新高考數(shù)學(xué)一輪復(fù)習(xí)計(jì)算題精練專題12 定義域的運(yùn)算（解析版）

函數(shù)定義域的相關(guān)計(jì)算1．函數(shù)SKIPIF1<0的定義域?yàn)開_______.【解答】令SKIPIF1<0，可得SKIPIF1<0，解得SKIPIF1<0.故函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為:SKIPIF1<0.2．函數(shù)SKIPIF1<0的定義域?yàn)開_____.【解答】由SKIPIF1<0，解得SKIPIF1<0，所以SKIPIF1<0，即函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.3．函數(shù)SKIPIF1<0的定義域?yàn)開_____________.【解答】依題意，SKIPIF1<0，解得SKIPIF1<0，所以原函數(shù)的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<04．函數(shù)SKIPIF1<0的定義域是__________．（結(jié)果寫成集合或區(qū)間）【解答】由題設(shè)SKIPIF1<0，則SKIPIF1<0，即SKIPIF1<0，所以定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<05．求函數(shù)SKIPIF1<0的定義域?yàn)開________．【解答】函數(shù)SKIPIF1<0有意義，則SKIPIF1<0，即SKIPIF1<0，解SKIPIF1<0，得SKIPIF1<0，解SKIPIF1<0，得SKIPIF1<0，于是SKIPIF1<0，所以所求定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<06．函數(shù)SKIPIF1<0的最小值為___________.【解答】函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.由復(fù)合函數(shù)的單調(diào)性可知,SKIPIF1<0在SKIPIF1<0上單調(diào)遞減,在SKIPIF1<0上單調(diào)遞增.而SKIPIF1<0.所以,函數(shù)SKIPIF1<0的最小值為1.故答案為:1.7．求函數(shù)SKIPIF1<0的定義域?yàn)開_________________.【解答】SKIPIF1<0的定義域需要滿足SKIPIF1<0，即SKIPIF1<0，所以SKIPIF1<0，其中SKIPIF1<0，即SKIPIF1<0，故答案為：SKIPIF1<0.8．函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】根據(jù)題意，得SKIPIF1<0，解得SKIPIF1<0，所以函數(shù)的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.9．函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】SKIPIF1<0，SKIPIF1<0，SKIPIF1<0或SKIPIF1<0；所以定義域?yàn)椋篠KIPIF1<0.故答案為：SKIPIF1<010．函數(shù)SKIPIF1<0的定義域?yàn)開_______.【解答】由SKIPIF1<0知SKIPIF1<0；又由SKIPIF1<0，故定義域?yàn)镽.故答案為：R11．函數(shù)SKIPIF1<0的定義域?yàn)開_______．【解答】由題設(shè)SKIPIF1<0，即SKIPIF1<0，所以SKIPIF1<0，可得SKIPIF1<0，故函數(shù)定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<012．函數(shù)SKIPIF1<0的定義域是___．【解答】為使函數(shù)SKIPIF1<0有意義，需滿足SKIPIF1<0，即SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0，∴SKIPIF1<0且SKIPIF1<0，∴函數(shù)SKIPIF1<0的定義域是SKIPIF1<0且SKIPIF1<0.故答案為：SKIPIF1<0且SKIPIF1<013．若SKIPIF1<0，則SKIPIF1<0_________.【解答】由SKIPIF1<0有意義可得；SKIPIF1<0，所以SKIPIF1<0或SKIPIF1<0，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，SKIPIF1<0，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，SKIPIF1<0，故答案為：SKIPIF1<0或SKIPIF1<0.14．函數(shù)SKIPIF1<0的定義域是_________．【解答】要使函數(shù)有意義，需SKIPIF1<0；解得：SKIPIF1<0即SKIPIF1<0；故答案為：SKIPIF1<015．函數(shù)SKIPIF1<0的定義域是__________.【解答】由題意可得SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0.因此，函數(shù)SKIPIF1<0的定義域是SKIPIF1<0.故答案為：SKIPIF1<0.16．函數(shù)SKIPIF1<0的定義域是_____________.【解答】SKIPIF1<0的定義域滿足SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，故答案為：SKIPIF1<017．函數(shù)SKIPIF1<0的定義域?yàn)開__________.【解答】要使函數(shù)SKIPIF1<0有意義，則SKIPIF1<0，解得SKIPIF1<0，即函數(shù)的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.18．函數(shù)SKIPIF1<0的定義域是__．【解答】由SKIPIF1<0，得SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，所以函數(shù)的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.19．已知函數(shù)SKIPIF1<0的定義域?yàn)開______．【解答】函數(shù)SKIPIF1<0有意義，則有SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，所以函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<020．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，解得：SKIPIF1<0.故答案為：SKIPIF1<0.21．函數(shù)SKIPIF1<0的定義域是_________．【解答】解：由解析式可知SKIPIF1<0，故函數(shù)的定義域?yàn)椋篠KIPIF1<022．函數(shù)y＝SKIPIF1<0的定義域?yàn)開____．【解答】解：若函數(shù)有意義，則SKIPIF1<0，解得SKIPIF1<0，故函數(shù)的定義域?yàn)镾KIPIF1<0．故答案為：SKIPIF1<0．23．函數(shù)SKIPIF1<0的定義域?yàn)開__．【解答】要使函數(shù)函數(shù)SKIPIF1<0有意義，需滿足SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，故函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0且SKIPIF1<0，故答案為：SKIPIF1<0且SKIPIF1<024．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】由題設(shè)SKIPIF1<0，故SKIPIF1<0，故定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<025．函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】由題意得SKIPIF1<0，則定義域?yàn)镾KIPIF1<0，故答案為：SKIPIF1<0.26．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】要使SKIPIF1<0有意義，只需SKIPIF1<0，解得SKIPIF1<0，或SKIPIF1<0，所以函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.27．函數(shù)SKIPIF1<0的定義域是__________.【解答】要使函數(shù)有意義則：SKIPIF1<0，所以函數(shù)的定義域?yàn)镾KIPIF1<0，故答案為：SKIPIF1<0.28．函數(shù)SKIPIF1<0的定義域?yàn)開_________．【解答】由題意得，SKIPIF1<0，解得SKIPIF1<0，即函數(shù)定義域?yàn)镾KIPIF1<0，故答案為：SKIPIF1<0．29．函數(shù)SKIPIF1<0的定義域?yàn)開_____.【解答】由SKIPIF1<0，所以函數(shù)SKIPIF1<0的定義域?yàn)椋篠KIPIF1<0.故答案為：SKIPIF1<0.30．函數(shù)SKIPIF1<0的定義域?yàn)開____________.【解答】要使函數(shù)SKIPIF1<0有意義，只需SKIPIF1<0解得：SKIPIF1<0且SKIPIF1<0，從而SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<031．函數(shù)SKIPIF1<0的定義域是________.【解答】由題意得SKIPIF1<0，即SKIPIF1<0，解得SKIPIF1<0，故定義域是SKIPIF1<0.故答案為：SKIPIF1<032．函數(shù)SKIPIF1<0的定義域?yàn)開_________．【解答】因?yàn)镾KIPIF1<0，所以SKIPIF1<0，即SKIPIF1<0，所以定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.33．函數(shù)SKIPIF1<0的定義域?yàn)開_________．【解答】根據(jù)題意可得，SKIPIF1<0，解得SKIPIF1<0；即函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為:SKIPIF1<034．函數(shù)SKIPIF1<0的定義域是______．【解答】函數(shù)SKIPIF1<0的定義域滿足：SKIPIF1<0.故答案為：SKIPIF1<0.35．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】由題意可得SKIPIF1<0,故SKIPIF1<0，即SKIPIF1<0.故函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為:SKIPIF1<0.36．函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】函數(shù)SKIPIF1<0有意義，需滿足SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，故函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，故答案為：SKIPIF1<037．函數(shù)SKIPIF1<0的定義域是______.【解答】函數(shù)SKIPIF1<0有意義應(yīng)滿足SKIPIF1<0，解得SKIPIF1<0，故答案為：SKIPIF1<038．函數(shù)SKIPIF1<0的定義域?yàn)開___________．【解答】由題意SKIPIF1<0，解得SKIPIF1<0，即SKIPIF1<0；故答案為：SKIPIF1<0.39．已知函數(shù)SKIPIF1<0的定義域是_____________.【解答】函數(shù)SKIPIF1<0的定義域應(yīng)滿足SKIPIF1<0，解得SKIPIF1<0.故函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為:SKIPIF1<0.40．函數(shù)SKIPIF1<0的定義域是______.【解答】依題意SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，所以SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<041．函數(shù)SKIPIF1<0的定義域?yàn)開____________．【解答】由已知得SKIPIF1<0，解得SKIPIF1<0，即函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.42．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】要使函數(shù)SKIPIF1<0有意義，則需滿足SKIPIF1<0，解得SKIPIF1<0或SKIPIF1<0，所以函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.43．函數(shù)SKIPIF1<0的定義域?yàn)開_________.【解答】由已知得SKIPIF1<0，解得SKIPIF1<0且SKIPIF1<0，即函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.44．函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】函數(shù)的定義域需滿足SKIPIF1<0，解得：SKIPIF1<0且SKIPIF1<0，所以函數(shù)的定義域是SKIPIF1<0.故答案為：SKIPIF1<045．函數(shù)SKIPIF1<0的定義域是______.【解答】由SKIPIF1<0，得SKIPIF1<0，解得SKIPIF1<0或SKIPIF1<0，所以函數(shù)的定義域?yàn)镾KIPIF1<0.故答案為：SKIPIF1<0.46．已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，則函數(shù)SKIPIF1<0的定義域?yàn)開_____．【解答】因?yàn)楹瘮?shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，則SKIPIF1<0，所以SKIPIF1<0，則有SKIPIF1<0，解得：SKIPIF1<0，所以函數(shù)SKIPIF1<0的定義