegralorsuperpositionintegralEq.willberepresentedsymbolicallyas
y(t)=x(t)h(t)ContinuousLTIsystems:theconvolutionintegralProcedureforevaluatingconvolution⑴Changetimevariablesandreverse:⑵Shiftlikethis:whent>0towardright;otherwisetowardleft⑶Multiplytogether⑷IntegralContinuousLTIsystems:theconvolutionintegralCompareExample2.6:Answer:ContinuousLTIsystems:theconvolutionintegralAnswer:Fort<0:BecauseThereforeFort>00101t0t>0t10t<0h(t-)1ContinuousLTIsystems:theconvolutionintegral
foralltExample:DetermineAnswer:01e2e-(t-)t01e2te-(t-)………0y(t)t…01e2x()=h()=e-(t<0)(t>0)ContinuousLTIsystems:theconvolutionintegral01e2e-(t-)t01e2te-(t-)0y(t)tContinuousLTIsystems:theconvolutionintegralExample2.7consider:Andthendetermine
x(t)={
1,0<t<T
0,otherwiseh(t)={t,0<t<2T0,otherwise1T0x(t)tT2T2Th(t)0tContinuousLTIsystems:theconvolutionintegralAnswer:(1)t<0andt>3T
(2)0<t<T(3)T<t<2T
1T0x()t-2T0tT1T<t<2TT2T2Th()0t-2T0tT10<t<TtContinuousLTIsystems:theconvolutionintegral(4)2T<t<3Ty(t)=0,t<0andt>3TAssignments(P139)2.10,2.11t-2T0tT1tT2T3T..…………y(t)0PropertiesofconvolutionThecommutativepropertyx(t)y(t)h(t)x(t)y(t)h(t)PropertiesofconvolutionThedistributivepropertyAlso,x(t)+y(t)+x(t)y(t)PropertiesofconvolutionTheassociativeproperty(c)y[n]x[n]=*(a)x[n]y[n](d)x[n]y[n](b)y[n]x[n]=*PropertiesofLTIsystemsLTIsystemswithandwithoutmemoryFordiscretesystemwithoutmemory:
h[n]=0forn≠0Inthiscasewherek=h[0]isaconstant,andconvolutionsumisPropertiesofLTIsystemsWithmemory:h[n]≠0forn≠0.Forcontinuoussystemwithoutmemory:
h(t)=0fort≠0
k—aconstantIfk=1,systemsbecomeidentitysystems,andPropertiesofLTIsystemsInvertibilityofLTIsystemIfthenthesystemwithistheinverseofthesystemwith.x(t)h0(t)w(t)=x(t)(a)h1(t)x(t)identitysystemh(t)=(t)x(t)(b)PropertiesofLTIsystemsSimilarly,ifthensystemofistheinversesystemofExample:considerdeterminePropertiesofLTIsystemsCausalityforLTIsystemsIfh[n]=0,forn<0orh(t)=0,fort<0thenthesystemiscausal.InthiscasePropertiesofLTIsystemsStabilityforLTIsystems
absolutelysummable.
absolutelyintegrable.Example:ifthenisstableifisn’tstable
Assignments:2.28(a)(d),2.29(a)(d)PropertiesofLTIsystemsTheunitstepresponseofanLTIsystemTheunitstepresponse,s(t)ors[n],correspondingtotheoutputwhen
x[n]=u[n]orx(t)=u(t)PropertiesofLTIsystems
Assignments:P1392.12,2.23CausalLTIsystemsdescribedbyequationsLinearconstant-coefficientdifferentialequationsAfirst-order
ageneralNth-order
(2.109)CausalLTIsystemsdescribedbyequations(1)theresponsetoaninputx(t)willgenerallyconsistofthesumofaparticularsolutionandahomogeneoussolution,i.e.(2)Inordertodeterminey(t),wemustspecifyauxiliaryconditions.(3)Wewillusetheconditionofinitialrestasauxiliarycondition.Thatis,ifx(t)=0for,weassumethat(4)Undertheconditionofinitialrest,thesystemdescribedbyEq.(2.109)iscausalandLTI.[determineh(t)fromeq(2.109),seeproblem2.56.]CausalLTIsystemsdescribedbyequationsLinearconstantcoefficientdifferenceequationsThenth-order(1)Inamannerexactlyanalogoustothatfordifferential(2)Auxiliaryconditionalsoisinitialrest,
i.eifx[n]=0forn<n0,theny[n]=0for
n<.ThissystemisLTIandcausal.CausalLTIsystemsdescribedbyequations(3)Eq.(2.113)canberearrangedintheformiscalledarecursiveequation(N≧1).Determineh[n]andy[n]ofEq.(2.115)bymeansofrecursion.CausalLTIsystemsdescribedbyequationsExample2.15considerdetermineh[n]=?Solution:Letandsystemisinitialrest,i.e.,forn≦-1.forn≧0,……infiniteimpulseresponsesystem,Assignment:2.18(P140)CausalLTIsystemsdescribedbyequationsBlockdiagramrepresentationsoffirst-ordersystemsdescribedbydifferentialanddifferenceequationsConsiderequation(2.126)Threebasicoperations:+(a)anadderx[n]aax[n](b)multiplicationbyacoefficientDx[n-1](c)aunitdelayx[n]CausalLTIsystemsdescribedbyequationsRewriteequation(2.126)asarecursive(2.127)BlockdiagramdescribedbyEq.(2.126)+Dy[n]-ay[n-1]x[n]bCausalLTIsystemsdescribedbyequationsAfirst-orderdifferentialequationrewriteitasThreebasicoperations:Additionmultiplicationbyacoefficientdifferentiationy(t)+Dx(t)CausalLTIsystemsdescribedbyequationsOursystemcanbeimplementedusinganintegrator.Assignment:p(148)2.38(a)2.39(b)x(t)+y(t)-abSingularityfunctionsTheunitimpulseasanidealizedshortpulseTheish(t)ofidentitysystem.Equation(2.134)isabasicpropertyof.again0t2t0SingularityfunctionsSimilarly,thelimitsasoformustbeunitimpulses,andsoonDefiningtheunitimpulsethroughconvolutionUptothepresent,bedefinedas
(or)Thelimitsofshortpulsewithdurationandthearea=1.
SingularityfunctionsSampling(orsifting)property:Definingtheunitimpulsethroughconvolution:1.letx(t)=1(forallt)Then2.Supposeanyfunctionx(t)andf(t)boundedeverywhereandcontinuousatt=0ort=,then
SingularityfunctionsInferenceAnd3.isevenfunction:SingularityfunctionsProve:Consi
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶(hù)所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶(hù)上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶(hù)上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶(hù)因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 2025年中考物理二輪復(fù)習(xí):電與磁 信息 能源 尖子生測(cè)試卷(含答案解析)
- 第五單元 第1章 第1節(jié) 腔腸動(dòng)物和扁形動(dòng)物(新教學(xué)設(shè)計(jì))2023-2024學(xué)年八年級(jí)上冊(cè)生物(人教版)
- 借款房屋轉(zhuǎn)讓合同范例
- 產(chǎn)品采購(gòu)合同范例加工商
- 主體裝修合同范本
- 互聯(lián)網(wǎng)醫(yī)療行業(yè)月度個(gè)人工作計(jì)劃
- 農(nóng)村安裝光伏合同范例
- 眼科相關(guān)治療
- 班級(jí)工作計(jì)劃執(zhí)行效率總結(jié)
- 學(xué)校學(xué)期校園文明創(chuàng)建計(jì)劃
- 流浪地球2:重返家園-漫游《宇宙的邊疆》 教學(xué)設(shè)計(jì)
- 《幼兒園課程》01 幼兒園課程概述
- 打井合同(范本8則)
- 風(fēng)電場(chǎng)道路和平臺(tái)工程施工設(shè)計(jì)方案
- GB/T 26695-2011家具用鋼化玻璃板
- GB/T 25052-2010連續(xù)熱浸鍍層鋼板和鋼帶尺寸、外形、重量及允許偏差
- GB/T 15057.1-1994化工用石灰石采樣與樣品制備方法
- GB/T 1094.2-2013電力變壓器第2部分:液浸式變壓器的溫升
- DB32/T 4402-2022 河湖和水利工程管理范圍劃定技術(shù)規(guī)程
- 高中課本劇 鴻門(mén)宴劇本
- 項(xiàng)目經(jīng)理崗位月度KPI績(jī)效考核表
評(píng)論
0/150
提交評(píng)論