計(jì)算概論之C程序設(shè)計(jì)-知到答案、智慧樹答案

計(jì)算概論之C程序設(shè)計(jì)-知到答案、智慧樹答案第一章單元測(cè)試1、問(wèn)題：世界上第一代計(jì)算機(jī)被叫做：選項(xiàng)：A:晶體管計(jì)算機(jī)B:電子管計(jì)算機(jī)C:集成電路計(jì)算機(jī)D:超大規(guī)模集成電路計(jì)算機(jī)答案:【電子管計(jì)算機(jī)】2、問(wèn)題：第一次數(shù)學(xué)危機(jī)源自對(duì)哪個(gè)問(wèn)題的討論？選項(xiàng)：A:有些量無(wú)法用整數(shù)表達(dá)B:三角形內(nèi)角和是否為180度答案:【有些量無(wú)法用整數(shù)表達(dá)】3、問(wèn)題：第二次數(shù)學(xué)危機(jī)源自對(duì)哪個(gè)問(wèn)題的討論？選項(xiàng)：A:質(zhì)數(shù)的出現(xiàn)規(guī)律B:微積分中的無(wú)窮小答案:【微積分中的無(wú)窮小】4、問(wèn)題：第三次數(shù)學(xué)危機(jī)源自對(duì)哪個(gè)問(wèn)題的討論？選項(xiàng)：A:集合定義的完備性B:數(shù)列的極限問(wèn)題答案:【集合定義的完備性】5、問(wèn)題：圖靈機(jī)模型的提出者是？選項(xiàng)：A:馮諾伊曼B:圖靈答案:【圖靈】6、問(wèn)題：十進(jìn)制123對(duì)應(yīng)的二進(jìn)制表示是？選項(xiàng)：答案:【】7、問(wèn)題：如下哪個(gè)是電子管的特點(diǎn)？選項(xiàng)：A:容易損壞，壽命短B:體積小答案:【容易損壞，壽命短】8、問(wèn)題：如下哪個(gè)是晶體管的特點(diǎn)？選項(xiàng)：A:主要原料是硅B:比電子管耗電答案:【主要原料是硅】9、問(wèn)題：如下哪個(gè)是集成電路的特點(diǎn)？選項(xiàng)：A:體積小B:壽命短答案:【體積小】10、問(wèn)題：如下哪個(gè)是當(dāng)前量子計(jì)算機(jī)的特點(diǎn)？選項(xiàng)：A:能進(jìn)行并行運(yùn)算B:能在常溫下工作答案:【能進(jìn)行并行運(yùn)算】11、問(wèn)題：導(dǎo)致CPU不能造得更大的主要原因是？選項(xiàng)：A:價(jià)格原因B:散熱原因答案:【散熱原因】12、問(wèn)題：如下哪個(gè)部分不是馮諾伊曼計(jì)算機(jī)的組成部分？選項(xiàng)：A:存儲(chǔ)器B:讀寫頭答案:【讀寫頭】13、問(wèn)題：如下那種存儲(chǔ)器的處理速度更快？選項(xiàng)：A:硬盤B:寄存器答案:【寄存器】14、問(wèn)題：下列哪個(gè)關(guān)于CPU指令集的說(shuō)法是錯(cuò)誤的？選項(xiàng)：A:對(duì)不同品牌的CPU而言，指令集通常是不同的B:指令集包含的指令數(shù)目越多，CPU運(yùn)算速度越快答案:【指令集包含的指令數(shù)目越多，CPU運(yùn)算速度越快】15、問(wèn)題：下列哪個(gè)關(guān)于程序執(zhí)行的說(shuō)法是錯(cuò)誤的？選項(xiàng)：A:用高級(jí)語(yǔ)言編寫的程序，不經(jīng)過(guò)編譯也能夠運(yùn)行B:程序都要經(jīng)過(guò)編譯變成CPU能夠接受的指令才能運(yùn)行答案:【用高級(jí)語(yǔ)言編寫的程序，不經(jīng)過(guò)編譯也能夠運(yùn)行】第二章單元測(cè)試1、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目1實(shí)現(xiàn)冒泡排序（程序抄寫題）答題地址：/ziyoulianxi/18/請(qǐng)完全按照如下的程序書寫代碼，并在書寫的過(guò)程中體會(huì)優(yōu)秀的代碼風(fēng)格：選項(xiàng)：A:7d90dd325006cfe3fa1c91da35852d19d71ef0e14a1fcb83b406fde2ed075ebbB:134dfa561a10e8163e953adec3d4e16a4bd4839300eb05180a28634fdfba212eC:db758a55d8ae037d1c673f2cb8f23c6c56298fec22be2b05685434a86d3ad8beD:fc4fb74a5a7ec315adae71dd7719c4848602fbb8d5fc641a3a9146e2f8d5ed13E:a466ca48a245f567d6414b404d8060982771bf568f8de201c68c60e2c2b4bc10答案:【134dfa561a10e8163e953adec3d4e16a4bd4839300eb05180a28634fdfba212e】2、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目2整數(shù)的個(gè)數(shù)答題地址：/ziyoulianxi/22/選項(xiàng)：A:dfa8c9b50a882f3396d0bf51dcf8423593a45c9a6384deda4325539f4da16e1bB:db48b934d30e6c8232650d0523dad4a6b2fc0e748a57d348536b5f3b6b8fc61fC:aa2f1a22072b68321cad2132b9e625cec2887ab82adc05b59056ca4ac8e0a3baD:eff53f8b060b7875ab269ac044b7d399bf55976de8d0293d234c00c447c74ff5E:b7c7a8c59878c814bb722d38c2f57cc37b3abff3427b774dc2a920ad002fb222答案:【b7c7a8c59878c814bb722d38c2f57cc37b3abff3427b774dc2a920ad002fb222】第三章單元測(cè)試1、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目1蘋果和蟲子答題地址：/ziyoulianxi/12/選項(xiàng)：A:7d90dd325006cfe3fa1c91da35852d19d71ef0e14a1fcb83b406fde2ed075ebbB:5ef8368af16374cabef8e5ae3ee39c4374a36a4c52b4b560bc8fc10ca47a6605C:db758a55d8ae037d1c673f2cb8f23c6c56298fec22be2b05685434a86d3ad8beD:fc4fb74a5a7ec315adae71dd7719c4848602fbb8d5fc641a3a9146e2f8d5ed13E:a466ca48a245f567d6414b404d8060982771bf568f8de201c68c60e2c2b4bc10答案:【5ef8368af16374cabef8e5ae3ee39c4374a36a4c52b4b560bc8fc10ca47a6605】2、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目2尋找下標(biāo)答題地址：/ziyoulianxi/03/選項(xiàng)：A:6f1918577ed2dd6eca7f81918bbe33d5b0f87fa658b8a691d35cfe1454f917ddB:731aa18fc52fef74b2971590b9ae42b30a82247503adfc5c8e83b83125671fc3C:c635624e1c024ff7e894136932b7bcbc25dd1ea0be0de4abf60e9bd4fdbabc71D:76d5b794424fa51268bcd739a1523ee8b4494657f152f3ca46c78de2d38b4172E:b22bc180f42c137de773abb2114134dc1e6286335c160a9724752c614ea6aa8f答案:【6f1918577ed2dd6eca7f81918bbe33d5b0f87fa658b8a691d35cfe1454f917dd】第四章單元測(cè)試1、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目1單詞翻轉(zhuǎn)答題地址：/ziyoulianxi/04/選項(xiàng)：A:7d90dd325006cfe3fa1c91da35852d19d71ef0e14a1fcb83b406fde2ed075ebbB:497210b9cce1d34853156ceb896b0ce1e2df4c5a3b7390521823b1fa5aa7a4bbC:db758a55d8ae037d1c673f2cb8f23c6c56298fec22be2b05685434a86d3ad8beD:fc4fb74a5a7ec315adae71dd7719c4848602fbb8d5fc641a3a9146e2f8d5ed13E:a466ca48a245f567d6414b404d8060982771bf568f8de201c68c60e2c2b4bc10答案:【497210b9cce1d34853156ceb896b0ce1e2df4c5a3b7390521823b1fa5aa7a4bb】2、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目2括號(hào)匹配問(wèn)題答題地址：/function2/5/選項(xiàng)：A:dfa8c9b50a882f3396d0bf51dcf8423593a45c9a6384deda4325539f4da16e1bB:db48b934d30e6c8232650d0523dad4a6b2fc0e748a57d348536b5f3b6b8fc61fC:aa2f1a22072b68321cad2132b9e625cec2887ab82adc05b59056ca4ac8e0a3baD:eff53f8b060b7875ab269ac044b7d399bf55976de8d0293d234c00c447c74ff5E:be68157240bff713c48932dfb78b11a9da883061e0ee903cf8b81f4425da8dfd答案:【be68157240bff713c48932dfb78b11a9da883061e0ee903cf8b81f4425da8dfd】第五章單元測(cè)試1、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目1計(jì)算矩陣邊緣之和答題地址：/ziyoulianxi/07/選項(xiàng)：A:4773e826c8795413d999979e686e7f97c4b1202ada08775315775407aa3afab9B:cbda7c667ca08285622c696473828f7cb780c463f38ab0ea33c2fb77dc0d39f7C:6d7c37ebf9599d2ae4d7375f0caa2bf2a3c2d2fc0c63a62cbcde69e8cc05baaaD:b6286400eb9a828cc5a16de2e61ffcc1a1ec8d88fa83b27f2b5c1f7e78d38400E:3c8a95adb9005a731a971860944f175e1b73e5b9f79b23c1c88e9b018556f598答案:【4773e826c8795413d999979e686e7f97c4b1202ada08775315775407aa3afab9】2、問(wèn)題：答題說(shuō)明：請(qǐng)大家到指定答題地址答題，提交代碼并通過(guò)測(cè)試后，會(huì)得到通過(guò)碼的下載地址，將文件下載下來(lái)用記事本打開即得到通過(guò)碼，將通過(guò)碼對(duì)應(yīng)的選項(xiàng)選出即可。題目2尋找山頂答題地址：/ziyoulianxi/06/選項(xiàng)：A:65113f78038971c2f610283f2150cc457732dc6474581bcb78fc09092d6364e2B:270ae2146a5493db7fb7176f88b4fabf0cd825e258e4ffadbb4cb50a3b38ba0cC:9b631c44999c90