脫硫計算公式

石灰石/石膏濕法脫硫,,,,,,,,,,

1,校核煤質(zhì),,,,,,,,,

,Car=,64,%,,Nar=,1,%,,,

,Har=,5,%,,War=,8,%,,,

,Oar=,6.6,%,,Aar=,16,%,,,

,Sar=,0.4,%,,Var=,15,%,,,

,換算成干燥無灰基的元素含量,,,,,,,,,

,Cdaf=,84.21052632,%,取,Cdaf=,84,%,,,

,Hdaf=,6.578947368,%,,Hdaf=,6.6,%,,,

,Odaf=,8.684210526,%,,Odaf=,8.7,%,,,

,Sdaf=,0.526315789,%,,Sdaf=,0.5,%,,,

,"Qdaf,net=",339Cdaf+1030Hdaf-109(Odaf-Sdaf)=,,,,344.3447368,MJ/kg,,,

,,,,取,"Qdaf,net=",34.4,MJ/kg,,,

,換算成低位收到基發(fā)熱量,,,,,,,,,

,"Qar,net=","Qdaf,net*76/100=",,,,26.144,MJ/kg,,,

,,,,取,"Qar,net=",25.8,MJ/kg,,,

,全廠效率為,,38,%,含硫量為,0.4,%,,,

,燃燒計算,,,,,,,,,

,mcoal=,,,,,,,,,

,mcoal=,0.073439412,=,73.4,t/h,,,,,

2,標(biāo)準(zhǔn)狀況下理論空氣量,,,,,,,,,

,Qa’=,4.76*（1.867CY+5.56HY+0.7SY-0.7OY）=,,,,6.8043248,m3/kg,,,

,,,,取,Qa’=,6.8,m3/kg,,,

3,標(biāo)準(zhǔn)狀況下理論煙氣量（空氣含濕量為12.93g/m3）,,,,,,,,,

,Qs’=,1.867（CY+0.375SY)+11.2HY+1.24WY+0.016Qa'+0.79Qa'+0.8NY,,,,,,,,

,,,,,=,7.3456805,m3/kg,,,

,,,,取,Qs’=,7.35,m3/kg,,,

4,標(biāo)準(zhǔn)狀況下實(shí)際煙氣量,,,,,,,,,

,空氣過剩系數(shù),,α=,1.3,,,,,,

,Qs=,Qs’+1.016(α-1)Qa',,,=,9.42264,m3/kg,,,

,,,,取,Qs=,9.4,m3/kg,,,

5,標(biāo)準(zhǔn)狀況下煙氣含塵濃度,,,,,,,,,

,排煙中飛灰占煤中不可燃組分的比例,,,,dsh=,16,%,,,

,C=,,=,0.002723404,kg/m3,,,,,

,,取,C=,0.002723,kg/m3,,,,,

6,標(biāo)準(zhǔn)狀況下煙氣中濃度,,,,,,,,,

,CSO2=,,=,851.0638298,mg/m3,,,,,

,,取,CSO2=,852,mg/m3,,,,,

,SO2濃度的校準(zhǔn),,,基準(zhǔn)氧含量為,,6,%,,,

,"CSO2,at4.6%=",,,,,,,,,

,"CSO2,at4.6%=",931.52,mg/m3,取,"CSO2,at4.6%=",932,mg/m3,,,

,二氧化硫排放標(biāo)準(zhǔn)（標(biāo)準(zhǔn)狀態(tài)下）：,,,,200,mg/m3,,,,

,,,,"CSO2,at6%=",218.6666667,mg/m3,,,,

,,,取,"CSO2,at6%=",219,mg/m3,,,,

,除硫效率為,,76.5258216,%,,,,,,

,,取,77,%,,,,,,

7,標(biāo)準(zhǔn)狀況下SO2燃燒產(chǎn)量,,,,,,,,,

,mSO2=,,,=,0.5872,t/h,,,,

,,,取,mSO2=,0.59,t/h,,,,

,SO2的脫除量,,,,,,,,,

,"mSO2,removal=",,0.4543,t/h,,,,,,

,取,"mSO2,removal=",0.45,t/h,,,,,,

8,煙氣中水蒸氣密度,,,,,,,,,

,由理想氣體狀態(tài)方程得,,,,,,,,,

,PVwater=nwaterRT,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρ=,0.778501328,kg/Nm3,,,,,,,

,取,ρ=,0.78,kg/Nm3,,,,,,

9,煙氣體積流量,,,,,,,,,

,"Vfluegas,wet=mcoal.Vfluegas",,,,,,,,,

,"Vfluegas,wet=",,689960,Nm3/h,,,,,,

,取,"Vfluegas,wet=",,690000,Nm3/h,,,,,

,"Vfluegas，dry=Vfluegas,wet.(1-0.083)=",,,,632730,Nm3/h,,,,

,取,"Vfluegas,dry=",,633000,Nm3/h,,,,,

,Vwater=,57000,Nm3/h,,,,,,,

10,煙氣質(zhì)量流量,,,,,,,,,

,"mfluegas,dry=Vdry.ρfluegas,dry",,,,,,,,,

,煙氣密度（標(biāo)準(zhǔn)狀態(tài)）：ρ=,,,1.34,kg/m3,,,,,

,"mfluegas,dry=",,848220,kg/h,,,,,,

,取,"mfluegas,dry=",,848000,kg/h,,,,,

,"mfluegas,wet=mfluegas,dry+mwater",,,,,,,,,

,mwater=,44460,kg/h,,,,,,,

,"mfluegas,wet=",,892460,kg/h,,,,,,

,取,"mfluegas,wet=",,892000,kg/h,,,,,

11,吸收塔飽和溫度計算,,,,,,,,,

,假定電除塵器出口溫度為,,,135,°C,,,,,

,GGH出口溫度為,,,108,°C,,,,,

,干煙氣水含量,,,,,,,,,

,,,,,,,,,,,

,x1=,0.052429245,,,,,,,,

,取,x1=,0.052,,,,,,,

,"在h,x圖上，108°C和0.052的交點(diǎn)的焓h=",,,,248,kJ/kg,,,,

,沿等焓線到飽和線可得到飽和溫度T,,,,,,,,,

,T=,48,°C,,x2=,0.077,,,,

,"mwater,vapourised=(xwater,outlet-xwater,inlet).mfluegas,dry",,,,,,,,,

,"mwater,vapourised=",,21200,kg/h,,,,,,

,,,,=,27179.48718,Nm3/h,,,,

,,取,"Vwater,saturation=",,27000,Nm3/h,,,,

12,吸收塔出口凈煙氣的計算,,,,,,,,,

,"Vwater,vapourised,cleangas=Vwater+Vwater,saturation",,,,,,,,,

,"Vwater,vapourised,cleangas=",,84000,Nm3/h,,,,,,

,"Vcleangas,wet=Vinlet,dry+Vwater,vapourised,cleangas",,,,,,,,,

,"Vcleangas,wet=",,717000,Nm3/h,,,,,,

13,吸收塔煙氣計算結(jié)果匯總,,,,,,,,,

,13.1吸收塔入口：,,,,,,,,,

,Vwet=,690000,Nm3/h,,,,,,,

,Vdry=,633000,Nm3/h,,,,,,,

,mwet=,892000,kg/h,,,,,,,

,mdry=,848000,kg/h,,,,,,,

,Vwater,57000,Nm3/h,,,,,,,

,mwatewr,44460,kg/h,,,,,,,

,T1=,108,°C,,,,,,,

,O2=,6,%(dry),,,,,,,

,SO2=,852,mg/m3,,,,,,,

,"SO2,6%O2=",932,mg/m3,,,,,,,

,13.2吸收塔出口：,,,,,,,,,

,Vwet=,717000,Nm3/h,,,,,,,

,Vdry=,633000,Nm3/h,,,,,,,

,mwet=,913200,kg/h,,,,,,,

,mdry=,848000,kg/h,,,,,,,

,Vwater,84000,Nm3/h,,,,,,,

,mwatewr,65520,kg/h,,,,,,,

,T1=,48,°C,,,,,,,

,O2=,,%(dry),,,,,,,

,SO2=,200,mg/m3,,,,,,,

,"SO2,6%O2=",219,mg/m3,,,,,,,

14,廢水流量的計算,,,,,,,,,

,假定煙氣中HCl的濃度CHCl，fluegas=,,,,46,mg/Nm3,HCl的去除率為,,98,%

,廢水中Cl-含量保持,,15,g/L,,,,,,

,"mCl-=0.98.CHCl,fluegasVdry",,,,,,,,,

,mCl-=,28.53564,kg/h,,,,,,,

,取,mCl-=,28.5,kg/h,,,,,,

,,,,,,,,,,,

,mwater=,1900,kg/h,,,,,,,

15,石灰石消耗量/石膏產(chǎn)量,,,,,,,,,

,SO2+CaCO3+2H2O+1/2O2→CaSO4.2H2O+CO2,,,,,,,,,

,石灰石耗量,,,,,,,,,

,0.70984375,t/h,,取,0.7,t/h,,,,

,石膏產(chǎn)量,,,,,,,,,

,1.22093125,t/h,,取,1.2,t/h,,,,

16,工藝水消耗量,,,,,,,,,

,"mwater=mwater,vapourised+mwashwater+mcrystalwater+mgypsum,moisture",,,,,,,,,

,mwater=,23484.49612,kg/h,取,mwater=,23484,kg/h,,,

,Vmater=,23.484,m3/h,,,,,,,

17,石膏脫水（石膏密度ρgypsum=,,,2.3,kg/l,水的密度ρwater=,,1,kg/l,

,假定,,,,,,,,,

,吸收塔石膏濃度Cgypsum=,,,13,%,,,,,

,旋流器底流石膏濃度Cgypsum=,,,50,%,,,,,

,真空皮帶機(jī)石膏濃度Cgypsum=,,,90,%,,,,,

,旋流器頂流石膏濃度Cgypsum=,,,3,%,,,,,

,17.1石膏漿液密度計算,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρs=,1.07930549,kg/l,,,,,,,

,取,ρs=,1.079,kg/l,,,,,,

,17.2旋流器底流密度計算,,,,,,,,,

,"ρs,hydrocyclone,underflow=",,,1.393939394,kg/l,,,,,

,取,"ρs,hydrocyclone,underflow=",,,1.394,kg/l,,,,

,17.3旋流器頂流密度計算,,,,,,,,,

,"ρs,hydrocyclone,overflow=",,,1.017249005,kg/l,,,,,

,取,"ρs,hydrocyclone,overflow=",,,1.017,kg/l,,,,

,17.4脫水石膏產(chǎn)量,,,,,,,,,

,mbeltfilter=,,,=,1333.333333,kg/h,,,,

,,,取,mbeltfilter=,1330,kg/h,,,,

,"mhydrocyclone,underflow=",,,,,=,2400,kg/h,,

,"Vhydrocyclone,underflow=",,,,,=,1.721664275,m3/h,,

,,,,取,"Vhydrocyclone,underflow=",,1.72,m3/h,,

,17.5吸收塔來石膏漿液計算,,,,,,,,,

,"mfrom,absorbor=mhydrocyclone,underflow+mhydeocyclone,overfloe",,,,,,,,,

,"mfrom,absorbor.Cgypsum=mhydrocyclone,underflow.Cgypsum,underflow+mhydeocyclone,overfloe.Cgypsum,overflow",,,,,,,,,

,聯(lián)立以上方程組解得,,,,,,,,,

,"mfrom,absorbor=",,11280,kg/h,,,,,,

,"mgypsum=mfrom,absorbor.Cgypsum",,,,,,,,,

,mgypsum=,1466.4,kg/h,,取,mgypsum=,1466,kg/h,,

,"mwater=mfrom,absorbor-mgypsum=",,,9814,kg/h,,,,,

,"Vfrom,absorbor=",,,,=,10.45412419,m3/h,,,

,,,取,"Vfrom,absorbor=",,10.45,m3/h,,,

18,石灰石漿液供給,,,,,,,,,

,石灰石耗量mCaCO3=,,0.7,t/h,,,,,,

,假定石灰石漿液濃度CCaCO3=,,,30,%,,,,,

,石灰石固體密度ρCaCO3=,,,2.8,kg/l,,,,,

,18.1石灰石漿液質(zhì)量流量,,,,,,,,,

,msuspension=,,,=,2.333333333,t/h,,,,

,,取,msuspension=,,2.33,t/h,,,,

,18.2石灰石漿液密度,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρsuspension=,,1.238938053,kg/l,,,,,,

,取,ρsuspension=,,1.24,kg/l,,,,,

,18.3石灰石漿液體積流量,,,,,,,,,

,Vsuspension=,,,=,1.879032258,m3/h,,,,

,,,取,Vsuspension=,1.88,m3/h,,,,

19,漿液池尺寸,,,,,,,,,

,假定漿液停留時間△t=,,,2,h,,,,,

,漿液罐體積,,,,,,,,,

,Vtank=Vsuspension.△t=,,3.76,m3,,,,,,

,D=(0.89.Vtank)1/3=,,1.495750938,m,,,,,,

,取,D=,1.5,m,,,,,,

,H=1.5×D=,,2.25,m,,,,,,

20,濾池箱尺寸計算,,,,,,,,,

,"假定濾布沖洗水量mwater,beltfilter=",,,5,t/h,,,,,

,以,50,%,的石膏質(zhì)量流量作為石膏沖洗水量,,,,,,

,20.1濾液量,,,,,,,,,

,"mwater,filtrate=mwater,beltfilter+mwater,wash",,,,,,,,,

,"mwater,filtrate=",,5.6,t/h,,,,,,

,"Vwater,filtrate≈",,5.6,m3/h,,,,,,

,假定濾液箱停留時間△t=,,,1,h,,,,,

,20.2濾液箱容積,,,,,,,,,

,"Vtank=Vwater,filtrate.△t=",,,5.6,m3,,,,,

,D=(0.89.Vtank)1/3=,,1.708150023,m,,,,,,

,取,D=,1.7,m,,,,,,

,H=1.5×D=,,2.55,m,,,,,,

21,吸收塔尺寸的設(shè)計,,,,,,,,,

,21.1循環(huán)漿液流量,,,,,,,,,

,煙氣流量Vwet=,,690000,Nm3/h,,,,,,

,二氧化硫濃度CSO2=,,932,mg/m3,,,,,,

,二氧化硫脫除率,,77,%,,,,,,

,假定液氣比L/G=,,12,l/Nm3,,,,,,

,吸收塔出口凈煙氣溫度T2=,,,48,°C,,,,,

,"Vwet,actual=",,,,,,,,,

,"Vwet,actual=",,842996.7051,Nm3/h,,,,,,

,取,"Vwet,actual=",,843000,Nm3/h,=,234.1666667,Nm3/s,,

,,,,取,"Vwet,actual=",,234,Nm3/s,,

,循環(huán)漿液流量,,,,,,,,,

,,,,10116,Nm3/h,,,,,

,設(shè)計噴淋塔層數(shù)為,,3,,,,,,,

,每層循環(huán)漿液流量,,,,,,,,,

,Q單循=,,3372,Nm3/h,=,0.936666667,Nm3/s,,,

,,,,取,Q單循=,0.937,Nm3/s,,,

,21.2吸收塔直徑,,,,,,,,,

,假定吸收塔煙氣流速ω=,,,3.7,m/s,,,,,

,d=,,,=,8.973505348,m,,,,

,,,取,d=,9,m,,,,

,21.3吸收塔循環(huán)區(qū)體積,,,,,,,,,

,假定循環(huán)漿液停留時間t=,,,4.3,min,,,,,

,Vabsorbersump=,,,724.98,m3,,,,,

,取,Vabsorbersump=,,725,m3,,,,,

,21.4吸收塔總高,,,,,,,,,

,漿液池位高度,,,,,,,,,

,H1=,,,11.39627988,m,,,,,

,,取,H1=,11.4,m,,,,,

,另外考慮到因注入氧化空氣引起的吸收塔漿液液位波動，漿液液位高度增加,,,,,,,0.5,m,

,取,H1=,12,m,,,,,,

,漿液液面距入口煙道高度H2,,,,,,,,,

,考慮到漿液鼓入氧化空氣和攪拌時液位有所波動，入口煙氣溫度較高、漿液溫度較低可對進(jìn)口管,,,,,,,,,

,底部有些降溫影響，加之該區(qū)間需接近料管，H2一般定位800mm～1300mm范圍為宜，此處,,,,,,,,,

,H2取,1.2,m,,,,,,,

,進(jìn)口煙道高度H3=,,4,m,,,,,,

,進(jìn)口煙道頂部距底層噴淋層高度H4=,,,,2.5,m,,,,

,噴淋層區(qū)域高度H5,,,,,,,,,

,設(shè)計噴淋層之間的間隔為,,,2,m,噴淋層數(shù),3,層,,

,H5=,4,m,,,,,,,

,除霧區(qū)高度H6=,,4,m,,,,,,

,出口煙道高度H7=,,3,m,,,,,,

,吸收塔總高H=H1+H2+H3+H4+H5+H6+H7=,,,,30.7,m,,,,

22,噴淋層設(shè)計,,,,,,,,,

,單層噴淋層漿液流量Q單循=,,,3372,Nm3/h,=,937,L/s,,

,假定噴嘴流量為,,5,L/s,,,,,,

,n=,Q單循/5=,187.4,,,,,,,

,,取整為,188,,,,,,,

,假定單管可選最大直徑Dmax=,,,0.06,m,,,,,

,噴淋管內(nèi)最大流速Vmax=,,,15,m/s,,,,,

,單噴管最大流量,,,,,,,,,

,"Qmax,s=π/4.Dmax2.Vmax=",,,42.41150082,L/s,,,,,

,,取,Qmax=,42.4,L/s,,,,,

,單噴淋層主噴管數(shù),,,,,,,,,

,,,23,,,,,,,

23,除霧器沖洗覆蓋率,,,,,,,,,

,設(shè)計噴嘴數(shù)量n=,,90,噴射擴(kuò)散角α=,,90,,,,

,除霧器有效流通面積A=,,,100,m2,,,,,

,沖洗噴嘴距除霧器表面垂直距離,,,0.8,m,,,,,

,沖洗覆蓋率=,,,,,180.9557368,%,,,

,,,,,取,181,%,,,

24,煙道尺寸設(shè)計,,,,,,,,,

,24.1凈煙氣煙道直徑,,,,,,,,,

,假定煙氣出口流速ω=,,18,m/s,,,,,,

,d=,,,4.068428945,m,,,,,

,,,d=,4.1,m,,,,,

,24.2原煙氣煙道直徑,,,,,,,,,

,Vactual=,286.394838,Nm3/s,,,,,,,

,取,Vactual=,286,Nm3/s,,,,,,

,d=,,=,4.497817432,m,,,,,

,,取,d=,4.5,m,,,,,

25,增壓風(fēng)機(jī)煙氣設(shè)計流量計算,,,,,,,,,

,"假定風(fēng)機(jī)入口煙氣溫度Tfan,in=",,,135,°C,,,,,

,100%BMCR工況下風(fēng)機(jī)入口處濕煙氣流量,,,,,,,,,

,"Qfan,in=",690000,Nm3/h,,,,,,,

,"Qfan,in,act=",,,,322.7529135,Nm3/s,,,,

,,,取,"Qfan,in,act=",323,Nm3/s,,,,

26,增壓風(fēng)機(jī)總壓損,,,,,,,,,

,假定吸收塔壓損,,10,mbar,GGH壓損,12,mbar,,,

,煙道壓損,7,mbar,考慮,20,%的裕量,,,,

,△Pd=,34.8,mbar,,,,,,,

,取,△Pd=,35,mbar,=,3500,Pa,,,

27,"電機(jī)功率Pf,d",,,,,,,,,

,假定風(fēng)機(jī)效率η1=,,85,%,電動機(jī)效率ηd=,,80,%,,

,增壓風(fēng)機(jī)所需功率Pf=,,,,1303.921569,kW,,,,

,,,取,Pf=,1